What’s the correct answer for this? Select all the ones that apply

Answer:

2.5

Step-by-step explanation:

it takes 1 cup to make 18 cookies so you divide 45 by 18 to get your answer

Answer:

Step-by-step explanation:

A) y = -20x + 2500

The above equation is written in slope intercept form - y=mx+b - the y int. is 2500, while the rate of change, aka the slope, is -20 feet per minute.

B) (0,2500)    (1,2480)    (2,2460)    (3,2440)    (4,2420)

For this question just plug in the x values 0 to 4 into the equation above. For example -20(0) +2500 = 2500

C) 1700 feet above the ground

Plug the number 40 into the equation above. -20(40) + 2500 = 1700

D) 125 minutes

The y-int. represents the time it takes him to reach the ground, this means you can set the equation equal to zero and solve to find the answer.

0 = -20x + 2500

subtract 2500 from both sides

-2500 = -20x

divide -20 from both sides

125 = x

Answer:50m

Step-by-step explanation: the highest

Answer:

The conclusion is that people are less likely to prefer dog food over all human food than would be expected by chance

Step-by-step explanation:

From the question we are told that

   The sample size for first sample is  [tex]n_1 = 18[/tex]

     The sample size for second sample  is [tex]n_2 = 18[/tex]

     The number that ranked the dog food first [tex]d = 2[/tex]

     The number that chose one of the other items is  [tex]h = 16[/tex]

The sample proportion for first sample  is  

    [tex]p(d) = \frac{d}{n}[/tex]

=>   [tex]p(d) = \frac{2}{18}[/tex]

=>  [tex]p(d) = 0.11[/tex]

The sample proportion for second sample   is  

         [tex]p(h) = \frac{h}{n}[/tex]

         [tex]p(h) = \frac{16}{18}[/tex]

         [tex]p(h) = 0.8889[/tex]

The value of the pooled proportion is evaluated as

      [tex]\= p = \frac{h+d}{18 +18}[/tex]

       [tex]\= p = \frac{2+16}{18 +18}[/tex]

      [tex]\= p = 0.5[/tex]

[tex]H0: p(d) = p(h)[/tex]

[tex]Ha : p(d) < p(h)[/tex]

Test statistics

        [tex]z = \frac{(p(d)) - (p(h))}{\sqrt{\= p (1- \= p) (\frac{1}{n_1} + \frac{1}{n_2} )} }[/tex]

        [tex]z = \frac{ 0.1111 - 0.8889}{\sqrt{0.5 (1- 0.5) (\frac{1}{18} + \frac{1}{18} )} }[/tex]

       [tex]z = -4.67[/tex]

So since the test  statistics is within the rejection region for the left tailed test

  The null hypothesis is rejected

The conclusion is  that people are less likely to prefer dog food over all human food than would be expected by chance

Answer:

(A) The equation for computing Gustin's profit per seminar; given the values of the relevant parameters is:

π = 0.01AC - 3500

Where π = profit per seminar

A = attendance per seminar

C = commission earning per new account opened

(B) A continuous random variable

(C) No

(D) An audience of 71 persons

STEP BY STEP EXPLANATION:

(A) Profit is equal to total revenue minus total cost.

TR = PAC

Where P = probability that an attendee will open a new account

A = number of attendees per seminar

C = commission Gustin gets from each new account opened.

TC = $3,500

Where cost of organizing 1 seminar is constant at $3,500

So the function for profit per seminar is given thus:

π = TR - TC = 0.01AC - 3500

(B) There are 2 types of random variable; discrete random variable and continuous random variable

We say the number of new accounts opened (NNAO) is a continuous random variable because it is not specific. It is a function of both P and A. It depends on both P and A.

From the profit function or equation we have, we can see that you can't derive the exact NNAO per attendee. It is based on probability so if you were to measure it distinctly, you would have a very minimal value.

Discrete random variables occur in specific intervals e.g. 4, 5, 6,... while continuous random variables occur over an interval; e.g. 4.01, 4.02, 4.03,...

(C) Constructing a spreadsheet simulation model to analyze the profitability of Gustin's seminars, I would not recommend that Gustin continue running the seminars!

(D) The question points to A; which is the total attendance per seminar.

So if we calculate profit with the values given in the full question, we see that profit is negative, hence Gustin is running at a loss with 25 people attending one seminar.

π = (0.01 × 25 × 5000) - 3500

π = -$2,250

So, to make a profit greater than zero, we first check how many attendees it takes for TR to equal TC or for Profit to equal 0.

We set pie π to zero.

0 = (0.01 × 5000 × A) - 3500

0 = 50A - 3500

50A = 3500

A = 70 attendees

So Gustin needs an audience of more than 70 persons before a seminars expected profit will be greater than zero.

[tex]\text{One of the expressions can be the simplified version}\\\\\text{Simplify:}\\\\-f-5(2f-3)\\\\\text{Use the distributive property}\\\\-f-10f+15\\\\\text{Combine like terms}\\\\\boxed{-11f+15}\\\\\text{That expression is equivalent to the expression listed in the question}[/tex]

Answer:

11f+5

Step-by-step explanation:

khan

Answer:

[tex]2 \frac{3}{8} [/tex]

Step-by-step explanation:

[tex]9 \frac{1}{2} \times \frac{1}{4} \\ \frac{19}{2} \times \frac{1}{4} \\ = \frac{19}{8} \\ = 2 \frac{3}{8} [/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

2 3/8

Hope this helps :)

Answer:

170

Step-by-step explanation:

5/100 ×680

=34

20%=34what about 100%=?

(100×34)÷20

170

Twenty percent of 170 is equal to five percent of 680.

The term ‘per cent’ means ‘out of a hundred’. In mathematics, percentages are used like fractions and decimals, as ways to describe parts of a whole.  When you are using percentages, the whole is considered to be made up of a hundred equal parts. The symbol % is used to show that a number is a percentage.

Let the number be x

According to question:

20% of x = 5%  of 680

[tex]\frac{20}{100}[/tex] x = [tex]\frac{5}{100}[/tex] × 680

20 x = 5 × 680

x = 170

Hence, Twenty percent of 170 is equal to five percent of 680.

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#SPJ2

Answer:

102

Step-by-step explanation:

We must calculate the value of z for each value and then compare each one and thus manage to see what is an outlier, we know that z is equal to:

z = (x - m) / sd

where x is the value to evaluate, m the mean and sd the standard deviation. Now we have to:

For x = 148:

z = (148 - 128.5) /8.2

z = 2.37

For x = 102:

z = (102 - 128.5) /8.2

z = -3.23

For x = 152:

z = (152 - 128.5) /8.2

z = 2.86

The value of this is generally between -3.09 and 3.09, so when x is 102, it goes out of range of the value of z, which means that this is the outlier.

Answer:

120

Step-by-step explanation:

15*8=120

Answer:

no pq

Step-by-step explanation:

Answer:

Line LM

Step-by-step explanation:

Got it right on Edge2020

Answer:

Average income of Eric for the remaining 8 months = [tex]\$1946[/tex]

Step-by-step explanation:

Given: Average income of Eric for the first 4 months of the year is equal to  $1,450.25

To find: average income for the remaining 8 months so that his average income for the year is  $1,780.75

Solution:

Average income = Total income for the year/Total number of months

Average income of Eric for the first 4 months = $1,450.25

So,

Total income of Eric for the first 4 months = 1,450.25 × 4 = 5801

Let x denotes total income of Eric for the remaining 8 months

Total income for the year = 5801 + x

Therefore,

Average income for the year = [tex]\frac{5801+x}{12}[/tex]

Also, average income for the year is  $1,780.75

[tex]1780.75=\frac{5801+x}{12}\\1780.75\times 12=5801+x\\21369=5801+x\\21369-5801=x\\15568=x[/tex]

Total income of Eric for the remaining 8 months = $15568

Average income of Eric for the remaining 8 months = [tex]\frac{15568}{8}=\$1946[/tex]

Answer:

sphere

Step-by-step explanation:

A volleyball is a three dimensional object

It is a three dimensional circle which is called a sphere

Answer:

sphere

Step-by-step explanation:

hope this helps:]

Answer:

[tex]F(t,y)=(2+7e^t)y+3(1-t)e^t +C[/tex]

Step-by-step explanation:

You have the following differential equation:

[tex]e^t(7y-3t)dt+(2+7e^t)dy=0[/tex]

This equation can be written as:

[tex]Mdt+Ndy=0[/tex]

where

[tex]M=e^t(7y-3t)\\\\N=(2+7e^t)[/tex]

If the differential equation is exact, it is necessary the following:

[tex]\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}[/tex]

Then, you evaluate the partial derivatives:

[tex]\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}[/tex]

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

[tex]F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)[/tex]        (1)

Next, you derive the last equation respect to t:

[tex]\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)[/tex]

however, the last derivative must be equal to M. From there you can calculate g(t):

[tex]\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t][/tex]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

[tex]F(t,y)=(2+7e^t)y+3(1-t)e^t +C[/tex]

where C is the constant of integration

The preceding help understand why the study doesn't really support such a conclusion: the sample size was too small.

The assumption is approximate [tex]\hat{P}[/tex] by a normal distribution will be:

→ [tex]np = 25\times 0.36[/tex]

       [tex]=9[/tex]

→ [tex]n (1-p) = 25\times (1-0.36)[/tex]

                [tex]= 25\times 0.64[/tex]

                [tex]= 16[/tex]

The above assumption is not satisfied. Thus the above answer i.e., "option A" is the appropriate one.

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Answer:

=5

Step-by-step explanation:

Given that an experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.

a) Experimental runs possible if use of single temperature, pressure and catalyst is there = no of temperatures x no of pressures x no of catalysts

= b) Here pressure and temperature have no choice as lowest is selected.

no of methods = no of catalysts x 1 x1

= 5

Answer:

$20.11

Step-by-step explanation:

Solution:-

- We will define the interest rate ( R ) earned on his deposits in the account per annum ( 365 days ).

- He deposits a principal amount of ( P ) = $6,000 once at the start of the accounting period.

- After the principal amount is deposited he deposits $ 150 in the account after every 6 days.

- We will first determine the amount in his account at the end of 30 days.

- We need to see how many additional deposits of $150 were made in these 30 days.

- The ( n ) number of additional deposits can be determined from the ratio of time-span of each deposition and the total accounting period:

                     [tex]n = \frac{30}{6} = 5[/tex]

- Horatio Reyes makes ( n = 5 ) additional deposits after the principal amount till the end of 30th day.

- Now we can calculate the total amount accumulated ( A ) in his account at the end of 30 days time period. It comprises of the initial principal amount and the 5 series of $150 deposits:

                   [tex]A = P + $150*n[/tex]

- Plug in the respective amounts ( P and n ):

                   [tex]A = 6000 + 150*5\\\\A = 6000 + 750\\\\A = 6750[/tex]

- At the end of 30th day Horatio Reyes has $6,750 in his account.

- The interest rate ( r ) applied at the end of the 30-day time period is sub-part of the total interest rate ( R ) applied per annum.

- So the interest rate applied at the end of 30-day tim period is determined from simple proportional ratios of time-period:

                      Rate(%)                     Time(days)

               R:   3.625                             365        

               r:       x                                   30

     ========================================

                      x = 30*3.625 / 365 = 0.29795%

     ========================================

- Now we will apply the rate ( r ) on the accumulated amount ( A ) by the end of 30-day time period in the account to determine the interest earned ( I ):

                        [tex]I= \frac{r*A}{100} \\\\I = \frac{0.29795*6750}{100} \\\\I = 20.111[/tex]

- The amount of interest earned ( I ) is $20.11 after 30 days.

Answer:

And based on the claim the system of hypothesis are:

Null hypothesis: [tex] \mu = 26589[/tex]

Alternative hypothesis: [tex] \mu \neq 26589[/tex]

And the best alternative would be:

b. [tex]H_1: \neq $26,589[/tex]

Step-by-step explanation:

For this case we want to test the hypotheis that the true mean is different from 26859. We have the following info given:

[tex] \bar X = 26589[/tex] represent the sample mean

[tex] \sigma =2659[/tex] represent the population deviation

And based on the claim the system of hypothesis are:

Null hypothesis: [tex] \mu = 26589[/tex]

Alternative hypothesis: [tex] \mu \neq 26589[/tex]

And the best alternative would be:

b. [tex]H_1: \neq $26,589[/tex]

Answer:

i) [tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

ii) [tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]

[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

And replacing we got:

[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]

iii) [tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]

Step-by-step explanation:

Let X the random variable of interest "number of inhabitants of a community favour a political party', on this case we now that:

[tex]X \sim Binom(n=20, p=0.25)[/tex]

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

Part i

We want this probability:

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

Part ii

We want this probability:

[tex]P(X\geq 3)[/tex]

And we can use the complement rule and we have:

[tex]P(X\geq 3) = 1-P(X<3)= 1-P(X \leq 2) =1- [P(X=0) +P(X=1) +P(X=2)][/tex]

And if we find the individual probabilites we got:

[tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]

[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

And replacing we got:

[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]

Part iii

We want this probability:

[tex] P(X <2)= P(X=0) +P(X=1)[/tex]

And replacing we got:

[tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]

Answer:

No instead of doing multiplication u did division

Step-by-step explanation:

This equation is called distributive property where u multiply the answer from the outside by the inside number

Answer:

a) [tex] 6.8 -2.110*1.2 =4.268[/tex]

[tex] 6.8 +2.110*1.2 =9.332[/tex]

b) [tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]

Step-by-step explanation:

For this case we have the following info given:

[tex] \bar X= 6.8[/tex] represent the sample mean

[tex] Se= 1.2[/tex] represent the standard error

[tex] n =18[/tex] the sample size

Part a

For this case the confidence interval for the mean is given by:

[tex] \bar X \pm t_{\alpha/2} SE[/tex]

The degrees of freedom are given by:

[tex] df =n-1=18-1=17[/tex]

And the critical value for a confidence interval of 95% is given by:

[tex] t_{\alpha/2}=2.110[/tex]

And the confidence interval would be:

[tex] 6.8 -2.110*1.2 =4.268[/tex]

[tex] 6.8 +2.110*1.2 =9.332[/tex]

Part b

The margin of error is given by:

[tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]

Answer:

The best correct option is C

x = 1.79 to x = 3

Step-by-step explanation:

Making the sport off all little thing that crowed. They are still grouped into 7. Option C is theost appropriate.

Answer:

An exponential function and a linear function are graphed below

Over which interval does the growth rate of the exponential function continue to exceed the growth rate of the linear function?

a) x=0 to x=3

b) x=0 to x=1.79

c) x=0.38 to x= 1.79

d) x= 1.79 to x=3 <<<<<<< correct answer

Step-by-step explanation:

EDGE 2021

Answer:

  {y | y ≤ 0}

Step-by-step explanation:

The vertical extent of the graph is all values of y less than or equal to zero:

  {y | y ≤ 0}

Answer: {y | y ≤ 0}

Step-by-step explanation: It is the correct answer <3 have an amazing day.

Answer:

t=13

Step-by-step explanation:

the ratio of the shorter sides is t/4 and the ratio of the longer sides is 26/8 so t=26×4/8=104/8=13

Answer: t=13in

Step-by-step explanation: As you can see in the smaller square, the number 4 is in the place of the letter t. Which means that the width (4) is half of the longitud (8). Therefore, in the bigger square all you need to do it divide the longitud (26) by two, to find the width (t). Which is equal to 13in.

I hope you found this answer helpful! If you did, give it a five-star rating and I thanks! It would really mean a lot.

(Even a brainliest if you feel like it ;D!)

Answer:

Hope this helps you to solve it

Answer:

1/7

Step-by-step explanation:

Since we do not know the number let us use the alphabet A to represent the unknown number

A × 1/3= 1/21

A/3= 1/21

Cross multiply both sides

A×21= 3×1

21A= 3

Divide both sides by the coefficient of A which is 21

21A/21=3/21

A=1/7

Hence the unknown number is 1/7

Answer:

The number to multiply with 1/3 to get 1/21 is 1/7.

Step-by-step explanation:

The question wants us to find the number you can multiply with 1/3 to get 1/21. The number is unknown but when you multiply that unknown number by 1/3 your answer should be 1/21.

Let

the number to be multiplied with = a

Therefore,

1/3 × a = 1/21

a/3 = 1/21

cross multiply

21a = 3

divide both sides by 21

a = 3/21

a = 1/7

The number to multiply with 1/3 to get 1/21 is 1/7.

Answer:

maybe 3/5

Step-by-step explanation:

I hope it's right

Answer:

volume = 75 cubic yards

Step-by-step explanation:

Base is 3×5 or 15 yd²

110-15-15=b×3×2+b×5×2

80=6b+10b

80=16b

Divide both sides by 16

b=5

The height of the rectangular prism is 5 yards

Now the volume is l×w×h

3×5×5=

75 yd³ or 75 cubic yards

Answer:

Volume = 75 yards³

Step-by-step explanation:

Surface Area = 110 yards²

But

Surface area = 2(wl+lb+bw) --(1)

Where w is the width , l is length and b is height

L = 5 yards, w = 3 yards

Putting in (1)

110 = 2{(3)(5)+(5)b+3b}

110 = 2(15+5b+3b)

110 = 2(15+8b)

110 = 30+16b

16b = 110-30

16b = 80

Dividing both sides by 18

b = 5

Now

Volume of rectangular prism = wlb

Where w is width, l is length and b is height

= (5)(3)(5)

= 75 yards³

Explanation:

In general, for arbitrary (x, y) pairs, the problem is called an "interpolation" problem. There are a variety of methods of creating interpolation polynomials, or using other functions (not polynomials) to fit a function to a set of points. Much has been written on this subject. We suspect this general case is not what you're interested in.

__

For the usual sorts of tables we see in algebra problems, the relationships are usually polynomial of low degree (linear, quadratic, cubic), or exponential. There may be scale factors and/or translation involved relative to some parent function. Often, the values of x are evenly spaced, which makes the problem simpler.

Polynomial relations

If the x-values are evenly-spaced. then you can determine the nature of the relationship (of those listed in the previous paragraph) by looking at the differences of y-values.

"First differences" are the differences of y-values corresponding to adjacent sequential x-values. For x = 1, 2, 3, 4 and corresponding y = 3, 6, 11, 18 the "first differences" would be 6-3=3, 11-6=5, and 18-11=7. These first differences are not constant. If they were, they would indicate the relation is linear and could be described by a polynomial of first degree.

"Second differences" are the differences of the first differences. In our example, they are 5-3=2 and 7-5=2. These second differences are constant, indicating the relation can be described by a second-degree polynomial, a quadratic.

In general, if the the N-th differences are constant, the relation can be described by a polynomial of N-th degree.

You can always find the polynomial by using the given values to find its coefficients. In our example, we know the polynomial is a quadratic, so we can write it as ...

  y = ax^2 +bx +c

and we can fill in values of x and y to get three equations in a, b, c:

  3 = a(1^2) +b(1) +c

  6 = a(2^2) +b(2) +c

  11 = a(3^2) +b(3) +c

These can be solved by any of the usual methods to find (a, b, c) = (1, 0, 2), so the relation is ...

   y = x^2 +2

__

Exponential relations

If the first differences have a common ratio, that is an indication the relation is exponential. Again, you can write a general form equation for the relation, then fill in x- and y-values to find the specific coefficients. A form that may work for this is ...

  y = a·b^x +c

"c" will represent the horizontal asymptote of the function. Then the initial value (for x=0) will be a+c. If the y-values have a common ratio, then c=0.

__

Finding missing table values

Once you have found the relation, you use it to find missing table values (or any other values of interest). You do this by filling in the information that you know, then solve for the values you don't know.

Using the above example, if we want to find the y-value that corresponds to x=6, we can put 6 where x is:

  y = x^2 +2

  y = 6^2 +2 = 36 +2 = 38 . . . . (6, 38) is the (x, y) pair

If we want to find the x-value that corresponds to y=27, we can put 27 where y is:

  27 = x^2 +2

  25 = x^2 . . . . subtract 2

  5 = x . . . . . . . take the square root*

_____

* In this example, x = -5 also corresponds to y = 27. In this example, our table uses positive values for x. In other cases, the domain of the relation may include negative values of x. You need to evaluate how the table is constructed to see if that suggests one solution or the other. In this example problem, we have the table ...

  (x, y) = (1, 3), (2, 6), (3, 11), (4, 18), (__, 27), (6, __)

so it seems likely that the first blank (x) will be between 4 and 6, and the second blank (y) will be more than 27.

Here is your answer     |  To determine the relationship between quantities, you must determine what to do to the x-values to make them into y-values. The correct operation must turn every x-value into the corresponding y- value in the table. Once you know the relationship, you can use the same operation on all of the x-values that have unknown y-values.

Answer:

250m

Step-by-step explanation:

2000m/ 8laps = 250m