What motion is expected of the scapula during arm elevation?

Answer:

40kg

Explanation:

w=m×

w=400n

g=10

m=?

400/10=m×10/10

m=40

The maximum energy stored in the spring bumpers is given as ¹/₂kx².

The maximum energy stored in a spring is given by the following equations;

E = ¹/₂kx²

where;

Thus, the maximum energy stored in the spring bumpers is given as ¹/₂kx².

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(a) The gas of interstellar medium can be detected from the radiations of photons of  wavelength 21 cm.

(b) The gas of interstellar medium can be detected from the absorption lines present in the light from distant stars, which must be caused by a medium of density and temperature other than that of the stars emitting the lights.

Interstellar medium is the matter and radiation that exist in the space between the star systems in a galaxy.

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The specific heat capacity of iron is greater than that of lead hence the iron will melt the ice more than the lead.

The specific heat capacity refers to the amount of heat that is required to raise the temperature of 1Kg of a body by 1 K.

We know that the specific heat capacity of iron is greater than that of lead hence the iron will melt the ice more than the lead.

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Answer:

[tex]2.5m/s^{2}[/tex]

Explanation:

Since the distance ,s = 500m

Initial velocity, u = 0m/s

Final velocity, v = 50m/s

We can one of the kinematics equations to find the acceleration.

[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]

Answer:

S=D÷T

Explanation:

50=0.5÷T

T= 100

Answer:

11.1845088571 N

Explanation:

F = k(q1q2)/(d^2)

electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.

b gained electrons

The acceleration of the car is 1.66 m per sec square.

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating.

Initial velocity=0

Final velocity= 60km/hr

To convert it into m/sec

1 km=1000 m

1 hr=3600 sec

So= (60×1000)÷3600=16.66 m/sec

time=10 sec

We know that acceleration is the rate of change of velocity per unit of time.

acceleration=(final velocity-initial velocity)÷ time taken

                     = (16.66-0)÷10

                     = 1.66 m per sec square

So, Acceleration will be, 1.66 m per sec square

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The quantity of heat required to raise the temperature of the water is approximately 35,500 J.

The quantity of heat required to raise the temperature of the water is calculated as follows;

H = mcΔθ

H = 100 x 4.18 x 85

H = 35,530 J

Thus, the quantity of heat required to raise the temperature of the water is approximately 35,500 J.

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Answer:

What is freezing point?

A liquid's freezing point is determined at which it turns into a solid. Corresponding to the melting point, the freezing point often rises with increasing pressure. In the case of combinations and for some organic substances, such as lipids, the freezing point is lower than the melting point. The first solid which develops when a combination freezes often differs in composition from the liquid, and the development of the solid alters the composition of the remaining liquid, typically lowering the freezing point gradually. Utilizing successive melting and freezing to gradually separate the components, this approach is used to purify mixtures.

What is melting point?

The temperature at which a purified substance's solid and liquid phases may coexist in equilibrium is referred to as the melting point. A solid's temperature goes up when heat is added to it until the melting point is achieved. The solid will then turn into a liquid with further heating without changing temperature. Additional heat will raise the temperature of the liquid once all of the solid has melted. It is possible to recognize pure compounds and elements by their distinctive melting temperature, which is a characteristic number.

The difference between freezing point and melting point:

Reference: Berry, R. Stephen. "When the melting and freezing points are not the same." Scientific American 263.2 (1990): 68-75.

Answer:

Resultant horizontal force = 143 N

Explanation:

Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;

Resultant horizontal force = 165 * cos 30

Resultant horizontal force = 142.89

Approximating to a whole number gives;

Resultant horizontal force = 143 N

Graph A best represents the relationship between pull is doubled, gravity and distance. depends on the mass and the force of gravity. Option A is correct.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

The expression for the gravitational force is given as;

[tex]\rm F = G\frac{Mm}{r^2}[/tex]

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Decreasing the distance would increase the gravity of the planet.

Gravity is the attraction force that draws two mass-containing objects together. the gravitational distance's strength.

The force of gravity weakens as the distance between the items rises. if the separation is just one-fourth as great as previously. In the graph, the link between pull and doubled is best represented by A.

Hence option A is correct.

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The peak voltage based on the information given will be 1.33V.

From the information given, Coil A has 75 turns and coil B has 100 turns.

The voltage will be:

IVa = IVb

We will then substitute the values. c

V = 100/75

V = 1.33V

Therefore, the peak voltage based on the information given will be 1.33V.

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Answer:

Loud to soft while pitch increases

Explanation:

Sound waves shown graphically display their amplitude (height of the graph) and their wavelength (the horizontal distance from peak to peak, or valley to valley... one full cycle).

Instead of wavelength, alternatively, one can observe the frequency of the wave (how many cycles are completed for a given unit of horizontal distance) which is in an inverse relationship with the wavelength (as a wavelength gets shorter, the frequency gets higher, and as the wavelength gets longer, the frequency gets lower).

The amplitude of a wave corresponds to how loud the sound is.

The frequency of a wave corresponds to the pitch of the sound.

Notice that on the graph, the height of the graph decreases over time (the peaks get shorter and shorter).  So, the sound volume will get quieter and quieter.  Using terminology that matches the answer choices, the sound will start loud and get soft.

Notice that on the graph, the wavelength decreases over time (starts with a pretty long distance between peaks, and then the distance between peaks gets shorter and shorter).  Alternatively, looking at frequency, notice that the frequency gets higher and higher (on the left, one finger-width doesn't is less than one full cycle, but on the right, the same finger-width is wider than multiple cycles).  So, the pitch of the sound will get higher and higher.

Thus, for this graph, the sound goes from loud to soft, and the pitch increases.

Since we assume the accelerations are constant, the instantaneous acceleration is the same as the average acceleration, so in the first 6.80 seconds we have

[tex]\alpha_1 = \alpha_{\rm ave} = \dfrac{\Delta \omega}{\Delta t} = \dfrac{8.70\frac{\rm rev}{\rm s}}{6.80\,\rm s} \approx 1.28 \dfrac{\rm rev}{\mathrm s^2}[/tex]

In this time, the tub undergoes an angular displacement of

[tex]\theta_1 = \dfrac12 \alpha_1 (6.80\,\mathrm s)^2 \approx 29.6\,\mathrm{rev}[/tex]

In the next 19.0 seconds the tub has acceleration

[tex]\alpha_2 = \dfrac{-8.70\frac{\rm rev}{\rm s}}{19.0\,\rm s} \approx -0.458 \dfrac{\rm rev}{\mathrm s^2}[/tex]

and in this time, the tube undergoes an additional displacement of

[tex]\theta_2 = \left(8.70\dfrac{\rm m}{\rm s}\right)(19.0\,\mathrm s) + \dfrac12 \alpha_2 (19.0\,\mathrm s)^2 \approx 82.7\,\mathrm{rev}[/tex]

So the tub completes [tex]\theta_1+\theta_2 \approx \boxed{112\,\mathrm{rev}}[/tex].

Answer:

liquid

Explanation:

due to high temperatures in the magma chamber all solids liquidify on reaching the surface with colder temperatures it now solidify to form igneous rock

Explanation:

v=u+at, where v,u,a and t are the final velocity, initial velocity, acceleration and time, respectively.

For t=0 s to t=30 s , a =8 m/s 2.

For t=30 s to t=50 s , a = 5 m/s 2.

For t=50 s to t=110 s , a = 0 m/s 2.

For t=110 s to t=130 s , a is such that the body comes to rest at the end of this period.

For t=0 s to t=30 s ,v=0+8t⇒v=8t m/s.

At t=30s,v=8×30=240 m/s.

For t=30 s to t=50 s ,v=240+5(t−30)⇒v=90+5t m/s

At t=50s,v=90+5×50=340 m/s.

For t=50 s to t=110 s ,v=340 m/s.

For t=110 s to t=130 s ,v=340+a(t−110).

The body comes to a halt at t=130 s ⇒0=340+a(130−110).

0=340+20a⇒a=−34020=−17 m/s2.

For t=110 s to t=130 s ,v=340−17(t−110)=2210−17t m/s.

Answer

100% - double

200% - triple

300% - 4X

For a 300% increase the KE must be 4 time as large

KE2 / KE1 = M V2^2 / M V1^2 = (V1 / V2)^2 = 4

So V2 = 2 V1 for the requested increase

M V2 / M V1 = V2 / V1 = 2

So the momentum would double for a 100% increase

Answer:

natural is the answer

Friction is a natural force which exist

From the calculation, the value of the acceleration is 5.8 m/s^2.

The term uniform acceleration refers to a situation in which the velocity increases by equal amounts in equal time intervals.

Given the fact that the car started from rest and reached a velocity of  780.34 mph or 348.84 m/s in 1 minute of 60 seconds;

v = u + at

a = v/t

a = 348.84 m/s/ 60 seconds

a = 5.8 m/s^2

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Based on the calculations, the amount of heat transferred is equal to 2,317 kJ.

Given the following data:

Volume of tank = 0.4 m³.

Initial pressure = 160 kPa.

Final pressure = 600 kPa.

Initial quality, x = 40% = 0.4

From the superheat table A-12, the specific volumes of the saturated liquid and vapor at 160 kPa are:

Next, we would determine the initial specific volume by using this formula:

V₁ = (1 - x)Vf + xVg

V₁ = (1 - 0.4)0.0007437 + (0.4)0.12348

V₁ = 0.049838 m³/kg.

Also, we would find the mass of this refrigerant at the initial state by using this equation:

m = V/V₁

m = 0.4/0.049838

Mass, m = 8.03 kg.

From the superheat table A-12, the internal energy of the saturated liquid and vapor at 160 kPa are:

At the initial state, we would find U₁ from the quality:

U₁ = (1 - x)Uf + xUg

U₁ = (1 - 0.4)31.09 + (0.4)221.35

U₁ = 107.19 kJ/kg.

From the superheat table A-13, the final specific volume and internal energy of the saturated liquid and vapor at 600 kPa are:

At the final state, we would find U₂ by extrapolating with the last two points in the table:

[tex]U_2 = 357.96 + (\frac{367.81 \; - \; 357.96}{0.057006\;-\;0.055522}) \times (0.049838\;-\;0.055522)\\\\U_2 = 357.96 + (\frac{9.85}{0.001484}) \times (-0.005684)\\\\U_2 = 357.96 + 37.73\\\\[/tex]

U₂ = 395.69 kJ/kg.

Now, we can calculate the amount of heat transferred:

Q = m(U₂ - U₁)

Q = 8.03(395.69 - 107.19)

Q = 8.03(288.5)

Q = 2,316.66 ≈ 2,317 kJ.

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The acceleration of the plane will be −8 m/s²

How to find the acceleration of a plane?

Acceleration is the rate of change in velocity over time (Δv/t).

Given, that the initial velocity of the plane u=480 m/s

The final velocity of the plane is zero after landing, v= 0 m/s

t= 1 minute= 60 seconds

we know, v=u + at

0= 480 + 60a

a=[tex]\frac{-480}{60}[/tex]  = -8m/s²

Thus, the acceleration of the plane is -8 m/s²

(negative acceleration implies that the object is slowing down)

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the work done on the car by the force of its engine is 78,000 J.

" The work done on the car by the force of friction is 24,000 J.

Increasing the car's kinetic energy at the end of the first 100 m is 54,000J

a. Completed work = force x distance. Engine output = 780 N, that is,

780 N x 100 m = 78,000 J.

b. Completed work = force x distance. Friction force = 240 N, that is,

240 N x 100 m = 24,000 J.

c. Kinetic energy = 1 \ 2 x m x v2

= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.

Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.

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Answer:

19.55 m/s

Explanation:

Here is HOW to get the answer:

Speed = wavelength * freq

           = 1.7 * 11.5 = 19.55 m / s

The specific heat capacity of the liquid is 2.51 x 10³ J/kg⁰C.

The specific heat capacity of the liquid is calculated as follows;

Q = mcΔФ

where;

c = Q/mΔФ

c = (65 x 120)/(0.78 x 3.99)

c = 2.51 x 10³ J/kg⁰C

The complete question is below:

An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120 s. The mass of the liquid is 0.780 kg and its temperature increases from 18.55°C to 22.54°C. a) Find the average specific heat capacity of the liquid in this temperature range.

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The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²

The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

[tex]B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}[/tex]

where;

m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)

m = 1.2 Am²

The complete question is below:

What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.

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In the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.

It should be noted that an interval scale means a measurement where the difference between the variables is meaningful and equal.

In this case, in the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.

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The motion of the inferior angle of the scapula in the superior and lateral direction is called upward rotation.

The scapula or the shoulder blade has about six different types of motion it undergoes.

The six ways of movement of the scapula are:

When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called upward rotation.

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