What is the mass percent of water in nickel(II) sulfate hexahydrate?

Answer:

74.1 amu

Explanation:

Given that,

The molecular mass of propanoic acid is 74.1 amu.

One of the isomer of propanoic acid is methyl ethanoate.

We know that, isomers are have same molecular formula. They also have same mass.

In this case, it is very clear that the molecular mass of methyl ethanoate is as same as molecular mass of propanoic acid i.e. 74.1 amu

Answer:  

Neptune is 34 times bigger than Earth.

Earth has life, Neptune does not.

Neptune is a gas planet, Earth is not.

Neptune has rings, Earth does not.

Neptune has 13 moons, Earth has 1.

Explanation:

The planets Earth and Neptune are different from each other as Neptune is 34 times bigger than Earth.Earth has life, Neptune does not.Neptune is a gas planet, Earth is not.Neptune has rings, Earth does not.

A planet is a large, rounded astronomical body that is neither a star nor its remnant. The best available theory of planet formation is the nebular hypothesis, which posits that an interstellar cloud collapses out of a nebula to create a young protostar orbited by a protoplanetary disk.

Planets grow in this disk by the gradual accumulation of material driven by gravity, a process called accretion. The Solar System has at least eight planets: the terrestrial planets Mercury, Venus, Earth and Mars, and the giant planets Jupiter, Saturn, Uranus and Neptune.

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Answer:

5.720 m

Explanation:

Step 1: Given data

Step 2: Calculate the moles of solute

The molar mass of ammonium chloride is 53.49 g/mol.

153.0 g × (1 mol/53.49 g) = 2.860 mol

Step 3: Calculate the kilograms of solvent

We will use the relationship 1 kg = 1000 g.

500.0 g × (1 kg/1000 g) = 0.5000 kg

Step 4: Calculate the molality of the solution

m = 2.860 mol / 0.5000 kg = 5.720 m

Answer:

1011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010101101010101010010101010110101010101001010101011010101010100101010, You're welcome

Explanation:

Answer:

2.31 g

Explanation:

Step 1: Given data

Step 2: Calculate the mass of water that can be vaporized with 1250 calories of energy

We will use the following expression.

Q = ΔH°vap × m

m = Q/ΔH°vap

m = 1250 cal/(540 cal/g)

m = 2.31 g

Answer:

1.98 M

Explanation:

Step 1: Write the balanced reaction

2 NH₃ + 3 BrO⁻⟶ N₂ + 3 Br⁻ + 3 H₂O

Step 2: Calculate the moles corresponding to 0.325 g of ammonia

The molar mass of NH₃ is 17.03 g/mol.

0.325 g × (1 mol/17.03 g) = 0.0191 mol

Step 3: Calculate the reacting moles of hypobromite

The molar ratio of NH₃ to BrO⁻ is 2:3. The reacting moles of hypobromite are 3/2 × 0.0191 mol = 0.0287 mol

Step 3: Calculate the molar concentration of the hypobromite solution

M = 0.0287 mol / 0.0145 L = 1.98 M

The concentration of the hypobromite solution (BrO⁻) needed for the reaction is 1.97 M

We'll begin by calculating the number of mole in 0.325 g of NH₃. This can be obtained as follow:

Mass of NH₃ = 0.325 g

Molar mass of NH₃ = 17.031 g/mol

Mole = mass / molar mass

Mole of NH₃ = 0.325 / 17.031

Next, we shall determine the number of mole of BrO⁻ needed to react with 0.01908 mole of NH₃. This can be obtained as follow:

2NH₃ + 3BrO⁻ —> N₂ + 3Br⁻ + 3H₂O

From the balanced equation above,

2 moles of NH₃ reacted with 3 moles of BrO⁻.

Therefore,

0.01908 mole of NH₃ will react with = [tex]\frac{0.01908 * 3 }{2}\\\\[/tex] = 0.02862 mole of BrO⁻.

Finally, we shall determine the concentration of the BrO⁻ solution.

Mole of BrO⁻ = 0.02862 mole

Volume of BrO⁻ solution = 14.5 mL = 14.5 / 1000 = 0.0145 L

Concentration = mole / Volume

Concentration of BrO⁻ = 0.02862 / 0.0145

Therefore, the concentration of the hypobromite solution (BrO⁻) is 1.97 M

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Answer:

Both empirical and molecular formulas are NH₃.

Explanation:

Hello.

In this case, since we know the percent compositions of both nitrogen and hydrogen, in order find out the molecular formula and the empirical formula of that compound, we can first assume we have 82.27 g of nitrogen and 17.76 g of hydrogen as a first approximation to compute the present moles:

[tex]n_N=82.27g/(14.01g/mol)=5.872mol\\\\n_H=17.76g/(1.01g/mol)=17.58mol[/tex]

Next, we compute the subscripts in the empirical formula first, by diving the moles of each element by the moles of the element with fewest moles:

[tex]N:\frac{5.872}{5.872}=1\\\\H:\frac{17.58}{5.872}=3[/tex]

It means that the empirical formula is NH₃ and its molar mass is about 17.04 g/mol which is about the same the reported molar mass slightly more than 17 g, it means that the molecular formula is also NH₃.

Best regards!

Answer:

It was deflected by a magnet charged particles

Answer:

product

Explanation:

Chemical reactions are said to be the formation of the products from the reactants. "In a chemical reaction, two reactants mix. The resulting substance is called a product." Thus, option C is correct.

A chemical reaction has been defined as the rearrangement of the atoms of the reactant molecules to result in new substances that differ in chemical properties and compositions. This results in the chemical transformation that results in product formation.

The products produced are new substances that are formed by the breaking or the combination of two or more reactants. The molecules of the reactant undergo collision that forms or breaks the bonds of the reactants.

The products produced are different in chemical properties and composition from the reactants it undergoes chemical changes. An example is iron rust, here iron undergoes oxidation to produce rust that is irreversible changes.

Therefore, option C. product is formed by mixing two or more reactants in a chemical reaction.

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Answer:

B. freezing

Explanation:

During freezing, atoms lose energy. In this process, the molecules lose heat energy and they cool down. This reduces randomness of the matter.

Answer:

B)Freezing

Explanation:

just took the test edge 2021

Answer:

Natural catastrophes, such as hurricanes, floods, fires or earthquakes, among others, are events generated by nature itself that negatively impact the ecosystem, causing damage to the environment and the species that inhabit it, including the humans. Thus, for example, fires seriously affect the ecosystems on which they develop, destroying the biodiversity of vegetation and fauna that inhabit there, which threatens large numbers of species and puts a limit on their development and reproduction.

Answer:

See explanation

Explanation:

a) Look at the electronic configuration of both species;

Cu^2+- [Ar]  3d9 4s0

Co^2+- [Ar]  3d7 4s0

We  can now see that a Jahn Teller effect occurs in [CuCl4]2– due to its d9 configuration. This  Jahn-Teller distortion causes the symmetry of  [CuCl4]2–  to change from tetrahedral  T

d  to trigonal pyramidal  C3v.

b) This is a consequence of Jahn-Teller effect in [CoF6]3– which makes the Co-F bonds lie along the z-axis and become elongated in comparison  to the remaining four Co-F bonds

Answer:

rip you

Explanation:

Answer:

The correct answer is - sp hybridization.

Explanation:

The molecular structure line with a carbon bound to the hydrogen with the single sigma bond and with 2 pi bond and one single sigma bond with carbon Nitrogen triple covalent bond.

To calculate the hybridization of an element like carbon by adding the sigma bond and the lone pair of that atom as here in  HCN molecule, zero lone electrons and two sigmas bond the C atom includes sp-hybridized orbital.

The hybridization for the carbon (C) atom in HCN (hydrogen cyanide) is sp. Therefore, option D is correct.

The electron configuration of carbon is 1s² 2s² 2p², with four valence electrons. In HCN, carbon forms three sigma bonds: one with hydrogen (H) and two with nitrogen (N). The sigma bonds are formed by overlapping atomic orbitals.

In the process of hybridization, the carbon atom promotes one of its 2s electrons to a 2p orbital to create a set of four hybrid orbitals. In HCN, only three hybrid orbitals are involved in bonding. One sp hybrid orbital of carbon overlaps with the 1s orbital of hydrogen to form the C-H sigma bond. The other two sp hybrid orbitals of carbon overlap with two nitrogen atoms, forming the C-N sigma bonds.

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Answer:

Find the molar mass of all the elements in the compound in grams per mole.

Find the molecular mass of the entire compound.

Divide the component's molar mass by the entire molecular mass.

You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.

Explanation:

Mass spectrometry is used to measure the mass of atoms and to determine the percent composition of compounds.

There have been qualitative and numerical implications for mass spectroscopy. These include distinguishing unrecognized compounds, determining out a molecule's elemental isotopic makeup, and figuring out a compound's structure by analyzing at how it fragmented.

In order to determine the mass-to-charge ratio (m/z) of one or more molecules present in a sample, mass spectrometry is a proven to be a valuable instrument. The precise molecular weight of the sample's individual components may typically be estimated using these measures and also.

Thus, mass spectrometry is used to measure the mass of atoms and to determine the percent composition of compounds.

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The empirical formula of the compound obtained when 2.97 g of iron combined with oxygen to produce 4.25 g of iron oxide is Fe₂O₃

Mass of Fe = 2.97 g

Mass of compound = 4.25 g

Mass of O = (Mass of compound) – (Mass of Fe)

Mass of O = 4.25 – 2.97

Fe = 2.97 g

O = 1.28

Divide by their molar mass

Fe = 2.97 / 56 = 0.053

O = 1.28 / 16 = 0.08

Divide by the smallest

Fe = 0.053 / 0.053 = 1

O = 0.08 / 0.053 = 1.5

Multiply by 2 to express in whole number

Fe = 1 × 2 = 2

O = 1.5 × 2 = 3

Therefore, the empirical formula of the compound is Fe₂O₃

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Considering the definition of empirical formula,  

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

In this case, in first place you know:

Then, you need to express the mass into percentage as follow:

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 69.88 grams of iron and 30.12 grams of oxygen.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Finally all coefficients are multiplied by a whole number to ensure that the smallest proportion of whole number subscripts is obtained. In this case, it is multiplied by 2:

Therefore the Fe : O mole ratio is 2:3

Finally, the empirical formula is Fe₂O₃.

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Total pressure in the flask : 468 mmHg

Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

The partial pressure is the pressure of each gas in a mixture  

For partial gas :

Pgas₁=x₁.P tot

x₁ = mole fraction of gas 1

mol of each gas :

H₂ = 14 g : 2 g/mol= 7 moles

N₂ = 84 g : 28 g/mol = 3 moles

O₂ = 2 moles

Total moles = 7+3+2= 12 moles

Partial pressure of O₂ :

[tex]\tt P_{O_2}=x_{0_2}\times P_{tot}\\\\78~mmHg=\dfrac{2}{12}\times P_{tot}\\\\P_{tot}=\dfrac{78\times 12}{2}=468~mmHg[/tex]

The study of chemicals is called chemistry.

The correct answer is 468mmhg.

Dalton's law defined as partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

The formula is stated as follows:-

[tex]P_{total} = P_1 + P_2 + P_3...[/tex]

The partial pressure is the pressure of each gas in a mixture. For partial gas is as follows :

[tex]P_{gas}_1=X_1.P_{total}[/tex]

The [tex]X_1[/tex] defined as a mole fraction of gas 1

The mole of each gas is as follows:-

[tex]H_2 = \frac{14}{2}= 7 molesN_2 = \frac{84}{28} = 3 molesO-_2 = 2 moles[/tex]

Total moles = [tex]7+3+2= 12 moles[/tex]

The partial pressure  [tex]O_2[/tex] is as follows:-

[tex]P_{total} = \frac{78*12}{2} =468mm[/tex].

Hence, the correct answer is 468mmhg.

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Answer:

Positive charged

Explanation:

Answer:

False

Explanation:

Answer:

Chromium (III) bromide.

Explanation:

Hello.

In this case, for the reaction:

[tex]3F_2+2CrBr_3\rightarrow 3Br_2+2CrF_3[/tex]

Since there is a 3:2 mole ratio between fluorine (molar mass = 38.0 g/mol) and chromium (III) bromide (molar mass = 291.7 g/mol) we can compute the available moles of fluorine and the moles of fluorine consumed by 22.22 g chromium (III) bromide in order to realize whether it is the limiting reactant or not:

[tex]n_{F_2}^{available}=22.22gF_2*\frac{1molF_2}{38.0gF_2}=0.585molF_2\\ \\n_{F_2}^{consumed}=22.22gCrBr_3*\frac{1molCrBr_3}{291.7gCrBr_3}*\frac{3molF_2}{2molCrBr_3} =0.114molF_2[/tex]

In such a way, since just 0.114 off 0.585 moles of fluorine are consumed, we conclude it is in excess and the chromium (III) bromide is the limiting reactant, it means it gets completely used up.

Best regards!

Answer:

267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm

Explanation:

The volume change work of a gas is the work necessary for the gas to go from an initial volume Vi to a final volume Vf. If the volume decreases, the gas will have been compressed and it is a compression work; whereas if the volume increases, the gas will have expanded and it is expansion work.

The work is calculated by:

W= - P*ΔV= -P*(Vfinal - Vinitial)

In this case:

Replacing:

W= -121590 [tex]\frac{N}{m^{2} }[/tex]*0.0022 m³= - 267.498 N*m= -267.498 J

267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm

The work require to expand the volume of the given pump is 267.5 J.

The given parameters;

The work require to expand the volume of the given pump is calculated as follows;

W = PΔV

W = 1.2 atm (2.2 L - 0 L)

W = 2.64 atm.L

[tex]W = 2.64 \ atm.L \times \frac{101325 \ Pa}{1 \ atm} \times \frac{0.001 \ m^3}{1 \ L} \\\\W = 267.5 \ J[/tex]

Thus, the work require to expand the volume of the given pump is 267.5 J.

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Answer:

The major advantage of using ground glassware in the organic chemistry laboratory is that the joints can quickly and easily fit to other apparatus so that various reactions can be conducted from these various assembling of apparatuses.

Explanation:

Ground glass is glass whose polished surface has been ground to produce a rough finish.

Most organic chemistry laboratory glasswares are designed with ground glass joints. The joints are leak-tight and have outer (female) and inner (male) joints that can be tightly connected together.

These glassware are very important in the organic chemistry laboratory because they can be assembled and disassembled for various reactions conducted in the laboratory without having to have a specific custom-made glassware for each reaction or synthesis process performed in the laboratory. For example, a Liebig condenser can be used for various distillation reactions in the laboratory due to its joint that can be fitted to other apparatus in these reactions.

Also, ground glassware joints are chemical resistant and heat resistant unlike corks or rubber bungs and glass tubes.

Answer:

Paper, some plastics, frosted glass, etc.

Explanation:

Answer: The freezing point of the solution will be [tex]4.3^0C[/tex]

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=(5.5-T_f)^0C[/tex] = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

[tex]K_f[/tex] = freezing point constant = [tex]4.90^0C/m[/tex]

m= molality

[tex]\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]

Weight of solvent (benzene)= 800 g = 0.8 kg

Molar mass of solute ( methyl salicylate) = 152.1 g/mol

Mass of solute ( methyl salicylate) = 30 g

[tex](5.5-T_f)^0=1\times 4.90^0C/m\times \frac{30g}{152.1 g/mol\times 0.8kg}[/tex]

[tex](5.5-T_f)0C=1.2[/tex]

[tex]T_f=4.3^0[/tex]

The freezing point of the solution will be [tex]4.3^0C[/tex]

Answer:

oxygen

Explanation:

I dont know if you still need it but here it is

Answer:

-183.15 °C

Explanation:

Given data:

Mass of F₂ = 5.00 g

Pressure = 119.96 KPa (119.96/101 = 1.2 atm)

Volume = 750.0 mL ( 750.0/1000 = 0.75L)

Temperature = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 5.00 g/ 38g/mol

Number of moles = 0.13 mol

Now we will calculate the temperature:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1.2 atm × 0.75 L = 0.13 mol ×0.0821 atm.L/ mol.K  × T

0.9 atm.L = 0.01 atm.L/ K  × T

T = 0.9 atm.L /0.01 atm.L/ K

T = 90 K

Kelvin to degree celsius:

90K -273.15 = -183.15 °C

Answer:

0.44 M

Explanation:

Answer:

Al = Reduced (Oxidizing agent)

Fe = Oxidized (Reducing agent)

Explanation:

Al became less positive meaning that it gained an electron and Fe became more positive meaning that it lost elections. remember OIL RIG. Oxidation in loss of electrons and Reduction involves gain of electrons

Answer: The answer would be Fe.

Explanation: As "Fe" loses electrons, it becomes the reducing agent.