urgent question is below

The graph is attached with the answer.

When function has different behaviour at different intervals , then it is called a piecewise function.

It is given that

f(x) = - 3x -5 at x ≤ -1

f(x) = -2x +3 at -1 <x<4

f(x) = 2 at x ≥ 4

All the piecewise Function are a straight line.

The table for functions is

f(x) = 3x -5

-1  -8

-2  -11

-3   -14

f(x) = -2x +3

0  3

1    1

2    -1

3   -3

f(x) = 2

4     2

5      2

6     2

7     2

The graph is attached with the answer.

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Distance from the origin to the points  ≈ 0.41.

The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

D = √[(x-p)² + (y-q)²]  

Point A (5, 3, 4) and point B (−4, 2, 6) are located away from the origin (0,0,0), and the points from the origin to this points are expressed as OB - OA where;

Let OB is the distance from the origin to the point B

Let OA is the distance from the origin to the point A

Using the formula for calculating the distance between two points;

OA = √(z2-z1)²+(y2-y1)²+(x2-x1)²

OA = √(4-0)²+(3-0)²+(5-0)²

OA = √(16)+(9)+(25)

OA = √50

OA = 7.071

Similarly;

OB = √(6-0)²+(2-0)²+(-4-0)²

OB = √(6)²+(2)²+(-4)²

OB = √36+4+16

OB = √56

OB = 7.4833

Distance from the origin to the points = 7.4833 - 7.071= 0.4123

Distance from the origin to the points  ≈ 0.41

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Answer:

height= 13.2 cm

Step-by-step explanation:

h = 2 × A/b

h = 2 × 33 /5

= 13.2

Step-by-step explanation:

PART 1:

on the graph you can make a triangle at any point and with any angle measures.

i recommend a smaller right triangle to be easiest.

i recommend the points (0,3) A (3,0) B and (0,0) C

∆ABC angle measurements:

m∠CAB=45°

m∠ABC=45°

m∠ACB=90°

PART 2:

(4,3) D (7,0) E and (4,0) F make an identical right triangle moved 4 squares to the right

m∠FDE=45°

m∠DEF=45°

to find the missing value of the angle EFD we will use subtraction and addition

180-(45+45)

180-90

90

therefore, the m∠EFD=90°

PART 3:

both the angle measures and the shapes of the triangles are the same

PART 4:

i used a 1:1 ratio

sorry for the wait :)

Answer:

5 < x ≤ 100

(this is inequality form)

{x| 5 < x ≤ 100}

(this is set notation form)

(options B and C)

Step-by-step explanation:

In interval notation,

(  or   ) : does not include value

[ or ]  : does include value

{and remember:

< or > : does not include value

≤ or ≥ : does include value}

when we write something in interval notation, the range of values is from (lowest value, highest value)

for this equation, we know that we are looking for : (5, 100]

which means that the range of numbers goes from

5 (does not include 5) to 100 [does include 100]

so, x > 5 (not equal to); x ≤ 100

we can combine these two concepts: 5 < x ≤ 100

(inequality form)

{when {x | ...} is present, it means the same thing as without it, so

{x| 5 < x ≤ 100} is also correct

(set notation)

hope this helps!!

Answer:

B and C

Step-by-step explanation:

from interval notation we are including 100 but not 5,

x > 5 and x ≤ 100

so B and C are correct

[tex]y=200(0.5)^2^t[/tex] is Decay

[tex]y=\frac{1}{2}(2.5)^\frac{t}{6}[/tex] is Growth

[tex]y=(0.65)^\frac{t}{4}[/tex] is Decay

Answer:

-51

Step-by-step explanation:

If the limits are reversed, then place a negative sign in front of the integral.

[tex]\int\limits^a_bf ({x}) \, dx =-\int\limits^b_a f({x}) \, dx[/tex]

[tex]\int\limits^a_3 f({x}) \, dx = 51\\[/tex] where [tex]\alpha =10\\[/tex]

[tex]\int\limits^3_\alpha f( {x}) \, dx =-51[/tex]  where[tex]\alpha =10[/tex]

Answer:

rise over run aka a measure of its steepness

Step-by-step explanation:

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

Answer:

Area of smaller square = [tex]\tt\underline{5cm}[/tex][tex]\tt{\times 5cm = }[/tex][tex]\tt\underline\green{25}[/tex] [tex]\tt{sq.cm}[/tex]

Area of bigger square = [tex]\tt{15cm \times}[/tex][tex]\tt\underline{ 15cm }[/tex][tex]\tt{=}[/tex] [tex]\tt\underline\green{225}[/tex] [tex]\tt{sq.cm}[/tex]

Total Area = [tex]\tt\underline\green{25sq.cm}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{225sq.cm}[/tex] [tex]\tt{=}[/tex] [tex]\normalsize \underline{\boxed{\tt \red{250}}}[/tex] [tex]\tt\underline{sq.cm}[/tex]

[tex]\\[/tex]

Area of square A = [tex]\tt\underline{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\underline\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{14m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{14m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{196}[/tex] [tex]\tt{sq.m}[/tex]

Total Area = [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{196}[/tex] [tex]\tt{=}[/tex][tex] \normalsize \underline{\boxed{\tt \red{294}}}[/tex][tex]\tt{sq.m}[/tex]

====================================

To find the area of square use this formula [tex]\large\tt{A = s \times s}[/tex]. Means side of the square multiply to the same side of the square

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

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૮₍´˶• . • ⑅ ₎ა

Answer:the equations are

y = x + 4 and y = 3x + 6

Now we can use substitution method to solve the system

So we can substitute value of y from one equation into other

So we get

x+4 = 3x+6

So Option B is correct

Step-by-step explanation:

Answer:

2x + 4 = 3x + 1

Explanation:

Equation A: y = 2x + 4

Equation B: y = 3x + 1

Simultaneously solving :

⇒ y  =  y

⇒ 2x + 4 = 3x + 1

⇒ 2x - 3x = 1 - 4

⇒ -x = -3

⇒ x = 3

Solve for y :

⇒ y = 2x + 4

⇒  y = 2(3) + 4

⇒ y = 10

Answer:

is B

Step-by-step explanation:

this is the best possible answer

8) 5 + 4 + 2 = 11

Since there are 5 guavas, the correct answer is B. 5/11

9) 3 + 4 = 7

Since there are 4 blue papers, the correct answer is A. 4/7

10) Count all of the numbers and add them. There are 4 twos, 2 fives, and 1 three:

4 + 2 + 1 = 7

Since there are 4 twos, the correct answer is C. 4/7

Based on the frequency table given, The option that closely matches the histogram I drew is option C but the last one suppose to be 7 and not 6.

Hours online   Frequency

5                           0-3

8                          4-7

10                         8-11

9                          12-15

7                           16-19

Note that in the image attached, you can see how the Hours online were said to be matched with the  Frequency.

So since option A and B was not shown to see which matches the option,  i can say option c is closest but if look at my own image, you can use it to find the right one.

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To calculate the distance between two points we use this formula:

[tex] \boxed{ \boxed{{d \: = \: \sqrt{(x_2 \: - \: x_1)^{2} \: + \: (y_2 \: - \: y_1)^{2} } }}}[/tex]

______________________

We apply the values already obtained to the formula to get the distance:

[tex]d \: = \: \sqrt{( - 3 \: - \:( - 5))^{2} \: + \: (0 \: - \: 8)^{2} }[/tex]

[tex]d \: = \: \sqrt{( - 3 \: - \: ( - 5))^{2} \: + \: ( - 8)^{2} }[/tex]

[tex]d \: = \: \sqrt{( - 3 \: + \: 5) ^{2} \: + \: 64 } [/tex]

[tex]d \: = \: \sqrt{ {2}^{2} \: + \: 64 } [/tex]

[tex]d \: = \: \sqrt{4 \: + \: 64} [/tex]

[tex]d \: = \: \sqrt{68} [/tex]

[tex]d \: = \boxed{ \bold{ \: 2 \sqrt{17} \: units}}[/tex]

[tex] \huge{\boxed{ \bold{2 \sqrt{17} \: units }}}[/tex]

Divide number in honor society by total students:

191/2000 = 0.0955

Multiply by 100 to get percent:

0.0955 x 100 = 9.55%

Answer is C. 9.55%

Answer:

C

Step-by-step explanation:

The slope of a horizontal line, such as that of y= 3, is equal to 0.

This can be proved using the slope formula.

[tex]\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }[/tex]

Let's choose 2 points on the line y= 3:

(0, 3) and (2, 3)

Slope

[tex] = \frac{3 - 3}{2 - 0} [/tex]

[tex] = \frac{0}{2} [/tex]

= 0

Thus, the line has a slope of zero.

On the other hand, vertical lines have an undefined slope.

Additional:

To learn more about horizontal lines and their slopes, do check out the following!

The expression 6x¹⁰ - 96x² can be written by factoring out the greatest common factor is 6x²(x⁸ - 16) and for a part, B expression can be simplified by applying identity.

It is defined as the combination of constants and variables with mathematical operators.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have an expression:

Part A)

= 6x¹⁰ - 96x²

= 6x²(x⁸ - 16)

Part B)

[tex]\rm =6x^2(\left(x^4\right)^2-4^2)[/tex]

[tex]\rm =6x^2(\left(x^4+4\right)\left(x^4-4\right))[/tex]

[tex]\rm =6x^2\left(x^2+2x+2\right)\left(x^2-2x+2\right)\left(x^2+2\right)\left(x^2-2\right)[/tex]

Thus, the expression 6x¹⁰ - 96x² can be written by factoring out the greatest common factor is 6x²(x⁸ - 16) and for a part, the B expression can be simplified by applying identity.

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Answer:

a=1.66

b=8368.12

Step-by-step explanation:

hope it helps

Answer: 8x+70

Step-by-step explanation:

[tex]\sum^{5}_{n=2} (2x+5n)=(2x+10)+(2x+15)+(2x+20)+(2x+25)=\boxed{8x+70}[/tex]

Answer:

Step-by-step explanation:

A function is defined so that for each input, there is no more than one output.

The function will be given as C(x) = 25 + 0.2(x) here x is in minutes.

A function in mathematics set up a relationship between the dependent variable and independent variable. on changing the value of the independent variable the value of the dependent variable also changes.

Given that:-

The cost of the 250 minutes is $25 and if the time extends from 250 minutes then the function will be expressed in the form of.

C(x) = 25 + 0.2 (x)

Here C(x) is the total cost and the x is in minutes.

Hence the function will be given as C(x) = 25 + 0.2(x) here x is in minutes.

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Answer:

All its side lengths are equal

(and all the agle of 60°)

Step-by-step explanation:

What is true of an equilateral triangle? Two of its side lengths are equal. All its side lengths are equal. None of its side lengths are equal. None of its interior angles are equal. What is true of an equilateral triangle ? Two of its side lengths are equal . All its side lengths are equal . None of its side lengths are equal . None of its interior angles are equal .​

Answer:

x=100/7

Step-by-step explanation:

The interior angles will sum to 360 so 72+89+99+7x=360

260+7x=360

7x=100

x=100/7

The triangle is not a right triangle. This is because the sum of the square of the two shorter lengths is not equal to the square of the longest length.

In order to determine if the triangle is a right triangle, Pythagoras theorem would be used.

The Pythagoras theorem: a² + b² = c²

where a = length

b = base

c = hypotenuse

12 ² + 24²

= 144 + 576 = 720

29² = 841

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Answer:

Perimeter = 2(l + b)

= 2(x + 5x³ + 4 - x²)

= 2x + 10x³ + 8 - 2x²

= 10x³ - 2x² + 2x + 8

Hence, ur answer is the first option.

Answer:

A.

Step-by-step explanation:

L = x

W = 5x³ + 4 - x²

P = 2L + 2W

P(x) = 2x + 2(5x³ + 4 - x²) = 2x + 10x³ + 8 - 2x²

P(x) 10x³ - 2x² + 2x + 8

L = x

W = 5x³ + 4 - x²

P= 2L + 2W

P(x) = 2x + 2(5x³ + 4 - x²) = 2x + 10x³ + 8 - 2x²

= P(x) 10x³ - 2x² + 2x + 8

Answer:

y = x + 4

when x is 5, y is 9

Step-by-step explanation:

the pattern from the table is that the y value is 4 more than the x value, so the equation would be y = x + 4.

if you plug in x = 5, then this would be y = 5 + 4 = 9