Answers
Answer:
The second and third equations are correct.
Step-by-step explanation:
Note that the equations are all the same, with the exception of the math operation (=,>,<,[tex]\leq[/tex], etc.). Let's do one calculation and then decide which of the statements is true.
The components may be simplified by separating the numbers from the exponents and doing the calculations separately:
(2.06x10^-2)(1.88x10^-1) becomes (2.06*1.88)*(10^-2 * 10^-1)
Left Side:
(2.06*1.88) = 3.91
(10^-2 * 10^-1) = 10^-3 [The exponents add when multiplying]
(2.06x10^-2)(1.88x10^-1) = 3.91x10^-3
Right side:
(7.69/2.3) = 3.343
(10^-2)/(10^-5) = 10^3 [The bottom exponent is subtracted from the top. ( -2 - (-5)) = 3 ]
(7.69x10^-2)/(2.3x10^-5) = 3.343x10^3
For all equations:
LEFT RIGHT
3.91x10^-3 3.343x10^3
We can now answer the question. Is the left side (3.91x10^-3 )
A. <
B. =>
C. >, or
D. =
to the right side (3.343x10^3)
We can drop the 10^-3 to make the comparison simpler, since it is the same on both sides. Think of it as dividing both sides by 10^3.
Correct?
A. 3.91 < 3.34 NO
B. 3.91 => 3.34 YES
C. 3.91 > 3.34, or YES
D. 3.91 = 3.34 NO
Related Questions
Please help me on this question!
Answers
Answer:
u = 10 ft
Step-by-step explanation:
cuboid volume = w × h × l
width * hight * length
560 = 7 × 8 × u
u = 10 ft
Answer:
u = 10 ft
Step-by-step explanation:
Volume of a rectangular prism = lwh
where:
l = lengthw = widthh = heightGiven:
Volume = 560 ft³width = 7 ftlength = 8 ftheight = uSubstitute the given values into the formula and solve for h:
⇒ 560 = 8 × 7 × u
⇒ 560 = 56u
⇒ 56u ÷ 56 = 560 ÷ 56
⇒ u = 10 ft
Therefore, the height of the prism is 10 ft.
question below
What matrix is the result of m*H?
Enter your answer by filling in the boxes. Enter any fractions as simplified fractions.
Answers
Answer:
[tex]m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right][/tex]
Step-by-step explanation:
Calculate the value of m
Given:
[tex]3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right][/tex]
Therefore:
[tex]\implies 3=\dfrac{2}{3}m[/tex]
[tex]\implies m=3 \times \dfrac{3}{2}[/tex]
[tex]\implies m=\dfrac{9}{2}[/tex]
Calculate the value of H
Given:
[tex]\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)[/tex]
Therefore:
[tex]\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right][/tex]
Calculating m × H
[tex]\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right][/tex]
[tex]\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right][/tex]
[tex]\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right][/tex]
Anne is visiting a friend who lives 18.5 km away. She travels 10 km by
train, 1.5 km by bus, and walks the rest of the way. If she walks at a rate
of 3.5 km per hour, for how long will Anne walk?
Answers
Answer:
Anne will walk for 2 hours.
Step-by-step explanation:
Distance formula = velocity × time
Total distance is 18.5 km
Anne travels by train = 10 km
and by bus = 1.5 km
let the distance covered by anne by walking be x
10 + 1.5 + x = 18.5
x = 18.5 - 10 - 1.5
x = 7km
Rate of walking is 3.5 km per hour
the time she will take while walking = 7 ÷ 3.5 = 2 hours.
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In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point (-2, 2, 0)?
Answers
The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m
How to calculate the electric field?Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,
The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k
Since V = 2x − 5x²y + 3yz²
dV/dx = d(2x − 5x²y + 3yz²)/dx
= d2x/dx - d5x²y/dx + d3yz²/dx
= 2 - 10xy + 0
= 2 - 10xy
dV/dy = d(2x − 5x²y + 3yz²)/dy
= d2x/dy - d5x²y/dy + d3yz²/dy
= 0 - 5x² + 3z²
= - 5x² + 3z²
dV/dz = d(2x − 5x²y + 3yz²)/dz
= d2x/dz - d5x²y/dz + d3yz²/dz
= 0 - 0 + 6z
= 6z
The electric field
So, E = -grad(V)
= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]
= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]
So, the electric field at (-2, 2, 0) is
E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]
E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]
E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]
E = -[42i + (-20 + 0)j + (0)k]
E = -[42i - 20j + 0k]
E = -42i + 20j - 0k
The magnitude of the electric field
So, the magnitude of E at (-2, 2, 0) is
|E| = √[(-42)² + 20² + 0²]
= √[1764 + 400 + 0]
= √2164
= 46.52 V/m
So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m
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If F= {(1,5), (4, 1), (2, 7)}and g= {(3, 1), (5 4) (-6,2)} represent fog in mapping of agram and to find fog in ordered pair form
Answers
From the given mappings, we have
[tex]f(1) = 5, f(4) = 1, f(2) = 7[/tex]
and
[tex]g(3) = 1, g(5) = 4, g(-6) = 2[/tex]
Then the composition of [tex]f[/tex] with [tex]g[/tex], or [tex]f\circ g[/tex], is
[tex]\boxed{f\circ g = \{(3,5), (5,1), (-6, 7)\}}[/tex]
since
[tex]g(3) = 1 \implies (f\circ g)(3) = f(g(3)) = f(1) = 5[/tex]
[tex]g(5) = 4 \implies (f\circ g)(5) = f(4) = 1[/tex]
[tex]g(-6) = 2 \implies (f\circ g)(-6) = f(2) = 7[/tex]
which of the following is a rational number
a.√5
b.π
c.1/2
d.√(77)
Answers
the quotient of two integers
find the area of the rectangle below
(3x+4) feet x
(x+3) feet
select the correct answer
Answers
Answer:
3x^2+ 13x + 12
Step-by-step explanation:
Multiply the length and width:
(3x+4) * (x+3)
FOIL method:
3x^2 + 9x + 4x + 12
Combine like terms
3x^2+ 13x + 12
Which equation represents the graph below?
Answers
Answer:
D
Step-by-step explanation:
The slope-intercept form is the equation of a straight line (y=mx+b)
m= gradient and b= y-intercept
m=2/3 (rise over run) b= 4 (it goes through the point (0,4)
y=(2/3)x+4
Get rid of the fraction by multiplying everything by 3
3y=2x+12
which is also -2x+3y=12
Maria is on a hike. if she hikes to the scenic lookout on the following map first, she will have to hike farther than if she went straight to the end of the hike. 3 connected points on a coordinate plane. the point labeled, "maria," is at 4, -4. the point labeled, "end," is at -5, 5. a solid line connect the points "maria" and "end." the point labeled, "scenic lookout," is at 2, 3. dashed lines connect "maria" to "scenic lookout" and connect "scenic lookout" to "end." coordinate values on the map are in kilometers. how much shorter is the path straight to the end of the hike than past the scenic lookout? round your final answer only to the nearest kilometer. \text{km}kmstart text, k, m, end text
Answers
The path straight to the end of the hike is 6 km farther than past the scenic lookout.
How to determine the difference in the parts?The map is not given, but the question can still be answered
From the question, the positions are given as::
Maria = (4, -4)
Scenic = (2, 3)
End = (-5, 5)
The distance between Maria and the end point is calculated using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]Route\ 1 = \sqrt{(4 + 5)^2 + (-4 -5)^2}[/tex]
[tex]Route\ 1 = 13[/tex]
The distance between Maria and the scenic lookout is calculated using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]Route\ 2 = \sqrt{(4 - 2)^2 + (-4 -3)^2}[/tex]
[tex]Route\ 2 = 7[/tex]
The distance between both routes is:
Distance = 13 - 7
Evaluate
Distance = 6
Hence, the path straight to the end of the hike is 6 km farther than past the scenic lookout.
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Peter's dog weighs 12 pounds more than Joe's dog. The dogs weigh 36
pounds all together. Write an equation to find the weight of Joe's dog.
Answers
Step-by-Step Explanation:
Let Joe’s dog’s weight be ‘x’ pounds
Peter’s dog’s weight be ‘x + 12’ pounds
Both dogs weigh 36 pounds together.
Therefore,
x + x + 12 = 36
2x + 12 = 36
2x = 36 - 12
2x = 24
x = 24/2
=> x = 12
Joe’s Dog’s Weight = x => 12
Peter’s Dog’s Weight = x + 12 => 24
Two planes that do not intersect are _____ parallel.
sometimes always never
Answers
Two planes that do not intersect are always parallel.
Can I have the solution with steps
Answers
Answer:
1/6
Step-by-step explanation:
As usual in trigonometry, there are so many relationships between the trigonometric functions, there is bound to be more than one method to arrive at the answer.
Knowing values for the sine and cosine function for certain angles on the unit circle proves to be quite helpful. In general, I recommend 0°, 30°, 45°, 60°, and 90° at a minimum.
Recall the following 6 things:
[tex]\cos(30^o)=\frac{\sqrt{3}}{2}[/tex][tex]\cos(60^o)=\frac{1}{2}[/tex][tex]\sin(30^o)=\frac{1}{2}[/tex][tex]\sin(60^o)=\frac{\sqrt{3}}{2}[/tex][tex]\tan(\theta)=\dfrac{\sin(\theta)}{\cos(\theta)}[/tex][tex]\tan^2(\theta)=\tan(\theta)\tan(\theta)[/tex]Knowing these 6 things (4 things from the unit circle, a way to write the tangent function in terms of sine and cosine, and the definition of a squared trig function), we can simplify the given expression down to a single number:
The definition of the tangent squared function is that the output of the tangent function is squared...
[tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1-(\tan(30^o))^2}{1+(\tan(60^o))^2}[/tex]
Using fact 5, and turning the tangent function into sines and cosines...
[tex]=\dfrac{1-\left(\frac{\sin(30^o)}{\cos(30^o)}\right)^2}{1+\left(\frac{\sin(60^o)}{\cos(60^o)}\right)^2}[/tex]
Using facts 1-4, and substituting known values for sines and cosines...
[tex]=\dfrac{1-\left(\frac{(\frac{1}{2})}{(\frac{\sqrt{3}}{2})}\right)^2}{1+\left(\frac{(\frac{\sqrt{3}}{2})}{(\frac{1}{2})}\right)^2}[/tex]
Division is multiplication by the reciprocal...
[tex]=\dfrac{1-\left(\frac{1}{2}*\frac{2}{\sqrt{3}}\right)^2}{1+\left(\frac{\sqrt{3}}{2}*\frac{2}{1}\right)^2}[/tex]
Reducing/simplifying common factors of 2...
[tex]=\dfrac{1-\left(\frac{1}{\sqrt{3}}\right)^2}{1+(\sqrt{3})^2}[/tex]
Squaring a square root...
[tex]=\dfrac{1-\left(\frac{1}{3}\right)}{1+(3)}[/tex]
Finding a common denominator...
[tex]=\dfrac{\frac{3}{3}-\frac{1}{3}}{4}[/tex]
Definition of subtracting fractions...
[tex]=\dfrac{\frac{3-1}{3}}{4}[/tex]
Arithmetic...
[tex]=\dfrac{\frac{2}{3}}{4}[/tex]
Division is multiplication by a reciprocal...
[tex]=\dfrac{2}{3}*\dfrac{1}{4}[/tex]
Simplification and reducing the fraction...
[tex]=\dfrac{1}{6}[/tex]
So, [tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1}{6}[/tex]
The nth term of a sequence is -2n - 4. Work out the 50th term of the sequence.
Answers
Answer:
-104
Step-by-step explanation:
1) Substitute 50 into n.
-2(50) - 4
-100 - 4
-104
La siguiente operación 147.3 = 441 es una:
División b- Sustracción c- Multiplicación
plis necesito la respuesta ahora dare estrellas lo juro
Answers
La operación que representa 147.3 = 441 es dada por una multiplicación, por eso opción c es correcta.
¿Qué operación está representada por 147 . 3 = 441?El resultado del producto entre 147 y 3 es de 441, por lo que se hace una operación de multiplicación.
Así, hay que la opción c es correcta.
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How much is the bill for a person who used 700 kWh in a month?
Answers
Answer:
700 kWh which is more than 200 so
0.10(x - 200) + 30
0.10( 700 -200)+ 30
0.10( 500) + 30
50 + 30
80
$80
Adam wins $30 in a "spot the ball" competition. He decides to save the money and opens a saving account with the $30. After his win, he continues to put $8 into his savings account each week. Identify a rule for the linear function that describes Adam's savings. Use the rule to find the amount Adam saved during the first 5 weeks.
Answers
Answer:
$110
Step-by-step explanation:
$30-$8=$22 each week
$22×5weeks=$110
What are the domain and range of the function below?
A. Domain: (-4,0)
Range: [-2,∞)
B. Domain: (-3,0)
Range: [-2,∞)
C. Domain: (-∞,∞)
Range: [-2,∞)
D. Domain:
Range: (-∞,∞)
PS don't mind that dot on the graph, didn't mean to put it there.
Answers
The domain is (-∞,∞) and the range is [-2,∞)
How to determine the domain and the range?From the graph, we can see that the x values extend at both sides of the graph.
This means that the domain is the set of real values i.e. (-∞,∞)
However, the minimum y value is -2 and it increases from their
This means that the range is [-2,∞)
Hence, the domain is (-∞,∞) and the range is [-2,∞)
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What is the best name for the part of the figure
identified by the arrow?
O line of reflection
O line of symmetry
O plane of reflection
O axis of symmetry
Answers
The best name for the part of the figure identified by the arrow is the plane of reflection option third is correct.
What is geometric transformation?It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.
We have given a three-dimensional figure.
As we can see the arrow is pointing at the plane.
A triangular prism is reflected over the given plane and creates a mirror image of a triangular prism.
A plane is a plane of symmetry.
Thus, the best name for the part of the figure identified by the arrow is the plane of reflection option third is correct.
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Solve x/3 = x+2/2. X=
Answers
Answer:
I will assume that the term "x+2/2" is meant to be "(x + 2)/2)." Otherwise the equation would read (x/3) = x + 1
Step-by-step explanation:
(x/3) = (x + 2)/2
x = 3*(x+2)/2 [Multiply both sides by 3]
x = (3x + 6)/2
x = (3/2)x + 6/2
x - (3/2)x = 3
-0.5x = 3
x = -6
====================
Check:
Does (x/3) = (x + 2)/2 for x = -6?
(-6/3) = (-6 + 2)/2
-2 = -4/2
-2 = -2 YES
Chloe bought an equal number of forks and spoons for a party. The forks were sold at 3 for 2$ and the spoons were sold at 4 for 3$. She spent 5$ more on spoons than on forks. How much did she spend altogether?
Answers
60 forks 60÷3=$20
60 spoons 60÷4=$15
$20+$15=$35 total spent for forks and spoons
36 students for 3 teachers =
1.0
5
12 students for 1 teacher.
Answers
Answer:
12
Step-by-step explanation:
36 divided by 3 =12 for 1 teacher
For her job, natasha spent a total of n minutes processing id card applications and driver's license applications. it takes natasha 15 minutes to process and id card aplication and 20 minutes to process a driver's license application. what is the value of n
Answers
Step-by-step explanation:
if I understand the question, write an equation for n in terms of i for number of Id cards an d for number driver license.
n = 15i + 20d
The value of n for a total minutes processing id card applications and driver's license applications would be 35 minutes.
Used the concept of addition that states,
The process of combining two or more numbers is called the Addition. The 4 main properties of addition are commutative, associative, distributive, and additive identity.
Given that,
For her job, Natasha spent a total of n minutes processing id card applications and driver's license applications.
And, it takes Natasha 15 minutes to process an id card application and 20 minutes to process a driver's license application.
Now by the given condition, we get;
n = 15 minutes + 20 minutes
n = 35 minutes
Therefore, the value n is 35 minutes.
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which of the following must be true?
Answers
Answer:
C
Step-by-step explanation:
Answer C is correct. The absolute value of 10 is 10 and that of -10 is 10. Same result.
If f(x) = 4x² + 1 and g(x)=x2-5, find (f- g)(x).
Answers
Answer:
3x² +6
Step-by-step explanation:
(f-g)(x) = f(x) -g(x) = (4x²+1) -(x²-5) . . . . . substitute the function definitions
... = 4x² +1 -x² +5 . . . . . . . . . . . eliminate parentheses
... = (4-1)x² +(1+5) . . . . . . . . . . . collect like terms
... = 3x² +6
3x[tex]3x^{2} +8x-10[/tex]
Answers
The solution to the quadratic equation 3x² + 8x - 10 by using the quadratic formula is x = 0.927 or -3.594
Solving quadratic equations.Quadratic equations are algebraic expressions that are represented in the power of the second degree. They usually take the form ax² + bx + c
From the given information, we are to solve the quadratic equation:
3x² + 8x - 10Using the quadratic formula:
[tex]\mathbf{=\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}[/tex]
where:
a = 3b = + 8c = - 10[tex]\mathbf{= \dfrac{-(8)) \pm \sqrt{(8)^2 - 4(3 \times (-10))}}{2(3)}}[/tex]
[tex]\mathbf{= \dfrac{-(8)) \pm \sqrt{64 -4 (-30)}}{6}}[/tex]
[tex]\mathbf{= \dfrac{-(8)) \pm \sqrt{64+120}}{6}}[/tex]
x = 0.927 or -3.594
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Select the correct answer.
What is the solution for x in the equation?
9-10x=2x+1-8x
OA.
O B.
O C.
O D.
x = 2
x = -2
X =
x
= -1
||
12
112
Answers
[tex]9-10x=2x+1-8x\\\\9-10x=-6x+1\\\\9=4x+1\\\\8=4x\\ \\ x=\boxed{2}[/tex]
The value of the x in the equation 9 - 10x = 2x + 1 - 8x is 2. The correct answer is A) x = 2.
An equation is a combination of numbers, variables, functions, and often symbols arranged in a peculiar order. The equation comprises two or more expressions distinguished by the equality sign(=). The equations are solved to estimate the values of variables.
The given equation is
9 - 10x = 2x + 1 - 8x
-10x - 2x + 8x = 1 - 9
-4x = -8
4x = 8
x = [tex]\frac{8}{4}[/tex]
x = 2.
Thus, the correct option is A) x = 2.
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The image of ΔABC after a reflection across Line E G is ΔA'B'C'.
2 triangles are shown. Line E G is the line of reflection. Line segment D D prime has a midpoint at point F. Line segment C C prime has a midpoint at point G. Points B and B prime share a point. Angle C G F is a right angle.
Which triangle must be a right triangle and why?
ΔA'B'C' is right because it is the image of ΔABC.
ΔADC is right because AA' intersects AC at A.
ΔBCC' is right because B lies of the line of reflection.
ΔBGC is right because Line E G is perpendicular-to CC'.
Answers
Δ DGC is right angled triangle because Line E G is perpendicular-to CC', Option D is the correct answer.
What is Triangle ?Triangle is a polygon with three sides , angles and vertices.
It is given that the there are two Triangles , ABC and A'B'C' as an image of the ABC
* Line segment AA' has a midpoint at point F
*D is the mid point of the line joining BB' .*
The figure is attached with the answer.
the line of reflection of the object is always perpendicular to the object and the image.
it is also given that CGF is a right angle.
Therefore triangle DGC is right angled triangle , (the option given in the question is incorrect ) , Line E G is perpendicular-to CC'.
Option D is the correct answer.
Please Refer to the image for correct coordinates.
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Which equation represents a side that is perpendicular to side d? O y = 2x+5 Oy=-2x+5 NG 0 Y=2x-5/2 OY--12-12 = Which equation represents a side that is perpendicular to side d ? O y = 2x + 5 Oy = -2x + 5 NG 0 Y = 2x - 5 / 2 OY -- 12-12 =
Answers
The equation represents a side that is perpendicular to side d is y = -2x+5. Option B is correct.
What is the slope?A numerical assessment of a line's angle relative to the ground is known as the slope.
The inclination of any line, ray, or line segment is the fraction of the perpendicular to the horizontal distance between any two positions on it.
The given linear equation in the problem is;
y = 2x+5
Compare the equation with the standard equation;
[tex]\rm y = mx+ c[/tex]
where,
m is the slope and c is the intercept. After comparing, we will get; Hence, the slope and y-intercept will be;
m = 2
The product of the slope of the two-line perpendicular to each will be -1.
m₁×m₂ = -1
The equation represents a side that is perpendicular to side d is;
y = -2x+c.
m₁=2
m₂=-2
m₁×m₂ = -1
The equation represents a side that is perpendicular to side d is y = -2x+5.
Hence, option B is correct.
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Please answer both questions math
Answers
Answer:
[tex]3[/tex] and perpendicular
Step-by-step explanation:
It's important to remember that equations of lines are always set up in the format of [tex]y=mx+c[/tex].
[tex]y[/tex] is the [tex]y[/tex] value, [tex]m[/tex] is the gradient/slope, [tex]x[/tex] is the [tex]x[/tex] value and [tex]c[/tex] is the y-intercept.
Therefore, we must always rearrange our line equations so that [tex]y[/tex] is the subject.
In the first question, we are given the equation [tex]2x+6y=12[/tex].
We rearrange to make [tex]y[/tex] the subject:
[tex]6y = 12-2x[/tex]
Then, we divide both sides by 6 to have the [tex]y[/tex] isolated:
[tex]\frac{6}{6} y = \frac{12}{6} - \frac{2}{6}x\\\\ y = 2 - \frac{1}{3}x[/tex]
To find a perpendicular slope, we use the negative reciprocal of the original slope. The negative part of that means we negate the value (it becomes inverse) and the reciprocal part means that we flip the fraction.
So here, the slope is [tex]-\frac{1}{3}[/tex].
So, the negative reciprocal of that would be [tex]3[/tex] because we inverse the sign (the negative becomes positive) and the fraction is flipped to create [tex]\frac{3}{1}=3[/tex].
So, the perpendicular slope is [tex]3[/tex].
In the second question, we have two equations. They both need to be rearranged to isolate the [tex]y[/tex].
[tex]4x-y=5\\4x = 5 + y\\y = 4x - 5\\\\4y = -x-12\\y = -\frac{1}{4}x - 3[/tex]
Look at the slopes of the two equations. If you look carefully, you will see that they are inverse of each other (one is positive and one is negative) and if you imagine [tex]4 = \frac{4}{1}[/tex], the fraction is flipped.
This means that the values are negative reciprocals of each other, meaning the lines are perpendicular.
The probabilities that Sani, Kolo and Tato will hit a target are 3/4, 2/3 and 7/3 respectively If all three men shot once what is the probability that target will be hit only once
Answers
Step-by-step explanation:
get the lcm of the numerals and the denominators then simplify
hope it is correct