The world health organization has studied the consumption of junk food in countries around the world since 2000. the function c = 179( 1.029 )^t models the amount of sods consumed in the world, where c is the amount consumed in billions of liters and t is the number of years since 2000.


approximately how much soda was being consumed when the study began in 2000?

Answer:

1: 250 000

( There are 1000 metres in a km and 100 cm in a m, thus you multiply 5 km by 100 000 to convert it to cm, then you divide by 2 in order to get the simplist form of the ratio )

Answer:

V = 58.14 ft²

Step-by-step explanation:

the volume (V) of the prism is calculated as

V = Bh ( h is the perpendicular height )

here B = 11.4 and h = 5.1 , then

V = 11.4 × 5.1 = 58.14 ft²

Answer:

V = 58.14 ft³

Step-by-step explanation:

V = B × h

  = 11.4×5.1

  = 58.14 ft³

The length of the base of the parallelogram that has a height of 5 yards and an area of 150 square yards is 30 yards

The given parameters are:

Area = 150

Height = 5

The area of a parallelogram is:

Area = Base * Height

So, we have:

Base * 5 = 150

Divide both sides by 5

Base = 30

Hence, the length of the base of the parallelogram is 30 yards

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Answer:

D. 8.5

Step-by-step explanation:

The full value of √8 is 8.48528137...

Hope this helped!

Answer:

first we all know that minus multiply by minus will give you plus so,

-255-15=-270

Answer:

FA Is the closest so thats your answer.

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

SUM/COUNT = formula

8+13+15/3

36/3

= 12

Answer:

i really dont know, i need help with it too

Step-by-step explanation:

Answer:

The probability that the sum is 5 or lower for each dice when rolled is 25/36, since all numbers equal to or below 5 count. Since there are 5 numbers out 6 possible, 5/6 is the probability fo rolling 5 or lower for one. Multiply 5/6 by itself, since we are rolling twice 5/6 * 5/6 = 25/36 or about a 69.5% chance

Step-by-step explanation:

Answer:

5/18

Step-by-step explanation:

Khan Academy

the diagram shows a regular dodecagon is the size of one interior angle

Answer:

[tex]P(5)=\frac{1}{6}[/tex]

Step-by-step explanation:

Since the number 5 appears once on a 6-sided die, then [tex]P(5)=\frac{1}{6}[/tex]

Answer:

Perimeter = [tex]16\sqrt{5}[/tex]

Area = [tex]80[/tex]

Step-by-step explanation:

To find the perimeter of the square, you can use the square perimeter formula, [tex]P=4a[/tex], where [tex]a[/tex] is equal to the length of one side:

[tex]P=4a[/tex]

[tex]P=4(4\sqrt{5})[/tex]

[tex]P=16\sqrt{5}[/tex]

Then, to find the area of the square, you can use the square area formula, [tex]A=a^2[/tex], where [tex]a[/tex] is equal to the length of one side:

[tex]A=a^2[/tex]

[tex]A=(4\sqrt{5})^2[/tex]

[tex]A=80[/tex]

Therefore, the perimeter of the square is [tex]16\sqrt{5}[/tex] millimeters and the area of the square is [tex]80[/tex] square millimeters.

I hope this helps!

Answer:

Kaylaa   do you use  desmos graphing calculator?  it's an online graphsing tool and would make this very easy for you. Maybe you are not allowed to use a calculator?

Step-by-step explanation:

with out  a calculator it's a long math process,  1st because each of the equations are equal to  Y,  we can set each of them equal to each other. like this

[tex]\sqrt{x-8}[/tex] + 3  =  - [tex](x-5)^{2}[/tex] + 18

[tex]\sqrt{x-8}[/tex]     =  - [tex](x-5)^{2}[/tex]  +18 -3

[tex]\sqrt{x-8}[/tex]   =    - [tex](x-5)^{2}[/tex]  + 15

[tex]\sqrt{x-8}[/tex]   = -[ (x-5)*(x-5) ] + 15

[tex]\sqrt{x-8}[/tex]  = -[ [tex]x^{2}[/tex] - 10x + 25] +15

[tex]\sqrt{x-8}[/tex]  = -[tex]x^{2}[/tex] + 10x -25 +15

 [tex]\sqrt{x-8}[/tex] = -[tex]x^{2}[/tex] + 10x -10

-  [tex]\sqrt{x-8}[/tex]  = [tex]x^{2}[/tex] - 10x +10

(-  [tex]\sqrt{x-8}[/tex])^2  = (  [tex]x^{2}[/tex]- 10x +10)^2

this turns into a 4 order polynomial.   I used a solver to find x

x = 8.75884....  approx

so the question asks what is the point at the nearest 1000th,  which is 8.759  

then they ask what is the point at the nearest 100th, which is  

8.76

I'm attaching the graph, if it helps  :P

Answer:

31200000

Step-by-step explanation:

Jeez who gave you this question?

Answer:

$980

Step-by-step explanation:

Regular hours- 40 per week

Regular wage- $10/hour

Regular Pay- (40 hours + 40 hours) × $10.00/hour = $800

First week: 43 hours = 40 hours regular + 3 hours overtime

Second week: 49 hours = 40 hours regular + 9 hours overtime

Overtime hours- 3 hours + 9 hours = 12 hours

Overtime wage- $10/hour × 1.5 = $15/hour

Overtime Pay- 12 hours × $15/hour = $180

Gross Pay-​ $800 + $180 = $980

Answer:

-2 > -9

or

-9 < -2

Step-by-step explanation:

-2 > -9

Inequalities represent values by comparing their size to other numbers.

Negative Numbers

While positive 9 might be larger than positive 2, remember that negative numbers work in the opposite way. -9 is more negative than -2, thus it is smaller. Another way to think about it is that -9 is further below 0 than -2.

Inequality Symbols

There are 2 main inequality symbol < (less than) and > (greater than). The symbol opens to the side of the larger number. Because we know that -2 is greater than -9, we can make the inequality -2 > -9.

Answer:

[tex]\boxed{k = \frac{L^2 + p}{4t}}[/tex]

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle L = \sqrt{4kt - p}[/tex]

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}[/tex]

Next, add p to both sides:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}[/tex]

Next, divide 4t by both sides:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}[/tex]

We can rewrite the new equation by swapping sides to obtain our final expression:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}[/tex]

∴ we have changed the subject of the formula.

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Topic: Algebra I

[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2} ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=\stackrel{KL}{2}\\ \theta =\stackrel{\widehat{LM}}{\frac{14\pi }{9}} \end{cases}\implies A=\cfrac{ ~~ \left( \frac{14\pi }{9} \right)(2)^2 ~~ }{2}\implies A=\cfrac{28\pi }{9}[/tex]

Reason:

Plug in w = 16 and compute.

D = 4w + 30

D = 4(16) + 30

D = 64 + 30

D = 94

This says at week 16, Jose will have $94 in his piggy bank.

Answer:

10 maybe

Step-by-step explanation:

The value of arcsin(1) is 90° and the value of arctan√3 is 60°

From the question, we are to determine the values of arcsin(1) and arctan√3. That is, sin⁻¹ (1) and tan⁻¹(√3)

NOTE:

If sin x° = y, then sin⁻¹ y = x°

If cos x° = y, then cos⁻¹ y = x°

If tan x° = y, then tan⁻¹ y = x°

From the trigonometry table of values, we have that

sin 90° = 1

∴ sin⁻¹ (1) = 90°

arcsin(1) = 90°

Alos, from the trigonometry table of values, we have that

tan 60° =  √3

∴ tan⁻¹(√3) = 60°

arctan√3 = 60°

Hence, the value of arcsin(1) is 90° and the value of arctan√3 is 60°

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The random sample is that where every result (student for the case) has the same probability to be selected.

Then you cannot use any method that select one student with preference.

Two possible valid methods are:

- Write the number of each student in separate papers, put all the papers in a closed box and  blind choose 102 papers.

- Assign a number to each student of the school and use a method to generate 102 random numbers.

Check the picture below, so the parabola looks more or less like so.

the vertex is always half-way between the focus point and the directrix, and since the parabola is opening downwards, the "p" distance is negative.

[tex]\textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} h=5\\ k=1\\ p=-1 \end{cases}\implies 4(-1)(y-1)~~ = ~~(x-5)^2\implies -4(y-1)=(x-5)^2 \\\\\\ y-1=-\cfrac{1}{4}(x-5)^2\implies y=-\cfrac{1}{4}(x-5)^2 + 1[/tex]

By using trigonometric relations, we see that the horizontal distance is 196.6.

Remember the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus).

In this case, the adjacent cathetus is the horizontal distance between the towers, the opposite cathetus is 40, and the angle is 11.5°.

Then we can write:

tan(11.5°) = 40/x

Solving for x:

x = 40/tan(11.5°)

This is the equation that you got, and it gives:

x = 40/tan(11.5°) = 196.6

Why you don't get this?

The problem may be that your calculator is in radians instead of degrees. It should say "DEG" instead of "RAD" if you want to evaluate trigonometric functions in degrees.

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{0}

The range of a function is the set of y-values within a function.

Finding the Range

As stated above, the range is all of the y-values. To find the y-values remember that in a coordinate pair the second point is the y-value. So, look at the second value of each pair. For all 4 points, the y-value is 0. This means that the range is 0.

Range Notation

Now that we know the range, we need to use the correct notation. When writing domain or range, make sure that the values are listed in order from least to greatest. Additionally, even if y-values repeat in the coordinate pairs, only state them once in the range. In this case, there is only 1 unique value, so the range should only have 1 value. Finally, the range is surrounded by braces. Therefore, the range should be written as {0}.

Answer:

1-30ft (half circle) /60ft (full circle)

2-22in  (half circle) 44in (full circle)

3-19yd  (half circle) 38yd (full circle)

4-12yd  (half circle) 24 yd (full circle)

5-6in  (half circle) 12 in (full circle)

6 34ft  (half circle) 58 (full circle)

Give brainliest :)

Answer:  

If the two side planks are equal lengths then the answer is 26 1/3.

The system of the equations that have the solution of (2, -3) are given below.

3x + 2y = 0 and 3y = 2x - 13

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

Write a system of equations with the solution (2, -3).

From a single point, an infinite number of lines pass through this point.

Let one line is passing through the origin. Then the equation of the line will be

[tex]\rm y = \dfrac{-3}{2} (x)\\\\y = -1.5x[/tex]

And the other line is perpendicular to the line which is passing through the origin and a point (2, -3).

[tex]\rm y = \dfrac{2}{3} x + c[/tex]

Then this line also passes through a point (2, -3). Then the value of c will be

[tex]\rm -3 = \dfrac{2}{3} \times 2 + c\\\\c \ \ = -13[/tex]

Then the equation of the line will be

3y = 2x -13

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