The starship Enterprise approaches the planet Risa at a speed of 0.8c relative to the planet. On the way, it overtakes the intergalactic freighter Astra. The relative speed of the two ships as measured by the navigator on the Enterprise is 0.5c. At what speed is Astra approaching the planet?

Answer:

im sure your already past this but it's E.

Explanation:

This is because in this case potential energy is linear to height, which means that the higher the more potential energy.

Answer:

a = ½ ρ A/M   v₁²

Explanation:

This is a problem of fluid mechanics, where the jet of water at constant speed collides with a paddle, in this collision the water remains at rest, we write the Bernoulli equation, we will use index 1 for the jet before the collision the index c2 for after the crash

           P₁ + ½ ρ v₁² + ρ g h₁ = P₂ + ½ ρ v₂² + ρ g h₂

in this case the water remains at rest after the shock, so v₂ = 0, as well as it goes horizontally h₁ = h₂

          P₁-P₂ = ½ ρ v₁²

         ΔP = ½ ρ v₁²

let's use the definition of pressure as a force on the area

         F / A = ½ ρ v₁²

         F = 1/2 ρ A v₁²

the density is

          ρ = m / V

the volume is

           V = A l

           F = ½ m / l v₁²

knowing the force we can focus on the acceleration of the mass palette M

         F = M a

         a = F / M

          a = ½ m/M  1/l   v₁²

as well it can be given depending on the density of the water

          a = ½ ρ A/M   v₁²

Answer:

1. The electric potential at any point in space, is the work done in moving a unit charge from infinity to that point.

2.The electric potential varies radially by decreasing as the distance from the electric field increases.

Explanation:

1. The electric potential at any point in space, is the work done in moving a unit charge from infinity to that point. It is defined mathematically as, V = W/q where V = electric potential, W = work done in moving charge q into electric field and q = charge. For the work done of moving a charge q into an electric field of charge q' at a distance r between them, W = kqq'/r and work done per unit charge in moving q in electric field is V = W/q = kqq'/r ÷q = kq'/r, Also, for an electric field, E, V = ∫E.dr where r is the direction moved by the charge in the electric field.

2. Since the electric potential V = kq'/r, V ∝ 1/r since k and q' are constant. So, the electric potential varies radially by decreasing as the distance from the electric field increases.

Answer:radiation

Explanation:

radiation is the only one that makes sense

Answer:

a) 342 m/s

b) 51*10^-6 m/s

c) 0.87m/s^2

Explanation:

The following function describes the displacement of the molecules in a sound wave:

[tex]s(x,t)=3.00nm\ cos(50.00\ m^{-1}x-1.71*10^4s^{-1}t)[/tex]  (1)

The general form of a function that describes the same situation is:

[tex]s(x,t)=Acos(kx-\omega t)[/tex]   (2)

By comparing equations (1) and (2) you have:

k: wave number = 50.00 m^-1

w: angular frequency = 1.71*10^4 s^-1

A: amplitude of the oscillation = 3.00nm

a) The speed of the sound is obtained by using the formula:

[tex]v=\frac{\omega}{k}=\frac{1.71*10^4s^-1}{50.00m^{-1}}=342\frac{m}{s}[/tex]

b) The maximum speed of the molecules is the maximum value of the derivative of s(x,t), in time. Then, you first obtain the derivative:

[tex]\frac{ds}{st}=-\omega A sin(kx-\omega t)[/tex]

The max value is:

[tex]v_{max}=\omega A[/tex]

[tex]v_{max}=(1.71*10^4s^-1)(3.00nm)=51300\frac{nm}{s}=51\frac{\mu m}{s}[/tex] = 51*10^-6 m/s

c) The acceleration is the max value of the derivative of the speed, that is, the second derivative of the displacement s(x,t):

[tex]a=\frac{dv}{dt}=\frac{d^2s}{dt^2}=-\omega^2A cos(kx-\omega t)\\\\a_{max}=\omega^2 A[/tex]

Then, the maximum acceleration is:

[tex]a_{max}=(1.71*10^4s^{-1})^2(3.00nm)=0.87\frac{m}{s^2}[/tex]

Answer:

Mass velocity and radius are all related to centripetal force

Explanation:

By frequency of its rotation and the radius of the circular path along which objects moves

Expand each vector into their component forms:

[tex]\vec A=(4.5\,\mathrm N)(\cos\theta_A\,\vec\imath+\sin\theta_A\,\vec\jmath)=(2.58\,\vec\imath+3.69\,\vec\jmath)\,\mathrm N[/tex]

Similarly,

[tex]\vec B=(-1.23\,\vec\imath+0.860\,\vec\jmath)\,\mathrm N[/tex]

[tex]\vec C=(-3.44\,\vec\imath-4.91\,\vec\jmath)\,\mathrm N[/tex]

Then assuming the resultant vector [tex]\vec R[/tex] is the sum of these three vectors, we have

[tex]\vec R=\vec A+\vec B+\vec C[/tex]

[tex]\vec R=(-2.09\,\vec\imath-0.368\,\vec\jmath)\,\mathrm N[/tex]

and so [tex]\vec R[/tex] has magnitude

[tex]\|\vec R\|=\sqrt{(-2.09)^2+(-0.368)^2}\,\mathrm N\approx2.12\,\mathrm N[/tex]

and direction [tex]\theta_R[/tex] such that

[tex]\tan\theta_R=\dfrac{-0.368}{-2.09}\implies\theta_R=-170^\circ=190^\circ[/tex]

Answer:

bro i think ur from the uni of arid agriculture rawalpindi and today is your networking paper

Explanation:

Answer:

b

Explanation:

If a substance is boiled repeatedly and stirred, but the solute never mixes with the solvent then the chemical properties of the solute and solvent are different, therefore the correct answer is option B.

A chemical compound is a combination of two or more either similar or dissimilar chemical elements.

For example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.

As given in the problem a substance is boiled repeatedly and stirred, but the solute never mixes with the solvent,

The correct response is option B because the chemical characteristics of the solute and solvent are different if the material is repeatedly boiled and stirred without the solute and solvent mixing.

To learn more about a chemical compound, refer to the link ;

brainly.com/question/12166462

#SPJ6

Answer:

If one places ones's hands into a sink full of hot water, heat is transferred from the hot water to the hands. Heat only flows when there is a temperature gradient, i.e when there is a difference in temperature between a hot and a cold body. Heat is always transferred from a hot body to a cold body and never the reverse in a normal system.

At the boundary of the hand and water, heat transfer is by conduction between the hot water molecules and the molecules of the hands. This heat is then further transferred to the internal body organs and body fluid through either convection or conduction. This heat transfer is maintained until both the water and the hands are at the same temperature, assuming the owner is able to withstand the heat.

Answer:

a = d > b = c

Explanation:

The information about amplitudes and phase differences for four pairs of waves of equal wavelengths are given below:

(a) 2 mm, 6 mm, and π rad

(b) 3 mm, 5 mm, and π rad

(c) 7 mm, 9 mm, and π rad

(d) 2 mm, 2 mm, and 0 rad

Whenever a wave has zero phase difference, its amplitude of the resultant wave will be twice the amplitude of any of the two waves. Nevertheless, let assume that the amplitude is a vector having angle Ø between them. The resultant vector will help us rank the four pairs according to the amplitude of their resultant wave by using phasor diagrams.

a.) 6 - 2 = 4mm

b.) 5 - 3 = 2mm

c.) 9 - 7 = 2mm

d.) 2 + 2 = 4mm

Therefore,

a = d and b = c

a = d > b = c

Please find the attached file for the phasor diagrams

Answer:

1

Explanation:

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Answer:

(b) It is located the right distance from its star to enable liquid water to exist on its surface.

Explanation:

The habitable zone according to astronomy and astrobiology is a region around a star that the planets around the star can hold and support liquid water. For our solar system, the habitable zone coincides approximately with the distance from the sun to Earth.

Given:

To be calculated:

Calculate the acceleration of given object ?

Formula used:

Acceleration = v - u / t

Solution:

We know that,

Acceleration = v - u / t

☆ Substituting the values in the above formula,we get

Acceleration ⇒ 300 - 200 / 20

⇒ 100/20

⇒ 5 m/s²

Answer:

The phenomenon of beats is the result of sound interference and sound diffraction in periodic vibrations. In periodic vibration, the beats of sounds produced by the interference and diffraction of the waves of different frequencies.

Explanation:

Beats. When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - a phenomenon which is called "beating" or producing beats.

Answer:

a)  it is essential that the waves lurk coherently

b)the light passes through the slits, the relative phase between the two rays is due to the optical path difference of each one,

Explanation:

In double slit interference experiments it is essential that the waves lurk coherently, that is, that the relative phase of the waves that reaches each slit is maintained over time, this is achieved when point sources are used by passing light through a initial slit and if a laser is used it is already consistent at the output.

When the light passes through the slits, the relative phase between the two rays is due to the optical path difference of each one, when this path difference is equal to a whole number of donut lengths, it has constructive interference and if it is a number sowing we have destructive interference.

                   d sin θ = m λ                 constructive

                   d sin θ = (m + ½) λ         destructive

where d is the distance between the two slits, lam is the wavelength and m is an integer called the interference order

Answer:[tex]3.6\ kW[/tex]

Explanation:

Given

Power Supplied [tex][tex]P_{input}=4\ kW[/tex][/tex]

Efficiency of the motor [tex]\neta =90\%[/tex]

and [tex]\neta =\dfrac{\text{Power output}}{\text{Power input}}[/tex]

[tex]\Rightarrow 0.9=\dfrac{P_{out}}{4}[/tex]

[tex]\Rightarrow P=0.9\times 4[/tex]

[tex]\Rightarrow P=3.6\ kW[/tex]

So, vacuum cleaner delivers a power of [tex]3.6\ kW[/tex]

Answer:

T' = 0.9677T

Explanation:

The period of a pendulum is given by the following formula:

[tex]T=2\pi \sqrt{\frac{l}{g}}[/tex]

l: length of the pendulum

g: gravitational acceleration

If the length of the pendulum is decreased in 6.35% the length of the pendulum becomes:

[tex]l'=l-0.0635l=0.9365l[/tex]

The new period for a length of l' is:

[tex]T'=2\pi \sqrt{\frac{l'}{g}}=2\pi \sqrt{\frac{0.9365l}{g}}=\sqrt{0.9365}(2\pi \sqrt{\frac{l}{g}})=0.9677(2\pi \sqrt{\frac{l}{g}})\\\\T'=0.9677T[/tex]

hence, the new period is 0.9677T

Answer:

Explanation:

The magnitude of the electric force on this charged particle A depends upon the following

5. the distance between the point charge Q and the charged particle A

8. the amount of the charge on the point charge Q

9. the magnitude of charge on the charged particle A

Answer:

The velocity of the ions relative to the earth observer is  [tex]v = 0.63 c[/tex]

Explanation:

From the question  we are told that

     The speed of the alien ship is  [tex]v_a = 0.3c[/tex]

     The speed of the iron gun is  [tex]v_g = 0.4c[/tex]

The motion of the ions  relative to the earths observer can be mathematically represented as

       [tex]v = \frac{v_a + v_g}{[\frac{1+ v_av_g}{c^2} ]}[/tex]

substituting values

     [tex]v = \frac{ 0.3c + 0.4c}{[\frac{1+ 0.3c * 0.4c}{c^2} ]}[/tex]

 =>   [tex]v = 0.63 c[/tex]

Answer:

Time taken for trip = 12.74 hour (Approx)

Explanation:

Given:

Distance of trip = 710-mi

Average speed for the trip = 55.7 mi/h

Find:

Time taken for trip = ?

Computation:

⇒ Time = Distance / Speed

⇒ Time taken for trip = Distance of trip / Average speed for the trip

⇒ Time taken for trip = 710-mi / 55.7 mi/h

⇒ Time taken for trip = 12.74 hour (Approx)

Answer:

E = 0.5N/C

Explanation:

In order to calculate the magnitude of the electric field you use the following formula:

[tex]E=\frac{F}{q}[/tex]

q: charge = 5.0*10^-4 C

F: force on the charge = 2.5*10^-4N

You replace the values of q and F in the equation for E:

[tex]E=\frac{2.5*10^{-4}N}{5.0*10^{-4}C}=0.5\frac{N}{C}[/tex]

hence, the magnitude of the electric field at the position of the carge is 0.5N/C

At the location of the test charge, the magnitude will be:

"0.5 N/C".

Whenever charge seems to be available inside any form, an electric property has been linked among each spatial position. This same size and direction are represented either by the quantity of E.

According to the question,

Charge, q = 5.0 × 10⁻⁴ C

Force on the charge, F = 2.5 × 10⁻⁴ N

We know the relation of the magnitude of electric field be

→ E = [tex]\frac{F}{q}[/tex]

By substituting the values, we get

     = [tex]\frac{2.5\times 10^{-4}}{5.0\times 10^{-4}}[/tex]

     = 0.5 N/C

Thus the approach above is correct.

Find out more information about electric field here:

https://brainly.com/question/14372859

Answer:

It may turn into sedimentary rock when exposed to pressure.

Explanation:

When successive layer of sand is deposited on top of sand, the bottom layers go deeper and deeper. They are exposed to high pressures and temperatures and turn into hard rocks.

Answer:

Explanation:

capacitance of the capacitor C = 4πε₀R

= 1 x .103 / (9 x 10⁹ )  [ 1/ 4πε₀  = 9 x 10⁹ . ]

= .0114 x 10⁻⁹ F

potential  V = 4.5 x 10³ v

charge Q = CV

.0114 x 10⁻⁹  x 4.5 x 10³

= .0515 x 10⁻⁶ C

charge on one electron = 1.6 x 10⁻¹⁹

no of electrons to be removed

= .0515 x 10⁻⁶ / 1.6 x 10⁻¹⁹

= .032 x 10¹³

3.2 x 10¹¹ electrons.

Answer:

WT =  3.32*10^34 J

Explanation:

The work done by the gravitational attraction between the Sun and the Earth in one complete orbit of the Earth can be calculated by using the following formula:

[tex]W_T=\int F_g dr[/tex]  (1)

Fg: gravitational force between Sun and Earth

The gravitational force is given by:

[tex]F_g=G\frac{m_sm_e}{r^2}[/tex]  (2)

G: Cavendish's constant = 6.674*10^-11 m^3 kg^-1 s^-2

ms: mass of the sun = 1.989*10^30 kg

me: mass of the Earth = 5.972 × 10^24 kg

r: distance between Earth and Sun, this value is a constant r = R = 149,597,870 km

You replace the formula (2) in (1):

[tex]W_T=\int G\frac{m_sm_e}{R^2}dr=G\frac{m_sm_e}{R^2}\int dr\\\\W_T=G\frac{m_sm_e}{R^2}(2\pi R)=2\pi G\frac{m_sm_e}{R}[/tex]

Next, you replace the values of all variables and solve obtain WT:

[tex]W_T=2\pi (6.674*10^{-11}m^3kg^{-1}s^{-2})\frac{(1.989*10^{30}kg)(5.972*10^{24}kg)}{(149597870*10^3 m)}\\\\W_T=3.32*10^{34}J[/tex]

hence, the work done on the Earth, in one orbit, is 3.32*10^34 J

Answer:

Explanation:

Given that:

Heater temperature ,T₁ = 1000K

Vaccum Chamber ,T₂ = 300K

emissivity of heater E₁ = 0.75

emissivity vaccum E₂ = 0.25

Heater diameter d₁ = 10 * 10⁻³mm

vaccum chamber d₂ = 50 * 10⁻³mm

When there is vaccum, then no air resistance will be there,

F₁₂ = 1

F₁₁ = 0

[tex]R_1= \frac{1-E_1}{E_1A_1} \\\\=\frac{1-0.75}{0.75*\pi * 10^-^2*L}[/tex]

[tex]R_2=\frac{1}{F_1_2 * A_1} \\\\=\frac{1}{1* \pi *10^-^2*L}[/tex]

[tex]R_3=\frac{1-0.25}{F_1_2 * A_1} \\\\=\frac{1}{0.25* \pi *5*10^-^2*L}[/tex]

Heat leaving from heater surface 1 to vaccum

[tex]Q_1_2 = \frac{L \pi \sigma (T_1^4- T_2^4)}{R_1+R_2+R_3}[/tex]

[tex]Q_1_2 = \frac{1000*10^-^3*\pi * 5.67*10^-^8(1000^4-300^4)}{\frac{0.25}{0.75*10^-2}+\frac{1}{10^-2} +\frac{0.75}{0.25*10^-^2*5} }[/tex]

[tex]Q_1_2 = \frac{1000*10^-^3*\pi * 5.67*10^-^8(1000^4-300^4)} {0.3333+1+0.6}\\\\Q_1_2= 91.39 \text {watt}[/tex]

Answer:

Kinetic energy is the energy of motion

Answer:

Energy which a body possesses by virtue of being in motion

Explanation:

Answer:

a

The speed of the quarterback backward is [tex]v_q = 0.08 \ m/s[/tex]

b

Known are

 [tex]m_Q , m_B , (v_{Bx})_i (v_{Qx})_f, (v_{Bx})_f[/tex]

Unknown

   [tex](v_{Qx})_f[/tex]

Explanation:

From the question we are told that

   The mass of the quarterback is [tex]m_Q = 80 \ kg[/tex]

    The mass of the ball is [tex]m_B = 0.43 \ kg[/tex]

     The speed of the ball is  [tex]v_{B x}= 15 \ m/s[/tex]

The law of momentum conservation can be mathematically represented as

       [tex]m_Q u_{Qx} + m_Bu_{Bx} = - m_{Q} v_{Qx} + m_B v_{Bx}[/tex]

Now at initial both ball and quarterback are at rest and the negative sign signify that the quarterback moved backwards after throwing the ball

  So

       [tex]m_Q v_{Qx} = m_B v_ {Bx}[/tex]

=>     [tex]v_{Qx} = \frac{m_Bv_{Bx}}{m_Q}[/tex]

substituting values

        [tex]v_q = \frac{0.43 * 15}{80}[/tex]

       [tex]v_q = 0.08 \ m/s[/tex]