Answer:
A liquid mixture of hydrocarbons that is present in certain rock strata and can be extracted and refined to produce fuels including gasoline, kerosen, diesal oil. :)
Explanation:
Yea mark brainleist pls
last question, PLEASE help
An athlete wants your shoe company to make his/her new basketball shoe. He is known for his speed down the court and doesn't want his shoes to have any pattern on the outsole, the bottom of the shoe, because he thinks it would slow him down. How would you convince this athlete that a pattern is needed because friction is important in his game?
Answer:
my answer is in explanation below
Explanation:
You would convince him by saying the pattern adds elevation to the shoe therefore causing more friction.
(If it's wrong, I am sorry, I'm not in college)
(If it's right, can I get that brainliest?)
11.
A current of 67 amps runs through a resistor of 37 ohms, how much voltage is lost?
The line segment joining the mid point of any side with the opssosite vertex is called?
A ball is thrown straight downward with a speed of 0.50 meter per second from a height of 4.0 meters. What is the speed of the ball 0.70 second after it is released? [Neglect friction.]
Answer:
The speed of the ball is 7.36 m/s
Explanation:
Constant Acceleration Motion
It happens when the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
[tex]v_f=v_o+at[/tex]
Since the situation corresponds to a vertical motion, the acceleration is g=9.8 m/s^2.
The ball is thrown downward at vo=0.5 m/s. Its speed at t=0.7 seconds is
[tex]v_f=0.5+9.8\cdot 0.7[/tex]
[tex]v_f=7.36\ m/s[/tex]
The speed of the ball is 7.36 m/s
Note: There is no use of the height it was released from
A 100 kg mass, initially at rest, is blown apart into a 60 kg piece and a 40 kg piece. After the blast, the two masses are moving apart with a relative velocity of 60 m/s. The speed of the 60 kg mass is
Answer:
Explanation:
According to law of conservation of momentum
(m1+m2)v = m1u1+m2u2
Let m1 and m2 be the masses
u1 and u2 be their respective velocities
v is the velocity of combined objects
Given
m1 =60kg
m2 = 40kg
v =0 m/s
u2 - u1 = 60 ............ 1
0 = 60u1 + 40u2 = 0 .......... 2
From 1: u2 = 60+u1
Substitute into 2:
60u1 + 40(60+u1) = 0
60u1 +2400 +40u1 = 0
100u1 = -2400
u1 = -2400/100
u1 = -24m/s
Hence the speed of the 60 kg mass is 24m/s (in the negative direction)
Problem 9.20 A sphere of uniform density with mass 18 kg and radius 0.8 m is spinning, making one complete revolution every 0.4 s. The center of mass of the sphere has a speed of 8 m/s. (a) What is the rotational kinetic energy of the sphere
Answer:
K = 567.91 J
Explanation:
Given that,
Mass of sphere, m = 18 kg
Radius of a sphere, r = 0.8 m
It makes one complete revolution every 0.4 s.
The speed of center of mass of the sphere is 8 m/s
We need to find the rotational kinetic energy of the sphere. It is given by the formula as follows :
[tex]K=\dfrac{1}{2}I\omega^2[/tex]
I is moment of inertia,
[tex]I=\dfrac{2}{5}mr^2\\\\I=\dfrac{2}{5}\times 18\times (0.8)^2\\\\I=4.608\ kg-m^2[/tex]
[tex]\omega[/tex] is angular speed
[tex]\omega=\dfrac{2\pi }{0.4}\\\\=15.7\ rad/s[/tex]
So,
[tex]K=\dfrac{1}{2}\times 4.608\times (15.7)^2\\\\K=567.91\ J[/tex]
So, the rotational kinetic energy of the sphere is 567.91 J.
The rotational kinetic energy of the sphere is 710.8 J.
Moment of inertia of the sphereI = ¹/₂mr²
I = 0.5 x 18 x (0.8)²
I = 5.76 kgm²
Angular speed of the sphereω = 2πf
ω = 2π x (1/0.4s)
ω = 15.71 rad/s
Rotational kinetic energyK.E = ¹/₂Iω²
K.E = 0.5 x (5.76) x (15.71)²
K.E = 710.8 J
Thus, the rotational kinetic energy of the sphere is 710.8 J.
Learn more about rotational kinetic energy here: https://brainly.com/question/25803184
Find relationship between‘ g’and ,‘G’
Answer:
The acceleration on an object due to the gravity of any massive body is represented by g (small g). The force of attraction between any two unit masses separated by unit distance is called universal gravitational constant denoted by G(capital g). The relation between G and g is not proportional.
Explanation:
If a coil stays at rest in a very large static magnetic field, no emf is induced in this coil. Group of answer choices True False
Answer:
True
Explanation:
Faraday's Law says that there is a emf induced in a conductor when the vector flux of the magnetic field across it changes in time.This can be true due to one of two facts, either the magnitude of the magnetic field changes in time, or the area through which the flux occurs changes due to the movement of the object.In this case, due to the magnetic field is constant, and the coil stays at rest, there is no possible change in flux, so emf induced is zero.Consider a car with a mass of 1250 kg moving at a constant speed of (22.0 A) m/s in a circular off ramp with a radius of (65.0 +B) m. What does the coefficient of static friction have to be for the car to just maintain its motion of ramp? Give your answer to 3 significant figures.
A=7
B=2
Answer:
Explanation:
weight of the car mg = m g
frictional force acting on the car = μ mg where μ is coefficient of friction
= m μ g
This force provides centripetal force , hence
m μ g = m v² / R
μ = v² / rg
= 22 x 22 / 65 x 9.8
= .759
How much time is required for an airplane to reach its takeoff speed of 77m/a if it starts from rest and its average acceleration is 8.2m/s^2?
Answer:
The time required is t = 9.39 [s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o} +(a*t)[/tex]
where:
Vf = final velocity = 77 [m/s]
Vo = initial velocity = 0
a = acceleration = 8.2 [m/s²]
t = time [s]
The initial speed is zero, since the airplane begins its movement from rest. The initial speed is zero, since the aircraft begins its movement from rest. Another important fact is that the sign of acceleration is positive since the plane is accelerating, that is, its speed is increasing.
Now replacing:
77 = 0 + (8.2*t)
t = 9.39 [s]
Which type of power plant uses the energy of moving water in nature to
generate electricity?
A. Radiant power
B. Natural gas
C. Coal
D. Hydroelectric
Answer:
D
Explanation:
Answer:
Hydroelectric power plants
Explanation:
This is because hydropower is a form of renewable energy that uses water stored in dams, rivers to create electricity
A string under a tension of 53.9 N is used to whirl a rock in a horizontal circle of radius 2.59 m at a speed of 21.8 m/s. The string is pulled in and the speed of the rock increases. When the string is 1.23 m long and the speed of the rock is 54.8 m/s, the string breaks. What is the breaking strength (in newtons) of the string
Answer:
The breaking strength of the string is 717.19 N
Explanation:
Given;
initial tension on the string, T₁ = 53.9 N
initial radius of the string, r₁ = 2.59 m
initial speed of the rock, v₁ = 21.8 m/s
final radius of the string, r₂ = 1.23 m
final speed of the rock, v₂ = 54.8 m/s
the final tension on the string = breaking strength, T₂ = ?
Apply centripetal force equation due to inward motion;
[tex]T= \frac{mv^2}{r}\\\\Tr = mv^2\\\\m =\frac{Tr}{v^2}\\\\ \frac{T_1r_1}{v_1^2} = \frac{T_2r_2}{v_2^2}\\\\T_2 = \frac{T_1r_1v_2^2}{r_2v_1^2}\\\\ T_2 = \frac{(53.9)(2.59)(54.8)^2}{(1.23)(21.8)^2}\\\\ T_2 = 717.19 \ N[/tex]
Therefore, the breaking strength of the string is 717.19 N
A 10-kg object is hanging by a very light wire in an elevator that is traveling upward. The tension in the rope is measured to be 75 N. What are the magnitude and direction of the acceleration of the elevator
Answer:
2.31m/s² downwards
Explanation:
The sum of forces on the object is expressed as;
T-W
T is the tension on the rope
W is the weight
According yo Newton's second law:
T-W= ma
m is the mass
a is the acceleration
Given
T = 75N
W = mg = 10×9.81
W = 98.1N
Substitute
75-98.1 = 10a
-23.1 = 10a
a = -23.1/10
a = -2.31m/s²
The magnitude of the acceleration is 2.31m/s² and directions is downwards
A 0.414 kg object is at rest at the origin of a coordinate system. A 2.08 N force in the positive x direction acts on the object for 1.57 s. What is the velocity at the end of this interval
Answer:
The value is [tex]v = 7.89 \ m/s[/tex]
Explanation:
From the question we are told that
The mass of the object is [tex]m = 0.414 \ kg[/tex]
The force is [tex]F = 2.08 \ N[/tex]
The time taken is [tex]t = 1.57 \ s[/tex]
Generally the force acting on the object according to Newton's second law is
[tex]F = \frac{ m (v -u )}{t}[/tex]
=> [tex]v = \frac{F * t}{m} + u[/tex]
Here u is the initial velocity with value 0 m/s since the object was initially at rest
[tex]v = \frac{2.08 * .57}{0.414 } + 0[/tex]
[tex]v = 7.89 \ m/s[/tex]
Use the drop-down menus to identify the parts of the diagram labeled A, B, and C.
Label A
Label B
Label C
Answer:
b
Explanation:
bcuz I looked it up and it was on there
Answer:
the answers are:
- cool fluid sinks
- warm fluid rises
- convention current
Explanation:
Im late but mark me as brainliest for helping you out cause the one on top is clueless
a 45 kg girl is bouncing on a trampoline. during a certain interval after she leaves t he surface of the trampoline, her kinetic energy decreases to 220 J from 420 J. how high does she rise during this interval neglect air resistance
Answer: Height = 0.45m
Explanation:
According to the conservation of energy, When there are no interactions outside a system ie neglecting air resistance,The change in kinetic energy is equal to the change in potential energy in a closed system.
Therefore the kinetic energy decrease, the potential energy increases, and decreases for increase in Kinetic energy
an is represented by the formulae
ΔKinetic energy + ΔPotential energy = 0
ΔKinetic energy = -ΔPotential energy ( where negative sign represent decrease as kinetic energy increases.
ΔK.E=ΔP.E
420J- 220J= mgh
mass = 45kg
g =gravitational acceleration =9.8 m/s^2
200J = 45 X 9.8 X h
h = 200/45 x 9.8 /= 0.45m
how much kinetic energy does a 2,000 kg car have when its traveling 5 m/s
Answer: 5000J
Explanation:
equation for kinetic energy is k=(mv^2)/2
plug in your mass and velocity
k = (2000*5^2)/2 = 5000J
An asteroid floating in space attracts a skyscraper on Earth’s with gravitational force of 12
newtons from a given distance. If the distance between the two objects is reduced to half, what is the
changed force of attraction between them?
a. 3 Newtons
b. 24 Newtons
c. 48 Newtons
d. 144 Newtons
Answer:
Explanation:
it is C
In a single process, a system does 125 J of work on its surroundings while 75 J of heat is added to the system. What is the internal energy change for the system
Answer:
-50JExplanation:
What is the first law of thermodynamics?
"The first law of thermodynamics state that energy is conserved"
the expression bellow is the Change in internal energy of a system
Change in internal energy of a system
= heat put into the system - work done by the system on its surroundings,
or
ΔU = ΔQ - ΔW.
given data
Work done=125J
Heat= 75J
change=?
Substituting we have
ΔU = 75- 125
ΔU = -50J
"ΔQ is positive if heat flows into the system, negative if it flows out of the system.
ΔW is positive if the system does work on its surroundings and it is negative if work is done on the system. "
Find the magnitude of the Sun's gravitational force on the Earth when the Earth is at perihelion and at aphelion. The perihelion and aphelion distances are 1.48 ✕ 1011 m and 1.52 ✕ 1011 m, respectively.
Answer:
Explanation:
Force F = GMm / R²
mass of the sun M = 1.99 x 10³⁰ kg
mass of the earth = 5.97 x 10²⁴ kg
value of G = 6.67 x 10⁻¹¹
for perihelion point R = 1.48 x 10¹¹ m
Force = 6.67 x 10⁻¹¹ x 1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.48 x 10¹¹ )²
= 36.17 x 10²¹ N
for aphelion point R = 1.52 x 10¹¹ m
Force = 6.67 x 10⁻¹¹ x 1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.52 x 10¹¹ )²
= 34.29 x 10²¹ N
I NEED HELP ASAP! PLS! <3
Answer:
a = - 1 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} = v_{o} +(a*t)[/tex]
where:
Vf = final velocity = 0 (velocity at 10 seconds)
Vo = initial velocity = 4 [m/s]
a = desacceleration [m/s²]
t = time = 4 [s]
From the graph, we can deduce that between the second 10 and the second 6 there are (10-6) = 4 seconds difference.
In the second 6, the velocity is 4 [m/s]
0 = 4 + (a*4)
4*a = -4
a = - 1 [m/s²]
Which atoms are deflected the most by the magnetic field?
Answer:
Different ions are deflected by the magnetic field by different amounts. The amount of deflection depends on: the mass of the ion. Lighter ions are deflected more than heavier ones.
How far will a motorcycle that accelerates at 1.28 m/s2 travel as its velocity increases from 10.0 m/s to 20.0 m/s?
Answer:
117
Explanation:
A hockey puck is sitting stationary on a frozen pond. A player slaps the puck, accelerating it from rest to 45 m/s in 0.03 s. What is the average force on the hockey puck while it is in contact with the stick
Answer:
F = 240 N
Explanation:
Let the mass of the puck, m = 160 g = 0.16 kg
Initial speed, u = 0 (at rest)
Final speed, v = 5 m/s
Time, t = 0.03 s
We need to find the average force on the hockey puck while it is in contact with the stick. Force is given by the formula as follows :
F = ma, a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.16\times (45-0)}{0.03}\\\\F=240\ N[/tex]
So, the average force is 240 N.
Write the electric field strength EE in all three regions as a function of rr: for r>r2r>r2, r1
Answer:
Explanation:
See attachment
A hopper jumps straight up to a height of 0.45 m. With what velocity will it return to the table?
Answer:
3 m/s
Explanation:
We can solve with kinematics or with energy.
Using kinematics, and taking down to be positive, we're given:
Δy = 0.45 m
v₀ = 0 m/s
a = 10 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (10 m/s²) (0.45 m)
v = 3 m/s
Or, we can use energy.
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 10 m/s² × 0.45 m)
v = 3 m/s
A woman runs up a flight of stairs. The gain in her gravitational potential energy is U. If she runs up the same stairs with twice the speed, what is her gain in potential energy?
Answer:
U
Explanation:
The change in gravitational potential energy only depends of the difference in height (in this case the number of stairs), so as the height remained the same, her gain in potential energy remained the same, independent from her climbing speed.For a smooth sphere with a 11 cm diameter thrown through air (air density of 1.25 kg/m3, air viscosity 1.83*10-5 Pa-s), what is the speed (in cm/s) when the Reynolds number is 2,511
Answer:
u = 0.334 m/s
Explanation:
The formula for Reynold's number is given as follows:
Re = ρuL/μ
where,
Re = Reynold's Number = 2511
ρ = Density of air = 1.25 kg/m³
μ = Dynamic Viscosity of Air = 1.83 x 10⁻⁵ Pa.s
L = Characteristic Length = Diameter of Sphere = 11 cm = 0.11 m
u = Speed = ?
Therefore,
2511 = (1.25 kg/m³)(u)(0.11 m)/(1.83 x 10⁻⁵ Pa.s)
u = (2511)/(7513.66 s/m)
u = 0.334 m/s
A physicist is creating a computational model of a falling person before and after opening a parachute. What boundary conditions would be important here?
the air resistance encountered as the person falls
the speed at which the person falls
the change in kinetic and potential energy
the location where potential energy is zero
Answer:
Air resistance
Explanation:
Air resistance encountered as the person falls
Answer:
the location where potential energy is zero
Explanation:
Which type of muscle helps the body move?
a
Cardiac
b
Smooth
c
Skeletal
d
None of the Above
Answer:
Cccccccc GIVE BRAINLYEST PLEASE
Answer: It´s c-skeletal
Explanation: