What hazard symbol does alcohol have? Why?

Answer:

3Fe + 4H₂O --> Fe3O4 + 4H2

Answer:

55 grams

Explanation:

 55 grams of calcium chloride is the equivalent weigh because 55 grams of calcium chloride would supply one mole of positive or negative charges when dissolved in water.

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Answer:

B

Explanation:

I took the test

The empirical formula for the compound is [tex]Fe_3PO_4[/tex] if A 8.63 g sample of a compound contains 5.51 g of iron, Fe, 1.02g of phosphorus, P, and oxygen, O.

An empirical formula tells us the relative ratios of different atoms in a compound.

We need to calculate the number of moles:

Given data:

Mass of iron - 5.51 g

Mass of phosphorus -1.02g

Mass of oxygen -2.1 g

Moles of iron - [tex]\frac{mass}{molar \;mass}[/tex]

Moles of iron - [tex]\frac{5.51 g}{56 g/mol}[/tex]

0.098 mole

Moles of phosphorus [tex]-\frac{mass}{molar \;mass}[/tex]

Moles of phosphorus -  [tex]\frac{1.02g}{31 g/mol}[/tex]

0.032 moles

Moles of oxygen -[tex]\frac{mass}{molar \;mass}[/tex]

Moles of oxygen - [tex]\frac{2.1 g}{16 g/mol}[/tex]

0.13moles

Dividing each mole using the smallest number that is divided by 0.032moles.

Fe:P:O :: 3:1:4

The empirical formula for the compound is [tex]Fe_3PO_4[/tex].

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The weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.

The weight of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.

However,

the number of moles of CoCl₂ must be calculated using the following formula:

no of moles = 0.5L × 1M

no of moles = 0.5moles

Molar mass of CoCl₂ = 99g/mol

mass of CoCl₂  = 0.5 × 99

mass of CoCl₂  = 49.5g

Hence, the weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.

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160 g of SO3 are needed to make 400 g of 49% H2SO4.

The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

[tex]SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]

1 mole of SO3 produces 1 mole of H2SO4

Molar mass of SO3 = 80 g/mol

Molar mass of H2SO4 = 98 g/mol

80 g of SO3 are required to produce 98 og 100%H2SO4

mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3

Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g

Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.

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Answer:

Natural Selection

The answer is:

A. Natural Selection

In the scientific sense the two examples of people doing work is: A and D

Work can be defined as a result of applying force to a particular object that changes its displacement in the direction of the applied force.

Work can only be done when their is a force that is being applied and a displacement that occurs.

In conclusion, In the scientific sense the two examples of people doing work is: A and D

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Answer:

V = 11 L

Explanation:

To find the missing value, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this formula,

 ----> P = pressure (atm)

 ----> V = volume (L)

 ----> n = number of moles

 ----> R = constant (0.0821 atm*L/mol*K)

 ----> T = temperature (K)

You have been given all of the values in the correct units. Therefore, you can plug these values into the equation and simplify to find volume. The answer should have 2 sig figs to match the given value with the lowest amount of sig figs.

PV = nRT

(9.4 atm)V = (4.5 moles)(0.0821 atm*L/mol*K)(286 K)

(9.4 atm)V = 105.6627

V = 11 L

The moles of nitrogen produced is 0.40 moles of ammonia.

The Percent yield of ammonia is 81.2%

The moles of ammonia produced is obtained from the mole ratio of the reaction.

The mole ratio of hydrogen to nitrogen is 3 : 2

Based on the mole ratio, the limiting reactant is hydrogen.

Moles of nitrogen produced = 0.600 * 2/3 = 0.40 moles of ammonia.

mass of ammonia expected = 0.4 * 17 g = 6.8 g

Percent yield = 5.52/6.8 * 100% = 81.2%

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Answer:

B decrease the amount of solute

2.73 atm is the pressure in the vessel. Hence, option B is correct.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= ?

V= 25.1 L

[tex]n= \frac{m}{molar \;mass \;of \;nitrogen} + \frac{m}{molar \;mass \;of \;hydrogen } +\frac{m}{molar \;mass \;of \;argon}[/tex]

[tex]n= \frac{2.80 g}{14} + \frac{0.605 g}{1} +\frac{79.9 g}{40}[/tex]

n= 2.8025

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=25°C + 273= 298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]2.8025 = \frac{P\; X \;25.1 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

P = 2.73 atm

2.73 atm is the pressure in the vessel. Hence, option B is correct.

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Answer:

A

Explanation:

Answer:

A nonmetal is a chemical element that generally lacks a predominance of metallic properties. Non-metals are mostly found in groups 5, 6 and 7. These non-metals will have 5, 6 or 7 electrons in the outer shell.

The outer shell of a non-metal is, therefore, more than half full of electrons.

Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.

Normality comes out to be 8.11

n-factor for [tex]Al_{2}S_{3}[/tex] is 6 and molar mass is 148g

So, on calculating equivalent mass is equal to 24.66g

FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)

                                           N=[tex]\frac{1000}{24.66*5}[/tex]

                                          N=8.11

Therefore, normality of 1 kg aluminum sulfide is 8.11

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Answer:

1,135 grams P₄O₁₀

Explanation:

To find the mass, you need to (1) convert molecules to moles (via Avogadro's Number) and then (2) convert moles to grams (via molar mass from periodic table values). It is important to arrange the ratios/ conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 4 sig figs to reflect the given value (2.408 x 10²⁴).

Avogadro's Number:

1 mole = 6.022 x 10²³ molecules

tetraphosphorus decaoxide = P₄O₁₀

Molar Mass (P₄O₁₀): 4(30.974 g/mol) + 10(15.998 g/mol)

Molar Mass (P₄O₁₀): 283.876 g/mol

2.408 x 10²⁴ molecules P₄O₁₀                     1 mole                         283.876 g
-------------------------------------------  x  ------------------------------------  x  -----------------
                                                         6.022 x 10²³ molecules           1 mole

=  1,135 grams P₄O₁₀

Answer:

4Al +3O₂ → 2Al₂O₃

Explanation:

To balance the chemical equation, start by identifying the number of atoms of each element on both sides of the equation.

Al +O₂ → Al₂O₃

Reactants (right-hand side of the arrow)

Al➭ 1

O➭ 2

Products (left-hand side of the arrow)

Al➭ 2

O➭ 3

Balancing the equation means that we need to ensure the number of atoms of each element is the same on both sides of the equation.

Let's balance the number of O atoms.

Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 1

O➭ 3(2)= 6

Products

Al➭ 2(2)= 4

O➭ 2(3)= 6

Balancing the number of Al atoms:

4Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 4

O➭ 6

Products

Al➭ 4

O➭ 6

The equation is now balanced.

Additional:

For a similar question on balancing equations, do check out the following!

The amount of energy absorbed by the 325g of water is 57,057J. Details about calorimetry can be found below.

The energy absorbed by a mass of substance can be calculated using the following formula;

Q = mc∆T

Where;

Q = 325g × 4.18 × (92 - 50)

Q = 57,057J

Therefore, the amount of energy absorbed by the 325g of water is 57,057J.

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The electrons are arranged in different orbitals, at different energy levels and sublevels.

An atomic orbital is a function describing the location and wave-like behavior of an electron in an atom.

This function can be used to calculate the probability of finding any electron of an atom in any specific region around the atom's nucleus.

Following are the sublevel with the maximum number of electrons that can be accommodated by it ;

Therefore, S-Subshell has 2 electrons, P-subshell has 3 electrons, d-subshell has 10 electrons and f-subshell has 14 electrons.

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Answer:

I believe it is 68

Explanation:

to convert Celsius to kelvins you must add it to 273.15 for example 29 + 273.15 is 302.15

im so very sorry if im wrong.

1.199 M is the concentration of KCI in the resulting solution.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

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The amount of ice converted into steam is 13.23 gram.

Heat of Vaporisation is the amount of heat required to convert 1 gm to liquid at its boiling point to vapour.

Let x gram of ice is there

At first x gm of ice will melt

The heat required is x * Heat of fusion = x * 79.9 = 79.9x

Then the heat required to rise the temperature of x gm of water from 0 degree to 100 degree Celsius .

= mc ΔT

= x * 1 * 100 = 100x

The heat required to convert x gm of liquid into x gm of steam

= x * 540 = 540x

The total heat supplied is 9522 cal

79.9x + 100x + 540x = 9522

719.9 x = 9522

x = 13.23 gm

The amount of ice converted into steam is 13.23 gram.

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Answer:

The total number of electrons in a valence shell is called valence electrons. The electron configuration of rubidium shows that the last shell of rubidium has an electron. Therefore, the valence electrons of rubidium(Rb) are one.

Gamma rays are high-energy electromagnetic waves given off during nuclear decay; option A.

Electromagnetic waves are waves which are produced as a result of the interaction of the magnetic and electric fields.

Types of electromagnetic waves include gamma rays, radio waves, ultraviolet waves.

Gamma rays are high-energy electromagnetic waves given off during nuclear decay

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Answer:

Answer: A. Simple structure, molecule, single bonds, two elements

Answer:

N-Cl

Explanation:

Look at the chart below. Since N-Cl bond has a electronegativity difference of (3.0-3.0) zero, they are non-polar.

The balanced redox equations of the reactions are:

Balanced redox equations are those in which the atoms and electrons transferred are equal on both sides of the equation.

The balanced redox equations of the reactions are given below:

(3a) Balanced REDUCTION half reaction of the equation under basic conditions:

(3b)Balanced OXIDATION half reaction of the equation under basic conditions:

(4a) Balanced REDUCTION half reaction of the equation under acidic conditions:

(4b) Balanced OXIDATION half reaction of the equation under acidic conditions:

Therefore, the balanced oxidation and reduction half reactions are balanced by adding the numerical coefficients to the reacting species as well hydrogen ions, hydroxide ions, water molecules and electrons to the appropriate side of the reactions.

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