Answer:
The answer is C
Explanation:
It just makes the most sense to me
How are a tundra and a desert different?
A desert has a low level of precipitation and a tundra has a high level of precipitation.
A desert is wet year-round and a tundra is dry.
A tundra has a lower levels of humidity.
A tundra has lower average temperatures year-round.
i am giving brainlyest!!!!!!!
Answer:
A tundra has a lower average temperatures year-round.
The air bags in automobiles were once inflated by nitrogen gas generated by the rapid decomposition of
sodium azide, NaN3.
2 NaNz (s) 2 Na (s) + 3 N2 (g)
If an air bag has a volume of 53.4 L and is to be filled with nitrogen gas at a pressure of 1.07 atm and a
temperature of 23.7°C, how many moles of NaNz must decompose? You may assume the Ny behaves as
an ideal gas.
Answer:
1.57 mol NaN₃
Explanation:
2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)First we use PV=nRT to calculate the number of N₂ moles that need to be produced:
P = 1.07 atmV = 53.4 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 KInputing the data:
1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86And solving for n:
n = 2.35 mol N₂Finally we convert N₂ moles into NaN₃ moles, using the stoichiometric coefficients of the balanced reaction:
2.35 mol N₂ * [tex]\frac{2molNaN_3}{3molN_2}[/tex] = 1.57 mol NaN₃Can somebody please help me!!!!
Answer and Explanation:
The answer is Motion.
We can see that part of the image is blurry, which shows that the fish are moving fast. Moving = motion, so that means the fish has motion.
#teamtrees #PAW (Plant And Water)
Answer:
motion
Explanation:
When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called..
The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1741 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 18.68 mL of the 0.1741-M Ce4+ solution is required to react completely with 30.00 mL of the H3AsO3 solution.
Calculate the concentration of the H3AsO3 solution.
Answer:
0.0542 M
Explanation:
Let;
CA = concentration of Ce4+ solution = 0.1741 M
VA = volume of Ce4+ solution = 18.68 mL
CB = concentration of H3AsO3 = ?
VB = volume of H3AsO3 = 30.00 mL
NA = Number of moles of Ce4+ solution = 2
NB = Number of moles of H3AsO3 = 1
From;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB = CAVANB/VBNA
CB = 0.1741 * 18.68 * 1/30.00 * 2
CB = 0.0542 M
How many moles of solute are present in 2 L of a 25M potassium nitrate (KNO3) solution?
0.5 moles
50 moles
25 moles
2 moles
50 moles
The formula used in this question is-
Mole= Molarity*Volume(in Litre)
So after putting the value
= (25)*(2)
=50 moles
What is molarity?
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
Learn more about Molarity here
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#SPJ2
How tightly particles are packed determines what state it takes.
True or False
Answer:
True
Explanation:
tighter the molecules the slower it moves and the harder it gets
solid has very tight particles packed together
gas has its particles spread out
The symbol for free energy is
a. DG.
b. DS.
c. DT.
d. DH.
As an FDA physiologist, you need 0.625 L of phosphoric acid acid / dihydrogen phosphate (H3PO4 (aq) / H2PO4 - (aq) ) buffer with a pH of 2.75. How do you prepare this solution from stock solutions of 1.0 M H3PO4 (formic acid) and 1.5 M NaOH
Answer:
0.4058L of 1.0M H3PO4
0.2192L of 1.5M NaOH
Explanation:
The pKa of the H3PO4 / H2PO4- buffer is 2.12
To solve this question we must use H-H equation for this system:
pH = pKa + log [H2PO4-] / [H3PO4]
2.75 = 2.12 + log [H2PO4-] / [H3PO4]
0.63 = log [H2PO4-] / [H3PO4]
4.2658 = [H2PO4-] / [H3PO4] (1)
Where [] could be taken as the moles of each reactant
As you have H3PO4 solution, the reaction with NaOH is:
H3PO4 + NaOH → H2PO4- + Na+ + H2O
As you can see, both H3PO4 and H2PO4- comes from the same 1.0M H3PO4 solution
The moles of H3PO4 are:
[H3PO4] = Moles H3PO4 - Moles NaOH
And for H2PO4-:
[H2PO4-] = Moles NaOH added
Replacing in (1):
4.2658 = [Moles NaOH] / [Moles H3PO4 - Moles NaOH]
4.2658 Moles H3PO4 - 4.2658 moles NaOH = Moles NaOH
4.2658 Moles H3PO4 = 5.2658 moles NaOH (1)
In volume:
0.625L = Moles H3PO4 / 1.0M + Moles NaOH / 1.5M
0.625 = Mol H3PO4 + 0.6667 Moles NaOH (2)
Replacing (2) in (1):
4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4 / 0.6667)
4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4) / 0.6667
4.2658 Moles H3PO4 = 5.2658*(0.9375 - 1.5 mol H3PO4)
4.2658 Moles H3PO4 = 4.9367 -7.8983 mol H3PO4
12.1641 mol H3PO4 = 4.9367
Mol H3PO4 = 0.4058moles * (1L / 1.0moles) =
0.4058L of 1.0M H3PO4
And:
0.625L - 0.4058L =
0.2192L of 1.5M NaOH
22.4 L is the volume of any gas regardless of atmospheric conditions.
O True
O False
What is the formula of compound formed from a calcium ion and As? Express your answer as a chemical formula
Answer:
its chemical formula is Ca3N2
Explanation:
hope it will help
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Answer:
ano po ito?? isa po ba itong story
The equation for the formation of ammonia from nitrogen and hydrogen is shown below. What is the formula for the equilibrium constant, Kc? {Hint, I’m just looking for letters/symbols, not numbers.}
H2(g) + N2(g) ⇌ NH3(g)
First, make sure to balance your equation.
3H2(g) + N2(g) ⇄ 2NH3(g)
Now, you can write your Kc expression. Remember that Kc is products over reactants, and the exponent for each product or reactant is based on its coefficient.
Kc = [NH3]^2 / [H2]^3[N2]
The reaction between nitrogen and hydrogen is called the Haber process. Kc for the reaction is the ratio of the concentration of ammonia to nitrogen and hydrogen.
What is the equilibrium constant?An equilibrium constant, kc is the concentration proportion of the products to the concentration of the reactants raised by their respective coefficients.
The balanced chemical Haber process is given as:
[tex]\rm 3H_{2}(g) + N_{2}(g) \leftrightharpoons 2NH_{3}(g)[/tex]
Now, the equilibrium constant for the reaction can be given as:
[tex]\rm Kc = \rm \dfrac{[NH_{3}]^{2}}{[H_{2}]^{3}[N_{2}]}[/tex]
Therefore, the ratio of the concentration of ammonia to hydrogen and nitrogen gives the equilibrium constant.
Learn more about the equilibrium constant here:
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7. The lowest whole-number ratio of the elements in a compound is called the
O empirical formula
O binary formula
O molecular formula
O representative formula
Answer: empirical formula is the answer. ur welcome.
Explanation:
Answer:
empirical formula
Explanation:
just took test
Arrange in terms of increasing atomic radius. From smallest to largest.
S, F, Sr, Na, Ga
Answer:
F<S<Na<Ga<Sr
Explanation:
Atomic radius increased from the right of the periodic table to left, and from the top to the down
The sum of the kinetic energy and the potential energy of a particle is its
Answer:
he total mechanical energy E of a particle is defined as the sum of the kinetic and potential energies
Explanation:
Answer:
thermal energy
Explanation:
Why is Potassium called an alkali metal?
Answer:
Explanation: potassium (Na) has one electron in outer shell
And it donates it easily and can even reduce
Hydrogen gas from water. An alkaline solution containing
Hydroxide ions (OH-) is then formed
Answer:
Because
Explanation:
Potassium is called Alkali metal because Potassium forms oxides which dissolve in water to form Alkali
True or False: Without electromagnetic energy, the world as we know it would not exist.
How many moles of C2H2 are required to produce 0.60 mol of H2O?
Express your answer to two significant figures and include the appropriate units.
Answer:
0.60 moles
Explanation:
From the reaction:
[tex]2C_2H_2 + 5O_2 \to 4CO_2+2H_2O[/tex]
From above, Only 2 moles of CH2CH2 are required to produce 2 moles of water (H_2O).
As such, 0.6 moles of H2O will require:
x (CH2CH2) × 2 moles of (H_2O) = 0.6 moles (CH2CH2) × 2 mole of (H_2O)
x mole of (CH2CH2) = 0.60 moles
∴
0.6 moles of H2O will require 0.60 moles of CH2CH2
Answer the following question by studying the given
structure of the stoma
1)Name the atoms of element
2)In which group of the periodic table do these element lie?
Answer:
1) A. carbon B. oxygen
2) A. semi metal. B. Non- metal( gas)
Which process takes place in the conversion of iron into steel?
Iron is changed into steel by blowing oxygen through the molten metal from the Blast Furnace. This oxidises the impurities in the molten metal. Carbon is a major impurity in Blast Furnace metal.
Observe the map what do the grey scar like represent?
Answer:
mid ocean ridge
Explanation:
A sample of hydrogen has an initial temperature of 122.0 °F. When the temperature is lowered to -23.0 °F, the volume of hydrogen becomes 212 cm3. What was the initial volume of the hydrogen?
Answer: The initial volume of gas was [tex]282cm^3[/tex]
Explanation:
Charles's Law: This law states that volume is directly proportional to temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas =?
[tex]V_2[/tex] = final volume of gas = [tex]212cm^3[/tex]
[tex]T_1[/tex] = initial temperature of gas = [tex]122.0^0F=323.15K[/tex]
[tex](32^0C=273.15K)[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-23.0^0F=242.59K[/tex]
[tex]\frac{V_1}{323.15}=\frac{212}{242.59}[/tex]
[tex]V_2=282cm^3[/tex]
Therefore, the initial volume of gas was [tex]282cm^3[/tex]
Which of the following statements about C3 carbon fixation is true? a. C3 carbon fixation is an adaptation for plants exposed to high light intensity. b. C3 carbon fixation occurs in more plants than C4 carbon fixation. c. C3 carbon fixation is more common in areas of high temperatures than C4 carbon fixation. d. C3 carbon fixation occurs in the inner cells of a leaf rather than the entire leaf.
Answer: The answer is B
Explanation:
RiP BoZo. shout out to faze gabi staright up bopped potato girl.
Answer:
B
:D
Explanation:
gloves worn when working with liquid oxygen must be able to resist.
Answer:
What is your question?
Explanation:
Can you give more context to ur question?
What's the wavelength in meters of an electron traveling at 9.5 x 10^7 m/s? The mass of an electron is 9.11 x 10^-28 g.
Select one:
a. 7.66 x 10-15 m
b.7.66 x 10-12 m
c. 3.47 x 1027 m
d. 3.47 x 1030 m
Answer:
where:
• A is the wavelength in m.
• h = 6.626 x 10-34Js is Planck's
constant.
• m is the mass of the particle, such as the electron, in kg. The particle must have a mass for this relation to work.
• v is the forward velocity of the particle, in m/s.
Hence, the wavelength is:
6.626 x 10-34J.s
(9.1094 × 10 −³¹kg) (5 × 10³m/s)
We know that 1 J 1 kg. m²/s². So:
6.626 × 10-³4 g · m² / ø
9.1094 x 10 - 31) (5 x 105 m/s)
= 1.455 x 10-9 m
=
= 1.455 nm
How many milliliters of 0.2560 M KCl solution will contain 20.00 g of KCl?
Answer is 1048 mL solution but how do I get to the answer?
Answer:
1048 mL
Explanation:
Step 1: Given data
Concentration of the solution: 0.2560 MMass of KCl (solute): 20.00 gStep 2: Calculate the moles corresponding to 20.00 g of KCl
The molar mass of KCl is 74.55 g/mol.
20.00 g × 1 mol/74.55 g = 0.2683 mol
Step 3: Calculate the volume of the solution
Molarity is equal to moles of solute divided by liters of solution.
M = moles of solute / volume of solution
volume of solution = moles of solute / M
volume of solution = 0.2683 mol / (0.2560 mol/L)
volume of solution = 1.048 L = 1048 mL
The gas phase decomposition of nitrogen dioxide at 383 °C
NO2(g)NO(g) + ½ O2(g)
is second order in NO2 with a rate constant of 0.540 M-1 s-1.
If the initial concentration of NO2 is 0.477 M, the concentration of NO2 will be
M after 12.4 seconds have passed.
Answer:
[tex][NO_2]=0.112M[/tex]
Explanation:
Hello there!
In this case, since the second-order integrated law is given by the following equation:
[tex]\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt[/tex]
Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:
[tex]\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}[/tex]
[tex][NO_2]=\frac{1}{8.933M^{-1}} =0.112M[/tex]
Best regards!
Human blood contains a buffer of carbonic acid (H_2 CO_3) and bicarbonate anion (HC〖O_3〗^-) in order to maintain blood pH between 7.35 and 7.45, as a value higher than 7.8 or lower than 6.8 can lead to death. In this buffer, hydronium and bicarbonate anion are in equilibrium with carbonic acid. Furthermore, the carbonic acid in the first equilibrium can decompose into CO_2 gas and water, resulting in a second equilibrium system between carbonic acid and water. Because CO_2 is an important component of the blood buffer, its regulation in the body, as well as that of O_2 , is extremely important. The effect of this can be important when the human body is subjected to strenuous condition.
Carbonic acid buffer:
H_2 CO_3 (aq)+ H_2 O(l) ↔H_3 O^+ (aq)+HC〖O_3〗^- (aq)
1. Write the equilibrium constant expression K_c for the carbonic acid buffer in the blood.
Kc = [H3O+][HCO3-] / [H2CO3]
Remember that Kc is products over reactants. Also, you do not include liquid water in a Kc expression, since liquid water has no concentration.
Part A. Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes Formula Nitric acid HNO3 Potassium hydroxide KOH Formic acid HCOOH Ethyl amine CH3CH2NH2 Sodium bromide NaBr Butanol C4H9OH Sucrose C12H22O11
Part B. Enter a molecular equation for the reaction that occurs between aqueous HBr and aqueous LiOH.
Answer:
1. Strong electrolytes = Nitric acid HNO3,Potassium hydroxide KOH, Sodium bromide NaBr
Weak electrolytes = Formic acid HCOOH Ethyl amine CH3CH2NH2, Butanol C4H9OH
Non-electrolyte = Sucrose C12H22O11
2. The reaction between aqueous HBr and aqueous LiOH is shown innthe equation below:
HBr + LiOH ----> NaBr + H₂O
Explanation:
Electrolytes are substances that when in molten state or in aqueous solution dissociate into ions both positively-charged and negatively-charged ions known as actions and anions, which are then able conduct electricity.
Strong electrolytes are aqueous or molten solutions of compounds which ionize completely to produce anions and actions. Ionic compounds such as organic salts, acids and bases are strong electrolytes.
Weak electrolytes only ionize partially, that is, they produce few ions. Some organic salts, acids and bases are weak elctrolytes
From the compounds given above;
Strong electrolytes = Nitric acid HNO3,Potassium hydroxide KOH, Sodium bromide NaBr
Weak electrolytes = Formic acid HCOOH Ethyl amine CH3CH2NH2, Butanol C4H9OH
Non-electrolyte = Sucrose C12H22O11
2. The reaction between aqueous HBr and aqueous LiOH is shown innthe equation below:
HBr + LiOH ----> NaBr + H₂O