What must be a factor of the polynomial function f(x) graft on the coordinate plane below

X - 6

x - 3

x + 1

x +6

Answer:

yes

Step-by-step explanation:

Explanation:

The equation for the total cost of the clothes is 4×80+25+c=430, where c is the cost of the coat.

320 + 25 + c = 430

         345 + c = 430

345 - 345 + c = 430 - 345

c = 85

The cost of the coat was $85.

Answer:

$85 for the coat

Step-by-step explanation:

1 dress = $80

4 dress =$80×4

=$320

sweater=$25

coat=?

4 dresses plus the sweater cost :

$320+$25=$345

The cost of all the item $430

cost of the coat :

$430-$345=$85

Answer:

So the answer is the first one

Answer:

D-Quadrilateral A'B'C'D' will be congruent to quadrilateral ABCD.

Step-by-step explanation:

The scale factor is equal to 1. Hence, the quadrilateral A'B'C'D' will be identical to quadrilateral ABCD, whose vertices are the same.

The algebraic expression of the dilation is:

[tex](x',y') = (x,y)[/tex]

Besides, the coordinates of the new quadrilateral are A'(3, 3), B'(5, 3), C'(7, 1), and D'(1, 1)

And quadrilateral A'B'C'D' will be congruent to quadrilateral ABCD.

Therefore, the right answer is D.

Answer: D-Quadrilateral A'B'C'D' will be congruent to quadrilateral ABCD.

Step-by-step explanation: just did a test with this question and got it right. Hope this helped! thx for the points :D

Answer:

34.83% of the population scored higher than Tim on the mathematics portion of the ACT

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 22, \sigma = 5.1[/tex]

Tim scored 24. What percent of the population scored higher than Tim on the mathematics portion of the ACT?

The proportion is 1 subtracted by the pvalue of Z when X = 24. The percentage is the proportion multiplied by 100.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{24 - 22}{5.1}[/tex]

[tex]Z = 0.39[/tex]

[tex]Z = 0.39[/tex] has a pvalue of 0.6517

1 - 0.6517 = 0.3483

34.83% of the population scored higher than Tim on the mathematics portion of the ACT

Answer:

(-5,13)

Step-by-step explanation:

because t=3

[tex]x = 1 - 2 \times 3 = - 5 \\ y = 4 \times 3 + 1 = 13[/tex]

Answer:

x= 13.7 (nearest tenth)

Step-by-step explanation:

Please see attached picture for full solution.

Answer:

Not correct

Step-by-step explanation:

Sample 8 has one free throw, sample 9 has 3 free throw success,

sample 10 has 3 free throw success

sample 11 has 5 free throw success

sample 12 has 5 free throw success

sample 13 has 2 free throw success

sample 14 has 1 free throw success;

See one sample should contain 15 free throw and the probability of success should be 0.7

Let's look at sample 8

Total no of success is 1

Total no of free throws 15

Probability is 1/15 = 1/15 * 100 =6.67%

Similarly you can do so for the others.

Answer:

  f(n) = -n^2 -3n +5

Step-by-step explanation:

Suppose the formula is ...

  f(n) = an^2 +bn +c

Then we have ...

  f(1) = 1 = a(1^2) +b(1) +c

  f(2) = -5 = a(2^2) +b(2) +c

  f(3) = -13 = a(3^2) +b(3) +c

__

Here's a way to solve these equations.

Subtract the first equation from the second:

  -6 = 3a +b . . . . . 4th equation

Subtract the second equation from the third:

  -8 = 5a +b . . . . . 5th equation

Subtract the fourth equation from the fifth:

  -2 = 2a

  a = -1

Then substituting into the 4th equation to find b, we have ...

  -6 = 3(-1) +b

  -3 = b

and ...

  1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation

  5 = c

The formula is ...

  f(n) = -n^2 -3n +5

Answer:

The approximate percentage of the Chipotle meals that have more than 471 calories is 95%.

Step-by-step explanation:

We are given that meal can be considered symmetric and mound-shaped with mean 1075 calories and standard deviation 302 calories.

Let X = Chipotle meals having calories

So, X ~ Normal([tex]\mu=1075, \sigma^{2} =302^{2}[/tex])

Now, the 68-95-99.7 rule states that;

So, the approximate percentage of the Chipotle meals that have more than 471 calories is given by;

                               [tex]\frac{X-\mu}{\sigma} = \frac{471-1075}{302}[/tex]

                                        =  -2

Since, it is stated above that 95% of the data values lies within two standard deviation points which means 95% values lies between -2 and 2 z score values.

SO, the approximate percentage of the Chipotle meals that have more than 471 calories is 95%.

Answer:

Step-by-step explanation:

The sum of 7 and 10 is 17. So 123 / 17 = 7.235 (roughly)

7.235 x 10 (for Adriana's aunt's age) equals 72.35

And to double check: We can find adriana's age by doing. 7.235 x 7 = 50.645. If we add 50.645 and 72.35 we get 122.995 which is roughly 123 and the reason why it is not 123 on the dot is because 123 / 17 is roughly 7.235 the full expanded one is: 7.23529411765

You may try checking with the full number without estimating but i am sure of my answer

Answer:

The answer is c

Step-by-step explanation:

The statement that best describes triangle MON is (c) The triangle is isosceles and possibly equilateral.

The congruent triangles are:

Triangle MNO and Triangle NMO

The above means that:

Sides MN and NO or MN and MO are equal

So, the triangles are isosceles triangles

However, it is possible that sides NO and MO are congruent

Hence, the statement that best describes triangle MON is (c) The triangle is isosceles and possibly equilateral.

Read more about congruent triangles at:

https://brainly.com/question/1675117

Since density is equal to mass per unit volume, mass is equal to density times volume. So we split up the lamina into tiny regions with "volume" (area) equal to dA, multiplied by the density, and integrated over the entirety of the lamina.

This is best done in polar coordinates:

[tex]\begin{cases}x=u\cos v\\y=u\sin v\end{cases}\implies\mathrm dA=\mathrm dx\,\mathrm dy=u\,\mathrm du\,\mathrm dv[/tex]

so that [tex]x^2+y^2=u^2\cos^2v+u^2\sin^2v=u^2[/tex].

The lamina is then the set of points

[tex]L=\left\{(u,v)\mid1\le u\le2\land0\le v\le\dfrac\pi2\right\}[/tex]

Now compute the integral: the mass of the lamina is

[tex]\displaystyle\iint_L(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_1^2u^3\,\mathrm du\,\mathrm dv=\frac\pi2\int_1^2u^3\,\mathrm du=\frac{15\pi}8[/tex]

Step-by-step explanation:

Abby’s Expression:

Double m, giving 2m. She then takes 20% of the result, which we can write 0.2(2m). Finally she subtracts this from 2m, giving 2m−(0.2)2m

2m − (0.2)2m

Renato’s Expression:

Divide m by 5, giving m ÷ 5 = m/5, and then multiplies the result by 8, giving:

8(m/5)

Answer:

2x(2x - 1)(x + 3)

Step-by-step explanation:

4x^3 + 10x^2 - 6x =

Factor out the common factor 2x.

= 2x(2x^2 + 5x - 3)

Factor the trinominal.

= 2x(2x - 1)(x + 3)

Answer:

[tex]=2x\left(2x-1\right)\left(x+3\right)[/tex]

Step-by-step explanation:

[tex]4x^3+10x^2-6x\\\mathrm{Factor\:out\:common\:term\:}2x:\quad 2x\left(2x^2+5x-3\right)\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\x^3=x^2x\\=4x^2x+10xx-6x\\\mathrm{Rewrite\:}6\mathrm{\:as\:}2\cdot \:3\\\mathrm{Rewrite\:}10\mathrm{\:as\:}2\cdot \:5\\\mathrm{Rewrite\:}4\mathrm{\:as\:}2\cdot \:2\\=2\cdot \:2x^2x+2\cdot \:5xx-2\cdot \:3x\\\mathrm{Factor\:out\:common\:term\:}2x\\=2x\left(2x^2+5x-3\right)\\\mathrm{Factor}\:2x^2+5x-3:\quad \left(2x-1\right)\left(x+3\right)[/tex]

[tex]2x^2+5x-3\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(2x^2-x\right)+\left(6x-3\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-x\mathrm{:\quad }x\left(2x-1\right)\\2x^2-x\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\=2xx-x\\\mathrm{Factor\:out\:common\:term\:}x\\=x\left(2x-1\right)\\\mathrm{Factor\:out\:}3\mathrm{\:from\:}6x-3\mathrm{:\quad }3\left(2x-1\right)\\6x-3\\\mathrm{Rewrite\:}6\mathrm{\:as\:}3\cdot \:2\\=3\cdot \:2x-3[/tex]

[tex]\mathrm{Factor\:out\:common\:term\:}3\\=3\left(2x-1\right)\\=x\left(2x-1\right)+3\left(2x-1\right)\\\mathrm{Factor\:out\:common\:term\:}2x-1\\=\left(2x-1\right)\left(x+3\right)\\=2x\left(2x-1\right)\left(x+3\right)[/tex]

Answer:

6m = b

Step-by-step explanation:

The area of triangle when angle and sides are given = 1/2* sin angle*ab

Area = 1/2 * sin 30 * 4*b

Area = 6m²

6 = 1/2 * sin 30 * 4*b

(6*2)/(sin 30 * 4)= b

12/(0.5*4) = b

12/2 = b

6m = b

Answer:

To simplify

√(-x) = √((x)(-1)) = √((x)(i^2))

√(-x) = √(i^2) × √x = i√x

For example;

Simplify √-9

√-9 = √(-1×9) = √-1 × √9

√-9 = √(i^2) × √9 = i × 3

√-9 = 3i

Step-by-step explanation:

Given a negative square root √(-x);

From our knowledge of complex numbers, we know that

i^2 = -1 and vise versa

To simplify

√(-x) = √((x)(-1)) = √((x)(i^2))

√(-x) = √(i^2) × √x = i√x

For example;

Simplify √-9

√-9 = √(-1×9) = √-1 × √9

√-9 = √(i^2) × √9 = i × 3

√-9 = 3i

Step-by-step explanation:

The square root of a number A, is a number B such that, when it is multiplied by itself, the result is A.

If A × A = B

Then √B = A.

Now the multiplication of two numbers gives a positive number if both numbers are positive, or both numbers are negative.

2 × 2 = -2 × -2 = 4

3 × 3 = -3 × - 3 = 9

And so on.

So, the square root of 4 = 2 or -2

The square root of 9 = 3 or -3

But if one of the numbers is positive while the other is negative, then the result is negative.

2 × -2 = -4

3 × -3 = -9

Clearly, √(-4) ≠ 2 ≠ -2

√(-9) ≠ 3 ≠ -3

It is impossible to find the square root of negative numbers on the real line. This gives rise to the introduction of Complex Number.

Let i² = -1, then we have that

√(-1) = i.

This is the idea of Complex number, and it helps solve the problem of the negative square roots, and every negative number can be written as the multiplication of -1 and the inverse of the number.

-A = -1 × A

So, √(-A) = √(-1 × A)

= √(-1) × √A

= i × √A

= i√A

Example, to simplify √(-16)

√(-16) = √(-1 × 16)

= √(-1) × √16

= i × ±4

= ±4i

Answer:

9x^3-21x^2+19x-6

Step-by-step explanation:

First you have to distribute the first equation into the second since the two are being multiplied:

(3x^2-5x+3)(3x-2)

9x^3-6x^2-15^2+10x+9x-6

(simplify)

9x^3-21x^2+19x-6

9x^3-21x^2+19x-6

First you have to distribute the first equation into the second since the two are being multiplied:

(3x^2-5x+3)(3x-2)

9x^3-6x^2-15^2+10x+9x-6

(simplify)

9x^3-21x^2+19x-6 is the answer to the question

Answer:

A=9404

Step-by-step explanation:

Answer:

9404

Step-by-step explanation:

Answer: (11/8)

Step-by-step explanation:

I will answer this in English.

a person collects 7/4 of an amount, spends 1/4 and lends 1/8. What fraction of the amount collected is left?

If the amount is A, then he collects:

C = (7/4)*A

Now, he spends 1/4 and lends 1/8 of the amount A, so the fraction left is:

Left = (7/4)*A - (1/4)*A - (1/8)*A

now i will write 7/4 as 14/8 and 1/4 as 2/8.

left = (14/8)*A - (2/8)*A - (1/8)*A  = ((14 - 2 - 1)/8)*A = (11/8)*A

Answer:

[tex]2mn[/tex]

Step-by-step explanation:

[tex]6m^3n,\:8mn^2[/tex]

Find the GCD of [tex]6,\:8[/tex]:

[tex]6[/tex]

[tex]=2\cdot \:3[/tex]

[tex]8[/tex]

[tex]=2\cdot \:4[/tex]

[tex]=2\cdot \:2\cdot \:2[/tex]

So the prime factor common to 6, 8 is:

[tex]2[/tex]

So the factor common to [tex]6m^3n,\:8mn^2[/tex]:

[tex]=2mn[/tex]

Step-by-step explanation:

3 + 15 + 75 + 375 + 1,875

This is a geometric series.  The first term is 3, the common ratio is 5, and the number of terms is 5.

∑₁⁵ 3 (5)ⁿ⁻¹

∑₀⁴ 3 (5)ⁿ

3 + 12 + 48 + 192 + 768

This is a geometric series.  The first term is 3, the common ratio is 4, and the number of terms is 5.

∑₁⁵ 3 (4)ⁿ⁻¹

∑₀⁴ 3 (4)ⁿ

4 + 32 + 256 + 2048 + 16,384

This is a geometric series.  The first term is 4, the common ratio is 8, and the number of terms is 5.

∑₁⁵ 4 (8)ⁿ⁻¹

∑₀⁴ 4 (8)ⁿ

2 + 6 + 18 + 54 + 162

This is a geometric series.  The first term is 2, the common ratio is 3, and the number of terms is 5.

∑₁⁵ 2 (3)ⁿ⁻¹

∑₀⁴ 2 (3)ⁿ

Answer:

6/5, or 1.2

Step-by-step explanation:

The right answer is 6/5

Look at the attached picture

Hope it will help you

Good luck on your assignment

The answer is [ 2 2 1]

look at the attached picture

Hope it helps

Good luck on your assignment

Answer:

1st one is 2. 2nd one is 5. 3rd one is less than. 4th one is, is smaller

Step-by-step explanation:

Answer:

1 = D 75 inches

2 = A 27

Step-by-step explanation:

1 - 6.3 times 12 = 75.6

2 - 6 times 9 = 54

54/2 = 27

:)

Answer:

Step-by-step explanation:

Answer:

Cost of tools: $100

Cost for each chair: $25

Step-by-step explanation:

You can see that before 1 chair, the cost is at 100. This means that the cost of the tools is $100. Another way to determine this is to see that at 1 chair, the cost is $125. At 2, it's $150, and at 3 it's $175, etc. This tells you that the cost to produce each chair is $25, but it also tells you that the tools cost 100 dollars, since the total cost at 1 chair is $125, and each chair only costs $25.

Hope this helps!

Answer:

100,25

Step-by-step explanation:

Answer:

The area of the region is 25,351 [tex]units^2[/tex].

Step-by-step explanation:

The Fundamental Theorem of Calculus: if [tex]f[/tex] is a continuous function on [tex][a,b][/tex], then

                                   [tex]\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}[/tex]

where [tex]F[/tex] is an antiderivative of [tex]f[/tex].

A function [tex]F[/tex] is an antiderivative of the function [tex]f[/tex] if

                                                    [tex]F^{'}(x)=f(x)[/tex]

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function [tex]x^5 + 8x^4 + 2x^2 + 5x + 15[/tex] and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

[tex]\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx[/tex]

[tex]\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx[/tex]

[tex]\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2[/tex]