Which equation represents a line that is perpendicular to the line on the graph ? O y = - 4x + 3 O O y = - 1/4 * x + 1 y = 1/4 * x - 2 O O y = 4x + 4

Answer:

813

* 9. 9*800= 7200

9*10. =90

7200

90. 9*3. =27

27

7317

The partial product is 7317.

The partial product method involves multiplying each digit of a number in turn with each digit of another where each digit maintains its place. (So, the 2 in 23 would actually be 20.)

Given:

9 x 813

Now, breaking the number according to their place value.

So, 813

=(800 + 10 +3)

Then the partial product will be written as

=9 * (800 + 10 +3)

=9* 800+ 9*10 + 9*3

=7200 + 90 + 27

= 7317

Hence, the partial product is 7317.

Learn more about partial product here:

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Answer:

B. 110

Step-by-step explanation:

In one day, Joe consumes 530 calories by drinking 1 serving of juice, 2 servings of milk, and 1 soda. Darius consumes 370 calories by drinking 2 servings of juice and 1 serving of milk. Marian consumes 510 calories by drinking 3 servings of milk and 1 soda. Using matrices to solve, how many calories are in 1 serving of milk?

A. 90

B. 110

C. 130

D. 180​

Answer:

Let x represent the amount of calories in 1 servings of juice, y represent the amount of calories in 1 servings of milk and z represent the amount of calories in 1 servings of Soda.

Joe consumption can be represented by:

x + 2y + z = 530           (1)

Darius consumption can be represented by:

2x + y = 370                 (2)

Marian consumption can be represented by:

3y + z = 510                  (3)

The equations can be represented in matrix form as:

[tex]\left[\begin{array}{ccc}1&2&1\\2&1&0\\0&3&1\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}530\\370\\510\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&2&1\\2&1&0\\0&3&1\end{array}\right] ^{-1}\left[\begin{array}{c}530\\370\\510\end{array}\right] \\\\\\[/tex]

[tex]\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}0.33&0.33&-0.33\\-0.67&0.33&0.67\\2&-1&-1\end{array}\right]\left[\begin{array}{c}530\\370\\510\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}130\\110\\180\end{array}\right][/tex]

The amount of calories in one serving of milk is 110 calories

Answer:

3 : 1

Step-by-step explanation:

The biggest circle has a radius of 20 cm

So that means, its area will be,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi * 20^{2}[/tex]

A = [tex]\pi * 400[/tex]

=> A = 400[tex]\pi[/tex]

We do not need to solve this because it is nit required

Then, one small circle has an area of,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi *5^{2}[/tex]

Area = [tex]\pi *25[/tex]

=> Area = 25[tex]\pi[/tex]

As there are 4 circles in, we get that the area covered by the small squares,

=> [tex]25\pi * 4[/tex]

=> [tex]100\pi[/tex]

So, the amount shaded = 100/400 (We can omit the [tex]\pi[/tex] at this stage because we are finding out a ratio)

=> 1/4

So, there is 1 cut region and the remaining is the uncut region,

As we need to find uncut to cut, the ratio will be,

=> remaining : 1

=> 3 : 1

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

Answer:

C) 53°

Step-by-step explanation:

We know that <3 and <4 are equal, so we can solve for y.

3y+7=5y-73

7+73=5y-3y

80=2y

y=40

Now plug that in to <3

3y+7=3(40)+7=127

We know that <3 and <2 equal 180.

180-127=53

So <2=53°

Answer:

one tree is 3 feet tall

most of the trees are less than 5 feet tall

Step-by-step explanation:

Answer:

x= 7.5

(that should be the answer)

Step-by-step explanation:

-7x+50 = x-10

10+50 = x+7x

60= 8x

60/8 = x

7.5= x

Answer:

-7 minus 9 = -16

-3-(-10) =7

8-12=-4

4-(-5)=9

Step-by-step explanation:

im in 7th grade on edginuity got it all right

592344435555544433234555

Answer:

The big container holds 30 gallons and the small container holds 20 gallons

Step-by-step explanation:

Let

The big container = x

Small container = y

The big container can hold 10 gallons less than twice the small

x = 2y - 10

Total gasoline in both containers = 50 gallons

x + y = 50

Substitute x = 2y - 10 into the equation

2y - 10 + y = 50

3y = 50 + 10

3y = 60

Divide both sides by 3

y = 60 / 3

= 20

y = 20 gallons

Recall,

x + y = 50

x + 20 = 50

x = 50 - 20

= 30

x = 30 gallons

The big container holds 30 gallons and the small container holds 20 gallons

Answer:

The big container has 30 gallons and the small container has 20 gallons.

Step-by-step explanation:

Answer:

Home Depot

Step-by-step explanation:

Home Depot Has better charges because you have to multiply the question to see which one is lower.

Answer:7 /13

Step-by-step explanation:

Answer:

[tex]Area = 270m^2[/tex]

Step-by-step explanation:

Given

[tex]A = \frac{1}{2}bh[/tex]

[tex]b = 18m[/tex]

[tex]h = 30m[/tex]

Required

Solve for A

Simply substitute 18 for b and 30 for h

[tex]A = \frac{1}{2}bh[/tex]

[tex]A = \frac{1}{2} * 18 * 30[/tex]

[tex]A = 270[/tex]

Hence:

The area is

[tex]Area = 270m^2[/tex]

Answer:   -2

:)

Step-by-step explanation:

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

[tex]A = \frac{1}{2}\cdot b\cdot h[/tex] (Eq. 1)

Where:

[tex]A[/tex] - Area of the triangle, measured in square centimeters.

[tex]b[/tex] - Base of the triangle, measured in centimeters.

[tex]h[/tex] - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

[tex]\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}[/tex] (Eq. 2)

Where:

[tex]\frac{dA}{dt}[/tex] - Rate of change of area in time, measured in square centimeters per minute.

[tex]\frac{db}{dt}[/tex] - Rate of change of base in time, measured in centimeters per minute.

[tex]\frac{dh}{dt}[/tex] - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

[tex]\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}[/tex]

[tex]\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}[/tex] (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

[tex]b = \frac{2\cdot A}{h}[/tex]

If we know that [tex]A = 130\,cm^{2}[/tex], [tex]h = 15\,cm[/tex], [tex]\frac{dh}{dt} = 2.5\,\frac{cm}{min}[/tex] and [tex]\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}[/tex], the rate of change of the base of the triangle in time is:

[tex]b = \frac{2\cdot (130\,cm^{2})}{15\,cm}[/tex]

[tex]b = 17.333\,cm[/tex]

[tex]\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)[/tex]

[tex]\frac{db}{dt} = -2.262\,\frac{cm}{min}[/tex]

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Answer:

1 oz

Step-by-step explanation:

Given that:

% solution of super grow fertilizer = 10%

To obtain mixture of 36oz of a 12.5% concentration

Let oz of pure supergrowth to be added = s

(Initial % * (36 - s) + s) / 36 = target concentration

(10% * (36 - s) + s) / 36 = 12.5%

(0.1(36 - s) + s) / 36 = 0.125

Cross multiply:

0.1(36 - s) + s =. 0.125 * 36

3.6 - 0.1s + s = 4.5

3.6 + 0.9s = 4.5

0.9s = 4.5 - 3.6

0.9s = 0.9

s =. 0.9/0.9

s = 1

Hence, 1 oz of pure supergrowth should be added to the 10% solution to get 36 oz of a 12.5% concentration.

Answer: 3

Step-by-step explanation:

N=7

Answer:

15

Step-by-step explanation:

Pretend a is the number.

We have: 31 + 3a = 76

=> 3a = 76 - 31 = 45

=> a = 45/3

=> a = 15

Answer:

This is literally me.

Step-by-step explanation:

Step-by-step explanation:

The answer is

[tex]q = \frac{cd}{p} [/tex]

Answer:

b

Step-by-step explanation:

Answer:

B) 8x + 6 + 4 = 3x - 2x - 4

Step-by-step explanation:

Just took the test on edg :)

Answer:

Cash it at the issuing bank (this is the bank name that is pre-printed on the check)

Cash a check at a retailer that cashes checks (discount department store, grocery stores, etc.)

Cash the check at a check-cashing store.

Deposit at an ATM onto a pre-paid card account or checkless debit card account.

Step-by-step explanation:

Answer:

Amscot?

Step-by-step explanation:

Answer:

R(x) = -50x2 + 300x + 2000

Maximum revenue of $2450 with x = 3

Step-by-step explanation:

For each 1$ reduced of the price, he sells 50 more candle sets, so if he reduces x times the price by 1$, the final price will be:

price = 10 - x

And the number of sets sold will be:

sets = 200 + 50x

If the revenue is the price times the number of sets sold, we have that:

R(x) = (10 - x) * (200 + 50x)

R(x) = 2000 + 500x - 200x - 50x2

R(x) = -50x2 + 300x + 2000

To find the value of x that gives the maximum revenue, we use the formula of the vertex of the quadratic equation:

x_v = -b / 2a

x_v = -300 / (-100) = 3

And the maximum revenue is:

R(x_v) = -50*3^2 + 300*3 + 2000 = $2450

Answer:

2606 + 7025 = 9631

Pls mark me brainliest

Answer: 9631

 2606

+7025

9631

Answer:

either 4032 or 56448

Step-by-step explanation:

you have to multiply length times height times width.

For section 3.01 black, number 1 is correct, but number 2 is wrong.

When you raise an exponent to an exponent, you multiply the 2 exponents.

(x^4)^5 is x^20.

Number 3 is also right.

For 3.02, you use the interest formula. (1 + i/100)^t times x

x is the amount of money you have originally. i is the interest rate, t is the time.

1,500(1.03)^5 = 1738.91111145

$1738.91

For section 3.01 red in fractional exponents the numerator are the powers and the denominator is the root.

[tex]\sqrt[4]{a^{3} } = a^{\frac{3}{4} }[/tex]

Answer:

For section 3.01 black, number 1 is correct, but number 2 is wrong.

When you raise an exponent to an exponent, you multiply the 2 exponents.

(x^4)^5 is x^20.

Number 3 is also right.

For 3.02, you use the interest formula. (1 + i/100)^t times x

x is the amount of money you have originally. i is the interest rate, t is the time.

1,500(1.03)^5 = 1738.91111145

$1738.91

For section 3.01 red in fractional exponents the numerator are the powers and the denominator is the root.

Step-by-step explanation:

Answer:

Step-by-step explanation:

the expression for compound interest is given as

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

A=$20,000

P=?

r=7.25%=0.0725

n=52 weeks

t=3 year

[tex]20000= P(1 + \frac{0.0725}{52})^{52*3}\\\\20000= P(1 + \frac{0.0725}{52})^{156}\\\\20000= P(1 +0.00139)^{156}\\\\20000= P(1.00139)^{156}\\\\20000=1.2419P\\\\P=20000/1.2419\\\\P=16104.35\\[/tex]

the manager need to invest $16,104.35

Answer: Whats the question? I dont see

Step-by-step explanation:

The image showing the complete question is attached.

Answer:

1) Scale factor = 2

2) Scale factor = 4

3) Scale factor = ½

4) Scale factor = 2

5) Scale factor = 1

6) Scale factor = ¼

7) Scale factor = 1

Step-by-step explanation:

Scale factor is a number by which the dimensions of an object are multiplied in order to create an enlarged or reduced object.

Now, from the image attached;

1) From P to Q, we see that the length of Q seems to be double that of P. Similarly, the width of Q seems to be double that of P. Thus, each dimension of P is said to be multiplied by 2 to achieve the enlarged dimensions of Q.

Thus, scale factor = 2

2) From P to R, we see that the length of R seems to be 4 times that of P. Similarly, the width of R seems to be 4 times that of P. Thus, each dimension of P is said to be multiplied by 4 to achieve the enlarged dimensions of R.

Thus, scale factor = 4

3) From Q to S, we see that the length of S seems to be half of that of Q. Similarly, the width of S seems to be half of Q. Thus, each dimension of Q is said to be multiplied by ½ to achieve the reduced dimensions of S.

Thus, scale factor = ½

4) From Q to R, we see that the length of R seems to be double that of Q. Similarly, the width of R seems to be double that of Q. Thus, each dimension of Q is said to be multiplied by 2 to achieve the enlarged dimensions of R.

Thus, scale factor = 2

5) From S to P, we can see that the dimensions of both rectangles remain the same. Thus, S was multiplied by a factor of 1 to get P. Scale factor = 1

6) From R to P, we see that the length of P seems to be a quarter that of R. Similarly, the width of P seems to be quarter of R. Thus, each dimension of R is said to be multiplied by ¼ to achieve the reduced dimensions of P.

Thus, scale factor = ¼

7) From P to S, we can see that the dimensions of both rectangles remain the same. Thus, P was multiplied by a factor of 1 to get S. Scale factor = 1