TWO forces, one of 12N and another or 24N

act on body in such a way that they make an angle of 90° with each other. Find the resaltant of two forces.

I would use a resistor rated for 1 W or more. Not less.

The power rating of a resistor that would be used in application that requires 0.6 W must be greater than 0.6 W.

The electrical power of an appliance shows the rating of the appliance, in terms of energy consumed at a given period of time.

Electrical power is calculated as follows;

P = IV

where;

[tex]P = (\frac{V}{R} )V\\\\P = \frac{V^2}{R}[/tex]

Thus, the power rating of a resistor that would be used in application that requires 0.6 W must be greater than 0.6 W.

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Answer:

The car skids in a distance of 61.275 meters.

Explanation:

Since the only force exerted on the car is the kinetic friction between the car and the horizontal road, deceleration of the vehicle ([tex]a[/tex]), measured in meters per square second, is determined by the following expression:

[tex]a = \mu_{k}\cdot g[/tex] (1)

Where:

[tex]\mu_{k}[/tex] - Coefficient of kinetic friction, no unit.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]\mu_{k} = 0.52[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then the net deceleration of the vehicle is:

[tex]a = 0.52\cdot \left(-9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]a = -5.1\,\frac{m}{s^{2}}[/tex]

The distance covered by the car is finally calculated by this kinematic expression:

[tex]\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)

Where:

[tex]v_{o}[/tex], [tex]v[/tex] - Initial and final speed, measured in meters per second.

[tex]a[/tex] - Net deceleration, measured in meters per square second.

If we know that [tex]v_{o} = 25\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]a = -5.1\,\frac{m}{s^{2}}[/tex], then the distance covered by the car is:

[tex]\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(25\,\frac{m}{s} \right)^{2}}{2\cdot \left(-5.1\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\Delta s = 61.275\,m[/tex]

The car skids in a distance of 61.275 meters.

Answer:

a. True

Explanation:

Electric field is a region of space where the effect of electric field lines or lines of forces are felt.

The electric field lines creates electric field and these field lines help to visualize the electric field.

Therefore,  electric field lines are tool used to visualize electric fields.

a. True

Answer:

a. spring constant = 125 N/m

b. This spring is less stiff than the one in Sample Problem A.

Explanation:

P.S - The Sample Problem A is as follows :

Given - Sample Problem A - A load of 45 N attached to a spring that is

            hanging vertically stretches the spring 0.14 m. What is the spring

             constant?

            Suppose the spring in Sample Problem A is replaced with a spring  

            that stretches 36 cm from its equilibrium position.

To find - a. What is the spring constant in this case?

            b. Is this spring stiffer or less stiff than the one in Sample Problem A.

Proof -

As given,

Load = 45 N

Amplitude = 0.14 m

Let the spring constant = k

As we know that,

Load = k (Amplitude)

⇒45 = k(0.14)

⇒k = [tex]\frac{45}{0.14}[/tex] = 321.43

∴ we get

Spring constant in Sample problem A = 321.43

Now,

a.)

Given, Amplitude = 36 cm = 0.36 m

Let the spring constant = k₁

⇒45 = k₁ (0.36)

⇒k₁ = [tex]\frac{45}{0.36}[/tex] = 125 N/m

b.)

AS we can see that k₁  < k

⇒ This spring is less stiff than the one in Sample Problem A.

a. spring constant = 125 N/m

b. This spring is less stiff than the one in Sample Problem A.

The spring constant generally shows the stiffness of the spring and is the ratio of the force applied to the deflection of the spring.

It is given in the question that:

Sample Problem A - A load of 45 N attached to a spring that is

hanging vertically stretches the spring 0.14 m.  

Suppose the spring in Sample Problem A is replaced with a spring  

that stretches 36 cm from its equilibrium position.

a. What is the spring constant in this case?

As given,

Load F = 45 N

Amplitude  x= 0.14 m

Let the spring constant = k

As we know that spring force will be

[tex]F=k\times x[/tex]

[tex]45=k\times 0.14[/tex]

⇒k = 321.43N/m

∴ we get

Spring constant in Sample problem A is   [tex]k=321.43\ \frac{N}{m}[/tex]

Now,

Given, Amplitude = 36 cm = 0.36 m

Let the spring constant = k₁

⇒45 = k₁ (0.36)

⇒k₁= 125 N/m

b.) Is this spring stiffer or less stiff than the one in Sample Problem A.

AS we can see that k₁  < k  new spring is less stiff than the one in Sample Problem A.

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Answer:

-the ratio of the speed of light

in air to the speed of light in the substance.

-speed of light in air 300,000 km/sec, which decreases when it passes through a transparent substance.

-e.g.. speed of light in substance = 200,000 km/sec, R.I. = 300,000/200,000 = 1.5

Explanation:

Answer: Throughout the scientific world where measurements are nearly always made in SI units, thermodynamic temperature is measured in kelvins (symbol: K). The Rankine scale uses the degree Rankine (symbol: °R) as its unit, which is the same magnitude as the degree Fahrenheit (symbol: °F).

Explanation:

Please mark me as the Brainiest if I got it right

what's the dimension symbol for thermodynamic temperature

Answer:

°R

Answer:

A) r = 20.0 m

B) T = 41.6 s

C) = 6.1 m/s²

Explanation:

A)

        [tex]a_{c} =\frac{v^{2}}{r} = \frac{(10.0m/s)^{2}}{r} = 5.00 m/s2 (1)[/tex]

       [tex]r = \frac{v^{2}}{a_{c} } = \frac{(10.0m/s)^{2}}{5.00m/s2} = 20.0 m (2)[/tex]

B)

        [tex]v = \frac{\Delta s}{\Delta t} = \frac{2*\pi*r}{T} (3)[/tex]

       [tex]T = \frac{\Delta s}{v} = \frac{2*\pi*r}{v} = \frac{2*\pi*265m}{40.0m/s} =41.6 s (4)[/tex]

C)

        [tex]a_{c} =\frac{v^{2}}{r} = \frac{(40.0m/s)^{2}}{265m} = 6.1 m/s2 (5)[/tex]

Answer:

No.

Explanation:

Velocity is a vector quantity which means that it has a certain direction so things that move in different directions DO NOT have the same velocity.

Answer:

It develops natural resources.

It works to eliminate poverty through development.

Answer:

The horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively.

Explanation:

Using the equation of the displacement in the x-direction, we have:

(let's recall we have a constant velocity in this direction)

[tex]x=v_{ix}t[/tex]

Where:

[tex]x=30(7)[/tex]    

[tex]x=210\: m[/tex]    

Now, we need to use the equation of the displacement in the y-direction to find the vertical distance. Here we have an acceleration (g)

[tex]y=v_{iy}t-\frac{1}{2}gt^2[/tex]

Where:

Then, the vertical position at 7 s is:

[tex]y=-\frac{1}{2}(9.81)(7)^2[/tex]

[tex]y=-240.35\: m[/tex]

Therefore, the horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively. The minus sign means the negative value in the y-direction.

I hope it helps you!

Answer:

(a) The volume of the liquid helium at 25 K is 5.13 L

(b)  The volume of the liquid helium at 293 K is 60.14 L.

Explanation:

Given;

mass of the liquid helium, m = 10 g

initial temperature of the liquid helium, T₁ = 4.2 K

pressure of the liquid helium, P = 1.00 atm

Atomic mass of Helium, = 4 g

number of moles of Helium, n  = 10 / 4 = 2.5 moles

The initial volume of the liquid helium is calculated as;

[tex]PV_1 = nRT_1\\\\V_1 = \frac{nRT_1}{P} \\\\[/tex]

where;

R is ideal gas constant,  = 0.08205 L.atm./mol.K

[tex]V_1 = \frac{2.5 \times 0.08205 \times 4.2}{1 } \\\\V_1 = 0.862 \ L[/tex]

(a) The volume of the liquid helium at 25 K.

Apply Charles law;

[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2} \\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{0.862 \times 25 }{4.2} \\\\V_2 = 5.13 \ L[/tex]

(b)  The volume of the liquid helium at 293 K.

[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2} \\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{0.862 \times 293 }{4.2} \\\\V_2 = 60.14 \ L[/tex]

Answer:

120 W lightbulb

Explanation:

Let the two lightbulb be A and B respectively.

Given the following data;

Power A = 120W

Power B = 90W

Voltage = 120V

To find the current flowing through each lightbulb;

a. For lightbulb A

Power = current * voltage

120 = current * 120

Current = 120/120

Current = 1 Ampere.

b. For lightbulb B

Current = power/voltage

Current = 90/120

Current = 0.75 Amperes

Therefore, the lightbulb that carries more current is A with 1 Ampere.

The  bulb that  carries more current is :

- A with 1 Ampere.

Let the two lightbulb be A and B respectively.

To find the current flowing through each lightbulb;

Thus, the lightbulb that carries more current is A with 1 Ampere.

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Answer:

yes. that is how a baby is conceived.

Answer:

a. Workdone = 44100 Joules

b. Power = 8820 Watts.

Explanation:

Given the following data:

Mass = 225kg

Distance = 20m

Time = 5 seconds

To find the workdone;

Workdone = force * distance

But force = mg

We know that acceleration due to gravity is equal to 9.8m/s²

Force = 225*9.8 = 2205N

Substituting the values into the equation, we have;

Workdone = 2205 * 20

Workdone = 44100 Joules

b. To find the power;

Power = workdone/time

Power = 44100/5

Power = 8820 Watts.

Answer:

the kinetic energy gained by the toy is 6J.

Explanation:

Given;

net applied to the toy by dog, F = 2 N

distance moved by the toy, d = 3 m

Apply the principle of work-energy theorem to determine the kinetic energy gained by the toy.

ΔK.E = W

         = F x d

         = 2 x 3

         = 6 J

Therefore, the kinetic energy gained by the toy is 6J.

Answer:

Nucleus

Explanation:

Answer: Nucleolus

Explanation: The nucleolus is like the cells brain. It controls all the other organelles (cell parts).

                                                 Hope I helped!

Answer:

1.32

Explanation:

Index of refraction of the glass = 1.52

Thickness = 104 nm

Length = 550 nm

 Using formula of index

n = L/4t

Where, L = length

t = thickness

Substituting the values into the formula we get

n = 500/(4×104)

n= 1.32

Hence, The index of refraction of the coating  is 1.32.

Answer:

1. D

Climate is generally defined as the weather condition that prevails in a particular region over a long period of time. Climate is usually measured by examining the pattern of variation in several climatic factors such as rainfall, temperature, relative humidity, wind, pressure, etc. While the weather of a place can change within a space of few hours, it takes years for a change in climatic condition to occur.  

2. d

3. c

4.a.

5. c

6. a.

7. c

Explanation:

The correct answers are (1) d. two of the above (average air temperature and humidity), (2)c. the relative humidity is 100 percent, (3)d. two of the above (water vapor condenses out of the air and air temperature decreases), (4)a. cirrocumulus, (5)c. cumulus, (6)c. steam fog, and (7)c. sleet.

Temperature is a physical quantity that measures the average kinetic energy of the particles in a substance or system. It is a measure of how hot or cold something is, and is typically measured in units such as degrees Celsius or Fahrenheit. Temperature can also be thought of as a measure of the direction in which heat energy flows, with heat energy naturally flowing from areas of higher temperature to areas of lower temperature.

Here in the Question,

1. Weather factors include d. two of the above (average air temperature and annual precipitation are two factors that affect weather, but humidity is also an important factor that can influence the feel of the air).

2. The dew point is the temperature at which b. water vapor starts to condense. When air cools, it can reach a point where it is unable to hold all of its moisture in the form of water vapor. At this point, the water vapor starts to condense into visible droplets, such as dew, and the temperature at which this happens is called the dew point. When the dew point is reached, the relative humidity is at 100 percent.

3. Relative humidity may decrease if d. two of the above (water vapor condenses out of the air and air temperature decreases) occur. If the air cools and reaches the dew point, water vapor will start to condense into droplets, which can reduce the amount of water vapor in the air and lower the relative humidity. Similarly, if the temperature drops without any change in water vapor content, the relative humidity will decrease because colder air can hold less moisture than warmer air.

4. The type of cloud that forms at high altitudes is a. cirrocumulus. These clouds are typically found at altitudes above 18,000 feet and are characterized by small, white, puffy clouds arranged in rows or ripples. They are often a sign of fair weather but can also indicate an approaching storm.

5. The type of cloud that forms when strong air currents carry warm air upward is c. cumulus. Cumulus clouds are large, puffy clouds that can develop vertically, forming a towering cloud with a flat top. They are often associated with thunderstorms and can produce heavy rain, hail, and lightning.

6. The type of fog that forms when cool air moves over a warm lake is c. steam fog. Steam fog, also called evaporation fog or sea smoke, occurs when cold, dry air moves over a warm, moist surface and causes water vapor to rise and condense into fog. This type of fog is often seen over bodies of water during the fall and winter.

7. Rain that passes through a layer of freezing air near the ground becomes c. sleet. Sleet is formed when raindrops fall through a layer of freezing air near the ground and freeze into small ice pellets before hitting the surface. It is different from hail, which forms in strong thunderstorms when updrafts carry raindrops upward into colder air where they freeze and then fall back to the ground, and snow, which forms in clouds when water vapor freezes directly into ice crystals. Glaze is a type of ice that forms when rain falls onto a surface that is below freezing, forming a layer of ice on top of the surface.

Therefore, The correct answers are:1. Weather factors include average air temperature, annual precipitation, and humidity. 2. The dew point is the temperature at which water vapor starts to condense. 3. Relative humidity may decrease if water vapor condenses out of the air or if the air temperature decreases. 4. The type of cloud that forms at high altitudes is cirrocumulus. 5. The type of cloud that forms when strong air currents carry warm air upward is cumulus. 6. The type of fog that forms when cool air moves over a warm lake is steam fog. 7. Rain that passes through a layer of freezing air near the ground becomes sleet, which is different from hail and snow.

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Answer:

D.

Explanation:

Answer:

the current is 16 amphere

Explanation:

The computation of Current is shown below:

As we know that

1 ms = 0.001s

So for 35 ms = 0.035

Now the current is

= 0.56 ÷ 0.035

= 16 AMphere

Hence, the current is 16 amphere

Answer:

the law of conservation of energy

Answer:

The answer would be 180 meters.

Explanation:

Answer:

the speed of the wave =1m/s

Answer:

D.) Sensory adaptation

Explanation:

Assuming you are talking about the cloth and metal monkey experiment performed in the field of psychology (not physics), the monkey formed an attachment to the cloth mother because it felt closer to it, as it was more appealing to its senses.

Answer:

a)  y₁ = ½ a, b) y₂ = 4 y₁, c)  y₃ = 9 y₁

Explanation:

For this exercise we can use the accelerated motion relationships.

Let's set a reference system where the x axis is parallel to the plane and its positive side is going down the plane.

          y = y₀ + v₀ t + ½ a t²

in that case where we throw the marble is the zero point, y₀ = 0, as part of rest its initial velocity is zero v₀ = 0 and a  is the acceleration along the inclined plane

           y = ½ a t²

a) in the first second t = 1

            y₁ = ½ a

b) in the next second of movement

           t = 2 s

           y₂ = ½ a 2²

           y₂ = 4 ½ a

           y₂ = 4 y₁

c) for the next second

            t = 3 s

            y₃ = ½ a 3²

            y₃ = 9 ½ a

            y₃ = 9 y₁

Answer:

2.66×10⁻⁹ N.

Explanation:

From the question,

Applying newton's law of universal gravitation,

Fg = GMm/r²............................... Equation 1

Where Fg = gravitational force, G = universal constant, M = mass of the mercury, m = mass of the human, r = radius of Mercury

Given: M = 3.31023 kg, M = 70 kg, r = 2.4106

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

Fg = 6.67×10⁻¹¹(70×3.31023)/(2.4106²)

Fg = 2.66×10⁻⁹ N.

Answer:

The answer is "Choice C ".

Explanation:

The relationship between the E and V can be defined as follows:

[tex]\to E= -\Delta V[/tex]

Let,

[tex]\to E= \frac{\delta V}{\delta x}[/tex]

When E=0

[tex]\to \frac{\delta V}{\delta x}=0[/tex]

v is a constant value

Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.

Answer:

797700000 J

Explanation:

From the question,

The work done by the rocket, is given as,

W = Ek+Ep............. Equation 1

Where Ek and Ep are the potential and the kinetic energy of the rocket respectively.

Ep = mgh............ Equation 2

Ek = 1/2mv²............. equation 3

Substitute equation 2 and equation 3 into equation 1

W = mgh+1/2mv².............. Equation 4

Where m = mass of the rocket, h = height, v = velocity of the rocket, g = acceleration due to gravity.

Given: m = 2000 kg, h = 12 km = 12000 m, v = 750 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 2000(12000)(9.8)+1/2(2000)(750²)

W = 235200000+562500000

W = 797700000 J