Two students engaged in a tug of war each pull a rope in opposite directions with a force of 400 N. The net force on the rope is ?

Answer:

Sound and light are similar in that both are forms of energy that travel in waves. They both have properties of wavelength, freqency and amplitude. Here are some differences: Sound can only travel through a medium (substance) while light can travel through empty space.

Answer:

im not too sure about that all i know is history

Answer: B. Red light is absorbed by the car.

Explanation:

The colour of the object is decided by the wavelength of light that it reflects.

Light with the longest wavelength appears red, and light with the shortest wavelength appears violet. The wavelengths of visible light that an object reflects or transmits determine the color that the object appears to the human eye.

The blue car appears blue as it absorbs red light and reflects blue colour.

Answer:

6.26 m/s

Explanation:

From the given information:

Using the conservation of Energy;

M.E at A =M.E at B

[tex]\dfrac{1}{2}mv_A^2 + mgh _A = \dfrac{1}{2}mv_B^2 + mgh_B[/tex]

Replacing the values given in the equation:

[tex](1) (9.8) (2 \ m) +\dfrac{1}{2}(0)^2 = 1 \times 9.8 \times 0 + \dfrac{1}{2}(1) \times v_B^2 \\\\ 19.6 + 0 = 0 + 0.5v_B^2\\ \\ v_B^2 = \dfrac{19.6}{0.5} \\ \\ v_B^2 = 39,2 \\ \\ v_B = \sqrt{39.2} \\ \\ \mathbf{v_B = 6.26 \ m/s}[/tex]

Answer:

i know da way ese'

Explanation:

Answer:

Left

Explanation:

newtons is a measure of force. Since there is more newtons(force) pushing to the left, the object will move left. the 15 newtons cancel each other out, leaving only 5 newtons pushing to one side with no resistance.

Answer:

P = d g h         pressure = density * g * depth

P = 1000 kg/m^3 * 9.8 m / s^2 * 1.1 * 10E4 m = 1.1 * 10E8 N/m^2

F = P * A = 1.1 * 10E8 N/m^2 * pi * .075^2 / m^2 = 1.9 * 10E6 N/m^2

The period of the vertical mass-spring is 0.64 s.

The angular speed of the vertical mass-spring is calculated as follows;

[tex]V_{max} = A \omega\\\\\omega = \frac{V_{max}}{A} \\\\\omega = \frac{7.02}{0.713} \\\\\omega = 9.85 \ rad/s[/tex]

The period of the vertical mass-spring is calculated as follows;

[tex]f = \frac{\omega }{2\pi} \\\\T = \frac{1}{f} \\\\T = \frac{2 \pi}{\omega } \\\\T = \frac{2\pi }{9.85} \\\\T = 0.64 \ s[/tex]

Thus, the period of the vertical mass-spring is 0.64 s.

Learn more about period of oscillation here: https://brainly.com/question/20070798

Answer:

Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.

Explanation:

FOR SUV:

[tex]ac_{suv} = \frac{mv^2}{r}\\[/tex]

where,

ac_suv = centripetal acceleration of the SUV = ?

m = mass of SUV = 6000 kg

v = speed of SUV = vo

r = radius of path

Therefore,

[tex]ac_{suv} = \frac{6000\ vo^2}{r}\\[/tex]---------------- equation (1)

FOR CAR:

[tex]ao = \frac{mv^2}{r}\\[/tex]

where,

ao = centripetal acceleration of the car = ?

m = mass of car = 2000 kg

v = speed of car = vo

r = radius of path

Therefore,

[tex]ao = \frac{2000\ vo^2}{r}\\[/tex]--------------------- equation (2)

Dividing equation (1) by eq(2):

[tex]\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao[/tex]

Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.

Answer:

B Electrons are negatively charged while protons are positively charged

Answer:

A. The amount of mass changes only slightly during a chemical

reaction.

The stress in the  rod is equal to [tex]2.55 \times 10^8\;N/m[/tex]

Given the following data:

To calculate the stress in the  rod:

First of all, we would determine the area of the rod by using this formula:

[tex]Area = \frac{\pi d^2}{4} \\\\Area = \frac{3.142 \times 0.01^2}{4}[/tex]

Area = 0.00007855 meter.

Mathematically, stress is given by this formula:

[tex]Stress = \frac{Force}{Area}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Stress = \frac{20000}{0.00007855} \\\\Stress = 2.55 \times 10^8\;N/m[/tex]

Read more: https://brainly.com/question/14468674

Answer:

length of train is 80m

Explanation:

40*2

Answer:

A)        d = 6.1857 10⁻⁵ m

Explanation:

In the double-slit experiment the constructive interference is given by the expression

          d sin θ = m λ

          d =[tex]\frac{m \lambda }{sin \theta}[/tex]

let's use the relationship between speed, wavelength and frequency

          c = λ f

          λ = c / f

          λ = 3 10⁸ / 5.60 10¹²

          λ = 5.357 10⁻⁵ m

I do not know India in order of interference, we will assume that  m= 1

          d = 1  5,357 10⁻⁵ / sin 60

          d = 6.1857 10⁻⁵ m

Answer:

A. α = - 1.047 rad/s²

B. θ = 14.1 rad

C. θ = 2.24 rev

Explanation:

A.

We can use the first equation of motion to find the acceleration:

[tex]\omega_f = \omega_i + \alpha t\\[/tex]

where,

ωf = final angular speed = 0 rad/s

ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s

t = time = 3 s

α = angular acceleration = ?

Therefore,

[tex]0\ rad/s = 3.14\ rad/s + \alpha (3\ s)\\[/tex]

α = - 1.047 rad/s²

B.

We can use the second equation of motion to find the angular distance:

[tex]\theta = \omega_i t + \frac{1}{2}\alpha t^2\\\theta = (3.14\ rad/s)(3\ s) + \frac{1}{2}(1.04\ rad/s^2)(3\ s)^2\\[/tex]

θ = 14.1 rad

C.

θ = (14.1 rad)(1 rev/2π rad)

θ = 2.24 rev

Answer:

spectrograph

hope it is helpful to you

Answer: spectograph

Explanation:

Answer:

N₂ = 19 turns

Explanation:

A transform is a system with two different windings where the variation of the magnetic beam is the same, if there are no losses in the system we can use Faraday's law

          V₁ = -N₁  [tex]\frac{d \Phi_B }{dt}[/tex]

          v₂ = - N₂ \frac{d \Phi_B }{dt}

           [tex]\frac{V_1}{N_1} = \frac{V_2}{N_2}[/tex]

in this case we look for the number of turns in the second winding

            N₂2 = [tex]N_1 \ \frac{ V_2}{V_1}[/tex]

calculate us

           N₂ = 360  6.30/ 120

           N₂ = 18.9 turn

The number of turns must be an integer

           N₂ = 19 turns

Answer:

[tex]1863.9\ \text{kg}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of car = 1571 kg

[tex]u_1[/tex] = Initial velocity of car = 129 km/h

[tex]u_2[/tex] = Initial velocity of the animal = 0

[tex]v[/tex] = Velocity of combined mass = 59 km/h

[tex]m_2[/tex] = Mass of the animal

As the momentum of the system is conserved we have

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow \dfrac{m_1u_1+m_2u_2}{v}-m_1=m_2\\\Rightarrow m_2=\dfrac{1571\times 129+0}{59}-1571\\\Rightarrow m_2=1863.9\ \text{kg}[/tex]

The mass of the animal is [tex]1863.9\ \text{kg}[/tex].

The wavelength of this radio signal is equal to 3.18 meters.

Given the following data:

Wavelength can be defined as the distance between two (2) successive crests (troughs) of a wave.

Mathematically, the wavelength of a wave is given by this formula:

[tex]\lambda = \frac{V}{F}[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]\lambda = \frac{3 \times 10^8}{9.45 \times10^7}[/tex]

Wavelength = 3.18 meters.

Find more information on waves here: brainly.com/question/23460034

The wavelength of the radio signal travel at speed of light is 3.17m.

Given the data in the question;

Wavelength the spatial period of a periodic wave. That is to say, when the shapes of waves are Wavelength , the distance over which they are repeated is called wavelength. Wavelength  is expressed as;

[tex]\lambda = \frac{v}{f}[/tex]

Where [tex]\lambda[/tex] is wavelength, f is the frequency of the wave and c is the velocity or speed of light ( [tex]c = 3*10^8m/s[/tex] )

We substitute our values into the expression above.

[tex]\lambda = \frac{c}{ f}\\ \\\lambda = \frac{3*10^8m/s}{9.45*10^7s^{-1}} \\\\\lambda = \frac{3*10^8ms/s}{9.45*10^7}\\\\\lambda = 3.17m[/tex]

Therefore, the wavelength of the radio signal travel at speed of light is 3.17m.

Learn more about wavelength: brainly.com/question/16776907

Answer:

-22.3

Explanation:

Acellus

The net force on particle q2 is 21.7 N.

The given parameters:

The net force on particle q2 is calculated as follows;

[tex]Q_2_{net} = q_{12} \ + \ q_{23}\\\\Q_2_{net} = \frac{kq_1q_2}{r_{12} ^2} \ + \ \frac{kq_2q_3}{r_{23}^2} \\\\Q_2_{net} = \frac{9\times 10^9 \times 8 \times 10^{-6} \times 3.5 \times 10^{-6} }{0.1^2} \ + \ \frac{9 \times 10^9 b\times 3.5 \times 10^{-6} \times (-2.5) \times 10^{-6} }{0.15^2} \\\\Q_2_{net} = 25.2 \ N \ - \ 3.5 \ N\\\\Q_2_{net} = 21.7 \ N[/tex]

Thus, the net force on particle q2 is 21.7 N.

Learn more about Coulomb's law here: https://brainly.com/question/24743340

Answer:

A point on the outside rim will travel 157.2 meters during 30 seconds of rotation.

Explanation:

We can find the distance with the following equation since the acceleration is cero (the disk rotates at a constant rate):

[tex] d = v*t [/tex]

Where:

v: is the tangential speed of the disk

t: is the time = 30 s  

The tangential speed can be found as follows:

[tex] v = \omega*r [/tex]

Where:

ω: is the angular speed = 100 rpm

r: is the radius = 50 cm = 0.50 m

[tex] v = \omega*r = 100 \frac{rev}{min}*\frac{2\pi rad}{1 rev}*\frac{1 min}{60 s}*0.50 m = 5.24 m/s [/tex]    

Now, the distance traveled by the disk is:

[tex] d = v*t = 5.24 m/s*30 s = 157.2 m [/tex]

Therefore, a point on the outside rim will travel 157.2 meters during 30 seconds of rotation.

I hope it helps you!

Answer:

yes, because you dont want to be mean and make her feel worse about it and hiv has something do with s3x not germs so yes go

Explanation:

Answer:

1: A

Explanation:

Answer:

d

Explanation:

middle of a current carrying solenoid creates Mutual inductance

Answer:

"6.67 mm" is the right solution.

Explanation:

The given values are:

As we know, the equation

⇒  [tex]\frac{y}{L} =\frac{x \lambda}{a}[/tex]

On substituting the values, we get

⇒  [tex]\frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}[/tex]

On applying cross multiplication, we get

⇒  [tex].0125a=2.5 (600\times 10^{-9})[/tex]

⇒          [tex]a=\frac{2.5(600\times 10^{-9})}{.0125}[/tex]

⇒             [tex]=1.2\times 10^{-4} \ m[/tex]

For new distance, we have to put this value of "a" in the above equation,

⇒  [tex]\frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]

⇒  [tex](1.2\times 10^{-4})y=1.5(600\times 10^{-9})[/tex]

⇒                     [tex]y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]

⇒                        [tex]=3.22\times 10^{-3} \ m[/tex]

The total distance will be twice the value of "y", we get

=  [tex]6.67\times 10^{-3} \ m[/tex]

or,

=  [tex]6.67 \ mm[/tex]