Answer:
C20
Explanation:
Element is a pure substance which is composed of atoms of similar elements. It can not be decomposed into simpler constituents using chemical reactions. Example: Carbon
Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass. It can be decomposed into simpler constituents using chemical reactions.
Example: Carbon monoxide.
Thus chemical symbol represents an element is C20
Pretty sure this is what you're looking for.
A gas has an initial volume of 5. 35l. What is the final volume if 588j of work is done on the gas by a constant external pressure of 2. 00atm?
Work done is the exchange of heat from the system and the surrounding. The final volume of the gas in the system is 2.45 L.
What is work done?Work done is the product of the pressure and the change in the volume of the gas in the system. The formula for work done is given as,
[tex]\rm w = -P\Delta V[/tex]
Given,
Initial volume = 5.35 L
Work done = 588 J
Pressure = 2.00 atm
Work done in joules is converted to L atm as, 588 joules = 5.80 Litres-atmosphere
Substituting values in the above equation:
[tex]\begin{aligned}\rm w &=\rm -P(V_{f} - V_{i})\\\\5.80 &= \rm - 2 (V_{f} - 5.35))\\\\5.80 - 10.7 &= \rm -2V\\\\&= 2.45\;\rm L\end{aligned}[/tex]
Therefore, 2.45 L is the initial volume of the gas.
Learn more about work done here:
https://brainly.com/question/25086088
#SPJ4
How many DIFFERENT ELEMENTS are in this compound?
H2SO4
Answer:
3 DIFFERENT ELEMENTS
Explanation:
H - Hydrogen
S- Sulfur
O- Oxygen
Therefore there are 3 elements
A solution is prepared by adding 91.9 g of ethanol, ch3ch2oh, to 481.0 ml of water. the final volume of the solution is 597.5 ml. assuming the density of water is 1.0 g/ml and the density of ethanol is 0.789 g/ml, calculate the molality of the ethanol in the solution.
Answer:
17.51M
Explanation:
first we make out what we've been given .
Mass of ethanol= 91.9g
volume of water = 481.0ml
volume of solution= 597.5ml
density of water = 1.0g/ml
density of ethanol= 0.789g/ml.
firstly find the volume of ethanol since the total volume of the solution is 597.5ml and we've been given the volume of water which is 481.0ml , we subtract the volume of water from the volume of the solution , to find out the volume of ethanol .
volume e =597.5ml - 481.0ml
= 116.5ml
Then we find the molecular mass of ethanol , which is 45.04g/mol .
then we find the number of moles of ethanol .
n=mass /molar mass
=91.9g/ 45.04g/mol
=2.04mols .
Then convert the volume from milliliters to liters , by dividing by a 1000 .
v= 116.5/1000
=0.1165L
since we have our number of moles and volume , we can now find the molarity . which is
M=n/v
= 2.04mols /0.1165L
= 17.51M .
Suppose 3.5g of calcium chloride reacts with 6.39g of silver nitrate.
How many moles of calcium nitrate would be produced?
Balanced Equation =
Limiting Reactant =
Excess Reactant =
CaCl₂+2AgNO₃⇒Ca(NO₃)₂+2AgCl
mole CaCl₂: 3.5 g : 111 g/mole = 0.032
mole AgNO₃: 6.39 g : 170 g/mole = 0.038
mole: coefficient
CaCl₂: 0.032 : 1 = 0.032
AgNO₃: 0.038 : 2 = 0.019
AgNO₃ smaller= limiting reactant, then CaCl₂ = excess reactant
PLEASE SOMEBODY EXPLAIN THIS :(((
Answer:
[tex] \boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}[/tex]
Explanation:In Analytical Chemistry chromatography is widely used for the separation of samples.
In thin layer chromatography, the mixture of components are separated on the basis of their polarity. The solvent solution(mobile phase) that we use are non polar & silica gel( TLC paper made of/stationary phase) are polar.Consider the mixture we have taken consist of two samples having large polar difference.Due to opposite nature of silica gel(polar) & solvent solution (non polar) the movement become easy & due to capillary action solvent solution rise to the top.The mixture of sample we have taken, the sample have less polarity have high peak or they travel more distance than that of more polar sample when they dipped into the solution.In the given diagram, mixture of 8 samples are separated on the basis of their polarity, the distance travelled by solvent is 35 mm, distance travelled by sample 1 is 11 mm & similarly distance travelled by sample 2,3,4,5,6,7 are 15,31,4,22,25,33 in mm respectively.
Rf Value: Rf value is retention factor which tells about relative absorption of each sample & range of Rf value is 0-1.
Formula to calculate Rf value is
[tex] \sf R_f \: value = \frac{distance \: moved \: by \: sample}{distance \: moved \: by \: solvent} [/tex]
Now, solving for Rf value of sample 1
Given:
Distance moved by sample 1 = 11 mm
Distance movedby solvent = 35 mm
To find:
Rf value of sample 1 = ?
Solution:
Substituting the given data in above formula,
[tex] \small \sf R_f \: value = \frac{distance \: moved \: by \: sample \: 1}{distance \: moved \: by \: solvent} \\ \small \sf R_f \: value = \cancel\frac{11 \: mm}{35 \: mm} = 0.3142[/tex]
[tex] \small \boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}[/tex]
Thanks for joining brainly community!