Why do you need to combust benzoic acid before testing the "unknown" sample you are interested in? Why do you need to combust more than one sample of the "unknown" you are testing?

Answer:

chemical reactions In our daily environment are

1) Cooking food

2) Photosynthesis

3) rusting

4) painting

5) respiration

6) combustion

7) Electrochemistry (including chemical batteries)

8)Digestion

9)Soap and detergent reactions

10)Acid-base reactions

11) fermentation

12) oxidation

13 ) burning of paper

14) riping of fruits

15) frying egg

16) souring of milk

17) baking

18) heating sugar

19) burning wood

20) rising bread

Answer:

A.

Explanation:

Well, Nicola Tesla was from Croatia.

Albert Einstein was from Germany.

Thomas Edison was from the U.S.

So I think all over.

3 moles of NaOH reacts with 1 mole of phosphoric acid.

The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:

[tex]3\:NaOH + H_{3}PO_{4} \rightarrow Na_{3}PO_{4} + 3\:H_{2}O \\ [/tex]

Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.

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A is the initial reaction when a chlorine bond splits into two chlorine radicals.

In chemistry, a radical is an atom, molecule, or ion that has an unpaired valence electron.

The question is based on Radical Chain Reaction. And these reactions have three different phases: Initiation, Propagation and Termination.

Reaction A- Initiation

Reaction B- Termination

Reaction C- propagation

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Answer: it would be a 1 to 1 ratio

Explanation: originally it would be 2 to 2 but you have to reduce

0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

V=5 L

P = 1.05 atm

T = 296 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]n= \frac{1.05 atm\; X \;5 L}{ 0.08206 L.atm / mol K X 296 K}[/tex]

Moles = 0.216 moles

Hence, 0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.

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Answer:

0.014

Explanation:

Use the formula PV=nRT; there are calculators for it online as well.

A thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.

A  thermodynamically-controlled process is a reaction in which the ratio of the product formed is determined by the relative stability of the products.

Thermodynamic control ensures that the most stable or more stable of two products is formed.

Therefore, a thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.

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Specialized periodicals in which scientists publish the results of their works are called scientific journals.

In educational publishing, a scientific journal is a periodical book intended to similarly the progress of technology, typically by way of reporting new studies.

Journal articles may include original research, re-analyses of studies, opinions of literature in a selected place, proposals of new but untested theories, or opinion pieces.

These scientific journals include the following.

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It can be done. Normally the boiling point of water is 100°C. It will boil at temperature greater than 100°C more quickly. Water can be boiled at 95°C but for that the atmospheric pressure of the water should be decreased which will decrease the boiling point of water.

To boil water at 95°C, decrease the atmospheric pressure.

At 105°C, the water will be boiling quickly than normal at 100°C.

The best way is add alcohol .

The common way is that decrease the atmospheric pressure .

This will work as per Boyles law ,and boiling point can be decreased.

but it has few restrictions

Hence there is a spare way

General alcohols like ethanol,butanol can decrease the boiling point of water

0.5 moles of ethanoic acid are required to produce 0.5 mol of the ester , Option B is the right answer.

The reaction in which a carboxylic acid combine with an alcohol to form ester and water is called esterification reaction.

It is given in the question that

Ethanoic acid reacts with ethanol to form an ester and water

C₂H₅OH  +  CH₃​COOH  →   CH₃COOH  +  H₂O

The moles of ethanoic acid required to produce 0.5 mole of ester.

In the following reaction it can be seen that the mole fraction of ethanoic acid to ester is 1: 1

Therefore 0.5 mole of ethanoic acid will be required to produce 0.5 mol of ester.

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Answer:

A.  -10,000

Explanation:

When x approaches zero, the graph tells us that F(x) either becomes extremely large or extremely small.  The best answer is therefore A:  -10,000.  Best, because we aren't given the exact value of x, but clearly the other results require that x be greater than 1 or less than -1, which is far from zero.

Answer:

C

Explanation:

with combustion you must know that your products must be carbon dioxide and water. I think you copied your question incorrectly.

The molarity of the sodium ion in the solution is 0.450 M.

The molarity of the sodium ion in a solution can be determined by the dissociation of the given solution Na2SO4(sodium sulfate).

The dissociation of Na2SO4 is computed as follows:

i.e.

[tex]\mathbf{Na_2SO_4 \to 2Na^{+} + SO_4^{2-}}[/tex]

The molarity for sodium-ion [Na+] is:

= 2 × 0.225 M

= 0.450 M

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Answer:

[tex]\fbox {C}[/tex]

Explanation:

By repeating the experiment with new amounts of each reactant, this conflict can be resolved as we can see the effect of a reactant on the final amount of product formed.

The number of moles of aluminum powder needed to produce 203.7 grams of manganese is 5 moles.

Heat, Mn, and Al2O3 are produced when aluminum powder and manganese dioxide are heated.

[tex]3MnO_{2} + 4Al - > 3Mn + 2Al_{2} O_{3} + Heat[/tex]

The balanced chemical equation in this situation indicates that there are 3 moles of manganese and 4 moles of aluminum involved in the reaction, which results in a 3:4 mole ratio.

You may make use of this mole ratio by calculating how many moles of aluminum are required to react with the 203.7g of Manganese. So,

Firstly, the mass of Aluminium has to be taken out

Let the mass be considered x.

So, the number of moles of Aluminium = x/27

Number of moles of Manganese = 203.7/54

Hence, the mass x will be,

[tex]x = 4 *203.7 * 27 / 3 * 54[/tex]

[tex]x = 135.8g[/tex]

Hence,  the number of moles of Aluminium is = 135.8/27 = 5 moles.

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The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

The 18O label will appear at position b in the product as indicated in the image.

This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).

While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.

Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

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[tex](40.0)(7.426)=\boxed{297.0 \text{ g (to 4 sf)}}[/tex]

5 moles of MnO form from 5.0 mol Mn. Details about stoichiometry can be found below.

The number of moles of a substance can be calculated stoichiometrically as follows:

According to this question, the following chemical equation is given as follows:

2Mn + O₂ → 2MnO

2 moles of Mn forms 2 moles of MnO

Hence, 5 moles of Mn will form 5 × 2/2 = 5 moles of MnO.

Therefore, 5 moles of MnO form from 5.0 mol Mn.

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Answer: 10.0

Explanation: i took the test

The thickness of the walls of each hollow lump of iron ore is: 0.295cm. This is determined using the knowledge of the Volume of a Hollow Sphere.

The formula for the Volume of a Hollow Sphere is give as:

Volume of a Hollow = 4/3 R³ – 4/3 r³

Step 1 - Find the apparent volume of 8cm diameter sphere including the wall the the hollow inside

V = 4/3 r³

V = (4/3) (8)³

V = (4/3) * (22/7) * 512

V = 2145.52cm³

Step 2 - Determine the mass of Gold required for the sphere to achieve the density of iron ore if the apparent volume is as given in Step 1 above.

Recall that Mass = Density * Volume

Mass = 5.15 *  2145.52

Mass = 11049.45

Step 3 - Find volume of gold based on mass calculated in Step 2 above

Recall that :

Volume = Mass/Density

Thus,

V = 11049.4/19.3

Thus, Volume = 572.51cm³

Step 4 - Find the width of the wall of a hollow sphere for the volume realized in step 3

Recall the initial formula:

Volume of a Hollow = 4/3 R³ – 4/3 r³

Thus, 572.51 = (4/3) (8³ - (8 - t)³)

572.51 = (4/3) *(22.7) *(8³ - (8 - t)³)

572.51 = (88/21) *(8³ - (8 - t)³)

Multiply both sides by 21 and we have

88 (512 - (8 - t)³) = 12,022.71

Simplify further
(8 - t)³ = 357.38

t = 0.9035cm

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Answer:

Explanation:

Calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.

Ca(NO₃)₂

Thus, calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.

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Answer:

B)There are six atoms of oxygen.

C)There are two nitrogen atoms.

Explanation:

edge 2023

Answer:

yes so for example one

Explanation:

yeah so

Answer:

5.0 mol

Explanation:

From the coefficients of the equation, we know that for every 2 moles of Mn consumed, 2 moles of MnO are produced.

Thus, the number of moles of Mn consumed is equal to the number of moles of MnO produced, and thus the answer is 5.0 mol.

The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.

In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.

In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.

Thus, the moles of oxygen consumed by 7 moles of Mn is:

2 moles Mn = 1 mole O₂

7 moles Mn = 3.5 moles O₂

The available moles of O₂ = 5 mol.

The remaining moles of O₂ = 5-3.5 moles

The remaining moles of O₂ = 1.5 moles

The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.

The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂

1 mole O₂ = 2 moles MnO

1.5 moles O₂ = 2 * 1.5 moles MnO

1.5 moles O₂ = 3 moles MnO

Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.

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Answer:

T₂ = 26.7 °C

Explanation:

Because you are dealing with pressure and temperature, you can use Gay-Lussac's Law to find the final answer. The equation looks like this:

P₁ / T₁ = P₂ / T₂

In this form, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. You have been given the values for all of the variables but "T₂". Therefore, by plugging these values into the equation, you can simplify to find "T₂".

P₁ = 2.11 atm                   T₁ = 25 °C

P₂ = 2.25 atm                 T₂ = ?

P₁ / T₁ = P₂ / T₂                                            <--- Gay-Lussac's Law equation
(2.11 atm) / (25 °C) = (2.25 atm) / T₂           <--- Plug variables into equation

0.0844 = (2.25 atm) / T₂                            <--- Divide 2.11 by 25

(0.0844) x T₂ = 2.25 atm                           <--- Multiply both sides by T₂

T₂ = 26.7                                                    <--- Divide both sides by 0.0844

Answer: 3

Explanation:

Density is mass/volume divide the mass 9.6 by the volume of 3.2

[tex]\frac{9.6}{3.2} =3[/tex]

The density of the object displaced in water is equal to 3 g/ml.

The density of a substance can be described as the substance's mass per unit of its volume. The symbol is generally used to represent density ρ and the letter D can be used.

The mathematical formula of the density of a material can be represented as shown below:

Density = Mass/volume

ρ = m/V

The density of a material varies with pressure as well as temperature. There is a small variation in the density of the solids and liquids but much larger for gases. Increasing the pressure of the substance decreases the volume and thus increases its density.

As the object displaced water of volume of 3.2 ml.  

Therefore, the volume of the object, V = 3.2 ml

The mass of the object, m = 9.6 g

The density of the object placed in water can be calculated as:

Density of object = 9.6/3.2 = 3 g/ml

Therefore, the density of the object is 3 g/ml.

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Al₂(SO₄)₃

= 2.Al+3.S+12.O

= 2.27 + 3.32+12.16

= 54+96+192

=342 g/mol

Answer:

The point at which the lines intersect represents the triple point.