What is the cause of space

The answer is letter C vro

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when the lava erupted from the volcano basalt was the rock that cooled quickly or basalt was the only one rock that cooled quickly after the lava erupted from the volcano

Explanation:

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In a double-slit arrangement the slits are separated by a distance equal to 120 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum(b) What is the distance between these maxima on a screen 5.79m from the slits?

Answer:

a

[tex]\theta  =  0.476 ^ o[/tex]

b

[tex]y =  0.0481 \ m [/tex]

Explanation:

From the question we are told that

   The  slit separation is  [tex]d =  120 \lambda[/tex]

Here [tex]\lambda[/tex] is the wavelength of the light

   Generally the condition for constructive interference is  mathematically represented as

      [tex]dsin (\theta) =  m *  \lambda[/tex]

=>    [tex]\theta  =  sin^{-1} [\frac{n *  \lambda}{ d } ][/tex]

=>     [tex]\theta  =  sin^{-1} [\frac{n *  \lambda}{  120 \lambda } ][/tex]

Here n is the order of maxima which is  1 given that we are considering the central maximum and an adjacent maximum

So  

        [tex]\theta  =  sin^{-1} [\frac{1}{  120} ][/tex]

=>     [tex]\theta  =  0.476 ^ o[/tex]

Generally given that the distance of the screen is  D =  5.79 m from the slit then the distance between these maxima is mathematically represented as

        [tex]y = D tan (\theta )[/tex]

=>      [tex]y = 5.79 *  tan (0.476)[/tex]

=>      [tex]y =  0.0481 \ m [/tex]

Answer:

Its rotation will be 3.89x10⁴ rad/s.

Explanation:

We can find the rotation speed by conservation of the angular momentum:

[tex] L_{i} = L_{f} [/tex]

[tex] I_{i}\omega_{i} = I_{f}\omega_{f} [/tex]   (1)

The initial angular speed is:

[tex] \omega_{i} = \frac{1 rev}{7 d} = 0.14 \frac{rev}{d} [/tex]

The moment of inertia (I) of a sphere is:

[tex] I = \frac{2}{5}mr^{2} [/tex]    (2)

Where m is 9 times the sun's mass and r is the sun's radius

By entering equation (2) into (1) we have:

[tex] \frac{2}{5}m_{i}r_{i}^{2}\omega_{i} = \frac{2}{5}m_{f}r_{f}^{2}\omega_{f} [/tex]

[tex]9m_{sun}(696342 km)^{2}0.14\frac{rev}{d} = \frac{3}{4}9m_{sun}(13 km)^{2}\omega_{f}[/tex]

[tex]\omega_{f} = \frac{4}{3}*0.14 \frac{rev}{d}(\frac{696342 km}{13 km})^{2} = 5.36 \cdot 10^{8} \frac{rev}{d}*\frac{1 d}{24 h}*\frac{1 h}{3600 s}*\frac{2\pi rad}{1 rev} = 3.89 \cdot 10^{4} rad/s[/tex]          

Hence, its rotation will be 3.89x10⁴ rad/s.

I hope it helps you!                                                        

Answer:

Where

Explanation:

Answer:

Explanation:

O.20 hour A

If a car is traveling at an average speed of 70 kilometers per hour, 0.2 hours it takes the car to travel 14 kilometers.

By multiplying the distance that an item travels in one unit by the amount of time it takes to go that distance, one may determine the speed of the object. The speed of the item on this voyage, denoted by the letter "s," is equal to s = D/T if "D" is indeed the distance traveled in certain time "T."

Understanding average speed will help you better comprehend the pace of a travel. On a travel, the pace could occasionally change. Knowing the average speed then becomes crucial to getting an idea of how quickly the route will be finished.

Distance covered = average speed × Time travelled

14=70× Time travelled

Time travelled = 0.2 hours

Therefore, 0.2 hours it takes the car to travel 14 kilometers.

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Answer:

8.29m/s

Explanation:

Given

Height of hill H = 3.50m

Initial velocity u = 0m/s

Required

Final velocity v

Using the equation of motion

v² = u²+2gH

v² = 0²+2(9.81)(3.5)

v² = 0+7(9.81)

v² = 68.67

v = √68.67

v = 8.29m/s

Hence the final velocity of the hoop is 8.29m/s

Answer:

* positive repulsion, which makes the electrons move as far away as possible

* Attraction with the core atomizes

he analysis is the foundations of quantum theorizing

Explanation:

Electrons are deposited in an atom following two principles.

* positive repulsion, which makes the electrons move as far away as possible

* Attraction with the core atomizes

The mathematical model used for the analysis is the foundations of quantum theorizing

Explanation:

Recreational water activities can have substantial benefits to health and well-being. Swimming pools, beaches, lakes, rivers and spas provide environments for rest and relaxation, physical activity, exercise, pleasure and fun. Yet they also present risks to health.

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Answer:

It demonstrated that the colonists were capable of local, self-government.  

Explanation:

this is the correct answer because i have already done this

Answer:

[tex]K=4\times 10^4\ J[/tex]

Explanation:

Given that,

Mass of cannon is,M =  2000 kg

Mass of projectile, m = 2 kg

Velocity of the projectile, v = 200 m/s

We need to find the kinetic energy of the projectile. We know that the formula for the kinetic energy of an object is given by :

[tex]K=\dfrac{1}{2}mv^2\\\\\text{Putting all the values, we get}\\\\K=\dfrac{1}{2}\times 2\times (200)^2\\\\K=40000\ J[/tex]

or

[tex]K=4\times 10^4\ J[/tex]

So, the kinetic energy of the projectile will be [tex]4\times 10^4\ J[/tex].

Explanation:

Resistors in circuits can either be connected in series or in parallel.

For a series connected resistors, the same current flows through the resistors while different voltages is passed across them. The formula for calculating effective resistances in a circuit is expressed as

[tex]R_T = R_1+R_2+R_3...+R_n[/tex] where R1, R2, R3 etc. are the resistances connected in series.

The effective resistances for series connected resistors is the sum of the individual resistors

For a parallel connected resistors, different current flows through the resistors while same voltage is passed across them. The formula for calculating effective resistances in a circuit is expressed as:

[tex]\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} +...\frac{1}{R_n}[/tex]

The effective resistances for parallel connected resistors is the sum of the reciprocal of the individual resistors

Answer:

y(i) = h

v(y.i) = 0

Explanation:

See attachment for elaboration

Answer:

Objects want to keep doing the same thing is a way of stating Newtons First Law.

The correct option is (a) inertia. "Objects want to keep doing the same thing" it implies a connection to the principle of inertia in physics. Inertia is the property of matter that resists changes in its state of motion or rest.

According to Newton's first law of motion, an object will remain at rest or continue moving in a straight line at a constant velocity unless acted upon by an external force. This property is commonly known as "the law of inertia." In other words, objects tend to maintain their current state of motion (whether at rest or in motion) unless influenced by an external force.

When we say "Objects want to keep doing the same thing," we're drawing an analogy between this scientific principle and human behavior. It suggests that objects, like humans, have a natural inclination to resist change and continue their current course of action. This analogy helps convey the idea that objects exhibit a tendency to persist in their existing state.

"Objects want to keep doing the same thing" to inertia emphasizes the notion that objects, like humans, tend to maintain their current state of motion or rest unless influenced by an external force.

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The correct question is:

Objects want to keep doing the same thing is a way of stating ......

a) inertia

b) force

c) power

d) moment

Answer:

5 meters per second squared

Explanation:

We calculate the acceleration using the formula:

a = (vf - vi) / t

where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.

In our case:

a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2

Answer:

2 x 10^10 years.

Explanation:

Given that the sun produces energy via nuclear fusion at the rate of 4×1026 J/s . Based on the proposed overall fusion equation, how long will the sun shine in years before it exhausts its hydrogen fuel? (Assume that there are 365 days in the average year.)

Let us first calculate energy from hydrogen gas.

4(1.007825) + 2(0.00549) - 4.002603 = 0.029795 amu

Since 4.0313 amu H+ > 0.029795 amu =  ratio of 1 to 0.00739

dE = ((2*10^30 kg) x 0.8 x 0.25)(3.00x10^8 m/s)^2 = 3.6x10^46 kg x m^2/s^2  

3.6x10^46 kg x m^2/s^2 x 0.00739 = 2.6604 x 60^44 kg x m^2/s^2

4x10^26 J/s x s = 2.6604x10^44 kg x m^2/s^2  solve for s.

s = 6.651x10^17 seconds

6.651x10^17 seconds x 1 min/60 s x 1 hr/ 60 min x 1 day/ 24 hr x 1 yr / 365 days = 2.1x10^10 years

 Based on the proposed overall fusion equation, it will therefore take the sun shine 2 x 10^10 years before it exhausts its hydrogen fuel.

Answer:

4.5 hours =

16200 seconds

Explanation:

here you go

Answer:

1800 m/s

Explanation:

The equation is v = fλ

λ= 0.75

f = 2400 Hz

V = 2400 × 0.75

V = 1800 m/s

[ you did not give units for wavelength, I assumed it would be m/s]

Answer:

The value is  [tex]v = 1.309*10^{5}\ m/s[/tex]

Explanation:

The radius is [tex]r = 7.40 *10^{20} \  m[/tex]

The mass of the ordinary matter is [tex]M_{rod} =  1.90 *10^{41}\  kg[/tex]

Generally the speed of the star is mathematically represented as

         [tex]v = \sqrt{\frac{G * M}{r} }[/tex]

Here G is the gravitational constant with a value

        [tex]G = 6.67384 * 10^{-11}[/tex]

So

      [tex]v = \sqrt{\frac{6.67384 * 10^{-11} * 1.90 *10^{41}}{7.40 *10^{20}} }[/tex]

=>    [tex]v = 1.309*10^{5}\ m/s[/tex]

Answer:

The volume in cubic centimeters is 1,440,000

Explanation:

You know that an object has a volume of 1.44 m³  and you want to calculate the volume in cubic centimeters cm³.

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

So, [tex]x=\frac{c*b}{a}[/tex]

Since 1 m³ is equal to 1,000,000 cm³ ( this is the conversion factor) , then you can apply the following rule of three: if 1 m³ is equal to 1,000,000 cm³, 1.44 m³ is equal to how many cm³?

[tex]cm^{3} =\frac{1.44m^{3}*1,000,000 cm^{3} }{1m^{3} }[/tex]

cm³=1,440,000

The volume in cubic centimeters is 1,440,000

Answer:

8.93*10^13 N.

Explanation:

       [tex]F_{g}= \frac{G*m_{1}*m_{s}}{r_{s}^{2} }[/tex]

       [tex]F_{g}= \frac{6.67e-11Nm^2/kg^2*1.99e30 kg*67.3 kg}{10e4m^2} = 8.93e13 N[/tex]

Answer:

t = 5.77 s

Explanation:

This exercise will use Newton's second law for rotational motion

            τ = I α

             α = τ / I

             α = 66/175

             α = 0.3771   rad/s²

now we can use the rotational kinematics relations, remember that all angles must be in radians

            θ = 1 rev = 2π radians

            θ = w₀ t + ½ α t²

as the wheel starts from rest w₀ = 0

             t = √ (2θ/α)

let's calculate

             t = √ (2 2π / 0.3771)

             t = 5.77 s

Answer:

T₂ = 49.3°C

Explanation:

Applying law of conservation of energy to the system we get the following equation:

Energy Supplied by Resistor = Energy Absorbed by Tank + Energy Absorbed by Water

E = mC(T₂ - T₁) + m'C'(T'₂ - T'₁)

where,

E = Energy Supplied by Resistor = 100 KJ = 100000 J

m = mass of copper tank = 13 kg

C = Specific Heat of Copper = 385 J/kg.°C

T₂ = Final Temperature of Copper Tank

T₁ = Initial Temperature of Copper Tank = 27°C

T'₂ = Final Temperature of Water

T'₁ = Initial Temperature of Water = 50°C

m' = Mass of Water = 4 kg

C' = Specific Heat of Water = 4179.6 K/kg.°C

Since, the system will come to equilibrium finally. Therefor:  T'₂ = T₂

Therefore,

(100000 J) = (13 kg)(385 J/kg.°C)(T₂ - 27°C) + (4 kg)(4179.6 J/kg.°C)(T₂ - 50°C)

100000 J = (5005 J/°C)T₂ - 135135 J + (16718.4 J/°C)T₂ - 835920 J

100000 J + 135135 J + 835920 J = (21723.4 J/°C)T₂

(1071055 J)/(21723.4 J/°C) = T₂

T₂ = 49.3°C

Answer:

a)  + Q charge is inducce that compensates for the internal charge

b) There is no excess charge on the external face q_net = 0

c) E=0

Explanation:

Let's analyze the situation when a negative charge is placed inside the cavity, it repels the other negative charges, leaving the necessary positive charges to compensate for the -Q charge. The electrons that migrated to the outer part of the sphere, as it is connected to the ground, can pass to the earth and remain on the planet; therefore on the outside of the sphere the net charge remains zero.

With this analysis we can answer the specific questions

a)  + Q charge is inducce that compensates for the internal charge

b) There is no excess charge on the external face q_net = 0

c) If we create a Gaussian surface on the outside of the sphere the net charge on the inside of this sphere is zero, therefore there is no electric field, on the outside

d) If it is very reasonable and this system configuration is called a Faraday Cage

e) We cannot apply this principle to gravity since there are no particles that repel, in all cases the attractive forces.

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attached file:

The two ways to charge an object are Friction and Induction.

To charge and object generally we can think of three ways, Friction, Conduction, and Induction. Here I am going to explain charging by friction and induction.

(i) Charging by Friction:

In this case, two objects are rubbed against each other. The friction between the two objects creates enough energy for the transfer of charges  ( electrons) from one object's surface to the other. So the imbalance in the electrons produces a charge on the objects.

(ii) Charging by induction:

In this case, an already charged object is brought near a neutral object but there is no contact between the objects. The charged object attracts or repels the electrons of the neutral object, depending upon the type of charge it has. Thus creating a charge imbalance in the neutral object.

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Answer:

The velocity is [tex]v_b = 20.17 \ m/s[/tex]

Explanation:

From the question we are told that

   The mass of the ball is  [tex]m = 0.245 \ kg[/tex]

   The radius is  [tex]r =  59.8 \  cm  =  0.598 \ m[/tex]

   The force is  [tex]F =  30.9 \ N[/tex]

   The speed of the ball is  [tex]v = 16.0 \ m/s.[/tex]

Generally the kinetic energy at the top of the circle is mathematically represented as

    [tex]K_t  =  \frac{1}{2} *  m  *  v^2[/tex]

=> [tex]K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2[/tex]  

=> [tex]K_t  =  31.36 \ J[/tex]  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       [tex]W =  F *  d[/tex]

Here  d is the length of  a semi - circular arc which is mathematically represented as

       [tex]d =  \pi * r[/tex]

So

      [tex]W =  30.9 *  0.598  [/tex]

      [tex]W = 18.48 \ J [/tex]

Generally the kinetic energy at the bottom is mathematically represented as

      [tex]K_b  =  \frac{1}{2} *  m *  v_b^2[/tex]

=>    [tex]K_b  =  \frac{1}{2} *  0.245  *  v_b^2[/tex]

=>   [tex]K_b  =  0.1225  *  v_b^2[/tex]

From the law of energy conservation

     [tex]K_t +  W  =K_b[/tex]

=>    [tex]31.36+  18.48 = 0.1225  *  v_b^2[/tex]

=>    [tex]v_b = 20.17 \ m/s[/tex]

Answer:

The answer is below

Explanation:

An LR series circuit has a differential equation in the form of:

[tex]L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=200,for\ 0 \leq t \leq\ 50. Hence:\\\\50\frac{di}{dt}+5i =200\\\\\frac{di}{dt}+0.1i =4\\\\Solving\ the\ differential\ equation:\\\\The\ integrating\ factor(I)=e^{\int\limits {0.1} \, dt }=e^{0.1t}. The\ DE\ becomes:\\\\e^{0.1t}\frac{di}{dt}+e^{0.1t}(0.1i) =4e^{0.1t}\\\\e^{0.1t}i=\int\limits {4e^{0.1t}} \, dt \\\\e^{0.1t}i=40e^{0.1t}+A\\\\i(t)=40+Ae^{-0.1t}\\\\but\ i(0)=0\\\\0=40+Ae^{-0.1(0)}\\\\A=-40\\\\i(t)=40-40e^{-0.1t}\\\\[/tex]

At 50 seconds:

[tex]i(50)=40-40e^{-0.1*50}\\\\i(50)=40-40e^{-5}[/tex]

[tex]L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=0,for\ t> 50. Hence:\\\\50\frac{di}{dt}+5i =0\\\\\frac{di}{dt}+0.1i =0\\\\\frac{di}{dt}=-0.1i\\\\\frac{di}{i}=-0.1dt\\\\\int\limits {\frac{di}{i}} =\int\limits {-0.1} \, dt\\ \\ln(i)=-0.1t+A\\\\taking\ exponential:\\\\i=e^{-0.1t+A}\\\\i=e^{-0.1t}e^A\\\\i(t)=Ce^{-0.1t}\\\\i(50)=40-40e^{-5}=Ce^{-5}\\\\C=40(e^5-1)\\\\i(t)=40(e^5-1)e^{-0.1t}\\\\[/tex]

[tex]i(t)=\left \{ {{40-40e^{-0.1t}\ \ \ \ 0 \leq t \leq 50 } \atop {40(e^5-1)e^{-0.1t}\ \ \ \ t>50}} \right.[/tex]

Answer:

breaking distance will increase by a factor 3.0625

Explanation:

From Newton's equation of motion, we can say that;

v² = u² + 2as

Where initial velocity is zero, we have;

v² = 2as

s = v²/2a

Where s is the distance and v is the final speed.

We will assume the deceleration(negative acceleration) is the same value,

Now, we see that the distance is directly proportional to the square of the velocity.

Now, 75% increase in speed means it has increased by a factor of 1.75

Thus means;

1.75²v² is directly proportional to the 1.75²d

Distance =

1.75²v² = 3.0625d

Thus, breaking distance will increase by a factor 3.0625

Answer:

The magnitude is [tex]B = \frac{450}{7.9* 10^5}[/tex]

The direction is  the positive x axis

Explanation:

From the question we are told that

   The  electric field is  E = 450 V/m in the negative y ‑direction

   The speed of the proton is  [tex]v= 7.9* 10^5\  m/s[/tex] in the positive z direction

Generally the overall force acting on  the proton is mathematical represented as

              [tex]F_E =  q(\vec E + \vec v  * \vec B)[/tex]

Now for the beam of protons to continue un-deflected along its straight-line trajectory then  [tex]F_E =0[/tex]

So

          [tex] 0  =  q( E (-y) + v(z)  * \vec B)[/tex]

=>      [tex]E\^y = v \^ z  * \vec B[/tex]

Generally from unit vector cross product vector multiplication

         [tex]\^ z  \ *  \  \^ x  =  \^  y[/tex]

So the direction of  B (magnetic field must be in the positive x -axis )

So

       [tex]E\^y = v \^ z  *  B\^ x [/tex]

=>     [tex]E\^y = vB ( \^ z  *  \^ x) [/tex]

=>     [tex]E\^y = vB ( \^y) [/tex]        

=>      [tex]E = vB [/tex]  

=>      [tex]B = \frac{450}{7.9* 10^5}[/tex]

=>      [tex]B =  0.0005696 \ T [/tex]  

.Answer:

1111.11 W

Explanation:

Power is the rate of doing work with respect to time, its S.I unit is in watts but it can also be expressed in J/s. Power is calculated using the formula:

[tex]Power=\frac{energy}{time}[/tex]

Power is also the rate at which energy is used per second.

Given that mass (m) = 100 kg, height (h) = 50 m, acceleration due to gravity (g) = 10 m/s and time = 45 s.

The man climb the stairs and experiences a potential energy, hence:

potential energy = mgh = 100 * 10 *50 = 50000 J,

[tex]Power=\frac{energy}{time}=\frac{50000}{45}=1111.11\ W[/tex]