Which is the dependent variable and what is the trend in the graph?
Experimental Solubility Data for a Sugar
140
130
120
110
Solubility (g/100g H,0)
100
90
80
0
10
50
60
20 30 40
Temperature (*C)
Solubility; decreasing
Solubility; increasing
Temperature; decreasing
Temperature; increasing

Answer: they become slower.

Explanation:  because they get pulled together.

Answer:

The atoms are pulled together by attractive forces and become more organized.

Explanation:

Atoms lose energy as a gas changes to a solid. ... Atoms gain energy as a solid changes to a liquid. If atoms energy during a change of state, they are pulled together by attractive forces and become more organized.

Reference by Quizlet.

Answer:

m = 0.172 [kg]

Explanation:

To solve this problem we must use the expression of thermal energy that relates the heat to the mass, the specific heat, and the temperature differential.

Q = m*Cp*(T_f - T_i)

where:

m = mass [kg]

Cp = specif heat = 126 [J/kg*C]

Q = 5000 [J]

T_f = final temperature = 250 [C]

T_i = initial temperature = 20 [C]

m = Q/ (Cp*(T_f - T_i))

m = 5000/ (126*(250 - 20))

m = 0.172 [kg]

The correct expression for the mass m of the bone is m=Fs-Fb/a.

The force is defined as the shear stress or pressure applied per unit area.

A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is m, the big dog’s leftward force magnitude is Fb and the small dog’s rightward force magnitude is Fs. The bone accelerates to the right along the table with no friction.

Across the bottom is green grass. In the center, there is a brown table with a large bone on top. To the left is a black outline of a large dog facing rightwards that is pulling leftwards on the bone. To the right is a black outline of a small dog facing leftwards that is pulling rightwards on the bone. The small dog stands on a grey box. Across the bottom is green grass.

Two dogs pulling on a large bone. Big dog and small dog images courtesy of pixabay. Consider rightward as the positive direction.

The net force acting on bone will be

F = Fs -Fb

From the Newton's second law of motion, Force  = mass x acceleration

F = ma

m = F/a

m = Fs-Fb/a

Thus, correct expression for the mass m of the bone is m=Fs-Fb/a.

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Answer:b

Explanation:

I got the answer right

The main advantage of using nuclear power over natural gas to generate the electricity that nuclear power does not contribute to climate change, therefore the correct answer is option B.

It is a particular kind of power plant where electricity is produced using a nuclear reactor that may use nuclear fusion or nuclear fission .

When a radioactive substance undergoes a nuclear reaction, a tremendous quantity of energy is produced .

As given in the problem , we have to find out what is an advantage of using nuclear power over natural gas to generate electricity .

Option B is the proper response , since employing nuclear power instead of natural gas to produce electricity has the advantage of not causing the climate change .

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Answer:

The object travels a distance of 40 meters before it stops.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time.

Torricelli's equation relates the speed to the space traveled by the body in u.a.r.m. To calculate the velocity of a body as a function of space, the expression is used:

[tex]v^{2} =v0^{2} +2*a*d[/tex]

Where :

In this case:

Replacing:

[tex](0\frac{m}{s} )^{2} =(20 \frac{m}{s} )^{2} +2*(-5\frac{m}{s^{2} }) *d[/tex]

Solving:

[tex]0\frac{m^{2} }{s^{2} } =400 \frac{m^{2} }{s^{2} } -10\frac{m}{s^{2} } *d[/tex]

[tex]0\frac{m^{2} }{s^{2} } -400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]

[tex]-400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]

[tex]\frac{ -400 \frac{m^{2} }{s^{2} }}{ -10\frac{m}{s^{2} }} = d[/tex]

40 m= d

The object travels a distance of 40 meters before it stops.

Answer:

C pollutants

Explanation:

Pollutants are dangerous substances in the ecosystem that are harmful to its organisms. They are contaminants and effluents that leads to pollution in the environment.  

Answer:

c

Explanation:

Answer:

The coordinates of the 4.0-kg mass must be [tex](x,y) = (-3\,m,-6\,m)[/tex].

Explanation:

We have a system formed by three particles with known masses and locations with respect to origin. The location of the center of mass is calculated by means of weighted means. That is:

[tex]\bar x = \frac{\Sigma\limits_{i=1}^{n}\,x_{i}\cdot m_{i}}{\Sigma\limits_{i=1}^{n}m_{i}}[/tex] (Eq. 1)

[tex]\bar y = \frac{\Sigma\limits_{i=1}^{n}\,y_{i}\cdot m_{i}}{\Sigma\limits_{i=1}^{n}m_{i}}[/tex] (Eq. 2)

Where:

[tex]\bar x[/tex], [tex]\bar y[/tex] - Coordinates of the center of mass of the system, measured in meters.

[tex]x_{i}[/tex], [tex]y_{i}[/tex] - Coordinates of the i-th particle, measured in meters.

[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.

If we know that [tex]m_{1} = 3\,kg[/tex], [tex]m_{2} = 1\,kg[/tex], [tex]m_{3} = 4\,kg[/tex], [tex]x_{1} = 0\,m[/tex], [tex]x_{2} = 12\,m[/tex], [tex]\bar x = 0\,m[/tex], [tex]y_{1} = 8\,m[/tex], [tex]y_{2} = 0\,m[/tex] and [tex]\bar y = 0\,m[/tex], the location of the 4.0 kg mass is:

[tex]\frac{(3\,kg)\cdot (0\,m)+(1\,kg)\cdot (12\,m)+(4\,kg)\cdot x_{3}}{3\,kg+1\,kg+4\,kg} = 0\,m[/tex]

[tex]12+4\cdot x_{3} = 0[/tex]

[tex]x_{3} = -3\,m[/tex]

[tex]\frac{(3\,kg)\cdot (8\,m)+(1\,kg)\cdot (0\,m)+(4\,kg)\cdot y_{3}}{3\,kg+1\,kg+4\,kg}= 0\,m[/tex]

[tex]24+4\cdot y_{3} = 0[/tex]

[tex]y_{3} = -6\,m[/tex]

The coordinates of the 4.0-kg mass must be [tex](x,y) = (-3\,m,-6\,m)[/tex].

The coordinates of the 4kg mass so that the center of mass of the three-mass system will be at the origin is (-3,-6)

The coordinates of the 3kg mass are (0.0 m, 8.0 m)

and the coordinates for the 1kg mass are  (12 m, 0.0 m)

Let the coordinates of the 4kg mass be (x,y)

The final coordinates of the center of mass of the system are (0,0),

so the equation for x-coordinate is given by:

[tex]0=\frac{3\times0+1\times12+4\times x}{3+1+4}[/tex]

12 + 4x = 0

x = -3

the equation for y-coordinate is given by:

[tex]0=\frac{3\times8+1\times0+4\times y}{3+1+4}[/tex]

24 + 4y = 0

y = -6

So, the coordinates of the 4kg mass are (-3,-6)

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Answer:

17.65N

Explanation:

We know that the relationship for the impulse and momentum is given as

Ft=mv

given data

mass m=0.15kg

t= 51ms= 26.5/1000= 0.051seconds

velocity v1= 21m/s

Velocity v2=15m/s

substituting in the expression we have

Ft=m(v1-v2)

make F subject of formula we have

F=m(v1-v2) /t

F=0.15(21-15)/0.051

F=0.15*6/0.051

F=0.9/0.051

F=17.65N

This question involves the concepts of momentum and impulse.

The average force of the bat on ball is "17.65 N".

According to Impulse Equation the change in momentum is equal to the product of applied force and time of contact. Mathematically:

[tex]\Delta P=F\Delta t\\\\F=\frac{m\Delta v}{\Delta t}[/tex]

where,

Therefore,

[tex]F=\frac{(0.15\ kg)(6\ m/s)}{0.051\ s}[/tex]

F = 17.65 N

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Answer:

V2=42.93cm3

Explanation:

According to Gay-Lussac's Law: "The Pressure Temperature Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. With an increase in temperature, the pressure will go up."

P1V1=P2V2

Given data

P1=4.25atm

V1=10.1cm³

P2=1atm

V2=?

V2=P1V1/P2

V2=(4.25*10.1)/1

V2=42.93cm3

Answer:

d. collection of photos taken by a person while moving around different places

Answer:

Moving object at equal time intervals

Answer:

Explanation:

In this problem we want to solve for the linear acceleration

Given data

radius r= 0.3m

angular acceleration α=17rad/s^2

we know that the expression relating angular acceleration and linear acceleration is given as

a=rα

Substituting we have

a=0.3*17

a=5.1m/s^2

Answer:

9.63 m

Explanation:

We know that

Δx = vt.

Therefore, v = Δx / t

v = 5 / 0.378

v = 13.23 m/s

h = ½gt, so that

h = ½ * 9.8 * 0.378²

h = 4.9 * 0.1429

h = 0.7 m

Finally, using the law of conservation of energy, we know that

½mv² = mg(H - h)

½v² = g(H - h)

½v²/g = H - h, substituting the values and solving, we have

(½ * 13.23²) / 9.8 = H - 0.7

(½ * 175) / 9.8 = H - 0.7

87.5 / 9.8 = H - 0.7

8.93 = H - 0.7

H = 8.93 + 0.7

H = 9.63 m

Answer:

Concave mirror

Explanation:

A concave mirror is a type that has the property of converging rays of light that are parallel to the principal axis to a point of focus. Thus, for the convergence of many rays of light (i.e a beam of light) as required in the given question, a concave mirror would serve the purpose. Curved mirrors have various applications in optics.

Answer:

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you

Explanation:

plz do so it is true

Answer:

9000 J

Explanation:

weight of bullet = 100 g

length of gun barrel = 0.6m

A) determine the work done by the gas on the bullet as the bullet travels the length of the barrel

The work done is an integral of force over distance in this scenario

lets represent the force using some constants ( arbitrary )

Fx = a  + bx + cx^2

where : a = 15000,  b = 10000, c = - 25000

hence work done ( W ) = [tex]ax_{f } + \frac{bx^{2} _{f} }{2} + \frac{cx^{3} _{f} }{3}[/tex]

where ; xf = 0.6

hence work done(W)

= 15000(0.6) + [(10000*0.6^2)/2] + [(-25000*0.6^3)/3]

 = 9000 J

Hi! Compressibility is the capacity of something to be flattened or reduced in size by pressure. I hope this helps you! Good luck and have a great day. ❤️

Answer:

D

Explanation:

Answer:

Hydroelectric power plants

Explanation:

This is because hydropower is a form of renewable energy that uses water stored in dams, rivers to create electricity

Answer:

2.385 m/s

Explanation:

Here there is a transformation of potential energy of the water at the top to Kinectic energy at the hole

This can be expressed as

Potential energy= Kinect energy

mgh= 1/2m v²

Where m= mass of water

h= Lenght below the level of the water that is in the tank.

v= the speed of the water as it leaves the hole

g= acceleration due to gravity= 9.81m/s

Here there is 'm' at both sides which can cancelled beach other out.

Then we have

gh= ¹/₂v²

making v² subject of the formular

v²=gh/(¹/₂)

v=√(2gh)

V=√2g h

V= √(2×9.81×0.29)

V=2.385 m/s

Therefore, the speed of the water as it leaves the hole is 2.385 m/s

Answer:the potential difference Vb − Va = -3 V

Explanation:

The potential difference Vb − Va s given by

Vb − Va=  Capacitance / Charge + current x resistance - Electromotive force

Vb − Va=Q/C + I X R - E

V=Q / C=(12 x 10^-3) / (3 x 10^-3)

=0.012/0.003ss

=4V

alsoV=  1R = 2.0 x 10^-3 x 4 x 10^3

=0.002 X 4000

=8

Vb − Va= 4V + 8V- 15V

= -3V

Therefore, the potential difference Vb − Va = -3 V

Answer:

Explanation:

The first train travels at a constant velocity of 80 mph and it takes 5 h to cover the  distance so distance between two station = 80 x 5 = 400 m

second train too takes 5 h to cover the same distance so its average velocity

= total distance / total time

= 400 / 5 = 80 m /h

average velocity = 80 m /h

Answer: 44.54 m/s

Explanation:

Let's break the problem into horizontal and vertical.

Horizontal:

Here we do not have any force, only a constant horizontal velocity, so we can write:

Vx(t) = 20m/s.

Vertical:

Here we have the gravitational acceleration acting on the rock, then we can write:

Ay(t) = -9.8m/s^2

For the vertical velocity, we need to integrate over time and get:

Vy(t) = (-9.8m/s^2)*t + V0

Where V0 is the initial vertical velocity, but the rock was thrown horizontally, so we do not have an initial velocity in the vertical axis.

Vy(t) = (-9.8m/s^2)*t.

Ok, now we want to know the magnitude of the velocity when t = 2.0s.

The magnitude will be equal to:

V = √( Vx(2s)^2 + Vy(2s)^2)

   = √(  (20m/s)^2 + (-2s*9.8m/s^2)^2) = 44.54 m/s

The magnitude of the velocity after 2 seconds is around 44.54 m/s

Answer:

Explanation:

weight of the car mg = m g

frictional force acting on the car = μ mg where μ is coefficient of friction

= m μ g

This force provides centripetal force , hence

m μ g  = m v² / R

μ = v² / rg

= 22 x 22 / 65 x 9.8

= .759  

Answer:

v₂f = 0.16 m/s (to the right)

Explanation:

        [tex]p_{o} = m_{1} * v_{o1} = 0.3 kg * 1.3 m/s (1)[/tex]

        [tex]p_{f} = m_{1} * v_{1f} + m_{2} * v_{2f} = 0.3 kg* (-0.86m/s) + 4.00 kg* v_{2f} (2)[/tex]

        As p₀ = pf, from (1) and (2), we can solve for v2f, as follows:

        [tex]v_{2f} = \frac{0.3kg* (1.3 + 0.86) m/s}{4.00kg} = \frac{0.3kg*2.16m/s}{4.00kg} = 0.16 m/s[/tex]

Answer:

200 kilometers per hour =

55.556 meters per second

Explanation:

have a great day

Answer:

200km × 1000m/1km = 200000 m

1h × 60 mins/h × 60sec/min = 3600s

now you divide 200000m/3600s

= 55.55m/s

Answer:

C. It is nonzero, because the net force is equal to the rate of change of the momentum

Explanation:

Momentum of an object is given as;

P = mv = ft

f = mv/t

or f = P/t

where;

P is the momentum of the object

m is mass of the object

v is velocity of the object

f is the applied force on the object

t is time

From the given equation above; the net force acting on the object is equal to the rate of change of the momentum, thus it is non-zero.

Therefore, the correct option is "C"

C. It is nonzero, because the net force is equal to the rate of change of the momentum.

The net force acting on the object is non-zero, because the net force is equal to the rate of change of the momentum. Hence, option (c) is correct.

The problem is based on the impulse-momentum concept. As per the impulse -momentum concept, the magnitude of impulse produced by an object is equal to the change in momentum. Then the expression is,

[tex]I = \Delta P[/tex]

here,

I is the magnitude of impulse. And its value is,

[tex]I = F \times t[/tex]

t is the impact time or time interval.

F is the magnitude of net force.

[tex]\Delta P[/tex] is the change in momentum.

Solving as,

[tex]I= \Delta P\\\\F \times t= \Delta P\\\\F = \dfrac{\Delta P}{t}[/tex]

Clearly, the net force is dependent of the change in momentum with respect to time. So, on increasing the momentum change with respect to time, the net force will also increase with non-zero value.

Thus, we can conclude that the net force acting on the object is non-zero, because the net force is equal to the rate of change of the momentum. Hence, option (c) is correct.

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