Answer:
Solar Cell
Explanation:
Claim 1: The sun (solar cells) is the best energy source for the rescue team.
Samantha was not feeling well. She had a fever and felt nauseous. Her mother took Samantha to the doctor who prescribed an antibiotic. What kind of infectious agent did Samantha have?
Group of answer choices
A)Parasitic
B)Fungal
C)Viral
D)Bacterial
Answer:
D
Explanation:
i did it before
Which would have the LEAST gravitational potential energy (GPE)? A ball sitting on the ground An airplane flying 30,000 feet above the ground A rock sitting on top of Mt. Everest
Answer:
(A) A ball sitting on the ground
Explanation:
The option with the least gravitational potential energy in the question is : A: A ball sitting on the ground.
Gravitational potential energy can be regarded as the energy that is been stored in an object due to its vertical position or height. The energy is stored in the object due to the gravitational attraction of the Earth as regards the object.To calculate the Gravitational potential energy, we can use[tex]U= mgh[/tex]
h= height of the object
m= mass of the object.
In The first option, the ball is on the ground, so it has no height or vertical position making it the least object with Gravitational potential energy. Unlike the airplane that is of some miles to the ground.Therefore, option A is right.
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what kind of bonds are there in H2O?
Answer: it is covalent and there are 2 hydrogen molecules and 1 oxygen molecule.
Explanation: it just is
Please help I need to turn this in already
Answer:
The acceleration will be .5 and the force will be 37.5
Have a nice day! :)
Answer:
Hello. The answer is 37.5N.
Explanation:
If you look carfully ، every time that you add one weight the force changes 2.5N so you can do this:
[tex](2.5 \times 5) + 25 = 37.5[/tex]
Determine each type of reaction. 2 C 2 H 2 ( g ) + 5 O 2 ( g ) ⟶ 4 C O 2 ( g ) + 2 H 2 O ( l ) 2CX2HX2(g)+5OX2(g)⟶4COX2(g)+2HX2O(l) Choose... N H 4 N O 3 ( s ) ⟶ N 2 O ( g ) + 2 H 2 O ( l ) NHX4NOX3(s)⟶NX2O(g)+2HX2O(l) Choose... C O ( g ) + 2 H 2 ( g ) ⟶ C H 3 O H ( l ) CO(g)+2HX2(g)⟶CHX3OH(l) Choose... 2 F e ( s ) + 6 H C l ( a q ) ⟶ 2 F e C l 3 ( a q ) + 3 H 2 ( g ) 2Fe(s)+6HCl(aq)⟶2FeClX3(aq)+3HX2(g) Choose... C a C l 2 ( a q ) + N a 2 C O 3 ( a q ) ⟶ 2 N a C l ( a q ) + C a C O 3 ( s ) CaClX2(aq)+NaX2COX3(aq)⟶2NaCl(aq)+CaCOX3(s) Choose...
Answer:
2 C 2 H 2 ( g ) + 5 O 2 ( g ) ⟶ 4 C O 2 ( g ) + 2 H 2 O ( l )- combustion reaction
N H 4 N O 3 ( s ) ⟶ N 2 O ( g ) + 2 H 2 O ( l )- decomposition reaction
C O ( g ) + 2 H 2 ( g ) ⟶ C H 3 O H ( l ) - combination reaction
2 F e ( s ) + 6 H C l ( a q ) ⟶ 2 F e C l 3 ( a q ) + 3 H 2 ( g )- Redox reaction
C a C l 2 ( a q ) + N a 2 C O 3 ( a q ) ⟶ 2 N a C l ( a q ) + C a C O 3 ( s )- double displacement reaction
Explanation:
We can determine the type of reaction by considering the reactants and products.
Combustion is a reaction between a substance and oxygen which produces heat and light. The first reaction is the equation for the combustion of ethyne.
A decomposition reaction is one in which a single reactant breaks down to form products. The second reaction is the decomposition of ammonium nitrate.
A combination reaction is said to occur when two elements or compounds react to form a single product. The third reaction is the combination of carbon dioxide and methane to form methanol.
An oxidation-reduction reaction is a reaction in which there is a change in oxidation number of species from left to right of the chemical reaction equation. The fourth reaction is the oxidation of iron (0 to +3 state) and reduction of hydrogen (+1 to 0 state).
A double displacement reaction is a reaction in which ions exchange partners from left to right in the reaction equation. The fifth reaction is a double displacement reaction. Both Na^+ and Ca^2+ exchanged partners from left to right of the reaction equation.
Reactions are the formation of the products from the reactant. The types of reactions are combustion, decomposition, combination, Redox and double displacement.
What are the types of reactions?The reaction is a chemical change in the properties of the reactant that forms the products. It can be of various types based on the formation of the product.
The first reaction is combustion as the reactants react and use oxygen to form heat, carbon dioxide and water. The combustion reaction of ethyne can be shown as,
[tex]\rm 2 C _{2} H _{2} ( g ) + 5 O _{2} ( g ) \rightarrow 4 C O _{2} ( g ) + 2 H _{2} O ( l )[/tex]
The second reaction is decomposition in which a single reactant decomposes to form two or more products. The decomposition of ammonium nitrate can be shown as,
[tex]\rm N H _{4} N O _{3} ( s ) \rightarrow N _{2} O ( g ) + 2 H _{2} O ( l )[/tex]
The third reaction is a combination reaction in which two compound or elements combines to form one product. The combination reaction between carbon monoxide and hydrogen to form methanol can be shown as,
[tex]\rm C O ( g ) + 2 H _{2} ( g ) \rightarrow C H _{3} O H ( l )[/tex]
The fourth reaction is redox and includes the oxidation and the reduction of the species of the reaction. In the reaction, iron undergoes oxidation and hydrogen reduction. The redox reaction can be shown as,
[tex]\rm 2 F e ( s ) + 6 H C l ( a q ) \rightarrow 2 F e C l _{3} ( a q ) + 3 H _{2} ( g )[/tex]
The fifth reaction is a double displacement reaction in which the calcium and sodium interchange their position in the product formation. The reaction can be shown as,
[tex]\rm C a C l _{2} ( a q ) + N a _{2} C O _{3} ( a q ) \rightarrow 2 N a C l ( a q ) + C a C O _{3} ( s )[/tex]
Therefore, the type of reactions is 1. combustion, 2. decomposition, 3. combination, 4. redox and 5. double displacement.
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An aqueous solution of calcium hydroxide is standardized by titration with a 0.117 M solution of hydrobromic acid.
Required:
a. If 24.7 mL of base are required to neutralize 16.0 mL of the acid. What is the molarity of the calcium hydroxide solution?
b. What volume of a 0.270 M hydrochloric acid solution is required to neutralize 22.8 mL of a 0.113 M calcium hydroxide solution?
c. How many milliliters of 10.8 M hydrobromic acid solution should be used to prepare 2.50 L of 0.400 M ?
Answer:
a) 0.0379 M
b) 24.89 mL
c) 0.09 mL
Explanation:
The equation of the reaction is:
2HBr(aq) + Ca(OH)2(aq) ---> CaBr2(aq) + 2H20(l)
a)
Concentration of acid CA = 0.117 M
Concentration of base CB= ??
Volume of acid VA = 16.0 ml
Volume of base VB = 24.7 ml
number of moles of acid NA = 2
number of moles of base NB= 1
From;
CA VA/CB VB = NA/NB
CAVANB =CBVBNA
CB = CAVANB/VBNA
CB = 0.117 *16 * 1/ 24.7 *2
CB = 1.872/49.4
CB = 0.0379 M
b)
CA = 0.270 M
CB = 0.113 M
VA = ??
VB =22.8mL
NA =2
NB =1
From;
CA VA/CB VB = NA/NB
CAVANB =CBVBNA
VA = CBVBNA/CANB
VA = 0.113 * 22.8 * 2/0.207 *1
VA = 24.89 mL
c)
using the dilution formula
C1V1 =C2V2
Where:
C1= initial concentration =10.8 M
V1 = initial volume = ??
C2= final concentration =0.400 M
V2= final volume = 2.5 L
V1 = C2V2/C1
V1 = 0.400 * 2.5/10.8
V1 = 0.09 mL
What is the most highly populated rotational level of Cl2 (i) 25deg C and (ii) 100 deg C? Take B=0.244cm-1.This question should not be resubmitted, it is a textbook question from the Atkins physical chemistry txtbook. 10 e.
Answer:
i
[tex]J_{m} = 20 [/tex]
ii
[tex]J_{m} = 22.5 [/tex]
Explanation:
From the question we are told that
The first temperatures is [tex]T_1 = 25^oC = 25 +273 =298 \ K[/tex]
The second temperature is [tex]T_2 = 100^oC = 100 +273 = 373 \ K[/tex]
Generally the equation for the most highly populated rotational energy level is mathematically represented as
[tex]J_{m} = [ \frac{RT}{2B}] ^{\frac{1}{2} } - \frac{1}{2}[/tex]
Here R is the gas constant with value [tex]R =8.314 \ J\cdot K^{-1} \cdot mol^{-1}[/tex]
Also
B is given as [tex]B=\ 0.244 \ cm^{-1}[/tex]
Generally the energy require per mole to move 1 cm is 12 J /mole
So [tex]0.244 \ cm^{-1}[/tex] will require x J/mole
[tex]x = 0.244 * 12[/tex]
=> [tex]x = 2.928 \ J/mol [/tex]
So at the first temperature
[tex]J_{m} = [ \frac{8.314 * 298 }{2* 2.928 }] ^{\frac{1}{2} } - 0.5 [/tex]
=> [tex]J_{m} = 20 [/tex]
So at the second temperature
[tex]J_{m} = [ \frac{8.314 * 373 }{2* 2.928 }] ^{\frac{1}{2} } - 0.5 [/tex]
=> [tex]J_{m} = 22.5 [/tex]
(a) Write a briefexperimental procedure for the chromic acid test.Include all observations such ascolor change, precipitation, etc.(5 points)(b) What functional groups can be distinguished by this test?(2points)(c) What is the reason for the color change if you get a positive chromic acid test?(3points)(d) Sketch a reaction mechanism for a positive chromic acid test with the above given molecules.(10points) g
Answer:
See explanation
Explanation:
a) -About 1-2 drops of the unknown is dissolved in approximately 1 mL of analytical grade acetone standard solution. The test solution is added and shaken thoroughly. If a positive test is not immediately observed, the set should be allowed to stand for 1-2 minutes. A positive result means the appearance of a green color.
b) The functional groups that can be distinguished by the test are alcohols and aldehydes.
Aldehydes give a positive test to chromic acid but ketones do not.
Primary and secondary alcohols give a positive test to chromic acid but tertiary alcohols do not.
c) Chromic Acid Test involves Cr in the +6 oxidation state. A positive test implies the reduction of orange Cr^6+ to green chromium Cr^3+.
d) The compounds were not shown but this image attached from lumen learning summarizes the reaction mechanism of chromic acid test.
What happens when the kinetic energy of molecules increases so much that electrons are released by the atoms,
creating a swirling gas of positive ions and negative electrons?
Matter changes to a solid state.
O Matter changes to a liquid state.
Matter changes to a plasma state.
Matter changes to a gaseous state.
Answer:
Matter changes to a plasma state
Explanation:
Plasma is superheated matter, so when matter is heated to the point that electrons are stripped off of atoms forming ionized gas. Palsma comprises over 99% of the observable universe. Plasma is visible in the form of stars, nebulas, and sometimes even auroras.
Answer:
C. Matter changes to a plasma state.
Explanation:
Correct on Edge 2022!!!
Good luck everyone, you got this! Have a great day!
what is the frequency of light emitted when the electron in a hydrogen atom undergoes a transition from energy level n
Complete question is;
What is the frequency of light emitted when the electron in a hydrogen atom undergoes a transition from energy level n=6 to level n=3?
Answer:
Frequency = 2.742 × 10^(14) s^(-1)
Explanation:
First of all, the energy of hydrogen electron from online values is;
E_n = -2.18 × 10^(-18) × (1/n²) J
n is the principal quantum number
We are told that hydrogen atom undergoes a transition from energy levels n = 3 to n = 6.
Thus, it means we have to find the difference between the electrons energy in the energy levels n = 3 to n = 6.
Thus;
E_n = E_6 - E_3
Thus;
E_n = [-2.18 × 10^(-18) × (1/6²)] - [-2.18 × 10^(-18) × (1/3²)]
E_n = (2.18 × 10^(-18)) × [-1/36 + 1/9]
E_n = 0.1817 × 10^(-18) J
From Planck expression, we can find the frequency. Thus;
E = hf
Where h is Planck's constant = 6.626 × 10^(-34) m²kg/s
Thus;
0.1817 × 10^(-18) = 6.626 × 10^(-34) × f
f = (0.1817 × 10^(-18))/(6.626 × 10^(-34))
f = 2.742 × 10^(14) s^(-1)
Atmospheric pressure arises due to the force exerted by the air above the Earth. At higher altitudes, the mass of the air above the Earth is _____ than at sea level, and atmospheric pressure therefore _____ with altitude.
Answer:
less, decreases
Explanation:
When the pressure of an atmosphere occurs because of the force exerted so at the time of the higher altitudes, the air mass i.e. above the earth should be less as the air is attracted towards surface of an earth because of the gravity and air contains the mass that shows near the surface area so automatically the air density reduced due to which the mass also decreased
6. A student is using colored beads to make a model of aluminum sulfate, Al2(SO4)3. Aluminum atoms are represented by blue beads, sulfur atoms by yellow beads, and oxygen atoms by green beads. What combination of beads should the student use for the model? F. 6 blue, 3 yellow, and 7 green G. 2 blue, 1 yellow, and 4 green H. 2 blue, 3 yellow, and 12 green J. 6 blue, 12 yellow, and 12 green
Answer:
H. 2 blue, 3 yellow, and 12 green
Explanation:
Aluminium atoms (Al) = Blue Beads
Oxygen Atoms (O) = Green Beads
Sulfur (S) = Yellow beads
From the compound Al2(SO4)3, the number of atoms present are;
Al = 2
S = 3
O = 12
This means the model would contain;
2 Blue beads
12 Green beads
3 Yellow beads
The correct option is; H. 2 blue, 3 yellow, and 12 green
Answer:
H
Explanation:
Al(blue):2
S(yellow):3
O(green):4*3=12
so 2 blue beads 3 yellow beads and 12 green beads don't time the 2*3 it's not the same compound
good luck!!!
When a substance changes its size, shape, or state, this is called a __________.
a
change of atoms
b
physical change
c
chemical change
d
change of state
Answer:
its a physical change
Explanation:
its b
The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.320 M NaOH. What is the initial concentration of HCl
This question is incomplete, the complete question is;
The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator.
The buret contains 0.320 M NaOH,
It requires 11.2 mL of the NaOH solution to reach the end point of the titration
What is the initial concentration of HCI?
Answer:
initial concentration of HCl is 0.3584 M
Explanation:
Given that;
the reaction between HCl and NaOH is 1:1 molar
HCl(aq) + NaOH(aq) -------> NaCl(aq) + H2O(l)
we know that molarity is the number of moles of solute per liter of solution
so moles of NaOH consumed
= ( 0.320 mol / 1000ml) × 11.2ml
= 0.003584 mol
now
0.003584 moles of NaOH reacts with 0.003584 moles of HCl
moles of HCl present in the 10.0ml solution = 0.003584 mol
therefore the initial concentration of HCl
= ( 0.003584 mol / 10.0ml )× 1000ml
= 0.3584 M
the initial concentration of HCl is 0.3584 M
Calculate the number of grams of CuSO4 found in 3.29 mL of a 4.00 M CuSO4 solution. ______ grams CuSO4
Answer:
0.0132 g CuSO₄
General Formulas and Concepts:
[tex]\text{Molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}[/tex]
Explanation:
Step 1: Define variables
3.29 mL
4.00 M CuSO₄
x g CuSO₄
Step 2: Define conversions
1000 mL = 1 L
Step 3: Solve
Convert mL to L: [tex]\text{3.29 mL}(\frac{\text{1 L}}{\text{1000 mL}} )[/tex] = 0.00329 LSubstitute: [tex]\text{4.00 M} \ CuSO_4=\frac{\text{x g} \ CuSO_4}{\text{0.00329 L}}[/tex]Multiply both sides by L: [tex]\text{0.01316} \ CuSO_4=\text{x g} \ CuSO_4[/tex]Rewrite: [tex]x = 0.01316 \ g \ CuSO_4[/tex]Step 4: Simplify
We are given 3 sig figs.
0.01316 g CuSO₄ ≈ 0.0132 g CuSO₄
The Earth can gain or lose matter. True False
Answer:
True
Explanation:
According to some calculations, the Earth is losing 50,000 metric tons of mass every single year, even though an extra 40,000 metric tons of space dust converge onto the Earth's gravity well, it's still losing weight.
Answer:
true
Explanation:
3. Why do elements in group 1-17 react to form bonds?
Answer:
Elements in the same group of the periodic table have the same number of valence electrons. These are the electrons in their outer energy level that can be involved in chemical reactions. ... All the elements in group 1 have just one valence electron. This makes them very reactive.
Explanation:
I'm being timed hurry please!Thank u!
Organic material provides nitrogen for plants. Which soil component contributes the most nitrogen to plants?
O clay
O humus
O sand
O slit
Answer: The largest one, and answer is Sand
Explanation:
Answer:
humus
Explanation:
A liquid has rhe following properties : one-phase,colorless,boils it varying temperature. Which of the following BEST describes this liquid
A.Solution
B.substance
C.suspension
D. Coarse mixture
Answer:
Solution
Explanation:
In science, the solution is a homogeneous mixture of two or more pure substances in proportional concentrations that can be continually varied up to what has been called the solubilization limit. The word solution is usually applicable to the fluid subatomic particle, but gaseous formulations are conceivable.
Problem:
[Ar]4s2
Identify the period (p) , group (g) and valence electrons block of the element
Answer:
it is Calcium (Ca)
4th period, 2nd group, 2 valence electrons
It is critical to watch or _________________ what is happening with every step of your experiment
It is critical to watch or observe what is happening with every step of your experiment
A stable atom of sodium contains 11 protons, 11 electrons, and 12 neutrons. Which is the composition of an ion of sodium?
A. 10 protons, 11 electrons, 12 neutrons
B. 11 protons, 11 electrons, 13 neutrons
C. 11 protons, 10 electrons, 12 neutrons
D. 12 protons, 11 electrons, 12 neutrons
If the earth was a guava fruit, the space where the seeds are would be the core/mantle
what is the mass of 2.0 moles of sodium
Answer:
The molar mass of Na (sodium) is 23.0 g/moles
Explanation:
Answer:
the molar mass of Na (sodium) is 23.0 g/mol.
Explanation:
A chemist measured the amount of calcium sulfide produced during an experiment. She finds that of calcium sulfide is produced. Calculate the number of moles of calcium sulfide produced.
Answer:
0.0836 mol
Explanation:
A chemist measured the amount of calcium sulfide produced during an experiment. She finds that 6.03 g of calcium sulfide is produced. Calculate the number of moles of calcium sulfide produced.
Step 1: Given data
Mass of calcium sulfide: 6.03 g
Step 2: Determine the chemical formula of calcium sulfide
Calcium cation has a charge +2 and sulfide anion has a charge -2. Then, the chemical formula of calcium sulfide is CaS
Step 3: Calculate the moles corresponding to 6.03 g of CaS
The molar mass of CaS is 72.14 g/mol. The moles corresponding to 6.03 g of CaS are:
6.03 g × (1 mol/72.14 g) = 0.0836 mol
What is the rule of Conservation of Mass?
Answer: It is the principle that matter cannot be created or destroyed.
Explanation:
Question 3
What is an area that is claimed by one or more
individuals?
A. Population
B. Carrying Capacity
C. Dispersion
D. Territory
Answer is D
Answer:
D. Territory
Explanation:
Territory is defined as an area that is claimed by one or more individuals.
Territory is often used as a form of ownership of land or water mass between two parties. It is important as it gives each party a knowledge of their designated areas.
This validates it being an area that is claimed by one or more parties as organisms use that to protect their interest of food, water and mates for their survival.
How many lbs are in 5 kilograms ?
Answer:
11.023 pounds
Explanation:
How many moles of each substance is produced when 7 moles of ammonium carbonate decompose?
(NH4)2CO3(s) ⟶ NH3(g) + CO2(g) + H2O(g)
Answer:
1. 14 moles of NH3 were produced.
2. 7 moles of CO2 were produced.
3. 7 moles of H2O were produced.
Explanation:
We'll begin by writing a balanced equation for the decomposition of ammonium carbonate, (NH4)2CO3.
This is illustrated below:
(NH4)2CO3(s) —> NH3(g) + CO2(g) + H2O(g)
There are 2 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NH3 as shown below:
(NH4)2CO3(s) —> 2NH3(g) + CO2(g) + H2O(g)
Now the equation is balanced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 2 moles of NH3, 1 mole of CO2 and 1 mole of H2O.
1. Determination of the number of mole of NH3 produced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 2 moles of NH3.
Therefore, 7 moles of (NH4)2CO3 will decompose to produce = 7 × 2 = 14 moles of NH3.
Therefore, 14 moles of NH3 were produced.
2. Determination of the number of mole CO2 produced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 1 mole of CO2.
Therefore, 7 moles of (NH4)2CO3 will also decompose to produce 7 moles of CO2.
Therefore, 7 moles of CO2 were produced.
3. Determination of the number of mole of H2O produced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 1 mole of H2O.
Therefore, 7 moles of (NH4)2CO3 will also decompose to produce 7 moles of H2O.
Therefore, 7 moles of H2O were produced.
A gaseous compound Y contains carbon and hydrogen only and has a density
of 1.696 g dm-3 at 95.3 kPa pressure and 298K. Assume that Y behaves ideally,
calculate its molar mass and deduce its molecular formula. Given 1kPa =1 x 103Nm-2
.
Answer:
[tex]M=44.06\frac{g}{mol}[/tex]
Explanation:
Hello.
In this case, knowing the temperature, density and temperature of Y which behaves ideally, we can write the ideal gas equation:
[tex]PV=nRT[/tex]
Whereas the moles are equal to the mass over the molar mass of Y:
[tex]PV=\frac{m}{M} RT[/tex]
Thus, solving for the molar mass we write:
[tex]M=\frac{mRT}{PV}[/tex]
Yet, since density is mass of over volume, we then write:
[tex]M=\frac{\rho RT}{P}[/tex]
Considering the pressure in atm and the density in g/L:
[tex]P=95.3kPa*\frac{1atm}{101.325kPa}=0.941atm\\\\\rho=1.696\frac{g}{dm^3} *\frac{1dm^3}{1L}=1.696\frac{g}{L}[/tex]
Therefore, by plugging the values in, we obtain:
[tex]M=\frac{1.696\frac{g}{L} *0.082\frac{atm*L}{mol*K}*298K}{0.941atm}\\\\M=44.06\frac{g}{mol}[/tex]
Thus, the gas may be propane ([tex]C_3H_8[/tex]) since it molar mass is 44.11 g/mol.
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