Which best ilustrates the way in which radiation transfers thermal energy?

Answer:

The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is 3.92 m/s.

Explanation:

Let's use Newton's 2nd Law to help solve this problem.

The force acting on the Ferris wheel is the centripetal force, given in the problem: [tex]F_c=115 \ \text{N}[/tex].

The mass "m" is the sum of the man and woman's masses: [tex]85+65= 150 \ \text{kg}[/tex].

The acceleration is the centripetal acceleration of the Ferris wheel: [tex]a_c=\displaystyle \frac{v^2}{r}[/tex].

Let's write an equation and solve for "v", the tangential (linear) acceleration.

The Ferris wheel's tangential velocity is 3.92 m/s.

Answer:

The dependent variable is the variable that is studied while the independent variable is the variable that is being manipulated

Answer: In this experiment, the

✔ fan speed

was intentionally manipulated. This was the independent variable.

The dependent variable measured was the

✔ acceleration

.

Explanation:

Answer:

5 m/s

Explanation:

Rate of movement is   distance / time

6 m / 1.2 s = 5 m/s

In the velocity vs. time graph, the displacement of the object after 1 second is 3 m.

The displacement of an object is the change in position of the object.

From the graph, the displacement of the object after 1 second is calculated as follows;

x = vt

where;

x = 3 x 1 = 3 m

Thus, in the velocity vs. time graph, the displacement of the object after 1 second is 3 m.

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Hello!

We can use the following equation for magnetic force on a moving particle:

[tex]F_B = qv \times B[/tex]

[tex]F_B[/tex] = Magnetic Force (? N)

q = Charge of particle (1.28 × 10⁻⁵C)
v =velocity of particle (5.63× 10⁷m/s)

B = Strength of magnetic field (8.91 × 10⁻⁴T)

This is a cross-product, so the magnetic force depends on the SINE of the angle between the particle's velocity vector and the magnetic field vector.

Since the charge is moving PERPENDICULAR to the field, the angle between the velocity and magnetic field is 90°. The sine of 90° = 1, so we can simplify the equation to:

[tex]F_B = qvB(1) = qvB\\[/tex]

Plug in the values and solve.

[tex]F_B = (1.28*10^{-5})(5.63*10^7)(8.91*10^{-4}) = \boxed{\text{A. } 0.6421 N}[/tex]

Jenny and Tina play jumping rope,Ben and Ted plays soccer and football and Bovet and Cris perform aerobic exercises​ are the following situations is reaction time exhibited. Option A,B and D are correct.

The reaction time of an organism is a measurement of how quickly it responds to a stimulus.

The time interval between the presentation of the stimulus and the manifestation of a suitable voluntary response in the subject is defined as RT.

In the following situations is reaction time exhibited is;

A. Jenny and Tina play jumping rope.

B. Ben and Ted play soccer and football .

D. Bovet and Cris perform aerobic exercises​.

Hence,option A,B and D are correct.

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Answer:

-10/3

Explanation:

the slope of the graph is negative,  the velocity is slowing.  so we know the positive answers are not correct.   next we just need to figure out how much of a slope the line has.   it's  down 10 and over 3... soo

-10/3 looks good ..     the format for the fraction is  rise / run .  in this case rise is negative, but other wise it's the same.

Answer:

A) The stomach breaks down the food and passes it to the small intestine to be digested further.

Explanation:

I am pretty sure it is the first option because there is no way the stuff you eat can be turned into a liquid, it wouldn't make sense for the stomach to pass the digested food from small intestine to large intestine, so it would have to be the first one. A out of all of the options makes more sense and the stomach has to pass the digested food somewhere.

I hope I helped you

Answer: The answers are, 1) B. 2) A.  3) C.   4) C.

here is the proof maybe u will understand it more than the numbers and letters lm.ao

Explanation:

The red ball with arrows pointing away is a negatively charged particle, the blue ball is a positively charged molecule, and the grey ball is an uncharged molecule. Electric fields don't move uncharged molecules.

Analyse each scenario to identify representations:

A negatively charged particle is the red ball in a box with all arrows pointing away from it. The red ball generates an electric field, and negatively charged particles radiate electric field lines. The arrows indicate how a positive test charge would move in the electric field.

A positively charged molecule is the blue ball in a box with all arrows pointing to it. An electric field converges on the blue ball, signifying its destination. The electric field lines point towards positively charged particles, indicating the direction a positive test charge would move.

A boxed grey ball depicts an uncharged molecule. The ball has no arrows. Uncharged molecules do not emit or experience electric fields. The grey ball is electrically neutral because it lacks electric pitch lines.

An electric field will not move the grey ball in a box (uncharged molecule). Electric fields do not interact with uncharged molecules. Thus, an electric field will keep the grey ball still.

Science and engineering require understanding these representations and their electric field behaviour. Scientists and engineers can create and manipulate electrical systems, electronics, and other technologies that use electric charge interactions by recognising charged particles, uncharged molecules, and electric field effects.

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Answer: 1.55 x 10 -19J on top

Explanation:

Find energy

[tex]\\ \rm\Rrightarrow E=-13.6\left(\dfrac{1}{6^2}-\dfrac{1}{4^2}\right)[/tex]

[tex]\\ \rm\Rrightarrow E=-13.6\left(\dfrac{1}{36}-\dfrac{1}{16}\right)[/tex]

[tex]\\ \rm\Rrightarrow E=-13.6(0.0278-0.0625)[/tex]

[tex]\\ \rm\Rrightarrow E=-13.6(-0.347)[/tex]

[tex]\\ \rm\Rrightarrow E=0.47eV[/tex]

Now

[tex]\\ \rm\Rrightarrow E=h\nu[/tex]

[tex]\\ \rm\Rrightarrow \nu=\dfrac{E}{h}[/tex]

[tex]\\ \rm\Rrightarrow \nu=\dfrac{0.47\times 10^{-19}}{6.626\times 10^{-34}}[/tex]

[tex]\\ \rm\Rrightarrow \nu=0.071\times 10^{15}[/tex]

[tex]\\ \rm\Rrightarrow \nu=7.1\times 10^{13}Hz[/tex]

Answer: 7.364 x 10^-4 N

Explanation:

[tex]$$Given:$$\begin{aligned}m_{1} &=7.5 \times 10^{5} \mathrm{~kg} \\m_{2} &=9.2 \times 10^{7} \mathrm{~kg} \\r &=2.5 \times 10^{3} \mathrm{~m}\end{aligned}$$Here, $m_{1}, m_{2}$, and $r$ are the first mass, the second mass, and the distance[/tex]

[tex]$$The gravitational force exerted between the masses is determined as follows.$$F=G \frac{m_{1} m_{2}}{r^{2}}$$Here, $G$ is the gravitational constant.Substitute the known values.$$\begin{aligned}F &=\left(6.67 \times 0^{-11} \mathrm{~N} \mathrm{~m}^{2} / \mathrm{kg}^{2}\right) \frac{\left(7.5 \times 10^{5} \mathrm{~kg}\right)\left(2.5 \times 10^{7} \mathrm{~kg}\right)}{\left(2.5 \times 10^{3} \mathrm{~m}\right)^{2}} \\&\bold{=7.364 \times 10^{-4} \bold{\mathrm{~N}}}\end{aligned}$$[/tex]

Answer:

12 cm/s

Explanation:

Quite simply, you are looking for  cm/s

  so   60 cm / 5s   = 12 cm/s

Answer:

12 cm/second

Explanation:

To calculate the speed of an object, simply obtain the distance traveled by the ball and divide it by the total time it took to travel 60 centimeters.

⇒ Distance/Time = Speed

In this case, the ball traveled 60 centimeters in 5 seconds.

Therefore, the speed of the ball is;

60 centimeters (Distance)/5 seconds (Time) = 12 cm/second

The angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].

The velocity of a particle when moving in the circular path.

Let speed of the bug with respect to ground is u.

Speed of bag with respect to ring will be

v = u - (- Rω) =

Then, u = v- Rω...............(1)

Angular momentum of ring and bug will remain conserved.

Initial  momentum: L ring + Lbug =0

Final  momentum:  -2m₁ R²ω + m₂uR =0...............(2)

Using equation (1) and (2), the angular velocity expression will be

ω =[m₂v / {(2m₁ +m₂)R}] in positive z direction

Thus, the angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].

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Answer:

MOST : E         LEAST :  D

Explanation:

Grav attraction = G m1 m1 / r^2    

        G  and   'r' are the same for all of the pictures, so the one picture with the biggest mass has the MOST attraction     and the  one with the least mass has the least attraction.

The pair with the largest gravitational attraction is the Earth and the Moon.

The pair with the smallest gravitational attraction is the Earth and a grain of sand.

The gravitational force between two masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In other words, the more massive the objects, the stronger the gravitational force between them. The closer the objects are, the stronger the gravitational force between them.

The Earth and the Moon are the most massive objects in the pair. The Earth has a mass of about 5.972 × 10²⁴ kg, and the Moon has a mass of about 7.34 × 10²² kg. The distance between the Earth and the Moon is about 384,400 km.

The grain of sand is much less massive than the Earth or the Moon. The mass of a grain of sand is about 10⁻⁶ kg. The distance between the Earth and a grain of sand is much greater than the distance between the Earth and the Moon.

Therefore, the gravitational attraction between the Earth and the Moon is much stronger than the gravitational attraction between the Earth and a grain of sand.

Here is a table of the gravitational attractions for each pair of masses:

Pair of masses Gravitational attraction

Earth and Moon 1.98 × 10²⁰ N

Earth and a grain of sand 1.0 × 10⁻¹⁷ N

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The height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.

The time of motion of the bullet is calculated as follows;

-h = vsinθ(t)  - ¹/₂gt²

-6.1 = (vt) sin63  - ¹/₂(32)t²

-6.1 = 0.89vt - 16t² ---(1)

X = vcosθ t

294 = (vt)cos63

294 = 0.454vt

vt = 294/0.454

vt = 647.577 ---(2)

solve (1) and (2) together;

-6.1 = 0.89(647.577) - 16t²

16t² = 576.344 + 6.1

16t² =  582.44

t² = 582.44/16

t² = 36.4

t = √36.4

t = 6.03 s

v = 647.577/t

v = 647.577/6.03

v = 107.4 ft/s

h = vt + ¹/₂gt²

h = (107.4 x sin63 x 6.03) + ¹/₂(32)(6.03)²

h = 1,158.8 ft

H = 1,158.8 ft + 6.1 ft = 1,164.9 ft

Thus, the height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.

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Hello!

A)
We can solve for the reactances of each element using the following equations.

Capacitive reactance:
[tex]X_C = \frac{1}{\omega C}[/tex]

[tex]X_C[/tex] = Capacitive reactance (Ω)
ω = Angular frequency (2000 rad/sec)

C = Capacitance (2 μF)

Plug in the given values and solve.

[tex]X_C = \frac{1}{(2000)(0.000002)} = \boxed{250 \Omega}[/tex]

Inductive reactance:
[tex]X_L = \omega L[/tex]

[tex]X_L[/tex] = Inductive reactance (Ω)
L = Inductance (70 mH)

Solve:
[tex]X_L = 2000 * 0.07 = \boxed{140 \Omega}[/tex]

We can solve for impedance using the following equation:
[tex]Z = \sqrt{R^2 + (X_L - X_C)^2}[/tex]

Z = Impedance (Ω)

R = Resistance (200Ω)

Find the impedance using the values above and the given resistance:
[tex]Z = \sqrt{200^2 + (140 - 250)^2} = \boxed{228.254 \Omega}[/tex]

B)
The maximum current amplitude is found using Ohm's law:

[tex]I_{Max} = \frac{V_{Max}}{Z}[/tex]

[tex]V_{Max}[/tex] = 80V

Z = 228.254 Ω

Solve.

[tex]I_{Max} = \frac{80}{228.254} = \boxed{0.3505 A}[/tex]

To find the max voltages across each element, we can also use Ohm's Law.

For the resistor:
[tex]V_{R, max} = i_{Max} R\\\\V_{R, max} = (0.3505)(200) = \boxed{70.097 V}[/tex]

For the capacitor:

[tex]V_{C, max} = i_{Max}X_C\\\\V_{C, max} = (0.3505)(250) = \boxed{87.622 V}[/tex]

For the inductor:
[tex]V_{L, max} = i_{Max}X_L\\\\V_{L, max} = (0.3505)(140) = \boxed{49.068 V}[/tex]

C)
The maximum voltage across each element is greater than 80 V because of the transfer of energy between the capacitor and inductor that occur at different times (energy is stored and released) and being in addition to the voltage of the power source.

Answer:

i think its 400 miles driven

Explanation:

attempted to do it...

If the trend changed toward traditional (pre-World War II) families, the women’s rights are employment in manufacturing sector.

The war between two countries to take over each other's kingdom using weapons to kill each other.

Before the world war, the army needs armor, weapons, guns and tanks. Their manufacturing is only possible with many workers to work for long hours. If the men are not enough, then women are given opportunities to work with them.

Thus, the women’s rights are employment in manufacturing sector when trend changed traditional families.

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Answer:

4

Explanation:

We can say the motion of the object is stopped when its velocity is 0. That means we just have to check how many times the line of the graph intersects the x-axis. Hence, we can say that the object of the motion is stopped 4 times.

∑F=m.a = m.(Δv/Δt)

∑F=2.16 x (27-0/10)

∑F=5.832 N

Answer:

the one with v = 25 m/s

Explanation:

Momentum = m * v

 if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s

Answer:

okay

Explanation:

power is rate of doing work

power is workdone over time taken

but you don't have information concerning the force

Power = work/time

Work = force x distance

Force = mass x acceleration

So Power = (mass x acceleration x distance) / (time)

acceleration = 8m/s / 2sec  =  4 m/s²

distance = (avg speed) x (time) = 8 m

time = 2 sec

we don't know the runner's mass

Power = (mass) x (4 m/s²) x (8 m) / (2 sec)

Power = (16 x mass in kg) watts

=============================================

Slightly easier way to do it:

Power = (runner's kinetic energy at the end) / (time)

Power = (1/2 m v²) / (time)

Power = (1/2 mass) (64 m²/s²) / (2 sec)

Power = (16 x runner's mass in kg) watts

Answer:

532063

Explanation:

If he's shooting 333 arrows per shot and has 177177177 arrows, you need to divide to find the number of arrows he can shoot total, ignoring the decimal since you can't shoot a partial arrow.

177177177/333=532063

Answer:

S = V t + 1/2 g t^2    where the ball has a speed of V and falls for .2 sec

6 = V t + 4.9 * .04 = V * .2 + .2

V = (6 - .2) / .2 = 29 m/s      speed entering area

T = V / g = 29 / 9.8

T = 2.96 sec      time to reach speed V

H = 1/2 g t^2   time to fall a distance H

H = 4.9 * 2.96^2 = 42.9 m      height from which ball was dropped

Check using first equation:

S = 29 * .2 + 4.9 + .2^2 = 6 m