what are the coordinates of each point after quadrillateral MNPQ is trans;ated 2units right and 5 units down

Answer: To compute the t-test statistic for the paired sample data, we need to first calculate the sample mean difference and the sample standard deviation of the differences. Then we can use the formula:

t = (sample mean difference - hypothesized mean difference) / (standard error of the mean difference)

where the standard error of the mean difference is calculated as:

standard error = sample standard deviation / sqrt(sample size)

Let's first calculate the sample mean difference:

x 9 6 7 5 12

y 6 8 3 6 7

The differences between each pair of x and y values are:

(9-6), (6-8), (7-3), (5-6), (12-7) = 3, -2, 4, -1, 5

The sample mean difference is the average of these differences:

sample mean difference = (3 - 2 + 4 - 1 + 5) / 5 = 1.8

Next, we need to calculate the sample standard deviation of the differences. To do this, we first calculate the deviations of each difference from the sample mean difference:

(3 - 1.8), (-2 - 1.8), (4 - 1.8), (-1 - 1.8), (5 - 1.8) = 1.2, -3.8, 2.2, -2.8, 3.2

The sample standard deviation of the differences is the square root of the sum of the squared deviations divided by (n-1):

sample standard deviation = sqrt[(1.2^2 + (-3.8)^2 + 2.2^2 + (-2.8)^2 + 3.2^2) / 4] = 3.153

Finally, we can calculate the t-test statistic:

t = (sample mean difference - hypothesized mean difference) / (standard error of the mean difference)

where the hypothesized mean difference is 0, and the standard error of the mean difference is:

standard error = sample standard deviation / sqrt(sample size) = 3.153 / sqrt(5) = 1.410

Substituting the values, we get:

t = (1.8 - 0) / 1.410 = 1.277

Rounding the final answer to three decimal places, we get:

t = 1.277

Therefore, the correct option is B. t = 1.292.

∠WTA and ∠HTC are vertical angles. Thus, they are equal.

As WA || HC, that means ∠AWT and ∠THC are alternate interior angles and are equal. Additionally, ∠WAT and ∠TCH are also alternate interior angles and are equal.

∠WTA = ∠HTC, ∠AWT = ∠THC, and ∠WAT = ∠TCH

Since both triangles have the same angle measurements, they are similar.

Adding -4(row 1) to row 3 in the matrix will produce: 0, -9, 2, and 12 respectively.

A rectangular array of numbers or mathematical objects which are arranged in rows and columns is called a matrix. Each row of a matrix is a horizontal sequence of numbers or objects that are separated by commas and enclosed within square brackets, and it represents a vector in the row space of the matrix.

row 1 of the given matrix are: 1, 2, 1, and -5, multiplying -4(row1) will gives;

-4 × 1 = -4

-4 × 2 = -8

-4 × 1 = -4

-4 × -5 = 20

-4(row 1) + row 3 will result to:

-4 + 4 = 0

-8 + (-1) = -9

-4 + 6 = 2

20 + (-8) = 12

Therefore, adding -4(row 1) to row 3 in the matrix will produce: 0, -9, 2, and 12 respectively.

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Answer:

The market trader should sell each of the remaining 20 packs of muffins for £1.30 to meet his target.

Step-by-step explanation:

To find out how much the market trader needs to sell the remaining 20 packs of muffins, we first need to calculate his total cost and his target revenue.

The cost of the loaves of bread is:

100 loaves x 84p/loaf = £84

The cost of the packs of muffins is:

60 packs x £1.10/pack = £66

Therefore, the total cost for the trader is:

£84 + £66 = £150

To make a 40% profit, the trader needs to make £150 x 40/100 = £60 in profit.

His target revenue is, therefore:

£150 + £60 = £210

The revenue from the loaves of bread is:

100 loaves x £1.20/loaf = £120

The revenue from the 40 packs of muffins sold at £1.60 per pack is:

40 packs x £1.60/pack = £64

So the total revenue from the loaves of bread and the 40 packs of muffins is:

£120 + £64 = £184

This means that the trader needs to make:

£210 - £184 = £26

from the sale of the remaining 20 packs of muffins.

To sell 20 packs of muffins to make £26, he needs to sell each pack for:

£26/20 = £1.30 per pack

Therefore, the market trader should sell each of the remaining 20 packs of muffins for £1.30 to meet his target.

The resulting matrix will be in the form :

5 9 -4

0 -14 15

A matrix is described as  a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns, which is used to represent a mathematical object or a property of such an object.

To get a 1 in row 1, column 1, we perform the following elementary row operation:

R2 - 2R1 -> R2

This will subtract 2 times the first row from the second row and give us the result:

5 9 -4

0 -14 15

Matrices are useful for describing systems of linear or differential equations, as well as representing a linear application.

In conclusion,  in  a matrix function, the input and the output values are matrices.

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Answer:

The surface area of the square pyramid is 18 km².

Step-by-step Explanation:

What is the surface area of a square pyramid with a slant height?

The surface area of a square pyramid with a slant height can be determined by the product of the base perimeter with the slant height divided by two.

Mathematically, it can be expressed as:

Surface Area S.A = P × l/2

where;

Side length (a) = 3

Base perimeter (P) = 4a = 4(3) = 12km

Slant length (l) = 3 km

Surface Area (S.A) = 12 × (3/2)

Surface Area (S.A) = 12 x 1.5 = 18 km²

Therefore, the surface area of the same pyramid is 18 square km.

[tex]\sf SA_{Pyramid} =\boxed{\sf 27km^{2}}.[/tex]

We're asked to calculate the surface area (SA) of a pyramid. Surface area of a tridimensional shape isn't more than calculating the area of all of its "faces" and then adding them all together. Some of these tridimensional shapes already have equations that provide a direct calculation of this parameters, without the need to add together the area of the different parts of the shape.

There's a developed formula for directly calculating the surface area of square pyramids, but in this case it is easier to just calculate the individual areas of each face and add them all together.

This is pretty easy to calculate, as the base forms the shape of a square. Therefore, multiplying the length and width of this square will give us that area:

[tex]\sf A_{Base} =lw=3km*3km=\boxed{\sf 9km^{2}} .[/tex]

Check attached image 1 to see where we got these values from.

So these faces form the sape of a triangle. Therefore, mul;tiplying their lengh by width and then dividing by 2 should give us the area.

[tex]\sf A=\dfrac{lw}{2} =\dfrac{(3km)(3km)}{2}=4.5km^{2}.[/tex]

Check attached image 2 to see where we got these values from.

This is the area of an individual triangular face of the pyramid, but we have a total of 4 faces. Hence, let's multiply this area by 4 to find the total area of all triangular faces:

[tex]4.5km^{2} *4=\boxed{\sf 18km^{2}}.[/tex]

So the total surface area, as stated at the beginning of this answer, is given by the addition of all individual areas from all the faces of the shape, so let's do just that:

[tex]\sf SA_{Pyramid} =9km^{2} +18km^{2}=\boxed{\sf 27km^{2}}.[/tex]

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Answer:{y,x}={-4,-1}

Step-by-step explanation:

Answer: 1st option

explanation: The ones that are crossed out include 1 whole number and 7 1/8 pieces. this is equal to 1 and 7/8. Then there is 3 whole 1 pieces so the answer is the 1st option

Answer:

f(2) = 3

Step-by-step explanation:

At f(2) we can notice that there is 2 y-values (one is an open circle and another is a closed circle)

But, an open circle means that the function is not defined at that point
But a closed circle means that it is defined

So we ignore the open circle and the closed circle is 3

So f(2) = 3

Therefore , the solution of the given problem of function comes out to be  f(x) = (4x² - 36)/(x - 9) has -3 and 3 as its x-intercepts.

On the midterm exam, there will be a variety of inquiries in each subject, including inquiries concerning both hypothetical and actual places as well as inquiries relating the creation of numerical variables. a diagram showing the relationships between different elements that cooperate to generate the same result. A service is composed of numerous distinctive components that cooperate to create distinctive results for each input.

Here,

Setting the y-value (or output) of a function to zero and then solving for the corresponding x-values will allow us to determine the x-intercepts of the function.

The function in this instance is f(x) = (4x² - 36)/(x - 9)

=> 4x² - 36 = 0

To make the equation simpler, we can factor out a 4:

=> 4(x² - 9) = 0

We can factor further based on the difference of squares we now have:

=> 4(x + 3)(x - 3) = 0

We may determine the x-values where the function crosses the x-axis by setting each element to zero:

=> x + 3 = 0 or x - 3 = 0

To find x, solve for:

=> x = -3 or x = 3

The function f(x) = (4x² - 36)/(x - 9) has -3 and 3 as its x-intercepts.

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The specified scalar is 12 as the result of u(v + w) is 12i + 12j.

The provided vectors are given to be u = 4i - j v = 3i + j w = i + 3j. First, we need to find the vector v + w,

v + w = (3i + j) + (i + 3j)

v + w = 4i + 4j

Now, we can find dot product, u(v + w),

u(v + w) = u(4i + 4j)

u(v + w) = 4ui + 4uj

Substituting the given values of u, we get,

u(v + w) = 4(4i - j)i + 4(4i - j)j

u(v + w) = 16i - 4j + 16j - 4i

Simplifying, we get,

u(v + w) = 12i + 12j

Therefore, the specified scalar is 12.

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Answer:

To answer these, we can use the standard normal distribution & z-scores. A z-score represents the number of standard deviations a value is from the mean. The formula to calculate a z-score is: z = (x - μ) / σ, where x is the value, μ is the mean and σ is the standard deviation.

A) To find the proportion of pregnancies that last more than 278 days, we first calculate the z-score for 278 days: z = (278 - 272) / 12 = 0.5. Using a standard normal distribution table, we find that the proportion of values above a z-score of 0.5 is approximately 0.3085. So, about 30.85% of pregnancies last more than 278 days.

B) To find the proportion of pregnancies that last between 257 and 275 days, we first calculate the z-scores for both values: z1 = (257 - 272) / 12 = -1.25 and z2 = (275 - 272) / 12 = 0.25. Using a standard normal distribution table, we find that the proportion of values between z-scores of -1.25 and 0.25 is approximately 0.3944. So, about 39.44% of pregnancies last between 257 and 275 days.

C) To find the probability that a randomly selected pregnancy lasts no more than 266 days, we first calculate the z-score for 266 days: z = (266 - 272) / 12 = -0.5. Using a standard normal distribution table, we find that the proportion of values below a z-score of -0.5 is approximately 0.3085. So, there is about a 30.85% chance that a randomly selected pregnancy lasts no more than 266 days.

D) To determine if very preterm babies are unusual, we first calculate the z-score for 242 days: z = (242 - 272) / 12 = -2.5. Using a standard normal distribution table, we find that the proportion of values below a z-score of -2.5 is approximately 0.0062. Since this value is less than 0.05, we can conclude that very preterm babies are unusual.

The value of the function g(f(-4)) = 536. Option D

From the information given, we have that the functions are;

f(x)= 4x+5

g(x) = 4x^2 -5x - 3

To determine the composite function,  g(f(-4)), we need to first determine the value of the function f(x) at -4

Now, substitute the value, we have;

f(-4) = 4(-4) + 5

expand the bracket, we get;

f(-4) = - 16 + 5

Add the values

f(-4) = -11

Now, substitute the value in the function g(x), we have that;

g(f(-4)) = 4(-11)² - 5(-11) - 3

find the square and expand the bracket

g(f(-4)) =484 + 55 - 3

Subtract the values, we have;

g(f(-4)) = 536

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Based on the data in the table, if Colin draws a marble 336 times, he predicts a yellow marble will be drawn roughly 63 times,  but probably not exactly 63 times.

Based on the data in the table, if Colin draws a marble 216 times, he predicts a white marble will be drawn roughly 2 times that a purple marble will be drawn.

If Colin draws a marble x times, he predicts a yellow marble will be drawn roughly 63 times.

The number of times = 63 / 3/16)

The number of times = 336 times.

If Colin draws a marble 216 times,

Number of times he can draw a white marble = 216 * 1/4

Number of times he can draw a white marble = 54 times

Number of times he can draw a purple marble = 216 * 1/6

Number of times he can draw a purple marble = 36 times

The number of times a white marble can be drawn more than a purple marble = 54/36 or 1.5 times more

The number of times a white marble can be drawn more than a purple marble is approximately two times.

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Answer:

Step-by-step explanation:

it think it 23 becasue u add

1 divide it by 2

Answer:

All of them have a combined of 2,227 Stamps

Mean: 2014

The quotient of the two fractions is (x - 5) / (x - 4).

Option D is the correct answer.

We have,

To divide two fractions, we can multiply the first fraction by the reciprocal of the second fraction.

In this case, that means we need to multiply:

(x² - 2x - 15) / (x + 2) x (x + 2) / (x² - x - 12)

Notice that the (x + 2) terms in the numerator and denominator of the first fraction cancel out with the denominator of the second fraction, so we can simplify before multiplying:

(x² - 2x - 15) / 1 x 1 / (x² - x - 12)

Now we can multiply the numerators and the denominators separately:

(x² - 2x - 15) / (x² - x - 12)

To simplify further, we can factor both the numerator and the denominator:

(x - 5)(x + 3) / (x - 4)(x + 3)

Notice that the (x + 3) terms in the numerator and denominator cancel out, leaving:

(x - 5) / (x - 4)

Therefore,

The quotient of the two fractions is (x - 5) / (x - 4).

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The graph of the function "g", which is defined for all "real-numbers" is shown below.

The function "g" which is defined for all "real-numbers" is represented as :

g(x) = {2 if x<0,

         {-1 if x=0

         {-3 if x>0

this function means that, for every input-value, which is less than 0, the output will be always 2,

For the input-value "0", the output-value will be = -1;

For all the input-value which are greater than "1", the out will be always "-3",

So, from the above information, the graph is plotted below,

The red-line represents "2 if x<0", the green line represents "-3 if x>0".

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To find the width of the suitcase, we need to use the formula for the volume of a rectangular prism:

Volume = Length × Width × Height

Given the volume of the suitcase as 8,556 cubic inches, the length as 32 inches, and the height as 15.5 inches, we can write the equation:

8556 = 32 × w × 15.5

Simplifying this equation, we can divide both sides by the product of 32 and 15.5:

8556 ÷ (32 × 15.5) = w

Solving for w, we get:

w ≈ 16.50 inches

Therefore, the width of the suitcase is approximately 16.50 inches.

Answer:

Correct ANSWER IS A

Step-by-step explanation:

For each coordinate pair (r,θ) listed in the table, first identify the ray on the graph created by the angle θ. On this ray, plot a point a distance of r from the pole.

Answer:

 50 cm

Step-by-step explanation:

To solve this answer you can find the area of the small triangle, and multiply it by 2 to get the area of the top part.

Then you can find the area of one of the bigger triangles and multiply it by 2.

Please could I get brainiest? I'm trying to get to the Expert level.

Answer:

  (-2, -1)

Step-by-step explanation:

You want the point that is 4 units left of (2, -1).

The x-coordinate of an (x, y) coordinate pair tells you the number of units to the right of the x=0 point. It increases for points farther right, and decreases for points farther left.

Moving left 4 units decreases the x-coordinate by 4 units. The x-coordinate of 2 becomes ...

  2 -4 = -2

The coordinates of the moved point are (-2, -1).

<95141404393>

Answer: 3.14 x 12 x 2

= 75.36

Step-by-step explanation:

Selling 80 items will produce maximum profit if the profit function is [tex]P(x) = 2400x + 105x^2 - x^3 - 167,000[/tex].

To find value of x that produces maximum profit, we must get critical points of the profit function and determine which one corresponds to a maximum.

The profit function is given as:

[tex]P(x) = 2400x + 105x^2 - x^3 - 167,000[/tex]

Taking the derivative of P(x) with respect to x, we get:

[tex]P'(x) = 2400 + 210x - 3x^2[/tex]

Setting P'(x) equal to zero and solving for x, we get:

[tex]0 = 2400 + 210x - 3x^2\\3x^2 - 210x - 2400 = 0\\x^2 - 70x - 800 = 0\\(x - 80)(x + 10) = 0[/tex]

Here, the critical points are x = 80 and x = -10.

To determine one that corresponds to a maximum, we can use the second derivative test. Taking the derivative of P'(x), we get:

[tex]P''(x) = 210 - 6x[/tex]

Evaluating P''(80), we get:

[tex]P''(80) = 210 - 6(80)\\P''(80) = 210 - 420\\P''(80) = -330[/tex]

Since P''(80) is negative, the critical point x = 80 corresponds to a maximum. So, selling 80 items will produce maximum profit.

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The rotation transformation of the quadrilateral IJKL, to obtain the quadrilateral I'J'K'L', are; I'(-2, 3), J'(0, -2), K'(-2, -3), L'(-3, 1)

A rotation transformation is one in which the coordinates of a geometric figure are rotated about a point.

The coordinates of the vertex points on the figure are;

J(0, 2), K(2, 3), L(3, -1), and I(2, -3)

The coordinates of the point (x, y) following a rotation of 180° about the origin are (-x, -y)

Therefore, the coordinates of the image of the figure J(0, 2), K(2, 3), L(3, -1), and I(2, -3), following a rotation about the origin are;

J(0, 2) ⇒ J'(0, -2)  

K(2, 3) ⇒ K'(-2, -3)

L(3, -1) ⇒ L'(-3, 1)

I(2, -3) ⇒ I'(-2, 3)

Therefore, we get;

The coordinates of the image are; I'(-2, 3), J'(0, -2), K'(-2, -3), L'(-3, 1)

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A sample of at least 139 individuals would need to be taken to estimate the population mean to within 4 units with 95% confidence.

To estimate the sample size needed to estimate the population mean to within 4 units with 95% confidence, we can use the formula:

n = (z * σ / E)²

where:

n = sample size

z = z-score for the desired level of confidence (95% in this case), which can be found using a standard normal distribution table or calculator. For 95% confidence, the z-score is approximately 1.96.

σ = population standard deviation (12 in this case)

E = margin of error (4 in this case)

Plugging in the values, we get:

n = (1.96 * 12 / 4)²

n = 34.5744

Rounding up to the nearest whole number, we get a sample size of 35. Therefore, a sample of at least 35 individuals would need to be taken to estimate the population mean to within 4 units with 95% confidence.

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The unknown angles in the circle are as follows:

a. m∠AEB = 73°

b. arc angle VW = 155°

a.

If two chords intersect inside a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle.

Therefore,

m∠AEB = 1 / 2 (99 + 47)

m∠AEB = 146 / 2

m∠AEB = 73 degrees

b.

If two secants intersect outside a circle , then the measure of an angle formed by the two lines is one half the positive difference of the measures of the intercepted arcs .

Therefore,'

arc angle VW = x

55 = 1 / 2 (x - 45)

55 = 0.5x  - 22.5

0.5x = 55 + 22.5

0.5x = 77.5

divide both sides by 0.5

x = 77.5 / 0.5

x = 155 degrees

Therefore,

arc angle VW = 155 degrees

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