The table of values represents a linear function g(x) where c is the number of days that have passed and g(x) is the balance in the bank account

Step-by-step explanation:

im sorry but im not sure about this question

Answer:

334.488 miles

Step-by-step explanation:

You don't have a specific request on what I should answer, if it was distance then here's your answer

The range of the function is

[tex]y \leqslant 1[/tex]

After calculating the value, l & w could be [tex]2x^{5} y^{8}[/tex] & [tex]12x^{} y^{7}[/tex].

The inquiry relates to the laws of indices

where, [tex]x^{a} * x^{b}=x^{a+b}[/tex]

Provided the query, A= [tex]24x^{6}y^{15}[/tex]

[tex]2* 12[/tex] might be used to calculate the length and width of 24.

Hence,

[tex]x^{6}=x^{5} * x^{1} =x^{5+1}[/tex]

& [tex]y^{15}= y^{8} * y^{7} =y^{8+7}[/tex]

So, it can be written as,

A=l * w

⇒ [tex]24x^{6}y^{15}[/tex] = [tex]2x^{5}y^{8}[/tex] * [tex]12xy^{7}[/tex]

Therefore, it is concluded that the dimensions of the rectangle could be [tex]2x^{5} y^{8}[/tex] & [tex]12x^{} y^{7}[/tex].

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The number of possible license plates that can be issued using this system is 67600000.

Combinations are selections made by taking some or all of a number of objects, irrespective of their arrangements.

Here, number plate contains 5 numbers and 2 letters

Total possible number (0-9) = 10

Total possible letters (A-Z) = 26

Possible number plates which contains 5 numbers and 2 letters are

          ¹⁰C₁ X  ¹⁰C₁ X  ¹⁰C₁ X  ¹⁰C₁ X  ¹⁰C₁ X ²⁶C₁ X ²⁶C₁

             10 X 10 X 10 X 10 X 10 X 26 X 26

                 10⁵ X 26²

                   676 X 10⁵

                 67600000

Thus, the number of possible license plates that can be issued using this system is 67600000.

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The value of expression is -(x- 4y/3 + 5z/3)

A fraction represents a part of a whole or, more generally, any number of equal parts.

Given:

1/3 · (-3x + 4y - 5z)

= 1/3(-3x) + 1/3 *4y + 1/3* (-5z)

= -x +4/3*y -5/3 *z

=-(x- 4y/3 + 5z/3)

Hence, 1/3 · (-3x + 4y - 5z)= -(x- 4y/3 + 5z/3)

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The cross-section parallel to the base of a cone is a circle

The cross-section parallel to the base of a cylinder is a circle

The cross-section perpendicular to the base of a cone is a triangle

The cross-section perpendicular to the base of a cylinder is a rectangle

Answer:

18, 36, 54

Step-by-step explanation:

Find the least common multiple of 6 and 9:

Multiples of 6: 6, 12, 18, ......

Multiples of 9: 9, 18, 27, ......

We see that 18 is the least common multiple of 6 and 9.

Additional multiples of 18 are 36 and 54.

If an integer is divisible by 6 and by 9 , then the integer must be divisible by 54.

Consider the statement as a contradiction.

The assertion exists that any natural number divisible by 6 and 9 exists also divisible by 54.

Let us consider divisible to mean that the outcome of the division of the number and 54 provides another natural number. We can take the prime factors of 6 and 9 which are {2,3} and {3,3}. We can consider that the product [tex]$2 \times 3 \times 3=18$[/tex] exists a number that exists divisible by 6 and 9 but exists not divisible by 54. Another instance exists the product of [tex]$2 \times 2 \times 3 \times 3=36$[/tex] which exists also not divisible by 54.

Therefore, the correct answer is option e) 54.

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Step-by-step explanation:

as we see in the sequence, each term is twice of the previous term.

we mark the Nth as a(N), then:

a(N)=2a(N-1)

Answer:

[tex]a_{n}[/tex] = 5[tex](2)^{n-1}[/tex]

Step-by-step explanation:

there is a common ratio between consecutive terms , that is

10 ÷ 5 = 20 ÷ 10 = 40 ÷ 20 = 80 ÷ 40 = 2

this indicates the sequence is geometric with explicit formula

[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

here a₁ = 5 and r = 2 , then

[tex]a_{n}[/tex] = 5 [tex](2)^{n-1}[/tex]

Firstly, let’s assume the the whole capacity the work requires is 1.

Then, let’s see how 1 man can do in 50 days: 1/5.

Further, let’s see how 1 man can do in 1 day : 1/(5×50) = 1/250.

Similarly, let’s see how 1 woman can do in 1 day: 1/(10×50) = 1/500.

Now, we have 8 men, and they can do 8*1/250 in 1 day, which is 4/125.

Besides, we have 4 women, and they can do 4×1/500 in 1 day, which is 1/125.

Therefore, all people we have can do 4/125 + 1/125 of the work in 1 day, which is 1/25.

As a result, the work takes 1/(1/25)= 25 days.

The unit rate at which Martin paints in walls per gallon is 1 7/25 walls per gallon

Unit rate of paint per gallon = Quantity of wall / gallon of paint

= 4/5 ÷ 5/8

= 4/5 × 8/5

= (4 × 8) / (5 × 5)

= 32/25

= 1 7/25 walls per gallon

Complete question:

Martin uses 5/8 of a gallon of paint to cover4/5 of a wall. What is the unit rate at which Martin paints in walls per gallon

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We conclude that after the discount and the coupon, Will paid $36 for the skateboard.

We know that the original price was $60, and two discounts were applied. One of 20% and other of 25%.

Then the amount that he paid is given by:

P = $60*(1 - 20%/100%)*(1 - 25%/100%)

P = $60*(0.8)*(0.75)  = $36

We conclude that after the discount and the coupon, Will paid $36 for the skateboard.

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Answer:

[tex]3^x=5[/tex]

Step-by-step explanation:

Given:

[tex]9^x=25[/tex]

Rewrite 9 as 3²:

[tex]\implies (3^2)^x=25[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies 3^{2x}=25[/tex]

Apply the same exponent rule:

[tex]\implies (3^x)^2=25[/tex]

Square root both sides:

[tex]\implies \sqrt{(3^x)^2}=\sqrt{25}[/tex]

[tex]\implies 3^x=5[/tex]

Answer: 90 degrees

Step-by-step explanation:

The hypotenuse is opposite the right angle, which is created by the two shortest sides.

Step-by-step explanation:

[-5, 4] because it is an empty circle, meaning less than

Answer:

12 sides

Explanation:

[tex]\sf interior \ angle = \dfrac{(n-2) \times 180}{n} \quad (where \ n \ denotes\ number \ of \ sides)[/tex]

Solving Steps:

[tex]\sf \dfrac{(n-2) \times 180}{n} = 150[/tex]

[tex]\sf (n-2) \times 180} = 150n[/tex]

[tex]\sf 180n-360 = 150n[/tex]

[tex]\sf 180n-150n = 360[/tex]

[tex]\sf 30n = 360[/tex]

[tex]\sf n = 12[/tex]

The Saturday will be the day on 18th February 2040 if  18th February 2030 falls on Monday

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have:

18th February 2030 falls on Monday

To find what will be the day on 18th February 2040

Calculate the expression:

= Given date + Month code + (difference between years) + Numbe of leap year

Leap year = difference between years/4

= (2040-2030)/4

= 10/4 = 2.5 ≈2

= 18 + 3 + (2040-2030) + 2

= 33

Divide 33 by 7 the remainder will be 5

Day code = given day code + remainder

= 1 + 5

= 6 (saturday from the table attahced)

Thus, Saturday will be the day on 18th February 2040 if  18th February 2030 falls on Monday.

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Answer:

x =83

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the two opposite interior angles.

x+43 = 126

Subtract 43 from each side

x = 126 -43

x =83

Let's take this problem step by step:

For the angle adjacent to the exterior angle of 126°:

  ⇒ exterior angle plus the that angle is equal to 180 degrees

      ⇒ since it is on a straight line

                 [tex]126 + that_.angle=180\\\rm \hookrightarrow that.angle=180-126\\\rm \hookrightarrow that.angle=54[/tex]

The sum of all the angles in a triangle is: 180°

                [tex]that.angle+43+x=180\\\rm \hookrightarrow 54+43+x=180\\\rm \hookrightarrow 97+x=180\\\rm \hookrightarrowx=83[/tex]

The size of angle x is 83°

Answer: 83°

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Let's see

[tex]\boxed{\sf log_aa=1}[/tex]

Now

[tex]\\ \rm\Rrightarrow log_{10}0.0001)[/tex]

[tex]\\ \rm\Rrightarrow log_{10}10^{-4}[/tex]

[tex]\\ \rm\Rrightarrow -4log_{10}10[/tex]

[tex]\\ \rm\Rrightarrow -4[/tex]

Answer:

This has already been answered correctly, but I'll add an additional perspective.  The log of (0.0001 to the base 10 is -4.

Step-by-step explanation:

log(base 10) says give us an exponent, x, that would be required to make [tex]10^{x}[/tex] equal to a specified number, in this case 0.0001.

[tex]10^{0}[/tex] = 1

[tex]10^{1}[/tex] = 10

[tex]10^{-1}[/tex] = 0.1

[tex]10^{-2}[/tex] = 0.01

[tex]10^{-4}[/tex] = 0.0001

The log of (0.0001) to the base 10 is -4.

Answer:

the answer is 4 units im pretty sure

Step-by-step explanation:

The height of the prism is 6 units.

The correct option is C.

A prism is a polyhedron in three dimensions with two identical ends.

To find the height of the prism, we need to use the formula for the volume of a prism, which is:

Volume = Base area x Height

Since the prism has two congruent hexagonal bases, we can find the base area by adding the areas of the two congruent isosceles trapezoids.

The area of an isosceles trapezoid is given by the formula:

Area = ((b1 + b2) / 2) x h

where b1 and b2 are the lengths of the two parallel bases, and h is the height of the trapezoid.

In this case, the two parallel bases have lengths of 5 and 8, and the height of each trapezoid is 3, so the area of one trapezoid is:

Area = ((5 + 8) / 2) x 3 = 19.5 square units

The base area of the prism is then:

Base area = 2 x 19.5 = 39 square units

We are given that the volume of the prism is 234 cubic units, so we can use the formula for the volume of a prism to find the height:

Volume = Base area x Height

234 = 39 x Height

Height = 6 units

Therefore, the height of the prism is 6 units.

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Answer:

broken line

Step-by-step explanation:

for the graph of an inequality with < or >  use a broken line

-----------------------------------

for the graph of an inequality with ≤ or ≥ use a solid line

Answer:

m=3

b=(0,5)

Step-by-step explanation:

Answer:

9 and 27

Step-by-step explanation:

let me know if you want an explanation

If the given differential equation is

[tex]\cos^2(x) \sin(x) \dfrac{dy}{dx} + \cos^3(x) y = 1[/tex]

then multiply both sides by [tex]\frac1{\cos^2(x)}[/tex] :

[tex]\sin(x) \dfrac{dy}{dx} + \cos(x) y = \sec^2(x)[/tex]

The left side is the derivative of a product,

[tex]\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)[/tex]

Integrate both sides with respect to [tex]x[/tex], recalling that [tex]\frac{d}{dx}\tan(x) = \sec^2(x)[/tex] :

[tex]\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx[/tex]

[tex]\sin(x) y = \tan(x) + C[/tex]

Solve for [tex]y[/tex] :

[tex]\boxed{y = \sec(x) + C \csc(x)}

which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}[/tex].

Answer:

6 green marbles should be added.

Step-by-step explanation:

If the probability of drawing a blue marble from 18 marbles is 2/3 then there are 12 blue marbles because 18 times 2/3 is 12. This means that to reduce this probability to 1/2 you need to add 6 more marbles to the total amount to get it to 24. Now the probability of getting a blue marble is 12/24 which is 1/2.

Answer:

The rectangular table

Step-by-step explanation:

Square table: 36*36=1296

Rectangular table: 20*42=1460 [tex]in^{2}[/tex]

Circular table: [tex]\pi * 21^{2}[/tex]≅1384

Answer:

Laurel has to cover this area with 2.64 ounces of seeds.

Step-by-step explanation:

Given

Base of Parallelogram = 30ft

Height of Parallelogram = 22ft

Area of Parallelogram = 1/2*base*height

Therefore, Area of Parallelogram =  1/2*30*22

                                                        = 330sq. ft

Given

One ounce of seed covers 125 sq. ft

Hence, No. of ounces needed to cover 330 sq. ft= 330/125

                                                                                  = 2.64

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[tex]14-a=19-12\\14-a=7\\a=14-7\\a=7[/tex]

Answer:

7

Step-by-step explanation:

14-a=19-12

14-a=7

14-7=a

7=a

Combine like terms

The equivalent expression to [tex]\left(\frac{4mn}{m^{-2}n^6}\right)^{-2}[/tex] is given by [tex]=\mathbf{\frac{n^{10}}{16m^6}}[/tex].

From the principle of indices we get,

Addition of exponent, [tex]a^{m+n}=a^m.a^n[/tex]

Subtraction, [tex]a^{m-n}=\frac{a^m}{a^n}[/tex]

Multiplication, [tex]a^{mn}=(a^m)^n[/tex]

negative exponent, [tex]a^{-m}=\frac{1}{a^m}[/tex]

Here in the problem given expression is [tex]\left(\frac{4mn}{m^{-2}n^6}\right)^{-2}[/tex]

Calculating we get,

[tex]\left(\frac{4mn}{m^{-2}n^6}\right)^{-2}[/tex]

[tex]=\left(4m^{1-(-2)}n^{1-6}\right)^{-2}[/tex], using addition and subtraction of indices formulae

[tex]=\left(4m^3n^{-5}\right)^{-2}[/tex]

[tex]=16^{-1}m^{-6}n^{10}[/tex], using multiplication of indices

[tex]=\frac{n^{10}}{16m^6}[/tex], using negative exponent formula

Hence the equivalent required expression is [tex]=\frac{n^{10}}{16m^6}[/tex].

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Answer:

b

Step-by-step explanation:

edge 23