What is this Simplify as √16y¹6

The points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible the answers are D, E, and H.

A graphing calculator is a portable computer that can plot graphs, solve multiple equations at once, and carry out other variable-related activities.

We have points shown in the coordinate plane.

As the window of a graphing utility is set at:

X(min) : -6

X(max): 6

Y(min) : -6

Y(max) : 6

The points out of 6 will not be visible.

We can draw a square as shown in the attached picture.

The points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible.

Thus, the points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible the answers are D, E, and H.

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The rise and run that would give us a similar right triangle on the same given line is: B. a rise of 8 and a run of 6.

The rise/run of any two points on the same line are have the same slope value.

Given the coordinates:

The rise of triangle ABC = change in y = 4 units

The run of triangle ABC = change in x = 3 units

Rise/run = 4/3

Therefore, a rise of 8 and a run of  6 would give us: 8/6 = 4/3.

This will give us a triangle similar to triangle ABC.

Therefore, the answer is: B. a rise of 8 and a run of 6.

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The value of x will be 50°. Then the correct option is D.

It is a polygon with four sides. The total interior angle is 360 degrees. A parallelogram's opposite sides are parallel and equal.

Then the sum of the adjacent angle of the parallelogram is 180 degrees.

Then the value of x that makes ABCD a parallelogram will be

The one angle is x+60°.

Then the another angle will be 70°.

Then we have

x + 60° + 70° = 180°

       x + 130° = 180°

                  x = 50°

Then the correct option is D.

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The answers to the question have been written below

1. If the number of sides of the polygon should increase then the measure of the interior angle would increase by 180.

2. A regular polygon has the sum of its external angles as 360. This is solved as 360/n = 0

Hence the value of the exterior would move towards 0 as its sides increases.

4. As the total sum of the of the polygon changes, it would tend towards infinity.

5. The total sum of the exterior angles as the number of sides changes would tends towards 360 degrees.

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Answer:

x1 = 4 y x2= 2

Step-by-step explanation:

escuchame

x2 - 5x -6 = 0

(4)^2 - 5(2) - 6 = 0

16 - 10 - 6 = 0

6 - 6 = 0

de nade :)

Answer :C)It is nonlinear because the increase in the “Total Houses Built” compared to the increase in the “Months Passed” does not show a constant rate of change.

:) hope you have a great day!

Answer:

30

Step-by-step explanation:

#1

Correct version

[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]

[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]

[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]

#2

[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]

[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]

Answer:

14.285714285714 %

Step-by-step explanation:

suppose the weekly payment is of x dollars

Then

Previous payment : $(x/40) per hour

New payment : $(x/35) per hour

Then

The percentage increase in the hourly rate of pay is :

[tex]=\frac{\frac{x}{35} -\frac{x}{40} }{\frac{x}{40} } \times100[/tex]

[tex]=\frac{\frac{5x}{1400} }{\frac{x}{40} } \times100[/tex]

[tex]=\frac{5x}{1400} \times \frac{40}{x} \times100[/tex]

[tex]=\frac{200}{1400} \times100[/tex]

[tex]=\frac{1}{7} \times100[/tex]

[tex]=14.285714285714[/tex]

Answer:

now we have to follow up with the formula n² - n¹

which is 7-1= 6

n³-n²

which is 13-7=6

so therefore the nth term=6

Answer:

ok the first point there is (-4;-3)

the second point is(0;-6)

Answer:

The place value of 3 is tens

the 3 is in the value of tens

Answer:

$20 × 14 days = $280

&30 × 3 = $90

&280 + $90 = $370

Answer:

For car she owes=

$20 x 14 = $280

For tank she owes=

$30 x 3 = $90

Therfore in total she owes,

$280 + $90 = $370

Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P at; D: 105°

From the given image, If we connect points C of the blue quadrilateral to point C' of the rotated quadrilateral using the center of rotation P, then we will notice that ∠CPC' will be greater than 90°.

Now, the rotation is counterclockwise and it therefore means that the angle of rotation is will be positive and since ∠CPC' is greater than 90°, then we can say that the only correct option is Option D which is 105°

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By using trigonometric identities we can solve the trigonometric equation Sin (5x-28) = cos (3x - 50) for x.

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

The question is incomplete.

The complete question is:

Solve for X given that sin(5X - 28)° = cos(3X - 50)°.​

We have given:

sin(5X - 28)° = cos(3X - 50)°.

[tex]\rm \sin \left(5x-28\right)=\sin \left(\dfrac{\pi }{2}-\left(3x-50\right)\right)[/tex]

[tex]\rm \left5x-28\right= \left\dfrac{\pi }{2}-\left(3x-50\right)\right[/tex]

[tex]\rm x=\dfrac{4\pi n+156+\pi }{16}[/tex]     (n = 0, 1, 2, ...)

[tex]\rm x=\dfrac{\pi +4\pi n-44}{4}[/tex]

Thus, by using trigonometric identities we can solve the trigonometric equation Sin (5x-28) = cos (3x - 50) for x.

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Answer:

“The slope is Negative three-fourths, and the y-intercept is 3.”

Step-by-step explanation:

the graph passes through the points (0 , 3) and (4 , 0)

Then

The slope is :

[tex]=\frac{0-3}{4-0}[/tex]

[tex]=-\frac{3}{4}[/tex]

Since , the graph passes through (0 , 3)

THen the y-intercept is 3.

Answer:

The formula for the volume of a cone is V=1/3hπr².

[tex]\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \dfrac{\sqrt{a}}{\sqrt{b}}=\sqrt{\dfrac{a}{b }},\:\quad \:a\ge 0,\:b\ge 0[/tex]

[tex]\dfrac{\sqrt{6}}{\sqrt{27}}=\sqrt{\dfrac{6}{27}}[/tex]

[tex]=\sqrt{\dfrac{6}{27}}[/tex]

[tex]\mathrm{ Cancel \ \ \dfrac{6}{27} \ \ \ ; \ \ \dfrac{2}{9} }[/tex]

[tex]=\sqrt{\dfrac{2}{9}}[/tex]

[tex]\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b }},\:\quad \:a\ge 0,\:b\ge 0[/tex]

[tex]=\sqrt{\dfrac{2}{9}}[/tex]

[tex]\sqrt{9}=3[/tex]

[tex]=\dfrac{\sqrt{2}}{3} \ \ === > \ \ \ Answer[/tex]

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer:

x = 59/12

Step-by-step explanation:

4x + 1/3 = 20

4x = 20 - 1/3

12x/3 = 60/3 - 1/3

12x = 60 - 1

12x = 59

x = 59/12

Check:

4*59/12 + 1/3 = 20

236/12 + 4/12 = 20

240/12 = 20

An asset loses value over time as a result of use, damage, or obsolescence.

An asset loses value over time as a result of use, damage, or obsolescence. Depreciation is the measurement for this decline.

The depreciation method that does not initially use the residual value in depreciation calculations is the depreciating balance.

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Answer:

Step-by-step explanation:

Find the volume of the sample container.

Given:

Volume formula:

Substitute to get:

Find the volume of the trace element, using the given proportion:

The set A satisfying the given inequality is A = (-[tex]\infty[/tex], -10].

Following are some facts which are true for an inequality relation:

[tex]\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)[/tex]

Since y ∈ B, -2 ≤ y ≤ 7. So,

[tex]\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\; y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.[/tex]

The set {-x | inequality (1) holds ∀ y ∈ B} is [10, [tex]\infty[/tex]) i.e.

10 ≤ -x ≤ [tex]\infty[/tex].

Multiplying -1 throughout gives

-10 ≥ x ≥ -[tex]\infty[/tex].

x, thus, lies in the range A = (-[tex]\mathbf{\infty}[/tex], -10}.

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Disclaimer: The question was incomplete. Please find the full content below.

Find the set A such that for x ∈ A

[tex]\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y[/tex]

∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.

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The equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]

Which expression is equivalent to [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

The expression is given as:

[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

Apply the exponent law of indices

[tex](\frac{x^{-9}y^5}{x^{-4}y})^{2}[/tex]

Next, we apply the common base law of indices

[tex](x^{4 -9}y^{5-1})^2[/tex]

Evaluate the difference

[tex](x^{-5}y^4)^2[/tex]

Remove bracket

[tex]x^{-10}y^8[/tex]

Hence, the equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]

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Answer:

y^8/x^10

Step-by-step explanation:

The guy above me is right but just forgot to distribute the negative out of x. :)

Answer:

09 l

Step-by-step explanation:

p0-9

The equivalent exponential expression for the given radical expression √(3 + 7) is √10.

To convert the given radical expression √(3 + 7) into its equivalent exponential expression. This process involves using exponentiation to represent the radical form.

The given radical expression is √(3 + 7). To find its equivalent exponential expression, we need to express the radical in terms of an exponent.

Recall that a radical expression of the form √(a) is equivalent to raising 'a' to the power of 1/2. In this case, 'a' is the quantity inside the radical, which is 3 + 7. So, we can write:

√(3 + 7) = (3 + 7)^(1/2).

Next, we simplify the expression inside the parentheses:

3 + 7 = 10.

Now, the expression becomes:

(10)^(1/2).

To further simplify, we raise 10 to the power of 1/2. Recall that raising a number to the power of 1/2 is the same as finding the square root of that number. So:

(10)^(1/2) = √10.

Therefore, the equivalent exponential expression for the given radical expression √(3 + 7) is √10.

To summarize, we transformed the radical expression √(3 + 7) into its equivalent exponential expression √10 by using the rule that √(a) is equal to a^(1/2). By raising the expression inside the radical to the power of 1/2, we simplified it and found the square root of 10 as the final result.

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Answer:

Domain is all x-values and range is all y values. See all of the x values and y values that are touching the graph. Also, when there is a circle/ hole, use parenthesis for the interval notation.  Hope it helps!

Answer: B. 4x-2y=2

Step-by-step explanation:

We will work this out one by one. Plug in the x and y values of the solution to the equations and you will see which one is true or false.

A. [tex]2(1)+y(1)=2\\2+1\neq 2[/tex]     B. [tex]4(1)-2(1)=2\\4-2=2[/tex]

C. [tex]2(1)-2(1)=2\\2-2\neq 2[/tex]     D. [tex]x(1)+y(1)=4\\1+1\neq 4[/tex]

With this information, we see that B is the correct answer.

I hope this helped!! Pls mark brainliest!! :))

Answer:

300.25

Step-by-step explanation:

The mass of 1 packet of low fat vegetable soup is 70.5g, the mass of 50 packets is 300.25g(70.5x50).

The mass of 50 low-fat vegetable soups has a mass equal to 300.25 g.

Given : The mass of 1 packet of low-fat vegetable soup is 70.5g

To find: The mass of 50 such packets

Concept: In mathematics, a product is the result of multiplication, or an expression that identifies factors to be multiplied. For example, 30 is the product of 6 and 5

The mass of 50 such packets is 70.5x50 i.e., mass of 1 pkt* number of packets given which is given to be 70.5 and 50 respectively

= 300.25 g.

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So there is a possibility I read it wrong, or you typed it wrong. but from what I see, there are NO right triangles.

Step-by-step explanation:

a right triangle has a 90 degree angle. none of these have one.

Answer:

Step-by-step explanation:

Please give me Brainliest!

1) Either [tex]\ell \parallel p[/tex] or [tex]\ell[/tex] ∦ [tex]p[/tex] (only two possibilities)

2) Assume [tex]\ell \parallel p[/tex] (one of two possibilities)

3) [tex]\angle 1 \cong \angle 2[/tex] (if two parallel lines are cut by a transversal, the corresponding angles are congruent)

4) But [tex]\angle 1[/tex] is not congruent to [tex]\angle 2[/tex] (given)

5) So [tex]\ell[/tex] ∦ [tex]p[/tex] (only other possibility)