What is the volume of the cylinder when the radius is 10 and the height is 15

Answer:

Bank 3

Step-by-step explanation:

No additional charges for automatic deposit and includes saving account.

Answer:

The Right option is D

Step-by-step explanation:

From the picture below,

For A,

15y  =  6x

Where we divide both side of the equation by 3

15y/3 = 6x/3

5y  = 2x

For B,

y = 2/5(x)

y×5 = 2x

5y = 2x.

For C,

10y = 4x

Divide both side of the equation by 2

10y/2 = 4x/2

5y = 2x.

For D,

5xy = 2. It can not be simplified futher.

Therefore,

From the above simplification, We can see that,

Equation A = Equation B = Equation C.

Equation D is the only Equation that does not belong to the other three.

Hence the right option is D

Welcome to the concept of the maths.

Here, we can see, that Linear equation always have highest power or degree of its variable as '1' ,

thus here, y = 3/x has degree as -1 and y = x^2 +5 has degree 2 ,

hence,

The equations that are NOT linear are

2.) y = 3/x and 5.) y = x^2 + 5

Answer:

the area is 200.96

Step-by-step explanation:

Answer:

89.135

Step-by-step explanation:

Answer:

Parents from the four ESO courses attend a school assembly. A quarter of the parents are from 1st ESO, a tenth are from 2nd ESO, a quarter are from 3rd ESO and 56 parents are from 4th ESO. a) How many parents attended the assembly? b) How many parents from 1ºESO attended the assembly? c) How many parents of 2nd ESO attended the assembly? d) How many 3rd grade parents attended the assembly?

Step-by-step explanation:

Answer:

(2x + 1)(x + 5).

Step-by-step explanation:

`y=2x^2+11x+5`

2 * 5 = 10

1 * 10 = 10 and  1 + 10 = 11 so we write:

y = 2^2 + 10x + x + 5

y = 2x(x + 5) + 1(x + 5)

= (2x + 1)(x + 5).

Answer:

a is the answer for this question

Answer:

Step-by-step explanation:

From what I understand, you are trying to solve for a.

So,

d=g+2ac

d-g=2ac

(d-g)/2c=a

So,

a = (d-g) / 2c

8) is B

9) is also B ([tex]y=2x+3[/tex])

Answer:

4.0/5

12

The second statement.

Step-by-step explanation:

Any increasing exponential function will always eventually be greater than any other non-exponential function.

The statement that is true from the function given above is:
"Over the interval [-2, 2], function f is increasing at a faster rate than function g is decreasing." (Option D)

A function in mathematics is known as an expression of a relationship involving two variables:

It is clear from the number array (attached) that x > 0, f(x) ↑ while x<  0 f(x) ↓.

While for g(x) it is confirmed that 0 <x<2, gx) ↓.

[-2< x< 0, g(x) may ↓ or ↑]

Hence, x from 0 to 2, g(x) from 6 to -16, that has been modified for 22 while the f(x) changes from 0 to 26, and changed from 26,  26 > 22.2

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Answer:

149500

Step-by-step explanation:

since there's 8 goats, each goat would be 1040000/8, which is 130000 per goat.

marketing at a 15% increase means the new percentage would be 115%, which could be represented by 1.15.

130000 * 1.15 = 149500 / goat

Answer:

4.8%

Step-by-step explanation:

Answer:4.8

Step-by-step explanation:

Trust

The lateral area of the cone is 20π square centimeters.

Given that a cone with base radius of 4 cm and the height is 3 cm, we need to find the lateral area of the cone,

The lateral area of a cone can be calculated using the formula:

Lateral Area = π r l

where:

π is a mathematical constant approximately equal to 3.14159.

r is the radius of the base of the cone.

l is the slant height of the cone.

To find the slant height, we can use the Pythagorean theorem.

The slant height (l) is the hypotenuse of a right triangle formed by the height (h) and the radius (r) of the cone.

The formula is:

l = √(r² + h²)

Given that the base radius (r) is 4 cm and the height (h) is 3 cm, we can calculate the slant height (l):

l = √(4² + 3²)

= √(16 + 9)

= √(25)

= 5

Now we can substitute the values into the formula for the lateral area:

Lateral Area = π r l

= π × 4 × 5

= 20π

Therefore, the lateral area of the cone is 20π square centimeters.

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Answer:

89m

Step-by-step explanation

area of the triangle 15

area of the rectangle 104

104-15=89m

Answer:

[tex]89[/tex] [tex]m^{2}[/tex]

Step-by-step explanation:

area of a triangle  = [tex]\frac{bh}{2}[/tex]

so [tex]\frac{(5)(6)}{2}[/tex] = 15 [tex]m^{2}[/tex]

area of a rectangle = [tex]\\ bh[/tex]

so [tex]\\ 8[/tex]×[tex]\\ 13[/tex] [tex]\\ = 104[/tex] [tex]m^{2}[/tex]

so the area of the figure is

[tex]\\ 104[/tex] [tex]m^{2}[/tex] -  15 [tex]m^{2}[/tex] = [tex]89[/tex] [tex]m^{2}[/tex]

Answer:

2/3

Step-by-step explanation:

A six sided number cube :

Sample space = (1, 2, 3, 4, 5, 6)

Non composite numbers on a six sided number cube = (1, 2, 3, 5)

Probability of an event = required outcome / Total possible outcomes

Required outcome = number of non composite numbers = 4

Total possible outcomes = sample space = 6

P(not composite) = 4 / 6 = 2/3

Answer:

Well, for (D), the answer would be 32.

Step-by-step explanation:

Because, 20 +12 =32. And 32 - 12 = 20. With the other ones that add, its the same way. You can just for example, if its -5 + b = -40, you can just go 5 - 40= which equals 35. Which should give you 40 if you add 35 and 5 together.

Answer:

:)

Step-by-step explanation:

  HM    TM    M    HTH    TTH    TH     H     T    O

1.                     2        4         5        8       2     3    6

2.             4     5       3          7        9        2     0   0

3.                              1           5        7       9      0   5

4.  3        7      8       2           6      4        3       3    5

5.                                          6        7        8     9     4

Answer:f(x)=-16(x-1)^2+22

Step-by-step explanation:

The equation for the trajectory of ball in the air is h(t) = -16t² + 32t + 6.

The differentiation of a function is defined as rate of change of its value at a point. It can be written as f'(x) =  lim h --> 0 (f(x + h) - f(x)) /(x + h - x).

It can also be said as the slope of the tangent for the  function at a given point.

Given that,

The maximum height reached by the ball  after 1 sec is 22 ft above ground.

And, the height at which it is thrown is 6 ft above the ground.

Which implies at 0 sec the height is 6 ft.

The quadratic function for the height can be written as,

h(t) = at² + bt + c

Substitute t = 0 to gat,

f(0) = a × 0² + b × 0 + c

=> c = 6

Now, for maximum height,

h'(t) = 0

=> 2at + b = 0

At maximum height t = 1

Then, the above expression becomes,

2a × 1 + b = 0

=> a = -b/2

Substitute t = 1 in h(t) = at² + bt + c to get,

22 = a + b + c

=> 22 = -b/2 + b + 6

=> b/2 = 16

=> b = 32

Then, a = -b/2

            = -32/2

            =-16

Thus substituting the corresponding values the equation can be written as h(t) = -16t² + 32t + 6.

Hence, the required equation for the path of the ball in the air is  h(t) = -16t² + 32t + 6.

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Answer:

[tex]5.5\times 10^{-1}[/tex]

Step-by-step explanation:

We need to find the value of the given expression i.e.

[tex]\dfrac{6.8\times 10^3-7.2\times 10^2}{1.1\times 10^4}[/tex]

We can solve it as follows :

[tex]=\dfrac{6800-720}{11000}\\\\=\dfrac{6080}{11000}\\\\=0.55[/tex]

or

[tex]=5.5\times 10^{-1}[/tex]

So, the required answer is equal to [tex]5.5\times 10^{-1}[/tex].

Answer:

This answer is 5

Step-by-step explanation:

Answer:

27.7 cm

Step-by-step explanation:

(12,45cm + 2.8cm)=(belinda's shoe+felix added cm)= felix's shoe

12,45cm= belinda shoe

combined lenght = 12,45+ 15,25=27.7 cm

The combined length of the Belinda's shoe which is 12.45 centimeters long and Felix's shoe is 27.7 centimeters.

Length measurement is the measurement of the size of a object. The units of length measurement are meter, feet, yards etc.

In the metric system of length measurement the units are meter, kilometer, centimeter etc.

Belinda's shoe is 12.45 centimeters long.  Felix's shoe is 2.8 centimeters longer than Belinda's shoe. Let suppose the length of Felix's shoe is x meters. Thus,

[tex]x=12.45+2.8\\x=15.25\rm\; cm[/tex]

In centimeters, the combined length of their two shoes is,

[tex]l=15.25+12.45\\l=27.7\rm\; cm[/tex]

Thus, the combined length of the Belinda's shoe which is 12.45 centimeters long and Felix's shoe is 27.7 centimeters.

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Answer:

x = 17.2

Step-by-step explanation:

[tex]x = 21 \: cos 35 \degree \\ \\ x = 17.20219293 \\ \\ x = 17.2[/tex]

Answer:

17.2

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos = adjacent/ hypotenuse

cos 35 = x/21

21 cos 35 =x

17.2021293=x

Rounding to the nearest tenth

17.2

Answer:

A.   (f + g)(1) = - 9

B.    (f - g)(0) = -7

C.    (fg)(3) = 0

Step-by-step explanation:

A.    (f + g)(1) = f(1) + g(1)               f(1) = 1^2 - 9 = 1 - 9 = - 8       g(1) = 1 - 2 = - 1

                    = -8 -1 = -9

B.     (f - g)(0) = f(0) - g(0)             f(0) = 0^2 - 9 = 0 - 9 =  -9      g(0) = 0 - 2 = -2

                      =  -9 + 2 = -7

C.      (fg)(3) = f(3)(g(3)                   f(3) = 3^2 - 9 = 9 - 9 = 0    g(3) = 3 - 2 = 1

                    = 0(1) = 0

Answer:

Yep......a lot of notifications on my phone.....lol

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Answer:

The maximum height of the ball is 380.25 feet in the air.

Step-by-step explanation:

The quadratic function:

[tex]h(t)=-16t^2+132t+108[/tex]

Models the ball's height h(t), in feet, above the ground t seconds after it was thrown.

We want to determine the maximum height of the ball.

Note that this is a quadratic function. Therefore, the maximum or minimum value will always occur at its vertex point.

Since our leading coefficient is leading, we have a maximum point. So to find the maximum height, we will find the vertex. The vertex of a quadratic equation is given by:

[tex]\displaystyle \left(-\frac{b}{2a},f\left(\frac{b}{2a}\right)\right)[/tex]

In this case, a = -16, b = 132, and c = 108. Find the t-coordinate of the vertex:

[tex]\displaystyle t=-\frac{132}{2(-16)}=-\frac{132}{-32}=\frac{33}{8}=4.125[/tex]

So, the maximum height occurs after 4.125 seconds of the ball being thrown.

To find the maximum height, substitute this value back into the equation. Thus:

[tex]h(4.125)=-16(4.125)^2+132(4.125)+108=380.25\text{ feet}[/tex]

The maximum height of the ball is 380.25 feet in the air.