What observation method exposes people to frustrations, temptations, pressure, and boredom in a controlled environment, and is used for firearms training in police departments?

The number that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.

Regional metamorphism occurs when rocks undergoes changes as a result of high temperatures and pressure deep within the earth's crust.

Regional metamorphic rocks are usually foliated or squashed in appearance.

Examples of regional metamorphism rocks are schist and gneiss rocks.

Therefore, the figure that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.

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Alpha particles have highest mass.

Alpha particles are most ionising.

Gamma particles are the most penetrating.

Beta particles are negatively charged.

Gamma particles have the highest speed.

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Higher wind speeds would increase the amount of electricity generated by a wind turbine.

A power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.

Stronger winds produce greater power because they enable the blades to revolve more quickly. Greater mechanical and electrical power from the generator result from faster spinning.

Hence, higher wind speeds would increase the amount of electricity generated by a wind turbine.

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The speed of the car moving after 7 seconds will be 31.5 m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the car = 1289  Kg.

u is the initial velocity  = 0 m/sec

a is the acceleration in m/sec²

v is the velocity after 7 seconds =?

The power developed is;

P =FV

F=ma

P=maV

183831=1289 kg × a × V

a = 142.61 / V

From Newton's second equation of motion;

V=u+at

V=0+at

V=(142.61/V)t

V²=142.61 × 7

V=31.5 m/sec

Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.

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Answer:

Damp Proofing:

Explanation:

The presence of damp proofing is very necessary to maintain the health of a structure. DPC plays an important role in all types of buildings and it should be necessary to know about the importance, requirements, and properties of DPC. In many of the buildings all over the world, the rising damp may be due to a damaged damp-proof course, or sometimes, there may be not any damp proof course in a building.

The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C

The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.

Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.

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An eclipse is an event in which the sun or moon is blocked from view due to the presence of another celestial body, whereas lunar phases are caused by the reflection of the sunlight.

An eclipse is an astronomical phenomenon where one celestial body (e.g., sun, moon) cannot be observed because another is interposed between the Earth and the first one.

Eclipses can be divided into moon eclipses (we cannot see the moon) and sun eclipses (we cannot see the sun).

On the other hand, moon phases occur due to how sunlight reflects the near side of the Moon.  

Moon phases can be divided into:

In conclusion, an eclipse is an event in which the sun or moon is blocked from view due to the presence of another celestial body, whereas lunar phases are caused by the reflection of the sunlight.

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Answer: the other person explained it all

Explanation:

Answer:

See below.

Explanation:

Newton's First Law

A body at rest persists in its state of rest, and a body in motion remains in constant motion along a straight line unless acted upon by an external force.

Newton's Second Law

A body's acceleration is directly proportional to the force exerted on it and is in the same direction as the force.  F=mA  (Force = Mass x Acceleration)

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A. A body of mass 2kg move vertically upwards has its velocity increased uniformly from 15m/s to 45m/s in 5s. neglecting air resistance, the upward vertical force acting on the body. [g=10ms 2] B. The velocity ratio and efficiency of pulley are 8 and 85% respectively. How much effort is required to lift a load of 120kg with this system [g=10m/s²] ​

Force = Mass x Acceleration

Acceleration is (45m/s - 15 m/s)/5 sec) or 6 m/sec^2

Force = 2kg*(6 m/sec^2)

Force = 12 kg*m/s^2    1 kg*m/s^2 is the SI unit for force, and is named 1 Newton(N), after . . . Newton.

Force = 12N

B.  I'm not sure how to interpret "The velocity ratio and efficiency of pulley are 8 and 85% respectively."  I'll assume "effort" is the energy required.  

I'll calculate the energy required in a perfect system, and then we'll consider the efficiency issues.

By lifting an object with mass off the Earth's surface (height = 0 meters) we impart a potential energy, PE, to the object.  This energy is stored in the object until it is allowed to move back closer to Earth.  This potential energy is given by the equation:

PE = mgh

where PE is potential energy in Joules, m is mass in kg, g is the acceleration due to Earth's gravity (9.8 m/sec^2, but we'll use 10 m/sec^2 as stated in the problem), and h is the vertical distance moved, in meters.

PE = (120kg)(10 m/sec^2)(h).  We aren't given a height, h.  Let's express the answer in terms of 1 meter:  How much potential energy is put into the 120kg load to raise it 1 meter?

PE = (120kg)(10 m/sec^2)(1 m)

PE = 1200 kg*m^2/sec^2 or 1200 kg*m/sec^2 per meter

The unit kg*m/sec^2 is 1 Joule

PE = 1200 Joules/meter

1200 Joules are required to raise 120kg 1 meter.  This is increased due to the less-tha-100% efficiency of 85%.

At 85% efficiency, the energy required would be 1200J/0.85 = 1412 J to raise 120kg 1 meter, with 85% efficiency,   I don't6 know how to handle the velocity ratio number.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

Nothing happens to the brightness of the light bulbs in the parallel circuit if the power supply is capable of supplying the additional current.

[tex] \huge \bold \red {Aɴswᴇʀ}[/tex]

Magnetite is a Natural magnet

The electric potential at the origin of the xy coordinate system is negative infinity

The electric field due to the 4.0 μC charge is E = kq/r² where

The electric field due to the -4.0 μC charge is E = kq'/r² where

Since both electric fields are equal in magnitude and directed along the negative x-axis, the net electric field at the origin is

E" = E + E'

= -2E

= -2kq/r²

So, the electric potential at the origin is V = -∫₂⁰E".dr

= -∫₂⁰-2kq/r².dr

Since E and dr = dx are parallel and r = x, we have

= -∫₂⁰-2kqdxcos0/x²

= 2kq∫₂⁰dx/x²

= 2kq[-1/x]₂⁰

= -2kq[1/x]₂⁰

= -2kq[1/0 - 1/2]

= -2kq[∞ - 1/2]

= -2kq[∞]

= -∞

So, the electric potential at the origin of the xy coordinate system is negative infinity

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Answer:

.409 N

Explanation:

For this to balance, the moments around the fulcrum must sum to zero.

On the left you have   .21   ( is that down? I will assume it is)

      Counterclockwise moments :

        .21 * 40     +  1.0 * 20    

     Clockwise moments :

        .5 * 20     +     F * 45

these moments must equal each other

.21*40 + 1 *20   =  .5 * 20 + F * 45

   F = .409 N

Answer:

[tex]\fbox {3.6kW}[/tex]

Explanation:

Formula used :

[tex]\boxed {P = F \times v} \leftarrow \rightarrow \boxed {P = \frac{F \times S}{t}}[/tex]

Given :

⇒ F = 6 × 10³ N

⇒ S = 18 m

⇒ t = 30 s

Solving :

⇒ P = 6 × 10³ × 18 / 30

⇒ P = 2 × 100 × 18

⇒ P = 3600 W

⇒ P = 3.6kW

Given that a ball is thrown into the air and its height in feet after t seconds is given by y = 45t - 15t²,  the instantaneous velocity when t=4 is -75ft/s.

Given that;

First, we determine the derivative of y = 45t - 15t²

y' = (1)45 - (2)15t

y' = 45 - 30t

We substitute in t = 4

y' = 45 - 30t

y' = 45 - 30(4)

y' = 45 - 120

y' = -75ft/s

Given that a ball is thrown into the air and its height in feet after t seconds is given by y = 45t - 15t²,  the instantaneous velocity when t=4 is -75ft/s.

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When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

Newton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.

The mathematical interpretation of the above law is

Removing the proportionality sign,

Where:

From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

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The centripetal acceleration of the tip of the fan blade is 96.23 m/s²

The acceleration developed when a body is moving in circular way, directed towards the center of the circular path.

The tip of a fan blade is 0.61 m from the center of the fan. the fan turns at a constant speed and completes 2 rotations every 1.0 s

ac = ω²r

where ω = angular speed = 2πN/60, N = Rotation per minute

From the question, N = 2 x 60/1 = 120  RPM

So, the angular speed will be

ω = 2π x 120 /60

ω  = 12.56 rad/s

Then, the centripetal acceleration is

ac =  (12.56)² x   0.61 m

ac = 96.23 m/s²

Thus, centripetal acceleration of the tip of the fan blade is 96.23 m/s²

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The patient apply pressure to his side of the tube is 15 x 10⁴ N/m². The correct option is D.

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

Given is a doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the other side. The ball rises with a force of 150 N. The cross section are of the tube is 0.001 m³

The pressure applied is

p = 150 /0.001

p = 15 x 10⁴ N/m²

Hence, the patient apply pressure to his side of the tube is 15 x 10⁴ N/m².

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Answer:

it have two answers a and c

Explanation:

please mark me as brainlyst

Answer: c)how far the object is from the light source
              d)the size of the screen

The size of the shadow depends on the distance of the source of light and on the angle at which the light rays fall on the object. If the source of light is closer to the object, a larger shadow is formed than when the source of light is far from the object.

The angle at which a light strikes an object affects the size and shape of its shadow. Shadows are longer when the light source is at a low angle (side on) and shorter when the light source is at a higher angle (overhead).

The position of the light source can change the size and shape of a shadow. A good example would be, when we are outside on a sunny day, we can see how our shadows change throughout the day. The Sun's position in the sky affects the length of the shadow.

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Concentrated solar power facilities are solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid .

Solar power refer to electric power or electricity that is generated from sun rays or radiations while using solar panels and other technologies.

Therefore, Concentrated solar power facilities solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid.

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Answer:

3.5

Explanation:

hope it helps good day

The Oort cloud extends to the gravitational limits of the solar system would comets come from.

It is a hypothetical idea of a cloud of mostly frozen planetesimals that would orbit the Sun at distances between 2,000 and 200,000 AU.

The Oort cloud reaches the solar system's outer gravitational boundaries, where comets originate.

Hence cloud extending to the gravitational limits of the solar system will be oorto cloud.

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Beryllium (Be) is the only alkaline earth metal that does not react with water.

What are alkali metals and their properties?

Alkali is a substance that produces hydroxide ions in aqueous solution.

PHYSICAL PROPERTIES OF ALKALIS:

CHEMICAL PROPERTIES OF ALKALI METAL

Beryllium (Be) is the only alkaline earth metal that does not react with water.

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(a) The force applied on the box is 98 N.

(b) When you stop pushing, the displacement of the box before coming to rest is 1.02 m.

The force exerted on the box is calculated from Newton's second law of motion.

F - Ff = ma

where;

at constant speed, a = 0

F - Ff = 0

F = Ff

Ff = μmg

Ff = 0.2 x 50 x 9.8

Ff = 98 N

F - Ff = ma

-Ff = ma

a = -Ff/m

a = -98/50

a = - 1.96 m/s²

v² = u² + 2as

when the box stops, v = 0

0 = u² + 2as

0 = (2)² + 2(-1.96)s

0 = 4 - 3.92s

3.92s = 4

s = 4/3.92

s = 1.02 m

When you stop pushing, the displacement of the box before coming to rest is 1.02 m.

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The mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.

Electric current is defined as the ratio of the charge flow in a given time interval. It is denoted by I. It has the unit is ampere.

Given data;

Electric current,I= 25 A

Thickness  = 0.1 mm

Length = 3 mm

Flux  = 1.4 w/m²

The charge density is found as;

[tex]\rm \rho =- \frac{1}{R_H} \\\\ \rho = 0.119 \times 10^{11} C/m^3[/tex]

The value of the hall voltage is;

[tex]\rm V_H = BVd \\\\ V_H = B \frac{I}{\rho dt} d \\\\ V_H = \frac{BI}{\rho t } \\\\ V_H = \frac{0.14 \times 25 }{0.119 \times 10^{11} \times 0.1 \times 10^{-3}} \\\\ V_H = \frac{3.5 }{0.119 \times 10^7} \\\\ V_H = 29.41 \times 10^{-6} \ v[/tex]

The mobility of electrons is;

[tex]\rm \mu_e = \frac{\rho}{n_e}\\\\ \mu_e = \frac{6.848 \times 10^7}{13.5 \times 10^{-30}\times 1.607 \times 10^{-19}} \\\\ \mu_e = 57.7 \times 10^{-4}[/tex]

Hence the mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.

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Answer:

C

Explanation:

you need to be able to see through a colour filter, which means youd need transparent or translucent

Transparent materials passes light and they reflect also. The color filters are made by transparent or translucent materials. Thus option c is correct.

The ability of a material to pass light through it is called transparency. Some transparent materials can reflect the light. For example mirror, glasses etc. The materials which passes light but are not transparent is called translucent materials.

The material which does not pass light inside is called opaque. Wood, plastics etc. are opaque materials. Transparent covers, glasses make their inside visible.

Colour filters are made by transparent or translucent materials. They are used to filter or choose a particular colour from a group of reflected lights.

Color filters are used in spectrometers and other optical devices. They filter the incoming wavelengths to select the desired one. Hence, option c is correct.

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If Kevin swims one 25.0-m stretch in 9.22 seconds, his average speed is approximately 2.71m/s.

Speed is expressed as distance over time.

Speed = Distance / time

Given the data in the question

Average speed = 25.0m / 9.22s

Average speed = 2.71m/s

If Kevin swims one 25.0-m stretch in 9.22 seconds, his average speed is approximately 2.71m/s.

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Answer:

[tex]\fbox {5 seconds}[/tex]

Explanation:

The formula which is used here :

[tex]\fbox {v = u + at}[/tex]

[tex]\longrightarrow \textsf {v : final velocity}[/tex]

[tex]\longrightarrow \textsf {u : initial velocity}[/tex]

[tex]\longrightarrow \textsf {a : acceleration}[/tex]

[tex]\longrightarrow \textsf {t : time taken}[/tex]

Solving :

v = u + at

0 = 50 + (-10)t

10t = 50

t = 5 seconds

The tension in the given string of 1.0 g and length of 0.64 m is closest to 2.84 N

The tension in the string at nth harmonic is calculated as follows;

[tex]f_n = \frac{n}{2l} \sqrt{\frac{T}{\mu} }[/tex]

where;

[tex]f_n = \frac{n}{2l} \sqrt{\frac{T}{\mu} }\\\\\frac{f_n(2l)}{n} = \sqrt{\frac{T}{\mu} }\\\\\frac{f_n^2(4l^2)}{n^2} = \frac{T}{\mu} \\\\T = \mu (\frac{f_n^2(4l^2)}{n^2})\\\\T = 0.00156(\frac{100^2 \times 4\times 0.64^2}{3^2} )\\\\T = 2.84 \ N[/tex]

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Answer:

Sonam will jump further than wangchuck