The point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.
What is electric field strength?
The electric field strength is defined as the ratio of electric force and charge. The field's direction is determined by the direction of the force acting on the positive charge.
The megnitude of the electric field for charge 1 is;
[tex]\rm E_1 = (9 \times 10^9 )\times \frac{0.700 \times 10^{-9}}{x^2}[/tex]
The megnitude of the electric field for charge 1 is;
[tex]\rm E_2 = 9.0 \times 10^9 \times \frac{9.00 \times 10^{-9}}{(1.80-x)^2}[/tex]
The net electric field at point p is;
[tex]\rm \frac{0.700}{x^2} = \frac{9.00}{(1.40-x)^2} \\\\( \frac{1.40-x}{x} )^2 = \frac{9.00}{0.700} \\\\\ \frac{1.40-x}{x}=3.58 \\\\ \frac{140}{x} -1=3.58\\\\\ \frac{140}{x}=3.58+1\\\\ x=0.3056 \ m[/tex]
Hence, the point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.
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a ball is thrown upward from the ground with an initial velocity of 50m/s. what is the total time spent by the ball in the air (g=10m/s2)
Answer:
[tex]\fbox {5 seconds}[/tex]
Explanation:
The formula which is used here :
[tex]\fbox {v = u + at}[/tex]
[tex]\longrightarrow \textsf {v : final velocity}[/tex]
[tex]\longrightarrow \textsf {u : initial velocity}[/tex]
[tex]\longrightarrow \textsf {a : acceleration}[/tex]
[tex]\longrightarrow \textsf {t : time taken}[/tex]
Solving :
v = u + at
0 = 50 + (-10)t
10t = 50
t = 5 seconds
and electric motor lifts an elevator a vertical distance of 18.0m in a time of 30.0s by exerting an upward force of 6.0x10^3 N . what power does the electric motor produce?
Answer:
[tex]\fbox {3.6kW}[/tex]
Explanation:
Formula used :
[tex]\boxed {P = F \times v} \leftarrow \rightarrow \boxed {P = \frac{F \times S}{t}}[/tex]
Given :
⇒ F = 6 × 10³ N
⇒ S = 18 m
⇒ t = 30 s
Solving :
⇒ P = 6 × 10³ × 18 / 30
⇒ P = 2 × 100 × 18
⇒ P = 3600 W
⇒ P = 3.6kW
You push a 50.0 kg box across a floor at a constant speed of 2.0m/s. If the coefficient of friction between the two surfaces is 0.20, then how much force are you exerting on the box? If you stop pushing, then how far will the box slide before coming to rest? Start by drawing a FBD.
(a) The force applied on the box is 98 N.
(b) When you stop pushing, the displacement of the box before coming to rest is 1.02 m.
Force exerted on the box
The force exerted on the box is calculated from Newton's second law of motion.
F - Ff = ma
where;
a is acceleration of the boxF is applied forceFf is frictional forceat constant speed, a = 0
F - Ff = 0
F = Ff
Ff = μmg
Ff = 0.2 x 50 x 9.8
Ff = 98 N
When you stop pushing, applied force = 0F - Ff = ma
-Ff = ma
a = -Ff/m
a = -98/50
a = - 1.96 m/s²
Displacement of the boxv² = u² + 2as
when the box stops, v = 0
0 = u² + 2as
0 = (2)² + 2(-1.96)s
0 = 4 - 3.92s
3.92s = 4
s = 4/3.92
s = 1.02 m
When you stop pushing, the displacement of the box before coming to rest is 1.02 m.
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A doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the other side, as shown in the image below. If the ball rises with a force of 150 N, what pressure did the patient apply to his side of the tube?
A.
0.15 Pa
b.
150Pa
c.
100,000 Pa
D.
150,000 Pa
The patient apply pressure to his side of the tube is 15 x 10⁴ N/m². The correct option is D.
What is pressure?The pressure is the amount of force applied per unit area. It is represented as
Pressure p = Force/Area
Given is a doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the other side. The ball rises with a force of 150 N. The cross section are of the tube is 0.001 m³
The pressure applied is
p = 150 /0.001
p = 15 x 10⁴ N/m²
Hence, the patient apply pressure to his side of the tube is 15 x 10⁴ N/m².
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What local group of galaxies is the Milky Way part of?
Quasar Cluster
Andromeda Mini-Cluster
Virgo Supercluster
Hubble Open Cluster
The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C
What are Virgo Supercluster?The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.
Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.
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which factors can change the size of the shadow of an opaque object
a)the color of the object b)the material the object is made from
c)how far the object is from the light source d)the size of the screen
Answer:
it have two answers a and c
Explanation:
please mark me as brainlyst
Answer: c)how far the object is from the light source
d)the size of the screen
The size of the shadow depends on the distance of the source of light and on the angle at which the light rays fall on the object. If the source of light is closer to the object, a larger shadow is formed than when the source of light is far from the object.
The angle at which a light strikes an object affects the size and shape of its shadow. Shadows are longer when the light source is at a low angle (side on) and shorter when the light source is at a higher angle (overhead).
The position of the light source can change the size and shape of a shadow. A good example would be, when we are outside on a sunny day, we can see how our shadows change throughout the day. The Sun's position in the sky affects the length of the shadow.
∩_∩
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If a ball is thrown into the air with a velocity of 45 ft/s, its height in feet after t seconds is given by y=45t-15t2. Find the instantaneous velocity when t=4
Given that a ball is thrown into the air and its height in feet after t seconds is given by y = 45t - 15t², the instantaneous velocity when t=4 is -75ft/s.
What is the instantaneous velocity when t=4?Given that;
Initial velocity = 45ft/sHeight in feet after t seconds is given by y = 45t - 15t² Instantaneous velocity = ?First, we determine the derivative of y = 45t - 15t²
y' = (1)45 - (2)15t
y' = 45 - 30t
We substitute in t = 4
y' = 45 - 30t
y' = 45 - 30(4)
y' = 45 - 120
y' = -75ft/s
Given that a ball is thrown into the air and its height in feet after t seconds is given by y = 45t - 15t², the instantaneous velocity when t=4 is -75ft/s.
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3. Magnetite is
a) Natural magnet
(b)Artificial magnet
(c) Not a magnet
[tex] \huge \bold \red {Aɴswᴇʀ}[/tex]
Magnetite is a Natural magnet
When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, you are obeying which law?
When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.
Newton's law of universal gravitationNewton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.
The mathematical interpretation of the above law is
F ∝Mm/r²Removing the proportionality sign,
F = GMm/r².Where:
F = Force of attractionG = Gravitational constantM = Bigger massm = Smaller mass r = Distance between the masses.
From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.
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With a burst of speed, Kevin swims one 25.0-m stretch in 9.22 s. What is Kevin's average speed over those 25 m
If Kevin swims one 25.0-m stretch in 9.22 seconds, his average speed is approximately 2.71m/s.
What is Kevin's average speed over those 25 m?Speed is expressed as distance over time.
Speed = Distance / time
Given the data in the question
Distance = 25.0mTime elapsed = 9.22sAverage speed = ?Average speed = 25.0m / 9.22s
Average speed = 2.71m/s
If Kevin swims one 25.0-m stretch in 9.22 seconds, his average speed is approximately 2.71m/s.
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8. in a hall experiment, a current of 25 a is passed through a long foil of ag, which is 0.1 mm thick and 3mm long. calculate the hall voltage produces across the width by a flux of 1.4 w/m2. if the conduction of ag is 6.8x10mho/m. estimate the mobility and hall coefficient.
The mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.
What is electric current?Electric current is defined as the ratio of the charge flow in a given time interval. It is denoted by I. It has the unit is ampere.
Given data;
Electric current,I= 25 A
Thickness = 0.1 mm
Length = 3 mm
Flux = 1.4 w/m²
The charge density is found as;
[tex]\rm \rho =- \frac{1}{R_H} \\\\ \rho = 0.119 \times 10^{11} C/m^3[/tex]
The value of the hall voltage is;
[tex]\rm V_H = BVd \\\\ V_H = B \frac{I}{\rho dt} d \\\\ V_H = \frac{BI}{\rho t } \\\\ V_H = \frac{0.14 \times 25 }{0.119 \times 10^{11} \times 0.1 \times 10^{-3}} \\\\ V_H = \frac{3.5 }{0.119 \times 10^7} \\\\ V_H = 29.41 \times 10^{-6} \ v[/tex]
The mobility of electrons is;
[tex]\rm \mu_e = \frac{\rho}{n_e}\\\\ \mu_e = \frac{6.848 \times 10^7}{13.5 \times 10^{-30}\times 1.607 \times 10^{-19}} \\\\ \mu_e = 57.7 \times 10^{-4}[/tex]
Hence the mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.
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3. State Newton's first and second laws of equation. A. A body of mass 2kg move vertically upwards has its velocity increased uniformly from 15m/s to 45m/s in 5s. neglecting air resistance, the upward vertical force acting on the body. [g=10ms 2] B. The velocity ratio and efficiency of pulley are 8 and 85% respectively. How much effort is required to lift a load of 120kg with this system [g=10m/s²]
Answer:
See below.
Explanation:
Newton's First Law
A body at rest persists in its state of rest, and a body in motion remains in constant motion along a straight line unless acted upon by an external force.
Newton's Second Law
A body's acceleration is directly proportional to the force exerted on it and is in the same direction as the force. F=mA (Force = Mass x Acceleration)
==============================================
A. A body of mass 2kg move vertically upwards has its velocity increased uniformly from 15m/s to 45m/s in 5s. neglecting air resistance, the upward vertical force acting on the body. [g=10ms 2] B. The velocity ratio and efficiency of pulley are 8 and 85% respectively. How much effort is required to lift a load of 120kg with this system [g=10m/s²]
Force = Mass x Acceleration
Acceleration is (45m/s - 15 m/s)/5 sec) or 6 m/sec^2
Force = 2kg*(6 m/sec^2)
Force = 12 kg*m/s^2 1 kg*m/s^2 is the SI unit for force, and is named 1 Newton(N), after . . . Newton.
Force = 12N
B. I'm not sure how to interpret "The velocity ratio and efficiency of pulley are 8 and 85% respectively." I'll assume "effort" is the energy required.
I'll calculate the energy required in a perfect system, and then we'll consider the efficiency issues.
By lifting an object with mass off the Earth's surface (height = 0 meters) we impart a potential energy, PE, to the object. This energy is stored in the object until it is allowed to move back closer to Earth. This potential energy is given by the equation:
PE = mgh
where PE is potential energy in Joules, m is mass in kg, g is the acceleration due to Earth's gravity (9.8 m/sec^2, but we'll use 10 m/sec^2 as stated in the problem), and h is the vertical distance moved, in meters.
PE = (120kg)(10 m/sec^2)(h). We aren't given a height, h. Let's express the answer in terms of 1 meter: How much potential energy is put into the 120kg load to raise it 1 meter?
PE = (120kg)(10 m/sec^2)(1 m)
PE = 1200 kg*m^2/sec^2 or 1200 kg*m/sec^2 per meter
The unit kg*m/sec^2 is 1 Joule
PE = 1200 Joules/meter
1200 Joules are required to raise 120kg 1 meter. This is increased due to the less-tha-100% efficiency of 85%.
At 85% efficiency, the energy required would be 1200J/0.85 = 1412 J to raise 120kg 1 meter, with 85% efficiency, I don't6 know how to handle the velocity ratio number.
The tip of a fan blade is 0.61 m from the center of the fan. the fan turns at a constant speed and completes 2 rotations every 1.0 s. what is the centripetal acceleration of the tip of the fan blade?
The centripetal acceleration of the tip of the fan blade is 96.23 m/s²
What is centripetal acceleration?The acceleration developed when a body is moving in circular way, directed towards the center of the circular path.
The tip of a fan blade is 0.61 m from the center of the fan. the fan turns at a constant speed and completes 2 rotations every 1.0 s
ac = ω²r
where ω = angular speed = 2πN/60, N = Rotation per minute
From the question, N = 2 x 60/1 = 120 RPM
So, the angular speed will be
ω = 2π x 120 /60
ω = 12.56 rad/s
Then, the centripetal acceleration is
ac = (12.56)² x 0.61 m
ac = 96.23 m/s²
Thus, centripetal acceleration of the tip of the fan blade is 96.23 m/s²
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What cloud extending to the gravitational limits of the solar system would comets come from?.
The Oort cloud extends to the gravitational limits of the solar system would comets come from.
What is oort cloud?It is a hypothetical idea of a cloud of mostly frozen planetesimals that would orbit the Sun at distances between 2,000 and 200,000 AU.
The Oort cloud reaches the solar system's outer gravitational boundaries, where comets originate.
Hence cloud extending to the gravitational limits of the solar system will be oorto cloud.
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what type of bulb is unaffected
Nothing happens to the brightness of the light bulbs in the parallel circuit if the power supply is capable of supplying the additional current.
A length 550cm of thin thread wraps around a cylinder exactly 25 times calculate the circumference and the radius of the cylinder.
Answer:
3.5
Explanation:
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solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid are called ________.
Concentrated solar power facilities are solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid .
What is solar power?Solar power refer to electric power or electricity that is generated from sun rays or radiations while using solar panels and other technologies.
Therefore, Concentrated solar power facilities solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid.
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Eclipses and Moon Phases Activity Student sample of a modeled eclipse. This lesson highlighted eclipses and lunar phases. If you had to teach another person about the difference between the two events, how would you explain it
An eclipse is an event in which the sun or moon is blocked from view due to the presence of another celestial body, whereas lunar phases are caused by the reflection of the sunlight.
What is an eclipse?An eclipse is an astronomical phenomenon where one celestial body (e.g., sun, moon) cannot be observed because another is interposed between the Earth and the first one.
Eclipses can be divided into moon eclipses (we cannot see the moon) and sun eclipses (we cannot see the sun).
On the other hand, moon phases occur due to how sunlight reflects the near side of the Moon.
Moon phases can be divided into:
New MoonFirst QuarterThird QuarterFull MoonIn conclusion, an eclipse is an event in which the sun or moon is blocked from view due to the presence of another celestial body, whereas lunar phases are caused by the reflection of the sunlight.
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Answer: the other person explained it all
Explanation:
a compact car is about 1289 kg and its engine has the ability to generate 183831 W. if all that power is applied from a stand still and no energy is dissipated, how fast will the car be moving after 7 seconds.
The speed of the car moving after 7 seconds will be 31.5 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
m is the mass of the car = 1289 Kg.
u is the initial velocity = 0 m/sec
a is the acceleration in m/sec²
v is the velocity after 7 seconds =?
The power developed is;
P =FV
F=ma
P=maV
183831=1289 kg × a × V
a = 142.61 / V
From Newton's second equation of motion;
V=u+at
V=0+at
V=(142.61/V)t
V²=142.61 × 7
V=31.5 m/sec
Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.
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the question is confusing
Alpha particles have highest mass.
Alpha particles are most ionising.
Gamma particles are the most penetrating.
Beta particles are negatively charged.
Gamma particles have the highest speed.
Comparing the three types of ionizing radiation-alpha particles have the greatest mass. Alpha particles have approx 4 times the mass of a proton or neutron and 8,000 times the mass of a beta particle. Ionising power of alpha particle is very high due to double positive charge, large mass as compared to a beta particle. Alpha particles can cause multiple ionisations within a very small distance. Beta radiation is more penetrating than alpha radiation. beta radiation can pass through the skin, but it is absorbed by a few cm of tissue of the body or a few mm of aluminum. Gamma radiation is the most penetrating of the three radiations. Alpha particles are positively charged, while beta particles are negatively charged, and gamma radiation is electrically neutral. Gamma rays are similar to visible light but they have higher energy. Gamma rays are emitted along with alpha or beta particles during radioactive decay.learn more about gamma rays here:
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two point charges of magnitude 4.0 μc and -4.0 μc are situated along the x-axis at x1 = 2.0 m and x2 = -2.0 m, respectively. what is the electric potential at the origin of the xy-coordinate system?
The electric potential at the origin of the xy coordinate system is negative infinity
What is the electric field due to the 4.0 μC charge?The electric field due to the 4.0 μC charge is E = kq/r² where
k = electric constant = 9.0 × 10 Nm²/C², q = 4.0 μC = 4.0 × 10 C and r = distance of charge from origin = x₁ - 0 = 2.0 m - 0 m = 2.0 mWhat is the electric field due to the -4.0 μC charge?The electric field due to the -4.0 μC charge is E = kq'/r² where
k = electric constant = 9.0 × 10 Nm²/C², q' = -4.0 μC = -4.0 × 10 C and r = distance of charge from origin = 0 - x₂ = 0 - (-2.0 m) = 0 m + 2.0 m = 2.0 mSince both electric fields are equal in magnitude and directed along the negative x-axis, the net electric field at the origin is
E" = E + E'
= -2E
= -2kq/r²
What is the electric potential at the origin?So, the electric potential at the origin is V = -∫₂⁰E".dr
= -∫₂⁰-2kq/r².dr
Since E and dr = dx are parallel and r = x, we have
= -∫₂⁰-2kqdxcos0/x²
= 2kq∫₂⁰dx/x²
= 2kq[-1/x]₂⁰
= -2kq[1/x]₂⁰
= -2kq[1/0 - 1/2]
= -2kq[∞ - 1/2]
= -2kq[∞]
= -∞
So, the electric potential at the origin of the xy coordinate system is negative infinity
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hello,help me with this out please i need it hurry but please ensure your answer is correct..I attach here with my question.
Topic:Forces in equilibrium.
Answer:
.409 N
Explanation:
For this to balance, the moments around the fulcrum must sum to zero.
On the left you have .21 ( is that down? I will assume it is)
Counterclockwise moments :
.21 * 40 + 1.0 * 20
Clockwise moments :
.5 * 20 + F * 45
these moments must equal each other
.21*40 + 1 *20 = .5 * 20 + F * 45
F = .409 N
Sonam and Wangchuk are taking part in a long jump event during their school's annual sports day. Sonam ran a few distances before taking the jump while Wangchuk jumped without running. Who will jump furthest? Justify your answer.
Answer:
Sonam will jump further than wangchuck
1. When building a house using bricks a damp course is laid just above the brick foundation. Explain why the damp course is necessary
Answer:
Damp Proofing:
Explanation:
The presence of damp proofing is very necessary to maintain the health of a structure. DPC plays an important role in all types of buildings and it should be necessary to know about the importance, requirements, and properties of DPC. In many of the buildings all over the world, the rising damp may be due to a damaged damp-proof course, or sometimes, there may be not any damp proof course in a building.
Which of the following consists of photovoltaic cells?
1. Solar panels
2. Rube Goldberg device
3. Solar oven
4. Electric generator
A 1.0-g string that is 0.64 m long is fixed at both ends and is under tension. This string produces a 100-Hz tone when it vibrates in the third harmonic. The speed of sound in air is 344 m/s. The tension in the string is closest to
The tension in the given string of 1.0 g and length of 0.64 m is closest to 2.84 N
Tension in the string
The tension in the string at nth harmonic is calculated as follows;
[tex]f_n = \frac{n}{2l} \sqrt{\frac{T}{\mu} }[/tex]
where;
n th harmonic = 3L is length of the string = 0.64 mμ is mass per unit length = (1 x 10⁻³ kg)/(0.64 m) = 0.00156 kg/mf is frequency = 100 HzT is tension in the string = ?[tex]f_n = \frac{n}{2l} \sqrt{\frac{T}{\mu} }\\\\\frac{f_n(2l)}{n} = \sqrt{\frac{T}{\mu} }\\\\\frac{f_n^2(4l^2)}{n^2} = \frac{T}{\mu} \\\\T = \mu (\frac{f_n^2(4l^2)}{n^2})\\\\T = 0.00156(\frac{100^2 \times 4\times 0.64^2}{3^2} )\\\\T = 2.84 \ N[/tex]
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Transparent or translucent materials
are used to make
A stop signs
B suitcases
C color filters
D toothbrushes
Answer:
C
Explanation:
you need to be able to see through a colour filter, which means youd need transparent or translucent
Transparent materials passes light and they reflect also. The color filters are made by transparent or translucent materials. Thus option c is correct.
What is transparency?The ability of a material to pass light through it is called transparency. Some transparent materials can reflect the light. For example mirror, glasses etc. The materials which passes light but are not transparent is called translucent materials.
The material which does not pass light inside is called opaque. Wood, plastics etc. are opaque materials. Transparent covers, glasses make their inside visible.
Colour filters are made by transparent or translucent materials. They are used to filter or choose a particular colour from a group of reflected lights.
Color filters are used in spectrometers and other optical devices. They filter the incoming wavelengths to select the desired one. Hence, option c is correct.
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Which of the following would increase the amount of electricity generated by a wind turbine
Higher wind speeds would increase the amount of electricity generated by a wind turbine.
What is a power plant?A power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.
Stronger winds produce greater power because they enable the blades to revolve more quickly. Greater mechanical and electrical power from the generator result from faster spinning.
Hence, higher wind speeds would increase the amount of electricity generated by a wind turbine.
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One of the properties of alkali metals is that they don’t react with water.
Beryllium (Be) is the only alkaline earth metal that does not react with water.
What are alkali metals and their properties?
Alkali is a substance that produces hydroxide ions in aqueous solution.
PHYSICAL PROPERTIES OF ALKALIS:
Alkalis have a BITTER taste & have a SOAPY touch.Alkalis turn RED litmus paper BLUE.Alkalis have a pH value > 7.Alkalis are CAUSTIC.Alkalis CONDUCT ELECTRICITY due to the presence of MOBILE IONS in solution.CHEMICAL PROPERTIES OF ALKALI METAL
Alkalis react with Acids to form salt and water. This reaction is called neutralisation reaction.Alkalis react with ammonium salts to form salt, water and ammonia gas. .Alkalis react with solution of metal salt to form another metal salt and hydroxide.Beryllium (Be) is the only alkaline earth metal that does not react with water.
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which of the numbers on this figure indicates typical continental conditions (regional metamorphism)?
The number that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.
What is regional metamorphism?Regional metamorphism occurs when rocks undergoes changes as a result of high temperatures and pressure deep within the earth's crust.
Regional metamorphic rocks are usually foliated or squashed in appearance.
Examples of regional metamorphism rocks are schist and gneiss rocks.
Therefore, the figure that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.
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