Which gland in the human body is a part of two human body systems (Digestive &
Endocrine)?
A. Testes
B. Ovaries
C. Both
D. Pancreas

Balanced Equation: 2 KCIO3 ⇒ 2 KCl + 3 O2

3 mol KClO3 x [tex]\frac{3 mol O2}{2 mol KClO3}[/tex] = 4.5 mol O2

Answer:

a. Larger molecular size

b. Ability to react with water

c. Polarity

d. Shorter bond length

Explanation:

Ethene is a larger molecule than oxygen and nitrogen hence it is more soluble than the both other gases .

SO2 dissolves readily in water to yield an acid solution. It is an acid anhydride.

Nitric oxide is a polar compound. It remains very much polar while nitrogen and oxygen are non polar.

Nitrogen is sp hybrized, this leads to a very short bond and does not easily interact with oxygen and nitrogen

the water will be increased

Answer:

The average speed must be 30mph so this means the car traveled for 2hrs 60/30

Explanation: solids are frozen like if you freeze tea it becomes a solid , liquids is like tea and gases is like when you boil water and it becomes a gas

Answer:

The correct answer is - 73.64 minutes.

Explanation:

We know that each gram of protein and carbohydrate produces 4 calories of energy whereas fat produces 9 cal energy per gram.

So, the Calories from carbohydrates

= 181 ×4

= 724 Cal

and, 27 g fat produces = 27 × 9 = 243 Cal

and, 16 g protien = 16 × 4 = 64 Cal

so the total energy will be - 243+ 724+ 64 = 1031 Cal

Thus, the time Fred need to run = 1031/14 =73.64 min

Answer:

The word “philosophy” literally means the “love” (philo in Greek) of “wisdom” (sophia). So, a philosopher is somebody who loves wisdom. This, of course, leaves us with 2 important questions: What is wisdom? And what does it mean to love wisdom?

The idea of philosophy goes all the way back to ancient Greece. It is said that the philosopher Pythagoras in the 6th century BCE was the 1st to call himself a philosopher—a philosophos, or “lover of wisdom.” In calling himself this, he was not claiming to be wise. Instead, he was merely saying that he was somebody who valued or cherished wisdom.

Later, the philosopher Plato, who lived in the 5th century BCE, explored these ideas in more depth. In a text called the Symposium, Plato claimed that a philosopher was somebody who was “between the wise and the ignorant.” In other words, a philosopher cared about wisdom but also knew that they were ignorant (we will see tomorrow how Plato was influenced in this by his teacher, Socrates).

Explanation:

Answer:

donate unused food to food banks

Explanation:

Becuse food banks processes food to make very fine particles which is mixed with soil and can be given to the plants

Answer:

symbiotic

Explanation:

There like a close friendship

Answer:

1. Wind speed

2. Wind change

3. Wind elevation

4. Wind direction

Answer:

For k12 its::

Explanation:

wind direction

wind speed

wind fetch

wind duration

Yw guys! ^^

Answer: Silver (I) fluoride molecule · AgF

Classification: Inorganic compound (Could be salt)

Ionic compound (Silver is a metal)

Valence of F (F must form an octet): 7

Valence of Ag: 11

Total valence electrons: 18

Molar mass: 126.87 g/mol

Explanation:

Answer:

8.45 × 10⁻²⁰ g

Explanation:

Step 1: Given data

Step 2: Calculate the mass, in grams, of 1 atom of Fe

We will use Avogadro's number: there are 6.02 × 10²³ atoms of Fe in 1 mole of Fe.

55.85 g/mol × 1 mol/6.02 × 10²³ atom = 9.27 × 10⁻²³ g/atom

Step 3: Calculate the mass corresponding to 912 atoms

9.27 × 10⁻²³ g/atom × 912 atom = 8.45 × 10⁻²⁰ g

Answer:

Explanation:

From the information given:

[tex]CaF_2 \to Ca^{2+} + 2F^-[/tex]

[tex]Ksp = 3.2 \times 10^{-11}[/tex]

no of moles of [tex]Ca^{2+}[/tex] = 0.01 L × 0.0010 mol/L

no of moles of [tex]Ca^{2+}[/tex] = [tex]1 \times 10^{-5} \ mol[/tex]

no of moles of [tex]F^-[/tex] = 0.01 L × 0.00010 mol/L

no of moles of [tex]F^-[/tex] = [tex]1 \times 10^{-6}\ mol[/tex]

Total volume = 0.02 L

[tex][Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\ \\ \[[Ca^{2+}}] = 0.0005 \ mol/L[/tex]

[tex][F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}[/tex]

[tex][F^{-}] = 5 \times 10^{-5} \ mol/L[/tex]

[tex]Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}[/tex]

Since Q<ksp, then there will no be any precipitation of CaF2

Answer:

The percent composition for nitrogen in chromium(III) nitrate is 6%.

Explanation:

The mass percent of nitrogen in chromium(III) nitrate is 17.655%.

Calculation,

Molar mass of one oxygen = 16 g

molar mass of nine oxygen = 9 × 16 g = 144 g

molar mass of one nitrogen atom = 14 g

molar mass of three nitrogen atom = 3 × 14 g = 42 g

molar mass of one chromium atom = 51.99 g

molar mass of chromium (III) nitrate molecule = 144 g + 42 g + 51.99 g = 237.99 g

Mass percent of nitrogen = mass of three nitrogen atom× 100 /mass of chromium(III)nitrate

Mass percent of nitrogen = 42 g/237.99 g × 100 = 17.655%

The percentage of the mass of the element or solute divided by the mass of the compound or solute is called mass percentage

learn about mass percentage,

https://brainly.com/question/16885872

#SPJ2

Answer:

Frogs

Explanation:

Answer:

Hello there! I'm assuming frog and or dog :)

Answer:

7

Explanation:

You divide the 14m/s by 2 and get the answer of the acceleration of 7

Answer:

100. mL

Explanation:

The computation of the volume in mL is shown below:

The balance equation of the double displacement reaction is

[tex]CaCl_{2} + Na_{2}CO_{3} \rightarrow 2 NaCl + CaCO_{3}[/tex]

Now determine the moles that corresponding to 1.00 g of CaCO₃

As,

The molar mass of CaCO₃ is 100.09 g/mol.

So,

= 1.00 g × 1 mol/100.09 g

= 0.0100 mol

Now

the moles of CaCl₂ needed to generate 0.0100 moles of CaCO₃

As we know that

The molar ratio of CaCl₂ to CaCO₃ is 1:1.

So, The moles of CaCl₂ needed is

=  1 ÷ 1 × 0.0100 mol

= 0.0100 mol.

Now volume of 0.100 M CaCl₂ that contains 0.0100 mol is  

= 0.0100 mol × 1 L/0.100 mol × 1000 mL/1 L

= 100. mL

Answer:

Bacteria are a type of biological cell. They constitute a large domain of prokaryotic microorganisms

some are good some are bad

Explanation:

Answer:

The octet rule is only applicable to the main group elements. The molecules of the halogens, oxygen, nitrogen, and carbon are known to obey the octet rule. In general, the elements that obey this rule include the s-block elements and the p-block elements (except hydrogen, helium, and lithium).

Explanation:

I hope this helps and pls mark me brainliest :)

Answer:

D

Explanation:

Answer:

193.5-195 °C.

Explanation:

Hello!

In this case, since the mixture is 50:50, we can infer that an average may be used to compute the required range; thus, we first compute the the inner limit by using 135 °C and 252 °C:

[tex]\frac{135+252}{2} =193.5\°C[/tex]

And the upper limit:

[tex]\frac{136+254}{2} =195\°C[/tex]

Thus, the average melting point would be around 193.5-195 °C.

Best regards!

Answer:

FALSE

Explanation:

false. kinematics equations are used for many purposes.it is used to drive equations and to find the motion of an object. but it is used more in physics rather than maths.

Answer:

What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?

Answer:

Implement rainwater harvesting systems to collect and store rainwater for drinking or recharging underground aquifers. Build wells to extract groundwater from underground aquifers. Provide home water-treatment capability through the use of filters, solar disinfection, or flocculants, to make drinking water safe.

Explanation:

the government of the United States preserves water sources by making waste water treatment and preventing water pollution

Answer:

0.03947 atm

Explanation:

The relationship between mmHg and atm is given as;

1 atm = 760 mmHg

x atm = 30 mmHg

Upon solving for x;

x * 760 = 30 * 1

x = 30 / 760 = 0.03947 atm

Answer: The final concentration of [tex]Cl_2[/tex] at equilibrium is 0.36 M

Explanation:

Moles of  [tex]PCl_5[/tex] = 0.64 mole  

Volume of solution = 1.0 L

Initial concentration of [tex]PCl_5[/tex] = [tex]\frac{moles}{Volume}=\frac{0.64mol}{1.0L}=0.64 M[/tex]

The given balanced equilibrium reaction is,

                     [tex]PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)[/tex]

Initial conc.       0.64 M         0M        0M  

At eqm. conc.     (0.64-x) M   (x) M      (x) M

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}[/tex]  

Now put all the given values in this expression, we get

[tex]0.47=\frac{(x)\times (x)}{(0.64-x)}[/tex]

By solving the term 'x', we get :

x = 0.36

Thus, the final concentration of [tex]Cl_2[/tex] at equilibrium is x = 0.36 M

The concentration of Cl2 is 0.36M.

Number of moles of PCl5 = 0.64 mol

Volume =  1.0 L

Concentration of PCl5 = 0.64 mol/1.0 L  = 0.64  M

The equation of the reaction is;

          PCl5 (g)→ PCl3 (aq) + Cl2 (g)

I         0.64            0                0

C       -x                 +x               +x

E     0.64 - x           x                  x

Kc = [PCl3] [Cl2]/[PCl5]

0.47 = x^2/0.64 - x

0.47(0.64 - x) =  x^2

0.3 - 0.47x =x^2

x^2 +  0.47x - 0.3 = 0

x = 0.36 M

The concentration of Cl2 is 0.36M.

Learn more about concentration:https://brainly.com/question/1195122

Answer:

thermal

Explanation:

a p e x

The full question is shown in the image attached to this answer

Answer:

6.2 * 10^-3

Explanation:

The reaction at equilibrium is as follows;

TiCl4(l) → Ti(s)+ 2Cl2(g)

We have to obtain the concentration of chlorine gas as follows;

[Cl2] = 1.08/70.91 g/mol × 5.2 L

[Cl2] = 0.079 M

Kc = [Cl2]^2

Kc = [ 0.079]^2

Kc = 6.2 * 10^-3

Answer:

a) the number-average molecular weight is 32,400 g/mol

b) the weight-average molecular weight is 36,320 g/mol

c) the degree of polymerization is 770

Explanation:

Given the data in the question;

Molecular                  Mean        Number      Weight      Number        Weight

weight                                                                             average         average

(g/mol)                    Mi(g/mol)         xi                wi          xiMi                  wiMi

8,000-16,000            12,000        0.07           0.03         840                360

16,000-24,000          20,000       0.15           0.09         3000              1800

24,000-32,000         28,000       0.26           0.21          7280              5880

32,000-40,000         36,000       0.27           0.27         9720               9720

40,000-48,000         44,000       0.18            0.28         7920              12320

48,000-56,000         52,000       0.07           0.12          3640              6240

∑                                                                                Mn=32,400     Mw=36,320

so;

a)  the number-average molecular weight

Mn = ∑Mixi

so from the table above; summation of Row Mixi

Mn = ∑Mixi = 32,400

Therefore, the number-average molecular weight is 32,400 g/mol

b) the weight-average molecular weight

Mw = ∑Miwi

so from the table above; summation of Row Miwi

Mw = ∑Miwi = 36,320

Therefore, the weight-average molecular weight is 36,320 g/mol

c) the degree of polymerization

the degree of polymerization of polypropylene can be determined using number-average molecular and repeat unit molecular weight.

now, for polypropylene { CH₂ = CH - CH₃ }

the repeat unit consist of 3 carbon atoms and 6 hydrogen atoms

given that;

Atomic weight of Carbon mC = 12.01 g/mol and

Atomic weight of  Hydrogen mH = 1.008 g/mol

now we find the repeat unit molecular weight of polypropylene

m = nCmC + nHmH

where n is the number of repeat of atoms

so we substitute

m = ( 3 × 12.01) + ( 6 × 1.008)

m = 36.03 + 6.048

m = 42.078 g/mol

now we calculate the degree of polymerization;

DP = Mn / m

so we substitute

DP = 32,400 / 42.078

DP = 769.9985 ≈ 770

Therefore,  the degree of polymerization is 770