WILL GIVE BRAINLIEST

Answer:

x=21

Step-by-step explanation:

69+90= 159

180-159=21

9514 1404 393

Answer:

  29

Step-by-step explanation:

Let w represent the number of wins. Then the number of losses is w-18. The total number of games played is ...

  wins + losses = 40

  w + (w-18) = 40

  2w = 58

  w = 29

The Rangers won 29 games.

Answer:

0.8

Step-by-step explanation:

Answer:

-1

Step-by-step explanation:

Answer:

8x + 245

Step-by-step explanation:

8(x + 30) + 5

8x + 240 +5

8x + 245

good luck, i hope this helps :)

Answer:

The opposite sides are always parallel.

Answer: 9420meters³

Step-by-step explanation:

The formula to calculate the volume of the cylindrical tank will be:

= πr²h.

where,

π = 3.14

r = radius = diameter/2 = 20/2 = 10

h = height = 30

Volume = πr²h

= 3.14 × 10² × 30

= 3.14 × 100 × 30

= 9420meters³

Answer:

c. is always true

Step-by-step explanation:

Answer:

8:6 and 16:12

Step-by-step explanation:

Answer:

hi

Step-by-step explanation:

Daniel bought 1 pound of jelly beans and 2 pounds of chocolates for $2.00. ... for $1.50. How much would he have to pay on his next trip to the candy store if he bought 1 pound of each of the 4 kinds ... How many are there? Assign ... Multiply each equation by a factor, so that all equations will have the same total price: 3(1j +.

Answer:

D) cannot factor

Step-by-step explanation:

D) cannot factor

D: cannot factor

it’s not factorable

Answer:

Step-by-step explanation:

36x⁴ /12x⁴ + 12x⁸ / 12x⁴

3x+x²

Answer:

a. [tex]dA(t)/dt = 50 - \frac{7A(t)}{400} where A(0) = 400[/tex]

b. [tex]A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}[/tex]

c. 3.717 kg

Step-by-step explanation:

a) Write the differential equation that represents the problem.

Let A(t) be the amount of dissolved oxygen in the tank at any time, t.

The net flow rate dA(t)/dt = mass flow in - mass flow out

Since 10 g/l of oxygen flows in at a rate of 5 l/min, the mass flow in is 10 g/l × 5 l/min = 50 g/min

Since A(t) is the amount of oxygen present in the tank at time, t, and the volume of the tank is 400 liters. The concentration of oxygen in the tank is thus A(t)/400 g/l.

Also, water is being pumped out at a rate of 7 l/min. So, the mass flow out is thus concentration × flow rate out = A(t)/400 g/l × 7 l/min = 7A(t)/400 g/min

So, dA(t)/dt = mass flow in - mass flow out

dA(t)/dt = 50 - 7A(t)/400 with A(0) = 400 l × 1 g/l = 400 g since the tank initially contains 1 g/l of dissolved oxygen and has a volume of 400 l

So, the differential equation is

dA(t)/dt = 50 - 7A(t)/400  where A(0) = 400 g

[tex]dA(t)/dt = 50 - \frac{7A(t)}{400} where A(0) = 400[/tex]

b) Solve the differential equation

To solve the equation, we use separation of variables, so

dA(t)/dt = 50 - 7A(t)/400  where A(0) = 400 g

dA(t)/(50 - 7A(t)/400) = dt

Integrating both sides, we have

∫dA(t)/(50 - 7A(t)/400) = ∫dt

-7/400 ÷ -7/400∫dA(t)/(50 - 7A(t)/400) = ∫dt

1/ (-7/400)∫-7/400dA(t)/(50 - 7A(t)/400) = ∫dt

(-400/7)㏑(50 - 7A(t)/400) = t + C

㏑(50 - 7A(t)/400) = -7t/400 + (-7/400)C

㏑(50 - 7A(t)/400) = -7t/400 + C'     (C' = (-7/400)C)

taking exponents of both sides, we have

50 - 7A(t)/400 = exp[(-7t/400) + C']

50 - 7A(t)/400 = exp(-7t/400)expC'

[tex]50 - \frac{7A(t)}{400} = e^{-7t/400}e^{C'} \\50 - \frac{7A(t)}{400} = Ae^{-7t/400} A = e^{C'}\\ \frac{7A(t)}{400} = 50 - Ae^{-7t/400} \\A(t) = \frac{400}{7} X 50 - \frac{400}{7} Ae^{-7t/400} \\A(t) = \frac{20000}{7} - \frac{400}{7} Ae^{-7t/400}[/tex]

when t = 0 , A(0) = 400. So,

[tex]A(t) = \frac{20000}{7} - \frac{400}{7} Ae^{-7t/400} \\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{-7(0)/400}\\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{0/400}\\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{0}\\A(0) = \frac{20000}{7} - \frac{400}{7} A\\400 = \frac{20000}{7} - \frac{400}{7} A\\\frac{400}{7} A = 400 - \frac{20000}{7}\\\frac{400}{7} A = \frac{2800}{7} - \frac{20000}{7}\\\frac{400}{7} A = -\frac{17200}{7}\\\\A = -\frac{17200}{7} X \frac{7}{400} \\A = -43[/tex]

So,

[tex]A(t) = \frac{20000}{7} - \frac{400}{7} X -43e^{-7t/400} \\A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}[/tex]

c) At 1 p.m., what is the amount of dissolve oxygen in the fish tank.

At 1 p.m, t = 60 min

So, the amount of dissolved oxygen in the fish tank is A(60)

So,

[tex]A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-7X60/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-420/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-1.05}\\A(60) = \frac{20000}{7} + \frac{17200}{7} X 0.3499\\A(60) = \frac{20000}{7} + \frac{6018.93}{7} \\A(60) = \frac{26018.93}{7} \\A(60) = 3716.99 g[/tex]

A(60) ≅ 3717 g

A(60) ≅ 3.717 kg

Answer:

it will take 12 hours

Step-by-step expl

Answer:

20%

Step-by-step explanation:

Not sure if this is exactly correct, but let's say we start with 1 unit. If it increased by 25%, we get:

1 × 1.25 = 1.25 units.

Now, to get back to 1 unit, we need to find:

1.25 × ?  = 1

? = [tex]\frac{1}{1.25}[/tex] = 0.80

So, 100% - 80 % = 20%

A 20% decrease.

Not completely sure though.

Answer:

C.

First, you square the x because it is inside the parentheses. Then, you multiply the -6 by 2, to get your exponent of -12 for the y.

Answer:

[tex] \huge \boxed{ \boxed{ \mathbb{C)} {x}^{2} {y}^{ - 12} }}[/tex]

Step-by-step explanation:

[tex] step - 1 : define[/tex]

[tex] {(xy}^{ - 6} ) ^{2} [/tex]

Answer:

(x, y) = (6, -6)

Step-by-step explanation:

Answer:

80 ft

Step-by-step explanation:

i dont really know if this is the right answer plz tell me if im wrong

Answer:

5n

Step-by-step explanation:

Answer:

Give me the questions and I'll edit my answer

Step-by-step explanation:

Answer:

what the question then I'll edit answer ;-;

Step-by-step explanation:

Answer:

A: 2

Step-by-step explanation:

EDGE 2021

Considering that the magnitude of the complex number x is of 13, a possible value of b is of 2.

A complex number is modeled by:

z = a + bi.

In which:

In this problem, the number is:

x = 3 + bi.

It's magnitude is given by:

[tex]|x| = \sqrt{3^2 + b^2}[/tex]

Then:

[tex]\sqrt{3^2 + b^2} = \sqrt{13}[/tex]

[tex]3^2 + b^2 = 13[/tex]

[tex]b = \pm \sqrt{4}[/tex]

[tex]b = \pm 2[/tex]

A possible value of b is of 2.

More can be learned about complex numbers at https://brainly.com/question/25572463

#SPJ2

Answer:

y = 5x + (anything except negative 10)

For example:

y = 5x + 5

Step-by-step explanation:

A parallel equation is any equation with the same slope, but a different y intercept. As long as your y intercept isn't - 10, your answer will be parallel.

Answer:

[tex]x \le 5[/tex]

Step-by-step explanation:

Given

Shape: Cube

Dimensions: x, 3x and 2x

[tex]Volume < 900[/tex]

Required

Show that [tex]x \le 5[/tex]

First, calculate the volume

[tex]Volume = x * 3x * 2x[/tex]

[tex]Volume = 6x^3[/tex]

[tex]Volume < 900[/tex] becomes

[tex]6x^3 < 900[/tex]

Divide both sides by 9

[tex]x^3 < 150[/tex]

For [tex]x^3 < 150[/tex], the value of x as to be: 1, 2, 3, 4 or 5

Hence:

[tex]x \le 5[/tex]

Answer:

huh?nani?

ksjn

lsjsmskkks

Answer:

wag na baka imyday mo pa

Step-by-step explanation:

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