The tree diagram represents an
experiment consisting of two trials.
.4
.5
.6
D
.3
С
.5
.7
D
Þ(B and D) = [?]
ter

Answer:

2.25km

Step-by-step explanation:

a scale of 1 : 25000 means:

1 cm on map ------> equals 25000 cm on ground  

hence,

9 cm on map ------> equals 25000 x 9 cm = 225,000 cm = 2.25km on ground

Answer:

(A)C,D,A,B

Step-by-step explanation:

[tex]f(x) = x^2- 2x\\g(x) = x^3-1[/tex]

a) f(-2)

[tex]f(-2) = (-2)^2- 2(-2)\\=4-(-4)\\=4+4\\=8$ (C)[/tex]

b) g(-2)

[tex]g(-2) = (-2)^3-1\\\=-8-1\\=-9 $(D)[/tex]

c) f(-1)+g(3)

[tex]f(-1) = (-1)^2- 2(-1)=1+2=3\\g(3) = (3)^3-1=27-1=26\\f(-1) + g(3)=3+26\\=29$ (A)[/tex]

d) f(5) : g(2)

[tex]f(5) = (5)^2- 2(5)=25-10=15\\g(2) = (2)^3-1=8-1=7\\f(5) :g(2)=15/7$ (B)[/tex]

Answer:

letra A confia

Step-by-step explanation:

Answer:

Given:

Body mass index values:

17.7

29.4

19.2

27.5

33.5

25.6

22.1

44.9

26.5

18.3

22.4

32.4

24.9

28.6

37.7

26.1

21.8

21.2

30.7

21.4

Constructing a frequency distribution beginning with a lower class limit of 15.0 and use a class width of 6.0.

we have:

Body Mass Index____ Frequency

15.0 - 20.9__________3( values of 17.7, 18.3, & 19.2 are within this range)

21.0 to 26.9__________8 values are within this range)

27.0 - 32.9____________ 5 values

33.0 - 38.9____________ 2 values

39.0 - 44.9 _____________2 values

The frequency distribution is not a normal distribution. Here, although the frequencies start from the lowest,  increases afterwards and then a decrease is recorded again, it is not normally distributed because it is not symmetric.

The frequency distribution is not a normal distribution because it is not symmetric and this can be obtained through the given data.

Given :

The data represents the body mass index​ (BMI) values for 20 females.

The frequency distribution begins with a lower class limit of 15.0 and uses a class width of 6.0 are as follows:

Body Mass Index                        Frequency

   15 - 20.9                                         3

   21 - 26.9                                         8

   27 - 32.9                                         5

   33 - 38.9                                         2

   39 - 44.9                                         2

The frequency distribution is not a normal distribution because it is not symmetric.

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Answer:

[tex]x\in(1.146,\infty)[/tex]

Step-by-step explanation:

We are given an inequality

[tex]e^x>14[/tex]

We have to solve the given inequality.

Taking both side ln of given inequality

Then, we get

[tex]ln(e^x)>ln(14)[/tex]

[tex]xlne>1.146[/tex]

We know that

lne=1

Using the value

[tex]x>1.146[/tex]

[tex]x\in(1.146,\infty)[/tex]

Hence, the value of x is given by

[tex]x\in(1.146,\infty)[/tex]

Answer:

  reflect over the x-axis and shift down 3

Step-by-step explanation:

The leading coefficient of -1 means the graph is reflected over the x-axis. The addition of -3 to the function means each graphed point is shifted down 3 units from the original.

The graph of y = -x^2 -3 is the result of the transformation ...

  reflect over the x-axis and shift down 3

Answer:

12c-49

Step-by-step explanation:

−8+(4)(c)+(4)(−9)+−5+6c+2c

=−8+4c+−36+−5+6c+2c

Combine Like Terms:

=−8+4c+−36+−5+6c+2c

=(4c+6c+2c)+(−8+−36+−5)

=12c−49

pls mark me brainliest

Answer:

The overall image would be 4 units to the right and 3 units down on the coordinate plane.

Step-by-step explanation:

We do not see an image. But that is okay. (x+4,y-3) means that the x value of each coordinate gets increased by 4 and the y value of each coordinate gets decreased by 3. The overall image would be 4 units to the right and 3 units down on the coordinate plane.

The image would be 4 units to the right and 3 units down on the coordinate plane.

In maths, a translation moves a shape left, right, up, or down but does not turn.

Given the translation of quadrilateral ABCD

(x+4,y-3) means that the x value of each coordinate gets increased by 4 and the y value of each coordinate gets decreased by 3.

Hence, The image would be 4 units to the right and 3 units down on the coordinate plane.

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Answer:

C. Domain : {Gem, Hesh, Sam}

Range : {Gale, Abby, Beni}

B. The relation in the figure is a function because each element in the range corresponds to exactly one element in the domain.

Step-by-step explanation:

The figure of the mapping is attached below.

From the diagram, the domain for the relation is the set of Fathers:

{Gem, Hesh, Sam}

The range is the set of Sons:

{Gale, Abby, Beni}

The relation is a function. This is because each element in the range corresponds to exactly one element in the domain.

Answer:

Option (2)

Step-by-step explanation:

Given in the question,

ln(3) = 1.10

ln(6) = 1.79

We have to calculate the value of ln(2).

Since ln(6) = ln(3 × 2)

                = ln(3) + ln(2) [From the property of logarithm, ln(a×b) = ln(a) + ln(b)]

         1.79 = 1.10 + ln(2)

         ln(2) = 1.79 - 1.10

         ln(2) = 0.69

Therefore, value of ln(2) will be 0.69.

Option (2) will be the answer.

Answer:

The answer is 0.69.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Slope of parallel lines are equal.

1) m = -2/3

(4,-7)

[tex]y-y_{1}=m(x-x_{1})\\\\y-[-7]=\frac{-2}{3}(x-4)\\\\y+7=\frac{-2}{3}*x-\frac{-2}{3}*4\\\\y+7=\frac{-2}{3}x+\frac{8}{3}\\\\y=\frac{-2}{3}x+\frac{8}{3}-7\\\\y=\frac{-2}{3}x+\frac{8}{3}-\frac{7*3}{1*3}\\\\y=\frac{-2}{3}x+\frac{8}{3}-\frac{21}{3}\\\\y=\frac{-2}{3}x-\frac{13}{3}[/tex]

2) 5x + y = 4

  y = -5x + 4

slope m = -5

(-1,4)

y - 4 = -5(x -[-1])

y- 4 = -5(x+1)

y - 4 = -5x - 5

y = -5x - 5 + 4

y = -5x -1

If two lines are perpendicular, m2 = -1/m1

m1 = -4/3

[tex]m_{2}=\frac{-1}{\frac{-4}{3}}=-1*\frac{-3}{4}=\frac{3}{4}\\[/tex]

(5,4)

[tex]y-4=\frac{3}{4}(x - 5)\\\\y-4=\frac{3}{4}x-\frac{3}{4}*5\\\\y-4=\frac{3}{4}x-\frac{15}{4}\\\\y=\frac{3}{4}x-\frac{15}{4}+4\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{4*4}{1*4}\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{16}{4}\\\\y=\frac{3}{4}x+\frac{1}{4}[/tex]

Answer:

3.) is y=3/4x+1/4 That's what i got but i hope this helps.

Step-by-step explanation:

Answer:

{x|x[tex]\in R[/tex]}

Step-by-step explanation:

We are given that a function

[tex]f(x)=2x+6[/tex]

We have to find the domain of the function in the correct set notation.

The given function is linear polynomial .

The linear polynomial is  defined for all real  values of x.

Therefore, the given function is defined for values of x.

Domain of f is given  by

{x|x[tex]\in R[/tex]}

Hence, the domain of the function in the correct set notation is given by

{x|x[tex]\in R[/tex]}

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

[tex](Y_1)^2 and (Y_2)^2[/tex] have [tex]x^2[/tex] distribution with 1 degree of freedom

and [tex]V=(Y_1^2)+(Y_2)^2[/tex] has x^2 with 2 degree of freedom

[tex]F_v(v)=\frac{e^{-\frac{v}{2}}}2[/tex]

Since we have to find the density formula

[tex]U=\sqrt{V}[/tex]

We use method of transformation

[tex]h(V)=\sqrt{U}\\\\=U[/tex]

There inverse function is [tex]h^-^1(U)=U^2[/tex]

We derivate the fuction above with respect to u

[tex]\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u[/tex]

Therefore,

[tex]F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U[/tex]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

[tex]\frac{dy}{dx} = 3t^{2} - 2t - 27[/tex]

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]\bigtriangleup = b^{2} - 4ac[/tex]

In this question:

[tex]3t^{2} - 2t - 27 = 0[/tex]

So

[tex]a = 3, b = -2, c = -27[/tex]

Then

[tex]\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328[/tex]

So

[tex]t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35[/tex]

[tex]t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685[/tex]

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

[tex]x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55[/tex]

[tex]y = t^{2} - 4 = (3.35)^2 - 4 = 7.22[/tex]

The first point is (27.55, 7.22)

t = -2.685

[tex]x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3[/tex]

[tex]y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21[/tex]

The second point is (-11.3, 3.21).

Answer:

wrong question hai right question do

Step-by-step explanation:

0

Answer:

0

Step-by-step explanation:

Zero, because you cannot have (0/17)

Answer:

1/15

Step-by-step explanation:

(2/5)/6 = 2/(5*6) = 2/30 = 1/15

Answer:

240

Step-by-step explanation:

8*10=80ft *3= 240 but thats over budget

The total cost to fence the rectangular garden is $108. Diego has enough money to fence the rectangular garden.

The perimeter of a rectangle is the total distance of its outer boundary. It is twice the sum of its length and width and it is calculated with the help of the formula: Perimeter = 2(length + width).

Given that, a rectangular garden needs to be at least 10 feet wide and at least 8 feet long.

Now the perimeter of rectangular garden is

2(8+10)

= 36 feet

Total cost of fencing = 36×3

= $108

Diego's budget is $120

Therefore, Diego has enough money to fence the rectangular garden.

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Answer:

1750 Students

Step-by-step explanation:

2500*0.7

Answer:

-45

Step-by-step explanation:

-34+15=-19

-29-(-3)= -29+3= -26

-19 + -26 = -45

Answer:

-45

Step-by-step explanation:

-34 + 15 - 29 - (-3)

-34-29 +15+3

-63+18

18-63

-45

Answer:

1025/4

Step-by-step explanation:

x^6 - x

---------------

4y

Let x =-4 and y = 4

(-4)^6 - (-4)

---------------

4*4

4096 +4

------------------

16

4100/16

1025/4

The answer is C. 1025/4

welll i kinda don get ur question but ummmm if u say like the graetest number then 48

Answer:

a) 34.46% probability that her pulse rate is greater than 70 beats per minute.

b) 2.28% probability that they have pulse rates with a mean greater than 70 beats per minute.

c) Because the underlying distribution(female's pulse rate) is normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Distribution of females pulse rates:

Here, i suppose there was a typing mistake, since the mean and the standard deviation are lacking.

Also, the question c. only makes sense if the distribution is normal, so i will treat it as being.

I will use [tex]\mu = 68, \sigma = 5[/tex]. I am guessing these values, just using them to explain the question.

a. If 1 adult female is randomly selected, find the probability that her pulse rate is greater than 70 beats per minute.

This is 1 subtracted by the pvalue of Z when X = 70. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{70 - 68}{5}[/tex]

[tex]Z = 0.4[/tex]

[tex]Z = 0.4[/tex] has a pvalue of 0.6554

1 - 0.6554 = 0.3446

34.46% probability that her pulse rate is greater than 70 beats per minute.

b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean greater than 70 beats per minute.

Now [tex]n = 25, s = \frac{5}{\sqrt{25}} = 1[/tex]

This probability is 1 subtracted by the pvalue of Z when X = 70. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{70 - 68}{1}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that they have pulse rates with a mean greater than 70 beats per minute.

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30

The sample size only has to exceed 30 if the underlying distribution is normal. Here, the distribution of females' pulse rate is normal, so this requirement does not apply.

Answer:

81 km²

Step-by-step explanation:

so the perimeter of the field is 288 : 8 = 36 km

the perimeter of square is 4 time side

4s = 36

s = 36 : 4 = 9 km

Area = side x side = s²

A = 9² = 81 km²

Answer:

0.9604 = 96.04% probability of you making it home for the holidays

Step-by-step explanation:

We have these following probabilities:

100 - 33 = 67% probability of the flight happening.

In the 33%, that is, when the flight does not happen, there is an 88% probability that you get the ride with Walter.

What is the probability of you making it home for the holidays?

0.67 + 0.88*0.33 = 0.9604

0.9604 = 96.04% probability of you making it home for the holidays

Answer:

38.11% probability that the mean of her sample will be between 2700 and 2800 calories

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 2760, \sigma = 500, n = 25, s = \frac{500}{\sqrt{25}} = 100[/tex]

Find the probability that the mean of her sample will be between 2700 and 2800 calories

This is the pvalue of Z when X = 2800 subtracted by the pvalue of Z when X = 2700.

X = 2800

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{2800 - 2760}{100}[/tex]

[tex]Z = 0.4[/tex]

[tex]Z = 0.4[/tex] has a pvalue of 0.6554

X = 2700

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{2700 - 2760}{100}[/tex]

[tex]Z = -0.6[/tex]

[tex]Z = -0.6[/tex] has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

38.11% probability that the mean of her sample will be between 2700 and 2800 calories

Answer:

(c) Pi/4

Step-by-step explanation:

3pi/4 = (3 x 180) / 4 = 135 degrees

135 degrees is equivalent to (180 degrees - 135 degrees) 45 degrees

45 degrees = Pi/4

Therefore, the reference angle of 3pi/4 is Pi/4

Thus, the correct option is (c) Pi/4

The reference angle for 3π/4 is π/4.

So, the correct answer is c) π/4.

Given is an angle 3π/4, we need to find its reference angle,

The reference angle is the acute angle formed between the terminal side of an angle and the x-axis in the coordinate plane.

To find the reference angle for an angle, you need to consider the position of the terminal side of the angle in the coordinate plane and determine the acute angle formed.

In this case, we are given the angle 3π/4. To find the reference angle, we need to consider the position of the terminal side of this angle.

The angle 3π/4 lies in the second quadrant of the coordinate plane, where both the x-coordinate and y-coordinate are negative.

To find the reference angle, we need to find the acute angle formed by the terminal side with the x-axis. In the second quadrant, this acute angle is formed by the vertical line connecting the terminal side to the x-axis.

If we draw a vertical line from the terminal side of 3π/4, it intersects the x-axis at π/4.

Therefore, the reference angle for 3π/4 is π/4.

So, the correct answer is c) π/4.

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Answer:

25 and 36

Step-by-step explanation:

5^2=25

6^2=36

Answer:

Im feeling pretty today so imma go with C

Step-by-step explanation:

lol i took the test like about 2 days ago and i just checked my answers and C was right, good luck

Answer:

9

Step-by-step explanation:

Please mark me brainliest

The right answer is 9.

please see the attached picture for full solution

Good luck on your assignment

Answer:

The name is derived from the Pythagorean theorem, stating that every right triangle has side lengths satisfying the formula a2 + b2 = c2; thus, Pythagorean triples describe the three integer side lengths of a right triangle.

Answer:

Option D: A hypothesis test regarding the difference between two population proportions from independent samples.

Step-by-step explanation:

A hypothesis test regarding the difference between two population proportions from independent samples. This type of test is used to compare the two population proportions if they are equal or not. It is appropriate under the condition that

The sampling method for each population is simple random sampling.

The samples are independent.

Each sample includes at least 10 successes and 10 failures.

Each population is at least 20 times as big as its sample.