Answer:
d. collection of photos taken by a person while moving around different places
Answer:
Moving object at equal time intervals
What is the total energy transported per hour along a narrow cylindrical laser beam 1.80 mm in diameter, whose B-field has an rms strength of
Am assuming the B-field has an rms strength of 1.10×10−10T which was omitted
Answer: E=1.686 x10⁻⁸J/hr
Explanation:
Intensity for electromagnetic wave is given as
I= cε₀(Emax)²....... equation 1
Also
B=Emax/c ....... equation 2
puting the value of B in equation 2 in equation 1 becomes
I= cε₀(Emax)²
I= c³ε₀B²
where
c = speed of light = 3 X 10⁸m/s
ε₀=permittivity of free space = 8.85x 10-12 F m-1
B=1.10×10−10T
I= (3 X 10⁸m/s)³ X (8.85 X 10⁻12F/m) x(1.10×10−10T)²
I=2.891 X 10⁻⁶ W/m²
Energy per unit hour
E= IAt
= 2.891 X 10⁻⁶ W/m² x πr²x 3600
2.891 X 10⁻⁶ W/m² x 3.142 x ( 1.80 x 10⁻³/2) x(3600/1hr)
E=1.686 x10⁻⁸J/hr
The total energy transported per hour will be 6.62 × 10⁻⁹J
Calculation of energy transported:The Intensity for an electromagnetic wave is given by:
I = cε₀E₀²
where c is the speed of light, and
E₀ is the maximum value of the electric vector
Also
B = E/c
where B is the magnetic field
Therefore:
I= cε₀E₀²
I= c³ε₀B²
Given that the magnetic field is:
B = 1.10×10⁻¹⁰ T
I= (3 X 10⁸m/s)³ X (8.85 X 10⁻12F/m) x(1.10×10−10T)²
I=2.891 X 10⁻⁶ W/m²
Energy transported per unit hour
E= IAt
where A is the area
and t is the time = 1hr = 3600s
E = 2.891 × 10⁻⁶ × πr² × 3600
E = 2.891 X 10⁻⁶ × 3.14 × ( 1.80 x 10⁻³/4)² x (3600)
E = 6.62 × 10⁻⁹J
Learn more about electromagnetic waves:
https://brainly.com/question/13803241?referrer=searchResults
Consider a rocket (initial mass m o) accelerating from rest in free space. At first, as it speeds up, its momentum p increases, but as its mass m decreases p eventually begins to decrease. For what value of m is p maximum
Answer:
m = m_o/e
Explanation:
The rocket equation is given as;
m(dv/dt) = -v_ex(dm/dt)
v_ex is the exhaust velocity
Now, formula for momentum is;
p = mv
Differentiating with respect to time, we have;
dp/dt = m'v + mv'
Where;
m' is mass rate
v' is rate of change in velocity
Since we are dealing with exhaust velocity and momentum(p) is Maximum when v = v_ex then mv' can also be written as: -m'v_ex.
Thus;
dp/dt = m'v - m'v_ex
dp/dt = m'(v - v_ex)
Now, from the rocket equation we dt will cancel out to give;
-dv/v_ex = dm/m
Integrating both sides;
-∫dv/v_ex = ∫dm/m
This gives;
-v/v_ex = In(m/m_o)
Since momentum(p) is Maximum when v = v_ex
Thus;
-v/v = In(m/m_o)
-1 = In(m/m_o)
e^(-1) = m/m_o
m = m_o(e^(-1))
m = m_o/e
A piece of pencil lead is connected in series with an ammeter and a power supply. The power supply is turned on. After a few minutes, although the potential difference across the pencil lead does not change, the current in the circuit increases significantly. Explain why the current increases.
Answer:
More electrons become free due to the potential which are charge carriers. More the charge carriers, more the current.
Current causes a heating effect. Resistance of lead decreases/ n increases [I=nAve]. Current increase
Explanation:
Find the resistance that must be placed in series with a 25.0Ω25.0 Ω galvanometer having a 50.0µA50.0 μA sensitivity (the same as the one discussed in the text) to allow it to be used as a voltmeter with a 0.100-V full-scale reading
Answer:
1975 ohm
Explanation:
The maximum current that can pass through the galvanometer is 50.0µA
p.d across the galvanometer at a full scale deflection is given by
V = IR
V = (50.0×10^-6)*25
V1 = 1/800 or 0.00125volts
Since the p.d across the multiplier and galvanometer at full scale deflection is 0.100volts,the p.d across the multiplier alone must be given by
V2 = 0.100-0.00125
= 0.09875volts
Current passing through the multiplier is (50.0×10^-6)A
Hence if R is the resistance of the multiplier, we have that
V2 = (50.0×10^-6)×R
0.09875volts = (50.0×10^-6)×R
Divide both sides by 0.09875volts
R = 0.09875/(50.0×10^-6)
R =( 0.09875) ÷ 1/20000
R = 0.09875×20000
R = 1975 ohms
A water balloon is thrown horizontally with a
speed of 8.31 m/s from the roof of a building of
height H=23.0 m. How far does the balloon travel
horizontally before striking the ground? (Use the
vertical formula Av=v0v+1 2aw/2 to solve for time
and plug your components into the equation for
the horizontal direction Ar-vxt)
Your answer
Answer:
18mExplanation:
Given
speed of water balloon = 8.31m/s
Height of building = 23.0m
Required
Horizontal distance
First we need to get the time using the equation of motion
S = ut + 1/2at²
23 = 0+1/2(9.81)t²
23 = 4.905t²
t² = 23/4.905
t² = 4.689
t = √4.689
t = 2.17secs
Next is to get the horizontal direction expressed as:
Sh = Vxt
Sh = 8.31 * 2.17
Sh = 17.99m
Sh ≈ 18m
Hence the horizontal distance of the object before striking the ground is approximately 18m
What is the net work, in joules, required to stop a bullet of mass 7.73 g that is moving at a speed of 409 m/s
Answer:
KE=1.58J
Explanation:
In this problem we are required to solve for the total energy
"The kinetic energy is the energy possessed by a body by virtue of motion"
KE=1/2mv²
Given
Mass m=7.73g
Velocity v=409m/s
In kg= 0.00773kg
KE=1/2*0.00773*409
KE=3.16157/2
KE=1.58J
A Carnot engine receives 250 kJ/s of heat from a heat source reservoir at 525 o C and rejects heat to a heat-sink reservoir at 50 o C. What are the power developed and the heat rejected
Answer:
Explanation:
efficiency of carnot engine = (Q₁ - Q₂) / Q₁ = (T₁ - T₂) / T₁
Q₁ = heat absorbed , Q₂ = heat rejected
T₁ = Temperature of source = 525 + 273 = 798 K
T₂ = Temperature of sink = 50 + 273 = 323 K
efficiency = (798 - 323) / 798
= 475 / 798 = .595
(Q₁ - Q₂) / Q₁ = .595
(250 - Q₂) / 250 = .595
250 - Q₂ = 148.75
Q₂ = 101.25 kJ
Heat rejected = 101.25 kJ .
output work = Q₁ - Q₂ = 250 - 101.25 = 148.75 kJ / s
power = 148.75 kJ /s
A spring stretches by 21.0 cm when a 135 N object is attached. What is the weight of a fish that would stretch the spring by 31 cm?
Answer:
199.28 N
Explanation:
It is given that,
A spring stretches by 21.0 cm when a 135 N object is attached.
We need to find the weight of a fish that would stretch the spring by 31 cm.
We know that, the force in a spring is given by as per Hooke's law as follows :
F = kx
Where k is spring constant
[tex]\dfrac{F_1}{F_2}=\dfrac{x_1}{x_2}\\\\\dfrac{135}{F_2}=\dfrac{21}{31}\\\\F_2=\dfrac{135\times 31}{21}\\\\F_2=199.28\ N[/tex]
So, the required weight of a fish is 199.28 N.
During which stage of sleep, also known as delta sleep, would a person have slow breathing and be difficult to wake.
A.
between stages 1 and 2 of non–rapid-eye-movement sleep
B.
in stage 4 of non–rapid-eye-movement sleep
C.
near the end of stage 3 of rapid-eye-movement sleep
D.
in stage 3 of non–rapid-eye-movement sleep
Answer:
In stage 3 so the answer is D
Answer:
It's D. in stage 3 of non-rapid-eye-movement sleep
Explanation:
**PLATO** "NREM-3 is when a person is in deep sleep and it lasts about 30 minutes. The person experiences slow breathing and pulse rates and limp muscles, and is difficult to wake. This stage is sometimes called delta sleep, because the brain produces slow delta waves."
If the wire is lowered farther from the compass, how does the new angle of deflection of the north pole of the compass needle compare to its initial deflection?
Answer:
The new angle of deflection north pole becomes smaller.
Explanation: The angle of deflection is the angle formed when an object changes course from its original course of direction or target.
The angle of deflection of a particular particle is directly proportional to its charge to mass ratio as it passed through an electric field.
As the wire is continously being lowered farther from the compass,the angle of deflection of the north pole ontinues to become smaller when compared to its initial deflection.
a model rocket of mass 0.5 kg is launched straight up. At an altitude of 140 m, when its speed is 90 m/s, it spontaneously blows apart into two equal pieces. One piece continues upward at a speed of 10 m/s. How fast is the other piece moving
Answer:
The other piece is moving at 170 m/s.
Explanation:
To find the speed of the second piece can be found by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{1}v_{1} = m_{2}v_{2} + m_{3}v_{3} [/tex]
Where:
m₁: is the rocket's mass = 0.5 kg
m₂ = m₃: is the mass of the two equal pieces = 0.25 kg
v₁: is the rocket speed = 90 m/s
v₂: is the speed of the first piece = 10 m/s
v₃: is the speed of the second piece =?
[tex] 0.5*90 = 0.25(10 + v_{3}) [/tex]
[tex] v_{3} = \frac{45}{0.25} - 10 = 170 m/s [/tex]
Therefore, the other piece is moving at 170 m/s.
I hope it helps you!
A 20 kg sled is coasting with constant velocity at 5 m/s over perfectly smooth, level ice. It enters a rough stretch of ice 20 m long in which the force of friction is 8 N. With what speed does the sled emerge from the rough stretch
Answer:
vf = 3 m/s
Explanation:
Applying the work-energy theorem, we know that the change in kinetic energy of the object while crossing the rough part of the ice, is equal to the work done by the friction force (as it is the only net force doing work on the sled), as follows:[tex]\Delta K = \frac{1}{2}* m* (v_{f}^{2} -v_{o} ^{2} ) = W_{Ffr} (1)[/tex]
Replacing for the givens, we get:
[tex]\Delta K = \frac{1}{2}* 20kg* (v_{f}^{2} -(5 m/s) ^{2} ) = -20 m * 8 N (2)[/tex]
Rearranging terms, and solving for vf, we get:[tex]v_{f} = \sqrt{-16 (m/s)2 + 25 (m/s)2} = \sqrt{9 (m/s2)} = 3 m/s[/tex]
vf = 3 m/s
Given that the tensile strength of aluminum foil is 311 megapascals, its thickness is approximately 15.0 micrometers, and a roll of household aluminum foil is 30.0 centimeters wide, how much force F is needed to pull off a sheet to use
Answer:
Explanation:
cross sectional area = width x thickness
A = 30 x 10⁻² x 15 x 10⁻⁶ = 450 x 10⁻⁸ m
tensile strength F / A = 311 x 10⁶ N / m²
F = A x 311 x 10⁶
= 450 x 10⁻⁸ x 311 x 10⁶
= 139950 x 10⁻²
= 1399.5 N .
In riot control, the riot squad uses a water hose that shoots water at a rate of 5 m/s and volume of 30 L/s. What is the average force exerted on a person assuming that the water splashes sideways in all directions? The density of water is 1000 kg/m3.
Answer:
The average force exerted on a person assuming that the water splashes sideways in all directions is 150 newtons.
Explanation:
From Fluid Mechanics and Newton's Laws we know that water stream is an example of a variable mass system at constant speed and the magnitude of the net force done by the water splash ([tex]F[/tex]), measured in newtons, is given by the following expression:
[tex]F = \rho\cdot \frac{dV}{dt}\cdot v[/tex] (Eq. 1)
Where:
[tex]\rho[/tex] - Density of water, measured in kilograms per cubic meter.
[tex]\frac{dV}{dt}[/tex] - Volume flow rate, measured in cubic meters per second.
[tex]v[/tex] - Flow velocity, measured in meters per second.
If we know that [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]\frac{dV}{dt} = 0.03\,\frac{m^{3}}{s}[/tex] and [tex]v = 5\,\frac{m}{s}[/tex], the average force exerted on a person is:
[tex]F = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(0.03\,\frac{m^{3}}{s} \right)\cdot \left(5\,\frac{m}{s} \right)[/tex]
[tex]F = 150\,N[/tex]
The average force exerted on a person assuming that the water splashes sideways in all directions is 150 newtons.
In which disorder does a person find it difficult to fall asleep or stay asleep for a long time?
A.
somnambulism
B.
narcolepsy
C.
insomnia
D.
sleep apnea
Answer:c
Explanation:
I have it
Answer:
C.
insomnia
Explanation:
plato answer
Which of the following statements is correct about the energy
of water stored in a tank?
1. Water stored in the tank has kinetic energy and potential
energy
2. Water stored in the tank has kinetic energy only.
3. Water stored in the tank has no energy.
4. Water stored in the tank has potential energy only.
Answer:
4. Water stored in the tank has potential energy only.
Explanation:
when water begins to move the potential energy is converted into kinetic but until it is being used it has potential energy only.
A car accelerates from a standstill to 60 km/hr in 10.0 seconds, what is its acceleration?
a= vf - vi/t
a= 60-0/10
a= 60/10
a= 6 m/s^2
Answer:
6 km/hr/s
Explanation:
need help with momentum!
Answer:
The total kinetic energy must be greater than the momentum of either ball
Explanation:
In order to solve this problem, we must clarify the following conditions, the balls are in motion that is, there is kinetic energy, the kinetic energy is a scalar magnitude, therefore this energy is greater than zero.
But however momentum is equal to zero, momentum is a vector quantity, that is, these velocities have a direction, momentum is defined as the product of mass by Velocity.
P = m*v (momentum lineal)
where:
P = lineal momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Since the masses of the balls are equal, we have:
m1 = m2
therefore:
m1*v1 + (m2*v2) = 0 (total momentum)
For the sum to be equal to zero, besides the equivalation of the masses, the velocities must also be equal, but the velocities must be of opposite sign, to meet equality to zero.
m1*v1 - m2*v2 = 0
And the kinetic energy of a body is defined by means of the following equation
Ek = 0.5*m*v²
Since the magnitude of the velocities is greater than zero, so that there is movement, we can say that the kinetic energy is much greater than zero, as well as greater than the total linear momentum
What is one way radio waves are used?
А
to carry signals for televisions
B
to kill germs in hospitals
с
to treat cancer with radiotherapy
D
to take images of bones
Answer:
A
Explanation:
because it is used in tvs all the time
A cart with a mass of 55 kg is pushed with a force of 220 N. What is the acceleration?
Answer:
4m/s^2
Explanation:
According to newton's second law of motion:
F= ma
a= F/m
F =220N
m =55kg
a= 220/55
= 4m/s^2
What is the angle between a wire carrying an 8.00-A current and the 1.20-T field it is in if 50.0 cm of the wire experiences a magnetic force of 2.40 N? (b) What is the force on the wire if it is rotated to make an angle of 90 ∘ 90∘ with the field?
Answer:
(a) the angle between the wire and field is 30⁰
(b) the force is 4.8 N
Explanation:
Given;
current in the wire, I = 8 A
magnetic field, B = 1.2 T
length of the wire, L = 50.0 cm = 0.5 m
magnetic force, F = 2.4 N
The magnetic force on the wire is given by;
F = BILsinθ
where;
θ is the angle between the wire and field
sinθ = F / BIL
sinθ = 2.4 / (1.2 x 8 x 0.5)
sinθ = 0.5
θ = sin ⁻¹ (0.5)
θ = 30⁰
(b) the force on the wire if it is rotated to make an angle of 90⁰
F = BIL(sin90⁰)
F = BIL(1)
F = BIL
F = 1.2 x 8 x 0.5
F = 4.8 N
What conditions are required so that the mechanical energy of a system is conserved? Select all that apply. View Available Hint(s) Select all that apply. No internal forces act on objects within the system. No net external force acts on the system No non-conservative forces, such as friction, act between objects within the system
Answer:
No non-conservative forces, such as friction, act between objects within the system
Explanation:
The law of conservation of mechanical energy in a closed system states that;'The total amount of mechanical energy, in a closed system in the absence of non-conservative forces, such as friction, remains constant.' Non-conservative forces cause energy to be lost from the system, this lost energy can't be gotten back
This implication of this is that energy can not disappear. Kinetic energy can be converted into potential energy and vice-versa in accordance with this principle.
The village blacksmith dunks a red-hot horseshoe into a large bucket of 22.0°C water. How much heat was lost by the horseshoe in vaporizing 0.0100 kg of water?
Answer:
25776J
Explanation:
Recall that heat lost/gained is obtained from
H=mcθ
H= heat lost/gained
m= mass of water = 0.0100 kg
c= 4200 J/kg°C
θ = temperature
Heat gained by the water in rising to 100°
H= 0.0100 * 4200 * (100-22)
H= 3276 J
Latent heat of vaporization of water = mL
Latent heat of vapourization = 0.0100*(22.5*10^5)=22500J
Heat lost by iron = heat gained by water
total heat gained by water =
22500+3276=25776J
A very bouncy ball is dropped from a height of 2.47 m to an asphalt playground surface and the height of its 5th bounce is measured to be 1.51 m. Find the coefficient of restitution of the ball for a collision with asphalt
Answer: the coefficient of restitution of the ball for a collision with asphalt=0.95
Explanation:
Initial height of the bounce from the ball, h =2.47m
height of the 5th bounce of the ball , h₁= 1.51m
Making e the coefficient of the restitution, then the height covered by the ball after the 5th bounce is
h₁= e²ⁿh
Where n = 5
h₁= e²⁽⁵⁾h
e¹⁰=h₁/h
e¹⁰=1.51/2.47
e= (1.51/2.47)¹/¹⁰
e=0.95198≈ 0.95
Therefore, the coefficient of restitution of the ball for a collision with asphalt is 0.95
Why do objects have specific colors?
Answer:
The color of an object is the wavelength of light that it reflects.
3. What would be the mass of a truck if it is accelerating at a rate of 5 m/s and hits a parked car with a
force of 14,000 N?
I
Answer:
We are given both the Force applied by the truck and the acceleration of the truck:
Force applied (F) = 14,000 N
Acceleration (a)= 5 m/s²
Solving for the mass of the truck:
From Newton's second law of motion,
F = ma (where F is the force applied , m is the mass of the object and a is the acceleration of the object)
replacing the variables:
14000 = (m)* 5
m = 14000/5
m = 2800
Therefore, the mass of the truck is 2800 kg
Answer:
m = 2800 N
Explanation:
14000 = (m)* 5
m = 14000/5
F= 14,000 N
a= 5 m/s^2
PLEASE HELP
You are walking to school one day and can't wait to give Mr. DeBaz the homework you finished. As you are walking down the street, a zombie comes out from behind the Dunkin' Donuts. He looks at you, growls, and starts coming after you. You are being chased by a zombie and you run 2 m/s. You are trying to get to the school, for safety, and it is 250 m away. How long will it take you to get there?
2. Which is a non-example of matter?
Answer: there are multiple
Explanation:
light from a torch, the heat from a fire, and the sound of a police siren. You cannot hold, taste, or smell these things. They are not types of matter, but forms of energy.
What is the speed of a jet plane that flies 8100 km in 27 hours (in km/hr)? *
A) 300 km/h
B )8100 km/h
C) 0.0033 km/h
D) 218700 km/h
Answer:
A
Explanation:
if you divide the 8100 km by the 27 hours you will get 300 km per hour
A running back weighing 100 kg runs headlong into a defender weighing 120 kg. The two players are moving at 7 m/s and 5 m/s, respectively. Calculate the total momentum and the total kinetic energy of the system. [Calculations including velocity should reflect direction of travel.]
Answer:
Explanation:
we know that momentum is given as
P=mv
given data
P1=?
mass m1=100kg
velocity v1=7m/s
P2=?
mass m2=120kg
velocity v2=5m/s
the total momentum =P1+P2
total=m1v1+m2v2
total= 100*7+120*5
total=700+600
total= 1300kgm/s
total kinetic energy
KE total= 1/2m1v1^2+1/2m2v2^2
KE total= 1/2*100*(7)^2+1/2*120*(5)^2
KE total= 1/2*100*49+1/2*120*25
KE total= 1/2*4900+1/2*3000
KE total=2450+1500
KEtotal=3950 J