Answer:
According to the Law of Cosines, the correct answer would be D) 50.2 feet
What is the value of x in the equation?4 (2x + 6) –10 = 30?
Answer: 10
Step-by-step explanation: 4(2 x 10 + 6) -10
simplify without using the table log 6 - log 16 + log 4 - log 3 + log 20 equals to
Answer:
[tex]1[/tex]
Step-by-step explanation:
[tex]log(6)-log(16)+log(4)-log(3)+log(20)[/tex]
[tex]0.77815125038-1.20411998266+0.60205999132-0.47712125472+1.30102999566[/tex]
[tex]=0.99999999998[/tex]
What is ansewer 1/6 of 30
Answer:
5
Step-by-step explanation:
The right answer is 5.
look at the attached picture
Hope it helps...
Good luck on your assignment
Micaela tried to rotate the square 180 about the origin. Is her rotation correct? If not, explain why
Answer:no the vertices of the image and pre image don’t correspond
Step-by-step explanation:
Just did it
No, the vertices of the image and pre-image do not correspond
Step-by-step explanation:
It’s correct
The Thomas Supply Company Inc. is a distributor of gas-powered generators. As with any business, the length of time customers take to pay their invoices is important. Listed below, arranged from smallest to largest, is the time, in days, for a sample of the Thomas Supply Company Inc. invoices.13 13 13 20 26 28 30 34 34 34 35 35 36 37 38
41 41 41 45 46 47 47 49 52 54 54 56 62 67 82(Round your answer to 2 decimal places.)a. Determine the first and third quartiles.
b. Determine the second decile and the eight decile.c. Determine the 67th percentile.
Answer:
Q1 = 33
Q3 = 49.75
D2 = 28.4
D8 = 29.6
67th percentile = 46.10
Step-by-step explanation:
Given the data:
13 13 13 20 26 28 30 34 34 34 35 35 36 37 38
41 41 41 45 46 47 47 49 52 54 54 56 62 67 82
The first quartile (Q1) ;
1/4(n + 1)
Where n = number of observations
n = 30
Q1 = 0.25(30 + 1) = 0.25 × 31 = 7.75
7 : corresponds to 30
0.75 : (34 - 30) × 0.75 = 4 × 0.75 = 3
30 + 3 = 33
Third quartile (Q3) :
3/4(n + 1)
Where n = number of observations
n = 30
Q3 = 0.75(30 + 1) = 0.75 × 31 = 23.25
23 : corresponds to 49
0.25 : (52 - 49) × 0.25 = 3 × 0.25 = 0.75
49 + 0.75 = 49.75
Determine the second decile and the eighth decile.
Second decile (D2)
((n+1) × (2)) / 10
= (30 + 1)(2)/10 = 6.2
6 : corresponds to 28 +
0.2 : (30 - 28 )× 0.20 = 0.4
28 + 0.4 = 28.4
Eight decile (D8)
((n+1) × (8)) / 10
= (30 + 1)(8)/10 = 24.8
24 : corresponds to 52 +
0.8 : (54 - 52 )× 0.80 = 1.6
28 + 1.6 = 29.6
67th percentile :
67% × n = 0.67 × 30 = 20.10
20: corresponds to 46
0.1 : (47 - 46) × (0.1) = 0.1
46 + 0.1 = 46.10
The first quartiles is 33 and third quartiles is 23.25.
The second decile is 24.8 and the eight decile is 29.6
The 67th percentile is 46.10.
Given that,
Sample of the Thomas Supply Company Inc. invoices.13 13 13 20 26 28 30 34 34 34 35 35 36 37 38.
41 41 41 45 46 47 47 49 52 54 54 56 62 67 82
We have to determine,
Determine the first and third quartiles.
Determine the second decile and the eight decile.
Determine the 67th percentile.
According to the question,
The first quartile (Q1) ; [tex]\dfrac{1(n+1)}{4}[/tex]Where n = number of observations
n = 30
Then,
[tex]= \dfrac{1(30+1)}{4}\\\\= 0.2 \times 31\\\\= 6.2[/tex]
Then, 7 : corresponds to 30,
[tex](34 - 30) \times 0.75 = 4 \times 0.75 = 3\\\\30 + 3 = 33[/tex]
And Third quartile (Q3) is; [tex]\dfrac{3(n+1)}{4}[/tex]
Where n = number of observations
n = 30
Then,
[tex]= \dfrac{3(30+1)}{4}\\\\= 0.75 \times 31\\\\= 23.25[/tex]
23 : corresponds to 49
[tex]0.25 : (52 - 49) \times 0.25 = 3 \times 0.25 = 0.75\\\\49 + 0.75 = 49.75[/tex]
To determine the second decile and the eighth decile.
Second decile (D2) ; [tex]\dfrac{2(n+1)}{10}[/tex]
Where n = 30
Then,
[tex]= \dfrac{2(30+1)}{10}\\\\= 0.2 \times 31\\\\= 6.1[/tex]
6 : corresponds to 28,
[tex](30 - 28 ) \times 0.20 = 0.4\\\\28 + 0.4 = 28.4[/tex]
And the Eight decile (D8); [tex]\dfrac{8(n+1)}{10}[/tex]
Where n = 30,
Then,
[tex]\dfrac{(30 + 1)(8)}{10} = 24.8[/tex]
24 : corresponds to 52,
[tex](54 - 52 ) \times 0.80 = 1.6\\\\28 + 1.6 = 29.6[/tex]
To determine the 67th percentile :
67% × n = 0.67 × 30 = 20.10
20: corresponds to 46
0.1 : (47 - 46) × (0.1) = 0.1
46 + 0.1 = 46.10
The 67th percentile is 46.10
To know more about Percentile click the link given below.
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Between what two integers does square root 10 lie on?
Answer:
between 3 and 4
Step-by-step explanation:
type sqrt(10) into your calculator
The requried, square root 10 lies between integers 3 and 4.
What are integers?Integers are a set of whole numbers and their negative counterparts. They include positive numbers, negative numbers, and zero.
Examples of integers include -3, -2, -1, 0, 1, 2, 3, and so on.
The integer squares nearest to 10 are 9 and 16, which are the perfect squares of 3 and 4, respectively.
Since [tex]$\sqrt{9}=3$[/tex] and [tex]$\sqrt{16}=4$[/tex], we know that [tex]$\sqrt{10}$[/tex] is between these two integers, we can say that [tex]$3 < \sqrt{10} < 4$[/tex].
Learn more about integers here:
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the value pi/24 is a solution for the equation 4 cos^4 (4x)-3
Answer:
False
Step-by-step explanation:
4 cos^4 (4x)-3 = 0
Substitute into the equation
4 cos^4 (4pi/24)-3 = 0
4 cos^4 (pi/6)-3 = 0
Take the cos pi/6
4 ( sqrt(3)/2) ^4 -3 =0
Take it to the 4th power
4 ( 9/16) -3 =0
9/4 -3 =0
9/4 - 12/4 = 0
-3/4 =0
False
Answer:
THE ANSWER IS TRUE.
Step-by-step explanation:
I did this on my homework.
The average life expectancy in a certain country is 50.2 years. Estimate the country's life expectancy in hours by rounding the life expectancy to the nearest year.
A consulting firm submitted a bid for a large research project. The firm's management initially felt they had a chance of getting the project. However, the agency to which the bid was submitted subsequently requested additional information on the bid. Past experience indicates that for of the successful bids and of the unsuccessful bids the agency requested additional information. a. What is the prior probability of the bid being successful (that is, prior to the request for additional information) (to decimal)?
Answer:
A or D i think..
Step-by-step explanation:
In a previous year, 54% of females aged 15 and older lived alone. A sociologist tests whether this percentage is different today by conducting a random sample of 700 females aged 15 and older and finds that 369369 are living alone. Is there sufficient evidence at the alphaαequals=0.10.1 level of significance to conclude the proportion has changed? Because np 0 left parenthesis 1-p 0 right parenthesis np01−p0 equals= nothing not equals≠ less than< greater than> equals= 10, the sample size is less than greater than 5% of the population size, and the sample cannot be reasonably assumed to be random, is given to be random, can be reasonably assumed to be random, is given to not be random, the requirements for testing the hypothesis are not satisfied. (Round to one decimal place as needed.) 1. Identify the null and alternative hypotheses for this test. Upper H 0: alpha α p μ greater than> not equals≠ equals= less than< nothing versus Upper H 1: α μ p equals= not equals≠ less than< greater than> nothing (Type integers or decimals. Do not round.) 2. Find the test statistic for this hypothesis test. z 0 equals= nothing (Round to two decimal places as needed.) 3. Determine the P-value for this hypothesis test. P-value equals= nothing (Round to three decimal places as needed.) 4. State the conclusion for this hypothesis test. A. Do not reject Upper H0. There is not sufficient evidence at the alpha α equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed. B. Reject Upper H 0. There is sufficient evidence at the alpha equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed. C. Reject Upper H 0. There is not sufficient evidence at the alpha α equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed. D. Do not reject Upper H0. There is sufficient evidence at the alpha α equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed.
Answer:
D.
Step-by-step explanation:
A model of a house was built using the scale 5 in: 25 ft. If a window in the model is 1.5 in. wide, how wide is the actual window?
Answer:
7.5 feet
Step-by-step explanation:
Scale of the Model =5 in: 25 ft.
If we divide both sides by 5
[tex]\dfrac{5 in.}{5} : \dfrac{25 ft.}{5}\\\\$1 inch: 5 feet[/tex]
If a window on the model is 1.5 inch wide, from the unit ratio derived above we then have that:
1 Inch X 1.5 : 5 feet X 1.5 feet
1.5 Inch : 7.5 feet
Therefore, if a window in the model is 1.5 in. wide, the actual window is 7.5 feet wide.
Any help would be appreciated
Answer: 18.48
Step-by-step explanation:
To solve this problem, you would use the order of operations. You would solve the parenthesis first and then solve the rest.
(5.6-2.3)(5.4+0.2)
3.3(5.6)
18.48
Answer:
18.48Step-by-step explanation:
(5.6 - 2.3) (5.4 + 0.2) 3.3 × 5.6
18.48
In the town of Maplewood a certain type of DVD player is sold at just two stores. 36% of the sales are from store A and the rest of the sales are from store B. 7% of the DVD players sold at store A are defective while 3% of the DVD players sold at store B are defective. If Kate receives one of these DVD players as a gift and finds that it is defective, what is the probability that it came from store A
Answer:
56.76% probability that it came from store A
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Defective.
Event B: Store A.
36% of the sales are from store A
This means that [tex]P(B) = 0.36[/tex]
7% of the DVD players sold at store A are defective.
This means that [tex]P(A|B) = 0.07[/tex]
Probability of a defective DVD:
36% come from store A, and of those, 7% are defective.
100 - 36 = 64% come from store B, and of those, 3% are defective. So
[tex]P(A) = 0.07*0.36 + 0.03*0.64 = 0.0444[/tex]
What is the probability that it came from store A
[tex]P(B|A) = \frac{0.36*0.07}{0.0444} = 0.5676[/tex]
56.76% probability that it came from store A
Find the value of x that will make a || B
Answer:
x = 30
Step-by-step explanation:
4x + 2x = 180
6x = 180
x = 30
What is the area of an rectangle with sides lengths of 5/12 foot and 2/3 foot
Answer:
Area = 5/18 square feet
Step-by-step explanation:
To find the area of a rectangle, you need to multiply 5/12 and 2/3. You multiply the numerators and then multiply the denominators. Then you should get 10/36. This fraction can be simplified into 5/18. To do this find the greatest common factor of 10 and 36 (you'll get 2 as the GCF). Then divide 2 to both the numerator and denominator.
Bacteria culture doubles every 20 minutes. After two hours there are 28800 bacteria. What was the initial amount?
Answer:
450 bacteria.
Step-by-step explanation:
To find this, we can set up an exponential equation as shown:
[tex]28800 = a (2)^{\frac{120}{20} }[/tex]
**'a' being the initial value
** '2' representing the culture doubling
Simplify the equation down:
[tex]28800 = a (2)^{6}[/tex]
[tex]28800 = 64a\\a = 450.[/tex]
Therefore, the initial amount of bacteria was 450.
A circle has a circumference that is greater than 8 meters. The inequality 3.14d> 8 can be used to determine the possible lengths
of the diameter of the circle. What are the possible values of d, the length of the diameter in meters?
d<25.1
d>25.1
d<25
d>2.5
Answer:
(D)d>2.5
Step-by-step explanation:
Given that the circumference of a circle is greater than 8 meters.
For a circle of diameter d:
Circumference[tex]=\pi d[/tex]
Since [tex]\pi =3.14[/tex]
[tex]3.14d>8[/tex]
To obtain possible values of the diameter d, we divide both sides of the equation by 3.14.
[tex]\dfrac{3/14d}{3.14}>\dfrac{8}{3.14}\\\\ d>2.5$ (correct to 1 decimal places)[/tex]
The correct option is D.
Answer:
To simplify the answer above, D
Step-by-step explanation:
choose the equation of the line that is parallel to the x axis x=4, x+y=0, x=y, y=4
Answer:
y=4
Step-by-step explanation:
if we draw a function we see that y=4 is paralel to the x axis
A line that is parallel to the x-axis will pass through the y-axis, horizontally.
The equation of line parallel to the x-axis is y = 4
A line that is parallel to the x-axis is represented with the following equation
y = n
Where n can be any real number.
In other words, the following equations are parallel to the x-axis
y = 2
y = 3
y = -2
y = 10
And so on....
Hence, the equation of line parallel to the x-axis is y = 4
Read more about parallel equations at:
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simplify the expression 4^4/4^6
Answer:
[tex]1/16[/tex]
Step-by-step explanation:
[tex]\frac{4^{4} }{4^{6} }[/tex]
[tex]4^{4-6}[/tex]
[tex]4^{-2}[/tex]
[tex]\frac{1}{4^{2} }[/tex]
[tex]\frac{1}{16}[/tex]
Solve the quadratic equation 3x² + 2x-4=0
Give your answers to 2 decimal places.
3x² + 2x - 4 = 0
Δ = b² - 4.a.c
Δ = 2² - 4 . 3 . -4
Δ = 4 - 4. 3 . -4
Δ = 52
x = (-b +- √Δ)/2a
x' = (-2 + √52)/2.3
x'' = (-2 - √52)/2.3
x' = 0,8685170918213297
x'' = -1,5351837584879966
2 Decimal places
x' = 0,87
x'' = -1,54
Answer: .8685
Step-by-step explanation:
A study is done by a community group in two neighboring colleges to determine which one graduates students with more math classes. College A samples 11 graduates and finds the mean is 4 math classes with a standard deviation of 1.5 math classes. College B samples 9 graduates and finds the mean is 3.5 math classes with a standard deviation of 1 math class. The community group believes that a student who graduates from college A has taken more math classes, on the average. Test at a 10% significance level. Assume the requirements for a valid hypothesis test are satisfied.
Answer:
[tex]t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890[/tex]
The p value for this case would be:
[tex]p_v =P(t_{18}>0.890)=0.193[/tex]
The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B
Step-by-step explanation:
Information given
[tex]\bar X_{1}=4[/tex] represent the mean for sample A
[tex]\bar X_{2}=3.5[/tex] represent the mean for sample B
[tex]s_{1}=1.5[/tex] represent the sample standard deviation for A
[tex]s_{2}=1[/tex] represent the sample standard deviation for B
[tex]n_{1}=11[/tex] sample size for the group A
[tex]n_{2}=9[/tex] sample size for the group B
[tex]\alpha=0.1[/tex] Significance level provided
t would represent the statistic
Hypothesis to test
We want to verify if the student who graduates from college A has taken more math classes, on the average, the system of hypothesis would be:
Null hypothesis:[tex]\mu_{1}-\mu_{2} \leq 0[/tex]
Alternative hypothesis:[tex]\mu_{1} - \mu_{2}> 0[/tex]
The statistic is given by:
[tex]t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}[/tex] (1)
And the degrees of freedom are given by [tex]df=n_1 +n_2 -2=11+9-2=18[/tex]
Replacing we got:
[tex]t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890[/tex]
The p value for this case would be:
[tex]p_v =P(t_{18}>0.890)=0.193[/tex]
The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B
Which problem situation matches the equation below 59+74+62+x/4=70
Answer:
x = 85Step-by-step explanation:
The equation is not properly written. Here is the correct expression
[tex]\frac{59+74+62+x}{4} = 70[/tex]
Find the problem situation that matches according to the steps below:
Step 1: We will cross multiply
[tex]59+74+62+x = 4*70\\59+74+62+x = 280\\195+x = 280\\[/tex]
Step 2: Subtract 195 from both sides of the equation
[tex]195+x-195 = 280-195\\x = 280-195\\x = 85[/tex]
Consider a sample with data values of 10, 20, 12, 17, and 16. (a) Compute the mean and median. Mean = Median = (b) Consider a sample with data values 10, 20, 12, 17, 16, and 12. How would you expect the mean and median for these sample data to compare to the mean and median for part a (higher, lower, or the same)? The input in the box below will not be graded, but may be reviewed and considered by your instructor. Compute the mean and median for the sample data 10, 20, 12, 17, 16, and 12. If required, round your answers to one decimal place.
Answer:
Step-by-step explanation:
Consider a sample with data values of 10, 20, 12, 17, and 16. (a) Compute the mean and median. Mean = Median = (b) Consider a sample with data values 10, 20, 12, 17, 16, and 12.
Mean = Total of values/ Total number of observations
Total of values = 10+20+12+17+16 = 75
Total number of observations = 5
Mean = 75/5 = 15
Median:
Arrange in ascending order = 10, 12,16,17,20
Median = [n+1] / 2
N = number of observation = 5
Median = [5+1]/2 = 3rd observation
Median = 16
I need help with this please.
at a school concert the total value of tickets sold was $994. Student tickets sold for $5 and adult tickets sold for $8. The number of adults tickets sold was 14 more than 2 times the number of student tickets. How many student tickets and adult tickets were sold?
Answer:
42 student tickets and 98 adult tickets
Step-by-step explanation:
Let's call the number of student tickets 's' and the number of adult tickets 'a'.
Then, we can write the two equations below:
5s + 8a = 994
a = 2s + 14
Using the value of 'a' from the second equation in the first one, we have:
5s + 8*(2s + 14) = 994
5s + 16s + 112 = 994
21s = 882
s = 42
Now, finding the value of 'a', we have:
a = 2*42 + 14 = 98
Answer:
The total sold was 98 tickets for adults and 42 for students.
Step-by-step explanation:
In order to calculate the number of tickets of each kind sold we need to create a system of equations with the given information. The first equation can be created is that the sum of adult tickets multiplied by its cost with the student tickets also multiplied by its cost must be equal to the total value of tickets sold, so:
[tex]5*\text{students} + 8*\text{adults} = 994[/tex]
We also know that the number of adult tickets was 14 more than 2 times the number of student tickets, therefore:
[tex]\text{adults} = 2*\text{students} + 14[/tex]
If we apply the second expression on the first one we can solve for the number of tickets sold to students, we have:
[tex]5*\text{students} + 8*(2*\text{students} + 14)= 994\\5*\text{students} + 16*\text{students} + 112 = 994\\ 21*\text{students} = 994 - 112\\\text{students} = \frac{882}{21} = 42[/tex]
We can use this value to find the number of adults ticket sold:
[tex]\text{adults} = 2*42 + 14\\\text{adults} = 98[/tex]
The total sold was 98 tickets for adults and 42 for students.
Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 222 days and standard deviation sigma equals 15 days.
What is the probability that a random sample of 26 pregnancies has a mean gestation period of 216 days or less?
The probability that the mean of a random sample of 26 pregnancies is less than 216 days is approximately
Answer:
[tex] z = \frac{216-222}{\frac{15}{\sqrt{26}}}= -2.040[/tex]
And we can find this probability on this way:
[tex]P(z<-2.040)=0.0207[/tex]
Step-by-step explanation:
Let X the random variable that represent the lenghts of the pregnencies of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(222,15)[/tex]
Where [tex]\mu=222[/tex] and [tex]\sigma=15[/tex]
We are interested on this probability
[tex]P(\bar X<216)[/tex]
The z score formula is given by:
[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we find the z score we got:
[tex] z = \frac{216-222}{\frac{15}{\sqrt{26}}}= -2.040[/tex]
And we can find this probability on this way:
[tex]P(z<-2.040)=0.0207[/tex]
What’s the correct answer for this?
Answer:
x=5
Step-by-step explanation:
5x- 7 = 18
5x=18+7
5x=25
Therefore, 5 will cancel 25 five(5) times.
x= 5.
Answer:
x = 5
Step-by-step explanation:
Since AB is the bisector, so MO is equal to NO
MO = NO
5x-7 = 18
5x = 18+7
5x = 25
Dividing both sides by 5
x = 5
On average, 24% of customers who buy shoes in a particular store buy two or more pairs. One weekend, 350 customers purchased shoes. How many can be predicted to buy two or more pairs? If 107 customers buy more than two pairs, did more customers than normal buy two or more pairs?
It is predicted that__________
customers bought two or more pairs out of 350 customers. There were customers than normal who bought two or ___ pairs.
Given a+b=7 and a–b=3, find: 3a÷3b
Answer & Step-by-step explanation:
We are given two equations...
a + b = 7
a - b = 3
We are asked to find 3a ÷ 3b. In order to find the value of a and b, we have to rearrange one of the equations so it will be easier to find the values of the variables. Let's rearrange the second equation.
a - b = 3 → a = 3 + b
Now that we have an equation that shows the value of a, we can use this equation and plug it into the first equation.
a + b = 7
a = 3 + b
(3 + b) + b = 7
3 + 2b = 7
2b = 4
b = 2
We have the value of b. Now, we have to find the value of a by plugging b into the second equation.
a - b = 3
b = 2
a - 2 = 3
a = 5
Now that we have the values of both variables, we can plug them into (3a÷3b)
3a ÷ 3b
3(5) ÷ 3(2)
15 ÷ 6
5/2 or 2.5
So, 3a ÷ 3b equals 5/2 or 2.5
who can answer this question the fastest
Step-by-step explanation:
1. 45/5 = 9
2. 53 is not a multiple of 5
3. 164 - 20 = 144
4. 372 rounded is 400.
5. 5 edges
6. 382 + 200 = 582
7. 6500 meters
8. -6
9. 65 cm
10. 90/2 = 45
11. idk since i live in us
12. 8 * 3 = 24
13. July 30th
14. 6
15. 28
16. 2.5 * 3 = 7.50