What are the domain and range of f(x) = 2x - 41?
O domain: x < 2; range: (-00,00)
O domain: (-00,00); range: f(x) > 0
O domain: (-0,00); range: f(x) ≤0
O domain: x ≥ 2; range: (-00,00)

The measure of the exterior angle PNM will be x < 77. Then the correct option is C.

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

Triangle NPO is shown.

Line ON extends through point M to form exterior angle PNM.

Angle NPO is 38 degrees.

Angle PON is 39 degrees.

Let the exterior angle PNM is x degrees and the interior angle PYO be y.  

Then we have

38 + 39 + y = 180°

                y = 103°

And we know that the sum of interior and exterior angle is a triangle is 180 degrees.

   x + y < 180

103 + x < 180

         x < 77

Then the correct option is C.

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The asymptote and the y-intercept of the function is asymptote: y = 2

y-intercept: (0,8) , Option A is the answer.

Asymptote is a straight line that approaches the curve but does not meet even at infinite distance.

It is given that f(x) = 6 (0.5)ˣ +2

The horizontal asymptote is at y = c

y = 2

From the curve it can be seen that

The intercept of y axis is determined when x = 0

then f(0) = 6 * (0.5)⁰ + 2

f(0) = 8

Therefore the y intercept is at (0,8)

Therefore Option A is the right answer.

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Answer:

C

Step-by-step explanation:

thats what i got

Answer:

The algebraic expression which represents the phrase “two times the quantity of a number minus 12” is : 2x- 12

Step-by-step explanation:

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.

for example :-

3x + 4y – 7,  4x – 10, etc.

These expressions are represented with the help of unknown variables, constants and coefficients. The combination of these three (as terms) is said to be an expression. It is to be noted that, unlike the algebraic equation, an algebraic expression has no sides or equal to sign

let the quantity mentioned in the question be 'x'

therefore according to the statement the algebraic expression which represents the phrase “two times the quantity of a number minus 12” is : 2x- 12 is

⇒2x - 12 (answer)

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Answer:

-3x-7

Step-by-step explanation:

Remember this in mind while solving.

negative + negative = negative.

= −3x−6+(−1)

= -3x-7

Therefore when −3x−6+(−1) is evaluated it is

-3x-7

Answer:

65.4

Step-by-step explanation:

5 × 6 = 30 square meter

30 × 2.18 = 65.4

Answer:

D. 240

Step-by-step explanation:

6 types of backpacks = 6

4 types of binders = 4

5 types of pencils = 5

2 types of notebook paper= 2

6×4×5×2=

24×10=

240

The number of possible outcomes will be 240. The correct option is D.

Expression in maths is defined as the relation of numbers variables and functions by using mathematical signs like addition, subtraction, multiplication and division.

Given that there are 6 types of backpacks, 4 types of binders, 5 types of pencils, and 2 types of notebook paper.

6 types of backpacks = 6

4 types of binders = 4

5 types of pencils = 5

2 types of notebook paper= 2

The number of possible outcomes will be calculated as:-

N = 6×4×5×2

N = 24×10

N = 240

Therefore, there will be 240 possible outcomes. The correct answer is D.

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Answer:

See Below

Step-by-step explanation:

The equation for this scenario would be  ( compounded annually)

6600 ( 1 + .006)^6         = £ 6841.19

Answer:

Brian will have £6841.19 after 6 years.

Step-by-step explanation:

The compound interest formula is:

[tex]A = P( 1 +\frac{r}{100} )^{n}[/tex] ,

where A is the final amount, P is the initial (principal) amount invested (£6600), r is the interest rate (0.6%) and n is the number of years the money is kept for (6 years).

Using the formula:

[tex]A = 6600(1 + \frac{0.6}{100} )^{6}\\\\A = 6841.19[/tex]

An equation is formed of two equal expressions. The correct option is B.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The complete option is:

Which values of a and b make the equation true?

[tex]\dfrac{(2xy)^4}{4xy}=4x^ay^b[/tex]

A)a = 0, b = 0

B)a = 3, b = 3

C)a = 4, b = 4

D)a = 5, b = 5

The given equation can be simplified as shown below,

[tex]\dfrac{(2xy)^4}{4xy}=4x^ay^b\\\\\dfrac{2^4 \times x^4 \times y^4}{4xy}=4x^ay^b\\\\\dfrac{16x^4y^4}{4xy} = 4x^ay^b\\\\4x^{(4-1)}y^{(4-1)} = 4x^ay^b\\\\4x^3y^3 = 4x^ay^b[/tex]

Now, comparing the two sides of the equation, the value of a and b should 3 for the equation to be satisfied.

Hence, the correct option is B.

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Answer:

So none of these would be a perfect square but the closet one to it would be 65

Step-by-step explanation:

The Arc Length BD from the given diagram is; 4.09π = 12.85 in

From the attached image, we are given;

m∠APC = 92°

Now, from the principle of vertical angles being congruent, we have;

m∠APC = m∠BPD = 92°

Thus;

Arc length BD = 2π * 8 * (92/360)

Arc Length BD = 4.09π = 12.85 in

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Answer:

This mapping isn't a function.

Step-by-step explanation:

A mapping specifies a relation between two sets of items (input and output). For example, a mapping of the form [tex]\lbrace (x_{0},\, y_{0}),\, (x_{1},\, y_{1})\rbrace[/tex] would map the input [tex]x_{0}[/tex] to output [tex]y_{0}[/tex] and map the input [tex]x_{1}[/tex] to output [tex]y_{1}[/tex].

A function is a mapping where each input is associated with exactly one output.

Note that both [tex](2,\, 1)[/tex] and [tex](2,\, 4)[/tex] are in the mapping given in this question. The input [tex]2[/tex] is mapped to more than one outputs. Thus, this mapping isn't a function.

4x² + 6x = 12

We move all the terms to the left:

The value of Δ is greater than zero, so the equation has two solutions

We use the following formulas to compute our solutions:

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b-\sqrt{\Delta} }{2a }| \ x_{2}=\dfrac{-b+\sqrt{\Delta} }{2a } } \end{gathered}$}[/tex]

The end solution:

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57} } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b-\sqrt{\Delta} }{2a}=\dfrac{-(6)-2\sqrt{57} }{2*4}=\dfrac{-6-2\sqrt{57} }{8} } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b+\sqrt{\Delta} }{2a}=\dfrac{-(6)+2\sqrt{57} }{2*4}=\dfrac{-6+2\sqrt{57} }{8} } \end{gathered}$}[/tex]

Answer:

1a7

Step-by-step explanation:

26+-25=1

Answer:

  (a)  18%

Step-by-step explanation:

The debt to credit ratio is found by dividing his debt by his credit limit.

__

  ratio = debt/credit limit = $1551.42/$8619.00 ≈ 0.18 = 18%

Quentin's debt to credit ratio is 18%.

Answer:

D.) Yes, because it passes the vertical line test.

Step-by-step explanation:

For a function to be a function, there must be one output for every input. IN other words, there must be one "y" value for every "x" value. One can see if a graph passes this test by performing the vertical line test.

In this case, the line on the graph passes the test and represents a function. Again, this is because each "x" value has only one "y" value.

Yes, The graph is function because it passes the vertical line test.

We have to given that,

A graph of function is shown in image.

Since, A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

And, The vertical line test is used to determine if a graph of a relationship is a function or not. if you can draw any vertical line that intersects more than one point on the relationship, then it is not a function.

Hence, By given graph,

it passes the vertical line test.

So, Graph shown is a function.

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Answer:

[tex]222cm^{2}[/tex]

Step-by-step explanation:

First we will find the length of BD.

By Pythagoras' Theorem,

[tex]c^{2} =a^{2} +b^{2} \\BD^{2} = AD^{2} +AB^{2} \\BD^{2} =12^{2} +16^{2} \\BD^{2} = 144+256\\BD^{2} =400\\BD = \sqrt{400} \\=20cm[/tex]

Now we will find Angle ADB.

[tex]\frac{AB}{sin(Angle ADB)} =\frac{BD}{Sin(AngleBAD)} \\\frac{16}{sin(AngleADB)} =\frac{20}{sin(90)} \\20sin(AngleADB)=16sin(90)\\20sin(AngleADB)=16\\sin(AngleADB)=\frac{16}{20} \\sin(AngleADB)=0.8\\AngleADB=sin^-1(0.8)\\=53.130deg\\[/tex]

Now we will find Area of triangle BCD

[tex]Angle BDC = 90 - Angle ADB = 90 - 53.130 = 36.87deg\\\\\\Area of Triangle BCD \\= \frac{1}{2} (BD)(CD)sin(AngleBDC)\\=\frac{1}{2} (20)(21)sin(36.87)\\= 126cm^{2}[/tex]

Then we will find the area of triangle BAD

[tex]=\frac{1}{2} (16)(12)\\= 96cm^{2} \\[/tex]

Area of quadrilateral = Area of Triangle BCD + Area of Triangle BAD

= 126+96

= [tex]222cm^{2}[/tex]

Answer:

Step-by-step explanation:

it is a trapezoid

so

A = ½ (a + b) h

A = ½ (16 + 21) × 12

A = ½ 37 × 12

A = ½ 444

A = 222 cm²

Answer:

x=79/5 or 15.8

Step-by-step explanation:

....................

Answer:

[tex]\frac{79}{5}[/tex]

Step-by-step explanation:

Combine [tex]\frac{1}{3}[/tex] and x.

[tex]\frac{x}{3} +\frac{11}{15}=6[/tex]

Move all terms not containing x to the right side of the equation.

[tex]\frac{x}{3}=\frac{79}{15}[/tex]

Multiply both sides of the equation by 3.

3[tex]\frac{x}{3}[/tex]=3([tex]\frac{79}{15}[/tex])

Then 3 cancels out on the left side so all is left is 3.

On the right side, you need to multiply.

3 times 79 is 237.

Now simplify and you get:

79/5

Hope this helped!

The Common Ratio is 1.05 . Option C is the answer.

The complete question is

Which value should she use as the common ratio?

0.05

0.5

1.05

5.0

In a Geometric Sequence the ratio between each if the consecutive number is called the common Ratio.

Let Yui saving at the end of first month is Rs.x .

As given in the question

each month’s total is 5% greater than the previous month’s total.

Saving after second month is = First Month Total + 5% of First Month Total

= x + (5 % of x )

= x + (5*x/100)

= x + 0.05x

= 1.05x.

Yui balance is 1.05 times of Previous Month balance

Common Ratio = {Next Month }/ {Previous Month}

Common Ratio = 1.05 x / x

Common Ratio = 1.05

Therefore Common Ratio is 1.05 . Option C is the answer.

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Answer:

Step-by-step explanation:

Based on the table, a possible taxable income for a taxpayer that's filing with the Single filing status in the 33% federal income tax bracket is $300,000.

Taxation is the involuntary fees that are levied on individuals or business firms by the government of a particular country, so as to generate revenues that can be used to fund public projects, institutions and activities.

In this scenario, we can infer and logically deduce that a possible taxable income for a taxpayer that is filing with the Single filing status in the 33% federal income tax bracket is $300,000.

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Step-by-step explanation:

hope you can understand

Answer:

Step-by-step explanation:

As host, we want to insure each guest has at least one slice of pie.  We can say  (1 Slice/Guest) and use this as a conversion factor.  We also know each pie has 8 slices:  (8 Slices/1 Pie).  Since this is a conversion factor, we can invert it to (1 Pie/8 Slices).  We expect 38 people and want to convert that number of people to the number of pies, p, we need.

  p (pies) [tex]\geq[/tex] (38 Guests)*(1 Slice/Guest)*(1 Pie/8 Slices)

We use the [tex]\geq[/tex] sign to note that we need a minimum of pies to be sure everyone is served.

p (pies) [tex]\geq[/tex] (38 )*(1 /)*(1 Pie/8 )

Note how the units cancel:

Guests and Slices both cancel and we are left with pies as the only remaining unit, as we hoped we'd see.

p [tex]\geq[/tex] (38/8) pies

p = 4 +(6/8) pies

Since we cannot purchase 6/8 of a pie, we need to round up to 5 pies.

5 pies, at 8 slices per pie, will provide 40 servings, enough for the 38 guests.

Answer:

x=5

\

Step-by-step explanation:

Answer:

x = 0

Step-by-step explanation:

Line segment UV and line segment VW together form line segment UW.

UV + VW = UW

(5 + x) + (6) = (2x + 11)

5 + x + 6 = 2x + 11

x + 11 = 2x + 11

x + 11 - 11 = 2x + 11 - 11

x = 2x

x - x = 2x - x

0 = x

You can also verify the result by substituting x with our result 0.

5 + x + 6 = 2x + 11

5 + (0) + 6 = 2(0) + 11

11 + 0 = 0 + 11

11 = 11

Left side of the equation is the same as the right side of the equation, therefore the result x = 0 is correct.

The average rate of the change from x = 2 to x = 5 is about 20 , The domain is constrained at x =0

A function is a mathematical statement used to derive a relation between a dependent variable and an independent variable.

A) The vertical axis of the graph shows a company's profit f(x), in dollars, depending on the price of pencils x, in dollars, sold by the company , i.e is the x axis .

So the x-intercepts represent prices of the pencil at which the profit is 0

and The maximum value of the graph represents the maximum profit that can be obtained for any price of the pencil.

The Profit is increasing from (x = 0 to 5) and starts decreasing from x =5 to 10

B) From the graph

(f(5) -f(2))/(5 -2) = (160-100)/3  = 20

The average rate of the change from x = 2 to x = 5 is about 20.

This indicates that the profit will increase at a an average rate of $20 for each $1 increase in price in that interval.

(C)The domain is constrained at x =0 as there it cannot be concluded that if the price is 0 , the profit will be 0 , and we are obligated to sell the pencil at x =6 , as the maximum profits are booked at that point.

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Answer:

20

Step-by-step explanation:

⇒ Multiply 2 by 3

2 * 3 = 6

4 (6 - 1)

⇒ Distribute terms

4 * 5

20

Hence, the answer is 20.

x=  10, NL= 8 , NP = 12

A secant is a line that intersects a curve at a minimum of two distinct points.

Using secant theorem,

NL* NM = NP* NO

(3+5)*3 = (2+x)*2

24=  (2+x)*2

12= 2+x

x= 12-2

x= 10

So, NP= 2+x

     NP = 12

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Answer:

[tex]5^{\circ}[/tex]

Step-by-step explanation:

[tex]~~~~~~~\tan \theta = \cot 85^{\circ}\\\\\implies \tan \theta = \tan\left(90^{\circ} - 85^{\circ} \right)\\\\\implies \tan \theta = \tan 5^{\circ}\\\\\implies \theta = 5^{\circ}[/tex]