What is the domain of the given function?
{x|x = -6, -1, 0, 3}
{y ly=-7, -2, 1, 9}
{x|x=-7, -6, -2, -1, 0, 1, 3, 9}
y ly=-7, -6, -2, -1, 0, 1, 3, 9}

The graph is attached with the answer.

When function has different behaviour at different intervals , then it is called a piecewise function.

It is given that

f(x) = - 3x -5 at x ≤ -1

f(x) = -2x +3 at -1 <x<4

f(x) = 2 at x ≥ 4

All the piecewise Function are a straight line.

The table for functions is

f(x) = 3x -5

-1  -8

-2  -11

-3   -14

f(x) = -2x +3

0  3

1    1

2    -1

3   -3

f(x) = 2

4     2

5      2

6     2

7     2

The graph is attached with the answer.

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[tex]y=200(0.5)^2^t[/tex] is Decay

[tex]y=\frac{1}{2}(2.5)^\frac{t}{6}[/tex] is Growth

[tex]y=(0.65)^\frac{t}{4}[/tex] is Decay

Divide number in honor society by total students:

191/2000 = 0.0955

Multiply by 100 to get percent:

0.0955 x 100 = 9.55%

Answer is C. 9.55%

Answer:

y = x + 4

when x is 5, y is 9

Step-by-step explanation:

the pattern from the table is that the y value is 4 more than the x value, so the equation would be y = x + 4.

if you plug in x = 5, then this would be y = 5 + 4 = 9

Answer:

graph A

Step-by-step explanation:

When looking at a graph, there are two different axes. The vertical values--marked by the center up/down line--are "y-values"; and this is called the "y-axis"

The horizontal values--marked by the left/right line--are "x-values"; and this is called the "x-axis"

For the x-axis, values to the left side of the origin (the place where the y-axis and x-axis intercept) are smaller than 0--they are all negative values.

Values to the right side of the origin are positive--greater than 0.

For the y-axis, positive numbers are on the top half [once again, the midpoint / 0 is where the two lines are both = to 0; the origin] and negative numbers are on the bottom half.

Ordered pairs (points) are written as (x,y)

(x-value, y-value)

We are looking for a graph that decreases (along the y-axis), hits a point below the origin, and goes flat/stays constant.

When a graph is decreasing (note: we read graphs from left to right), the line of the graph is slanted downwards (it looks like a line going down).

So, if we look at the graphs, we can see Graph A descending, crossing the y-axis {crossing the middle line /vertical line / y-axis} at a value of -7, and then staying constant (it is no longer increasing or decreasing because the y-values stay the same)

hope this helps!!

Part 1: Finding slope

The slope is [tex]\frac{-3-15}{5-(-10)}=\frac{-18}{15}=\boxed{-\frac{6}{5}}[/tex]

Part 2: Finding the equation

Using the point (-10, 15) to substitute into point-slope form,

[tex]y-15=-\frac{6}{5}(x+10)\\\\y-15=-\frac{6}{5}x-12\\\\\boxed{y=-\frac{6}{5}x+3}[/tex]

Answer:

Using the given points we find that the slope is -1.2 and using the slope-point form we find that the equation of line is y+1.2x = 3.

Step-by-step explanation:

In the question, two points are given, (5,-3) and (-10,15). Using them we can find the slope using the formula, (y2 - y1) / (x2 - x1). So, the slope is

(-3-15) / (5+10) = -18 / 15 = -1.2

Now, we have to find the equation of line. We have two points and a slope. Using any one point and the slope, we can find the equation of line using slope-point form of line. Let us take (5,-3).

(y+3) / (x-5) = -1.2

y+3 = -1.2(x-5)

y+3 = -1.2x + 6

y+1.2x = 3

So, the slope of line is -1.2 and the equation of line is y+1.2x = 3.

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8) 5 + 4 + 2 = 11

Since there are 5 guavas, the correct answer is B. 5/11

9) 3 + 4 = 7

Since there are 4 blue papers, the correct answer is A. 4/7

10) Count all of the numbers and add them. There are 4 twos, 2 fives, and 1 three:

4 + 2 + 1 = 7

Since there are 4 twos, the correct answer is C. 4/7

The triangle is not a right triangle. This is because the sum of the square of the two shorter lengths is not equal to the square of the longest length.

In order to determine if the triangle is a right triangle, Pythagoras theorem would be used.

The Pythagoras theorem: a² + b² = c²

where a = length

b = base

c = hypotenuse

12 ² + 24²

= 144 + 576 = 720

29² = 841

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Answer:

rise over run aka a measure of its steepness

Step-by-step explanation:

Answer:

option c (19.2, -6.7) is correct

Step-by-step explanation:

Mid point - it is the middle point of a line segment. It is equidistant from both endpoints and it is the centroid both of the segment and of the endpoints.

if ([tex]x,y[/tex]) and ([tex]x_{1},y_1[/tex]) are the end points of a line segment then mid point is

given by :- [tex](x+x1)/2 , (y+y1)/2[/tex]

according to question :

given : end point T(-16.8, 31.7)  and mid point M(1.2, 12.5)

let coordinates of another end point S (a, b)

therefore, using mid point formula

1.2 = (-16.8 + a)/2

2.4= (-16.8 + a)

19.2 = a

and,

12.5 = (31.7 + b)/2

25 = 31.7 + b

-6.7 = b

so the option c (19.2, -6.7) is the correct answer

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The base is 60, the part is 40 and the rate is 150%.

The base is the whole quantity or amount that the problem is about.

The part is referred to as the percentage is the portion of the base. The rate is the number with the percentage.

In this case, the base is 60, the part is 40 and the rate is 150%.

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Answer:

a=1.66

b=8368.12

Step-by-step explanation:

hope it helps

Answer: 8x+70

Step-by-step explanation:

[tex]\sum^{5}_{n=2} (2x+5n)=(2x+10)+(2x+15)+(2x+20)+(2x+25)=\boxed{8x+70}[/tex]

Answer:

Perimeter = 2(l + b)

= 2(x + 5x³ + 4 - x²)

= 2x + 10x³ + 8 - 2x²

= 10x³ - 2x² + 2x + 8

Hence, ur answer is the first option.

Answer:

A.

Step-by-step explanation:

L = x

W = 5x³ + 4 - x²

P = 2L + 2W

P(x) = 2x + 2(5x³ + 4 - x²) = 2x + 10x³ + 8 - 2x²

P(x) 10x³ - 2x² + 2x + 8

L = x

W = 5x³ + 4 - x²

P= 2L + 2W

P(x) = 2x + 2(5x³ + 4 - x²) = 2x + 10x³ + 8 - 2x²

= P(x) 10x³ - 2x² + 2x + 8

Distance from the origin to the points  ≈ 0.41.

The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

D = √[(x-p)² + (y-q)²]  

Point A (5, 3, 4) and point B (−4, 2, 6) are located away from the origin (0,0,0), and the points from the origin to this points are expressed as OB - OA where;

Let OB is the distance from the origin to the point B

Let OA is the distance from the origin to the point A

Using the formula for calculating the distance between two points;

OA = √(z2-z1)²+(y2-y1)²+(x2-x1)²

OA = √(4-0)²+(3-0)²+(5-0)²

OA = √(16)+(9)+(25)

OA = √50

OA = 7.071

Similarly;

OB = √(6-0)²+(2-0)²+(-4-0)²

OB = √(6)²+(2)²+(-4)²

OB = √36+4+16

OB = √56

OB = 7.4833

Distance from the origin to the points = 7.4833 - 7.071= 0.4123

Distance from the origin to the points  ≈ 0.41

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To calculate the distance between two points we use this formula:

[tex] \boxed{ \boxed{{d \: = \: \sqrt{(x_2 \: - \: x_1)^{2} \: + \: (y_2 \: - \: y_1)^{2} } }}}[/tex]

______________________

We apply the values already obtained to the formula to get the distance:

[tex]d \: = \: \sqrt{( - 3 \: - \:( - 5))^{2} \: + \: (0 \: - \: 8)^{2} }[/tex]

[tex]d \: = \: \sqrt{( - 3 \: - \: ( - 5))^{2} \: + \: ( - 8)^{2} }[/tex]

[tex]d \: = \: \sqrt{( - 3 \: + \: 5) ^{2} \: + \: 64 } [/tex]

[tex]d \: = \: \sqrt{ {2}^{2} \: + \: 64 } [/tex]

[tex]d \: = \: \sqrt{4 \: + \: 64} [/tex]

[tex]d \: = \: \sqrt{68} [/tex]

[tex]d \: = \boxed{ \bold{ \: 2 \sqrt{17} \: units}}[/tex]

[tex] \huge{\boxed{ \bold{2 \sqrt{17} \: units }}}[/tex]

Answer:

is B

Step-by-step explanation:

this is the best possible answer

Examine the right triangle ABC. Which rise and run would create a similar right triangle on the same line?a rise of 6 and a run of 8a rise of 8 and a run of 6a rise of 6 and a run of 5a rise of 5 and a run of 6

Step-by-step explanation:

Answer:

Step-by-step explanation:

A function is defined so that for each input, there is no more than one output.

Answer:

5 < x ≤ 100

(this is inequality form)

{x| 5 < x ≤ 100}

(this is set notation form)

(options B and C)

Step-by-step explanation:

In interval notation,

(  or   ) : does not include value

[ or ]  : does include value

{and remember:

< or > : does not include value

≤ or ≥ : does include value}

when we write something in interval notation, the range of values is from (lowest value, highest value)

for this equation, we know that we are looking for : (5, 100]

which means that the range of numbers goes from

5 (does not include 5) to 100 [does include 100]

so, x > 5 (not equal to); x ≤ 100

we can combine these two concepts: 5 < x ≤ 100

(inequality form)

{when {x | ...} is present, it means the same thing as without it, so

{x| 5 < x ≤ 100} is also correct

(set notation)

hope this helps!!

Answer:

B and C

Step-by-step explanation:

from interval notation we are including 100 but not 5,

x > 5 and x ≤ 100

so B and C are correct

Answer:

it will increase the production

Step-by-step explanation:

Answer:

x=100/7

Step-by-step explanation:

The interior angles will sum to 360 so 72+89+99+7x=360

260+7x=360

7x=100

x=100/7

Answer:

-51

Step-by-step explanation:

If the limits are reversed, then place a negative sign in front of the integral.

[tex]\int\limits^a_bf ({x}) \, dx =-\int\limits^b_a f({x}) \, dx[/tex]

[tex]\int\limits^a_3 f({x}) \, dx = 51\\[/tex] where [tex]\alpha =10\\[/tex]

[tex]\int\limits^3_\alpha f( {x}) \, dx =-51[/tex]  where[tex]\alpha =10[/tex]

Step-by-step explanation:

PART 1:

on the graph you can make a triangle at any point and with any angle measures.

i recommend a smaller right triangle to be easiest.

i recommend the points (0,3) A (3,0) B and (0,0) C

∆ABC angle measurements:

m∠CAB=45°

m∠ABC=45°

m∠ACB=90°

PART 2:

(4,3) D (7,0) E and (4,0) F make an identical right triangle moved 4 squares to the right

m∠FDE=45°

m∠DEF=45°

to find the missing value of the angle EFD we will use subtraction and addition

180-(45+45)

180-90

90

therefore, the m∠EFD=90°

PART 3:

both the angle measures and the shapes of the triangles are the same

PART 4:

i used a 1:1 ratio

sorry for the wait :)

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

Answer:

Area of smaller square = [tex]\tt\underline{5cm}[/tex][tex]\tt{\times 5cm = }[/tex][tex]\tt\underline\green{25}[/tex] [tex]\tt{sq.cm}[/tex]

Area of bigger square = [tex]\tt{15cm \times}[/tex][tex]\tt\underline{ 15cm }[/tex][tex]\tt{=}[/tex] [tex]\tt\underline\green{225}[/tex] [tex]\tt{sq.cm}[/tex]

Total Area = [tex]\tt\underline\green{25sq.cm}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{225sq.cm}[/tex] [tex]\tt{=}[/tex] [tex]\normalsize \underline{\boxed{\tt \red{250}}}[/tex] [tex]\tt\underline{sq.cm}[/tex]

[tex]\\[/tex]

Area of square A = [tex]\tt\underline{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\underline\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{14m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{14m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{196}[/tex] [tex]\tt{sq.m}[/tex]

Total Area = [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{196}[/tex] [tex]\tt{=}[/tex][tex] \normalsize \underline{\boxed{\tt \red{294}}}[/tex][tex]\tt{sq.m}[/tex]

====================================

To find the area of square use this formula [tex]\large\tt{A = s \times s}[/tex]. Means side of the square multiply to the same side of the square

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

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૮₍´˶• . • ⑅ ₎ა

Answer:

height= 13.2 cm

Step-by-step explanation:

h = 2 × A/b

h = 2 × 33 /5

= 13.2

Answer:

[tex]0.09y^2 - 0.81 = (0.3y+0.9)(0.3y-0.9)[/tex]

Step-by-step explanation:

The difference of squares formula gives us

[tex]a^2 - b^2 = (a+b)(a-b)[/tex]

(you can multiply this out to confirm)

[tex]0.09y^2 = (0.3y)^2[/tex]

and

[tex]0.81 = 0.9^2[/tex]

Thus, by the difference of squares formula

[tex]0.09y^2 - 0.81 = (0.3y+0.9)(0.3y-0.9)[/tex]