What are the solutions to the following system?

The answer to this question is choice B

Using it's formula, it is found that the estimate monthly payment is of $480.42.

It is given by:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

In which:

The parameters are given as follows:

P = 25000, n = 60, r = 0.0575.

Hence:

r/12 = 0.0575/12 = 0.00479167.

Hence the payment will be of:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

[tex]A = 25000(0.00479167)\frac{(1+0.00479167)^{60}}{(1+0.00479167)^{60}-1}[/tex]

A = 480.42.

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Thank you for asking this question. Here is your answer:

We will consider the price of the truck to be $x

And the amount of tax in the percentage would be 13%

13/100

= $ 0.13x (this is the actual amount of the tax)

Now we will calculate the total price of the truck =

$x + $ 0.13x

= $ x(1 + 0.13)

If there is any confusion please leave a comment below.

Using the t-distribution, the correct option regarding the test statistic and the p-value is given as follows:

t = –1.85; the P-value is between 0.025 and 0.05.

The null hypothesis is:

[tex]H_0: \mu = 25[/tex]

The alternative hypothesis is:

[tex]H_1: \mu < 25[/tex]

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

In this problem, the values of the parameters are given as follows:

[tex]\overline{x} = 23.5, \mu = 25, s = 4.8, n = 35[/tex]

Hence the value of the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{23.5 - 25}{\frac{4.8}{\sqrt{35}}}[/tex]

t = -1.85.

Using a t-distribution calculator, with a left-tailed test, as we are testing if the mean is less than a value and 35 - 1 = 34 df, the p-value is of 0.0365.

Hence the correct statement is:

t = –1.85; the P-value is between 0.025 and 0.05.

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The new coordinate will be T'(3.2 , -1.6) .

Dilation is the transformation that changes the size of the object without changing its shape .

If a coordinate point is (x,y) and a dilation of scale factor f is applied then the new coordinates will be (fx ,fy)

The coordinate given in the question is T(8, -4)

The scale factor is 0.4

The new coordinate is

T'( 0.4 * 8 , 0.4 * (-4))

T'(3.2 , -1.6)

Therefore the new coordinate will be T'(3.2 , -1.6)

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Conditional statements are ones that begin with a hypothesis and end with a conclusion. The correct option is A and C.

Conditional statements are ones that begin with a hypothesis and end with a conclusion. It is sometimes referred to as a "If-then" statement. If the hypothesis is correct but the conclusion is incorrect, the conditional statement is incorrect.

The two statements that among which one is original and the other one is its converse is If the object weighs a ton, then the scale reads 2000 pounds, and  If the scale reads 2000 pounds, then the object weighs a ton.

Hence, the correct option is A and C.

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Answer:

a

Step-by-step explanation:

Answer:

16 or -2

Step-by-step explanation:

Let the number be x.

Difference between the number and 7

= x -7 or 7-x

The square of the difference between x and 7

= (x -7)²

(x -7)²= 81

Square root both sides:

[tex]x - 7= \pm \sqrt{81} [/tex]

[tex]x - 7 = \pm9[/tex]

Add 7 to both sides:

[tex]x = 7\pm9[/tex]

x= 16 or x= -2

Thus, the number could either be 16 or -2.

Answer:

x² - 10x + 9 = (x-9)(x-1)

the factored expression would be (x-9)(x-1)

Answer:

A,E

Step-by-step explanation:

Answer:

x = 3
x = -8

Step-by-step explanation:

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[tex] \: \: [/tex]

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[tex]\Large{ \boxed{ \tt{ \blue{S}}}}\Large{ \boxed{ \tt{ \pink{O}}}}\Large{ \boxed{ \tt{ \green{L}}}}\Large{ \boxed{ \tt{ \purple{U}}}}\Large{ \boxed{ \tt{ \red{T}}}}\Large{ \boxed{ \tt{ \pink{I}}}}\Large{ \boxed{ \tt{ \blue{O}}}}\Large{ \boxed{ \tt{ \pink{N}}}}[/tex]

[tex] \: \: [/tex]

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keep learning

Answer:

Step-by-step explanation:

sin θ=1/4,tan θ>0

so θ lies in first quadrant.

cos θ=√(1-sin²θ)=√(1-(1/4)²)=√(1-1/16)=√(15/16)=√15/4

[tex]2cos^2 \frac{\theta}{2} =1+cos \theta[/tex]

[tex]2~cos^2\frac{\theta}{2} =1+\frac{\sqrt{15} }{4} =\frac{4+\sqrt{15}}{4} \\cos~\frac{\theta}{2} =\sqrt{\frac{4+\sqrt{15} }{4 \times 2} } \\cos\frac{\theta}{2} =\frac{\sqrt{8+2\sqrt{15}} }{4}[/tex]

Answer:

1/5764801

Step-by-step explanation:

7^-1 × 7^-7

= 1/7(7^-7)

= 1/7(1/823543)

= 1/5764801

12a - 8 -5a + 12

arranging like terms

12a - 5a - 8 + 12

a ( 12-5) - 8 - 12

a(7) - 4(2 - 3)

a(7) -4(-1)

a(7) + 4

7a + 4

simplifing the expressions

Answer:

12a-5a-8+12

=(12-5)a+4

=7a+4

Based on the definition of a circumcircle, the center of the circle as shown in the image below is located: B. inside the triangle.

A circumcircle, as shown in the diagram attached below, is a circle that is drawn so that all the vertices of a triangle touches the circumference of the circle.

Thus, as shown in the image attached below, the center of the circle is located: B. inside the triangle.

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Answer: OUTSIDE THE TRIANGLE

Step-by-step explanation: ANSWER ON EDMENTUM/PUTO

The solution of the system of equations is (1, -3/4)

Here we have the system of equations:

y = (1/4)*x - 1

y = -(1/2)*x - 1/4

To solve it, we use the fact that the variable "y" is the same in both equations, then we can write:

(1/4)*x - 1 = -(1/2)*x - 1/4

Now we can solve that for x:

(1/4)*x - 1 = -(1/2)*x - 1/4

(1/4)*x + (1/2)*x = 1 - 1/4

(1/4)*x + (2/4)*x =  1 - 1/4

(3/4)*x = 3/4

x = 1

To get the y-value of the solution, we just evaluate x = 1 in any of the two given lines, using the first one:

y =  (1/4)*(1) - 1 = -3/4

So the solution is (1, -3/4)

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Answer:

x= 14, –12

Step-by-step explanation:

The given question might make you believe that it's difficult due to it's frightening digit (168) but in fact in you use the following methods, it's going to be a pieces of cake.

the delta formula:

Δ=b²–4ac===> (–2)²–4(1)(–168)=676

[tex]x 1 = \frac{ - ( - 2) + \sqrt{676} }{2} = 14 [/tex]

[tex]x2 = \frac{ - ( - 2) - \sqrt{676} }{2} = - 12[/tex]

well this can be on of the methods and the other one is

The full square formula:

[tex]x ^{2} - 2x - 168 = 0 \\ {x}^{2} - 2x = 168[/tex]

[/tex]

now what you need to do is to put this on both side of the equation (½b)²=1

[tex] {x}^{2} - 2x + 1 = 168 + 1 \\ {(x - 1)}^{2} = 169 \\ x - 1 = 13 = = > x = 14 \\ x - 1 = - 13 = = = > x = - 12[/tex]

Answer:

216

Step-by-step explanation:

4x+8yz+3y

Let x=3 y=4 z=6

Substitute the values into the expression

4(3)+8(4)(6)+3(4)

Multiply first

12+192+12

Then add

216

Answer:

29, 36, 38

Step-by-step explanation:

The pattern is add 7 then 2, then 7, then 2, then 7, then 2. You should get the hang of it. All you have to do is just do the same thing for the next three numbers.

Answer:

[tex]x+4\geq 12[/tex]

Step-by-step explanation:

x - a number

x+4 - a number plus 4

x+4[tex]\geq[/tex] - a number plus 4 is greater than or equal to

x+4[tex]\geq[/tex]12 - a number plus 4 is greater than or equal to twelve

Answer:

Inequality:  x + 4 ≥ 12

Solution:  x ≥ 8

Step-by-step explanation:

Plus:  "+" →  to add something to something else

Greater than or equal to:  "≥" → the expression on the left side of the inequality sign is greater than the expression on the right side of the sign.

Let x be the unknown number.

A number plus four is greater than or equal to twelve:

x + 4 ≥ 12

To solve the found inequality, subtract 4 from both sides:

⇒ x + 4 - 4 ≥ 12 - 4

⇒ x ≥ 8

Therefore, the solution to the inequality is x ≥ 8.  The unknown number x can be any real number equal to or greater than 8.

Based on the par value of the bond and the percentage it was issued at, the cost of the bond is $852.50.

The current cost of the bond is the present value of the bond's cashflows and its par value.

This is taken into account when the bond is issued at a certain percentage which in this case is 85 ¹/₄%.

The cost of the bond is:

= 1,000 x 85 ¹/₄%

= $852.50

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Answer:

See below ~

Step-by-step explanation:

1) a) 50 km / 2 h

⇒ 25 km/h

b) 540 kg / 3 days

⇒ 180 kg/day

c) 125 m / 5 min.

⇒ 25 m/min.

A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate…

a) 50km/2h

=> 25 kilometers per hour

b) 540kg/3d

=> 180 kilogram per day

c) 125m/5min

=> 25 meter per minute

The minimized value is 50 and the maximized value is 130

The objective function is:

P = 10x + 5y

Subject to

2x+3y ≤30

2x+y ≤ 26

-2x+3y ≤ 30

x, y >0

Next, we plot the graph of the constraints (see attachment)

From the graph, the vertices of the feasible regions are:

(0, 10),(12, 2) and (6,14)

Substitute these values in P = 10x + 5y

P = 10(0) + 5(10) = 50

P = 10(12) + 5(2) = 130

P = 10(6) + 5(14) = 130

Hence, the minimized value is 50 and the maximized value is 130

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A parabola is a mirror-symmetrical planar curve that is nearly U-shaped. The vertex of the parabola will lie at (-3,2).

A parabola is a mirror-symmetrical planar curve that is nearly U-shaped.

y = a(x-h)² + k

where,

(h, k) are the coordinates of the vertex of the parabola in the form (x, y);

a defines how narrower is the parabola, and the "-" or "+" that the parabola will open up or down.

Comparing the given equation with the equation of a parabola, we will get,

y =  a(x -h)² + k

y = -4(x+3)² + 2

Hence, the vertex of the parabola will lie at (-3,2).

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Step-by-step explanation:

Part A:

So the height is going to be x when you fold the sides up. So that's one part of the volume but for the width it was going to be 4 but since two corners were cut out with the length x the new width is going to be (4-2x). The same thing applies for the length which should be 8 inches but since two corners were removed with the length x it's now (8-2x)

v = x(4-2x)(8-2x)

Part B:

The volume can be graphed although there must be a domain restriction since the height, width, or length cannot be negative. So let's look at each part of the equation

so for the x in front it must be greater than 0 to make sense

for the (4-2x), the x must be less than 2 or else the width is  negative.

for the (8-2x) the x must be less than 4 or else the length is negative

so the domain is going to be restricted to 0 < x < 2 so all the dimensions are greater than 0

By using a graphing calculator you can see the maximum of the given equation with the domain restrictions is 0.845 which gives a volume of 12.317  

Step-by-step explanation:

the answer is 2.27. hope this helps

The cost to paint a is 12/13 square feet per dollar.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Jacob spends 13/4 dollars to paint 9/3 square feet.

[tex]\dfrac{\dfrac{9}{3}}{ \dfrac{ 13}{4}} = \dfrac{9}{3} \times \dfrac{ 4}{13}\\\\= \dfrac{ 36}{39}\\\\= \dfrac{ 12}{13}[/tex]

Hence, the cost to paint a is 12/13 square feet per dollar.

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Answer:

28 cm

Step-by-step explanation:

The corner to corner cut is a hypotenuse. We know one leg, 45cm. So use Pythagorean theorem to solve for the other leg. See image.

False

Step-by-step explanation:

Answer:

true.

Step-by-step explanation:

[tex]b^t=\frac{n}{a}; \ = > \ t=log_b\frac{n}{a}; \ = > \ t=\frac{log\frac{n}{a}}{logb}.[/tex]