Answer:
meter
Explanation:
Answer: The International System of Units is a system of measurement based on 7 base units
Explanation: the metre, kilogram, second, ampere, Kelvin, mole, and candela. These base units can be used in combination with each other.
. Suppose you walk 18.0 m straight west and then 25.0 m straight north. How far are you from your starting point? What is your displacement vector? What is the direction of your displacement? Assume the +x-axis is to the east.
Answer:
Explanation:
The total distance is how far you walk from the starting point.
Distance through west = 18.0m
Distance through north = 25.0m
Total distance covered = 18.0+25.0m
Total distance covered = 43.0m
This means that I am 43.0m from the starting point
Displacement is the distance covered in a specified direction. The displacement will be gotten using the Pythagoras theorem as shown:
[tex]d^2 = 25^2 + 18^2\\d^2 = 625+324\\d^2 = 949\\d = \sqrt{949}\\ d = 30.81m[/tex]
The direction of your displacement is 30.81m
Direction is gotten according to the formula;
[tex]\theta = tan ^{-1}{\frac{y}{x} }\\\theta = tan ^{-1}{\frac{25}{-18} }\\\theta = tan ^{-1}-1.3889}\\\theta = -60.27^0\\\theta = 180-60.27\\\theta = 119.7^0[/tex]
Note that the direction to the west is negative, that is why the x is -18.0m
The distance from the starting point is 43 m, the displacement vector is 30.81 m and the direction of the displacement is 119.7 degrees.
Given-
Distance travel through the west is 18 m.
Distance travel through the north is 25 m.
Distance from starting point-
To know the total distance, add both the covered distance. Thus total distance x is,
[tex]x=18+25[/tex]
[tex]x=43[/tex]
Hence, the distance from the starting point is 43 m.
The displacement vector-
Displacement is calculated as the shortest distance between starting and final point. This shortest distance can be calculated using the Pythagoras theorem which states that in a right-angled triangle, the square of the hypotenuse [tex]d[/tex] is equal to the sum of the squares of the other two sides. Therefore,
[tex]d^2=18^2+25^2[/tex]
[tex]d^2=324+625[/tex]
[tex]d^2=949[/tex]
[tex]d=\sqrt{949}[/tex]
[tex]d=30.81[/tex]
The displacement vector is 30.81 m.
The Direction of displacement-The direction of displacement [tex]\theta[/tex] with these two sides can be calculated with the formula,
[tex]\theta=tan^{-1}\dfrac{25}{-18}[/tex]
Here due to the west direction(opposite side), the sign is taken negatively.
[tex]\theta=tan^{-1}(-1.389)[/tex]
[tex]\theta=-60.27^o[/tex]
For the other quarter,
[tex]\theta=180-60.27=119.7^o[/tex]
Hence, the distance from the starting point is 43 m, the displacement vector is 30.81 m and the direction of the displacement is 119.7 degrees.
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What is it called when scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claim?
academic claim
academic review
peer claim
peer review
Answer:
When scientists in the same or similar field of study judges the quality of a fellow scientist’s scientific claim, it is known as peer review.
When scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claim it is called Peer review.
what is the scientific claim?Scientific claims are statements made in science based on an experiment.
These Scientific claims are backed by the experimental data and their true results obtained from scientific investigation and experimentation.
Peer review is done when scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claims.
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A shopper pushes a cart 40.0 m south down one aisle and then turns 90.0° and moves 15.0 m. He then makes another 90.0° turn and moves 20.0 m. Find the shopper’s total displacement.
Answer:
25.0mExplanation:
Find the diagram attached for the schematic diagram of motion of the cart. The displacement of the cart is the length AD.
To get the length AD, we will apply Pythagoras theorem on ΔAED.
According to the theorem:
AD² = AE²+ED²
AD² = 20²+15²
AD² = 400+225
AD² = 625
AD = √625
AD = 25.0m
Hence the shopper’s total displacement is 25.0m
A stone is released from rest from the edge of a building roof 190 m above the ground. Neglecting air resistance, the speed of the stone, just before striking the ground, is:___________.
Answer:
61 m/s
Explanation:
If the stone is realeased from rest, this means that its initial velocity is 0.As tha stone is only influenced by gravity, and the acceleration due to it is constant (near the surface of the Earth), we can apply the following kinematic equation:[tex]v_{f}^{2} - v_{o}^ {2} = 2* g* h (1)[/tex]
Replacing by the values of g=9.8 m/s², and h=190 m, rearranging and solving for vf, we get:vf = √2*g*h =√2*9.8 m/s²*190 m = 61 m/s (assuming that the downward direction is the positive one).On top of a cliff of height h, a spring is compressed 5m and launches a projectile perfectly horizontally with a speed of 75 m s . It hits the ground with speed 90 m s . How high above the ground was the cliff? (Hint: use energy conservation to make the problem easier!)
Answer:
The height of the cliff is 121.276 m
Explanation:
Given;
initial velocity of the projectile, v₁ = 75 m/s
final velocity of the projectile, v₂ = 90 m/s
spring compression = 5 m
Apply the law of conservation of energy;
mgh₀ + ¹/₂mv₁² = mgh₂ + ¹/₂mv₂²
gh₀ + ¹/₂v₁² = gh₂ + ¹/₂v²
gh₁ - gh₂ = ¹/₂v₂² - ¹/₂v₁²
g(h₀ - h₂) = ¹/₂ (v₂² - v₁²)
h₀ - h₂ = ¹/₂g (v₂² - v₁²)
h₀ = h(cliff) + 5m
when the projectile hits the ground, Final height, h₂ = 0
[tex]h_o - 0 = \frac{1}{2g}(v_2^2-v_1^2)\\\\h_{cliff} + 5= \frac{1}{2g}(v_2^2-v_1^2)\\\\h_{cliff} = \frac{1}{2g}(v_2^2-v_1^2) - 5\\\\h_{cliff} = \frac{1}{2*9.8}(90^2-75^2) - 5\\\\h_{cliff} = 121.276 \ m[/tex]
Therefore, the height of the cliff is 121.276 m
The emf of the battery is 1.5 V. In Nichrome there are 9 × 1028 mobile electrons per m3, and the mobility of mobile electrons is 7 × 10−5 (m/s)/(N/C). Each thick wire has length 29 cm = 0.29 m and cross-sectional area 9 × 10−8 m2. The thin wire has length 6 cm = 0.06 m and cross-sectional area 1.3 × 10−8 m2. (The total length of the three wires is 64 cm.) In the steady state, calculate the number of electrons entering the thin wire every second. Do not make any approximations, and do not use Ohm's law or series-resistance equations.
Answer:
The number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
Explanation:
Given;
emf of the battery, V = 1.5 V
electron density, = 9 × 10²⁸ mobile electrons per m³
mobility of electron, u = 7 × 10⁻⁵ (m/s)/(N/C)
length of thin wire, L = 6 cm = 0.06 m
cross sectional area of the thin wire, A = 1.3 x 10⁻⁸ m²
The magnitude of the electric field in the thin wire is given by;
E = V/L
E = (1.5) / (0.06)
E = 25 N/C
the number of electrons entering the thin wire every second is given by;
[tex]e/s = mobility \ x \ Electric \ field\\\\number \ of \ electrons \ per \ second =\frac{7*10^{-5} (m/s)}{N/C} *25 (N/C)\\\\number \ of \ electrons \ per \ second = 1.75*10^{-3} \ m/s[/tex]
Therefore, the number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
The number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
Calculation of the number of electrons:Since
emf of the battery, V = 1.5 V
electron density, = 9 × 10²⁸ mobile electrons per m³
mobility of electron, u = 7 × 10⁻⁵ (m/s)/(N/C)
length of thin wire, L = 6 cm = 0.06 m
cross sectional area of the thin wire, A = 1.3 x 10⁻⁸ m²
So here the magnitude should be
E = V/L
E = (1.5) / (0.06)
E = 25 N/C
Now the number of electrons should be
= 7 × 10⁻⁵ *25
= 1.75 x 10⁻³ mobile
hence, The number of electrons entering the thin wire every second is 1.75 x 10⁻³ mobile electrons / second
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which statement is correct about the strength of forces?
-Electrostatic forces are exactly 10 times stronger than gravitational forces.
-Electrostatic forces are exactly 10 times weaker than gravitational forces.
-Electrostatic forces are trillions of times stronger than gravitational forces.
-Electrostatic forces are trillions of times weaker than gravitational forces.
Answer:
Thanks!!!!! adding this so it doesn’t get deleted.
Explanation:
1. Electrostatic forces are trillions of times stronger than gravitational forces. 2. normal force and friction 3. contact forces 4. The electrostatic forces from the contact of the hands with the paper causes the paper molecules to separate. 5. The electrostatic forces between the molecules of the board prevent the force of gravity from breaking the board apart.
The correct statement over here is that electrostatic forces are trillions of times stronger than gravitational forces. Hence, option C is correct.
What is an Electrostatic Force?One of the basic forces in the cosmos is electrostatic force. In the universe, there are four basic forces. These include gravitational force, electromagnetic force, weak nuclear force, and strong nuclear force. Under the umbrella of electromagnetic force is electrostatic force. Two charges placed apart are subject to the electrostatic force. The size of each charged and the separation between them determines how much electrostatic force there will be.
When two charges of the same type are brought together, whether positive or negative, they repel one another. It is known as the electrostatic force of repelling when it operates among two charges that are similar.
Therefore, the electrostatic forces are trillions of times stronger than the gravitational forces.
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What is the probability that a junior non-Physics major and then a freshman non-Physics major are chosen at random?
Answer:
Probability = 0.0244
Explanation:
Probability that Junior Non Physics Major & then a Freshman Non Physics Major are chosen:
Prob (Jr No-Ph Mjr) = Jr No-Ph Mjr / Total
= 18 / 82 = 0.2195
Prob (Fr No-Ph Mjr) = Fr No-Ph Mjr / Total (remaining)
= 9 / 81 = 0.1111
Prob [ Jr No-Ph Mjr & Fr No-Ph Mjr ] = 0.2195 x 0.1111 = 0.02439
≈ 0.0244
HELP ASAP. will mark brainiest
Answer:
4.8min
Explanation:
The police car is traveling at 100/km and is 1.6km away from red car that is traveling at 80/km
Question #2
2. Stan walks 10km west to the grocery store. He shops
then walks back 10 km east back to his house. What
distance did he cover? What was his displacement?
Answer:
Distance 20 km and Displacement 0 km
His displaceent is 0 km because he ends his walk where he started. The total distance of his walk is 20 km because he walks 10 km to the store + 10km back home.
A velocity selector uses a fixed electric field of magnitude E and the magnetic field is varied to select particles of various energies. If the electric field strength is 2.2 x 104 N/C, what should be the value of the magnetic field (in tesla) to select protons of velocity 6.4 x 105 m/s
Answer:
The value is [tex]B = 0.034 \ T [/tex]
Explanation:
From the question we are told that
The electric field strength is [tex]E = 2.2*10^{4} \ N/C[/tex]
The velocity is [tex]v = 6.4 *10^{5} \ m/s[/tex]
Generally the magnetic field is mathematically represented as
[tex]B = \frac{E}{v}[/tex]
=> [tex]B = \frac{2.2*10^{4}}{6.4 *10^{5}}[/tex]
=> [tex]B = 0.034 \ T [/tex]
Hypothesis
If an object rolls over plywood board (type of material). (describe the prediction of distance, it
will travel).
Answer:
it depend what you are.rolling down and how far would be the lighter the object the farther like a marble
Which of the following processes results in the greatest gain in kinetic energy?
A. freezing
B. condensation
C. evaporation
D. sublimation
Thanks for asking your question!
Answer:
D: Sublimation
Explanation:
Sublimation occurs when a substance changes from a solid into a gas. Increases in temperature causes the kinetic energy of particles to also increase. This allows the particles to overcome the intermolecular forces and become mobile. Low pressure also increases the particles' kinetic energy.
a car is moving at 12 m/s and has a mass of 600 kg what is the. kinetic energy of the car?
Answer:
43200 J
Explanation:
(1/2(mass)) (speed)^2
3. A car traveling initially at 7.0 m/s accelerates uniformly until it reaches 80.0 m/s. If the car
took 245 s to accelerate, what is its acceleration?
Answer:
1.1111.22222
Explanation:
Sally is on a large sailboat that comes to a stop a small distance from the dock. Since it is such a small distance, Sally decides to jump to the dock. She makes the jump, but the large sailboat moves away from her as she jumps. Since Sally is interested to see what happens on other boats, she makes the same jump from a rowboat that is much smaller than the large sailboat. Which boat will move away from Sally more slowly
Answer:
The rowboat will move away from sally more quickly because the rowboat because the sailboat is larger in mass
Explanation:
Gnerally the row boat will move away from her quicker than the sailboat this is because the mass of the sail boat is larger than the row boat , hence the frictional force that opposes motion will be greater in the sailboat than in the row boat.
Based on the information in the table, which elements are most likely in the same periods of the periodic table?
Answer:
Just to help, periods on the periodic table are those running horizontally from left to right
Answer:
The answer is A.Boron and carbon are likely together in one period because they have very close atomic numbers, while gallium and germanium are likely together in another period because they have very close atomic numbers.
Explanation:
just took test
A 4.45 g object moving to the right at 18.6 cm/s makes an elastic head-on collision with an 8.9 g object that is initially at rest.
18.6 cm/s
4.45 g
8.9 g
Find the velocity of the first object immediately after the collision. The acceleration of gravity is 9.8 m/s 2 . Answer in units of cm/s.
Answer:
v₁f = -6.2 cm/s
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved, as follows:[tex]m_{1} *v_{1o} = m_{1}* v_{1f} + m_{2}* v_{2f}[/tex]
As the collision is elastic, total kinetic energy must be conserved also:[tex]\frac{1}{2}*m_{1}*v_{1o}^{2} = \frac{1}{2}*m_{1}*v_{1f} ^{2} + \frac{1}2}*m_{2}*v_{2f}^{2}[/tex]
From the givens, we know that m₂ = 2* m₁Replacing in the above equations, rearranging both sides and simplifying, we can find the following expression for v₁f:[tex]v_{1f} = \frac{-m_{1} }{3*m_{1}} *v_{1o} =\frac{-v_{1o}}{3} = -\frac{18.6 cm/s}{3} = -6.2 cm/s[/tex]
v₁f = -6.2 cm/s (which means that it bounces back after the collision).A car starts from rest and accelerates uniformly over a time of 5 second and reaches a velocity of 122 m/s. Determind the acceleration of the car.
Answer:
23.44444444
Explanation:
Velocity which stone gains when falling from height of 80 m is approximately equal to *
A. 0
B. 1 m/s
C. 8 m/s
D. 40 m/s
E. 300 m/s
Answer:
40
Explanation:
A 12 kg bowling ball would require what force to accelerate it down an alley at a rate of 2.5 m/s ^ 2
Answer:
hi
Explanation:
hiijjjjjjjjjjjjjjj
the diagram shows a contour map. letter a through k are reference points on the map. which points are located at the same elevation above sea level?
Answer:
K and I
Explanation:
Contour maps use lines that represent spaces in a map that have the same elevation, this means that all the lines should be continuous and closed, in this case, we are not able to see the full extent of most of the lines, but since the points are located in different lines we can assume that they are at different heights, so since only point K and point I are on the same line, we know that these two points are at the same height.
Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist her and parks their car 14 meters from the front of her car. Marcella grabs the car bumper and pulls very hard, with 200 N of force. The work she does transfers energy out, it reduces the K of the car, as it gradually approaches the other car. a) What is the initial kinetic energy before she tries to stop the car? b) What is the final kinetic energy, when her car hits the other car? What is the speed? c) Suppose the other person also slowed her car, pushing it from the front. How much force would be needed to stop her car 1 meter from the other car? [1 m allows the person not to be crushed!]
Answer:
Explanation:
a) KE = (1/2) * m * ([tex]v^{2}[/tex]) = F * d = 14m * 200N = 2800 m/N or 2.8 * [tex]10^{3}[/tex] m/N
b) 0J and 0m/s (if Marcella stopped after going 14 meters)
c) Known from part (a) that KE = 2800 J = F1 * d1,
2800J = F1 * (14m - 1m) => F1 = 2800J/13m = 215.384 N
What are the three different types of muscle tissue?
Answer:
skeletal,cardiac,and smooth.
Explanation:
Answer:
Skeletal, smooth, and cardiac.
Explanation:
Skeletal Muscles:
Skeletal muscles are the most familiar type of muscles; they make up most of the muscle mass in the body. Flexible bands of connective tissue called tendons attach these muscles to the bones in the body. Skeletal muscles control voluntary movement in the body.
Smooth Muscles:
Smooth muscles are involuntary muscles that we don’t consciously control. They are found within the walls of many organs and control the movement of these organs. For example, they enable the movement of food through the digestive system.
Cardiac Muscles:
Cardiac muscles are a special type of involuntary muscle. Located in the heart, these muscles control the contractions of the heart.
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To pull a nail out of a wood board a carpenter does 1000 J of work. The hammer he uses does 835 J of work. What is the efficiency of the hammer?
Answer:
83.5%
Explanation:
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive force of 115 N to the tire's rim. The mass of the wheel is 1.80 kg and, for the purpose of this problem, assume that all of this mass is concentrated on the outside radius of the wheel. The diameter of the wheel is 50.0 cm. A chain passes over a sprocket that has a diameter of 8.50 cm. In order for the wheel to have an angular acceleration of 4.30 rad/s2, what force, in Newtons, must be applied to the chain
Answer:
The force is [tex] F_c = 789.03 \ N [/tex]
Explanation:
From the question we are told that
The tangential resistive force is [tex]F_t = 115 \ N[/tex]
The mass of the wheel is m = 1.80 kg
The diameter of the wheel is [tex]d = 50.0 cm = 0.5 \ m[/tex]
The diameter of the sprocket is [tex]d_c = 8.50 \ cm =0.085 \ m[/tex]
The angular acceleration considered is [tex]\alpha = 4.30\ rad/s^2[/tex]
Generally the radius of the wheel is
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.5}{2}[/tex]
=> [tex]r = 0.25 \ m [/tex]
Generally the radius of the sprocket is
[tex]r_c = \frac{d_c}{2}[/tex]
=> [tex]r_c = \frac{0.085}{2}[/tex]
=> [tex]r_c = 0.0425 \ m [/tex]
Generally the moment of inertia of the wheel is mathematically represented as
[tex]I = m * r^2[/tex]
=> [tex]I = 1.80 * 0.25^2[/tex]
=> [tex]I = 1.1125 \ kg \cdot m^2[/tex]
Generally the torque experienced by the wheel due to the forces acting on it is mathematically represented as
[tex]\tau = F_c * r_c - F_t * r [/tex]
Here [tex]F_c[/tex] is the force acting on the sprocket
So
[tex]\tau = F_c * 0.0425 - 115 * 0.25 [/tex]
[tex]\tau = 0.0425F_c - 28.75 [/tex]
Generally the torques that will cause the wheel to move with [tex]\alpha = 4.30\ rad/s^2[/tex] is mathematically represented as
[tex]\tau = I * \alpha[/tex]
So
[tex] 0.0425F_c - 28.75 = I * \alpha [/tex]
[tex] 0.0425F_c - 28.75 = 1.1125 *4.30 [/tex]
[tex] 0.0425F_c - 28.75 = 1.1125 *4.30 [/tex]
[tex] F_c = 789.03 \ N [/tex]
A 31.0 cm long spring is hung vertically from a ceiling and stretches to 36.9 cm when an 8.00 kg mass is hung from its free end.
(a) Find the spring constant (in N/m).
(b) Find the length of the spring (in cm) if the 8.00 kg weight is replaced with a 185 N weight.
Answer:
The length of the spring is 44.92 cm
Explanation:
Hooke's Law
Suppose a spring of constant k and natural length x0. If a force F is applied to the spring and it stretches to a distance x1. Hooke's Law states that:
[tex]F=k.x[/tex]
Where x is the elongation of the spring:
[tex]x=x1-x0[/tex]
We are given the characteristics of a spring of x0=31 cm. When a mass of m=8 Kg is hung from the spring, it stretches to x1=36.9 cm. We need to calculate the force of the mass of 8 Kg. It can be done by calculating the weight:
[tex]F = m.g=8\ Kg\cdot 9.8\ m/s^2[/tex]
[tex]F=78.4\ N[/tex]
The elongation of the spring is
[tex]x=36.9\ cm - 31\ cm = 5.9\ cm[/tex]
Converting to meters:
[tex]x=5.9/100=0.059\ m[/tex]
(a)
From Hooke's Law, we solve for k:
[tex]\displaystyle k=\frac{F}{x}=\frac{78.4}{0.059}[/tex]
[tex]k=1,329\ N/m[/tex]
(b) With the value of k, the equation for the spring is:
[tex]F=1,329.x[/tex]
Now if a weight of F=185 N is hung from the spring, the elongation is:
[tex]\displaystyle x=\frac{F}{1,329}=\frac{185}{1,329}[/tex]
[tex]x=0.1392\ m=13.92\ cm[/tex]
Thus, the length of the spring is:
[tex]x1=xo+x=31\ cm+13.92\ cm=44.92\ cm[/tex]
The length of the spring is 44.92 cm
(a)The spring constant will be 1,329 N/m.
(b)The length of the spring will be 44.92 cm.
What is the spring constant?Spring constant is defined as the ratio of force per unit displaced length. The spring force is balanced by the weight;
The given data in the problem is;
L₁ is the long spring is hung vertically from a ceiling= 31.0 cm
L₂ = 36.9 cm
m is the mass= 8.00 kg
The net elongation of the spring is
x= 36.9-31 =5.9 cm = 0.059 m
The force acted on the spring due to which the elongation is done;
F=mg
F= 8 × 9.81
F=78.4 n
From the Hooke's law the spring constant is found as;
[tex]\rm K = \frac{F}{x} \\\\ \rm K = \frac{78.4}{0.059} \\\\ \rm K = 1,329 \ N/m[/tex]
Hence the spring constant will be 1,329 (in N/m).
(b) The length of the spring will be 44.92 cm.
For the weight of F=185 N is hung from the spring, the elongation is:
[tex]\rm x= \frac{185}{1,329} \\\\ \rm x=0.10392 m = 13.92 \ cm[/tex]
The length of spring is;
[tex]\rm x_1 = x_0+x \\\\ \rm x_1 = 31+13.92 \\\\ \rm x_1=44.92\ cm[/tex]
Hence the length of the spring will be 44.92 cm.
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A region around the nucleus of an atom where electrons are likely to be found
Answer:
The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.
Explanation:Hope this helps :)
By definition, a region around the nucleus of an atom where electrons are likely to be found is called an orbital.
First of all, an atom is the smallest constituent unit of ordinary matter that has the properties of a chemical element.
All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged.
In other words, every atom consists of a nucleus in which neutrons and protons meet and energy levels where electrons are located.
This is, the atomic nucleus is the central part of the atom that is made up of protons and neutrons, while the orbitals or peripheral region is an area where electrons are found.
In summary, a region around the nucleus of an atom where electrons are likely to be found is called an orbital.
Learn more:
https://brainly.com/question/10866484?referrer=searchResultshttps://brainly.com/question/1275002?referrer=searchResultsbrainly.com/question/1814899?referrer=searchResults brainly.com/question/2449569?referrer=searchResultsWhich of the following is an example of benefits?
Travel
Physical activity
Salary
Insurance
Insurance is an example of benefits therefore the corrct answer is option D.
What is exercise?The exercise has a beneficial effect on the body and differs the type of death a person undergoes. If a person exercises but sits for too long can result in many diseases that ultimately lead to death. Along with exercise, the person should do mobile activities so that it increases their fitness.
It is among the most notable and significant advantages of insurance. According to insurance plans, the insured person or companies are protected from liabilities. The correct kind of insurance coverage might help you protect yourself from losses brought on by various life uncertainty.
Insurance is a good example of a benefit because, unlike salaries, which are things you earn as a base when you start a job, benefits are things you only receive as a result of working in certain jobs.
Thus,the correct answer is option D.
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Children ages 6-15 normal heart rate is __________ beats per minute ??
Answer:
70-100 BPM
Explanation: