Answer:
F ∪ H = {c, d, e, f, g, h}
F ∩ H = { }
Step-by-step explanation:
The union is the list of elements that are in either of the two sets.
F ∪ H = {c, d, e, f, g, h}
The intersection is the list of only those elements that appear in both sets. (There are none.)
F ∩ H = { } . . . . the empty set
what is the slope of the line that contains the points (4 -1) and (-1,4)
Answer:
-1
Step-by-step explanation:
The slope formula when given two points is
m = ( y2-y1)/(x2-x1)
= (4 - -1)/(-1 -4)
= (4+1)/(-5)
= 5/-5
=-1
Answer:
-1
Step-by-step explanation:
Use the equation for slope.
[tex]m=\frac{y_{2}-y_{1} }{x_{2}- x_{1} }[/tex]
Plug in the given points into the equation.
[tex]m=\frac{4-(-1) }{-1- 4 }\\m=\frac{4+1 }{-5 }\\m=\frac{5}{-5 }\\m=\frac{1}{-1 }\\m=-1[/tex]
The slope is -1.
A padaria Beira Baixa vem perdendo dinheiro com a sua política de produção de venda do pãozinho francês. Atualmente, a cada dia é feita uma quantidade igual à procura do dia anterior. O proprietário, Sr. Joaquim, recolheu os seguintes dados:
Lucro na venda= $ 0,20 por unidade
Perda no pão não vendido = $ 0,05
(os pães não vendidos são moídos e vendidos como farinha de rosca: cada pão equivale a $0,15 de farinha de rosca)
Distribuição de frequência da demanda diária. Quantos pães devem ser fabricados diariamente para maximizar o lucro médio do Sr. Joaquim
1000 0,10
1100 0,10
1200 0,10
1300 0,15
1400 0,20
1500 0,15
1600 0,10
1700 0,05
1800 0,05
Answer:
The number of loaves to be made daily to maximize Mr. Joaquim's average profit is 1400.
O número de pães a serem feitos diariamente para maximizar o lucro médio do Sr. Joaquim é 1400.
Step-by-step explanation:
The table gives the daily demand of bread and the average profit that corresponds to each demand.
The daily demand values recorded ranged from 1000 to 1800.
And the corresponding average profit for the demands for each daily demand provided showed a steady increase from $0.10 as at a daily demand of 1000, through $0.15, then peaking at $0.20 at a daily demand of 1400.
After this point, the average profit begins to decline again as we move further away from the peak obtained at a daily demand of 1400.
Hence, it is evident that the daily demand that corresponds to the maximum average profit is 1400.
A daily demand of 1400 is where the peak average profit of $0.20 is obtained.
Any other demand lower or higher than 1400 corresponds to a departure from the peak profit obtained at that point according to the table of daily demand and average profits provided in the question.
In portugese/Em português
A tabela fornece a demanda diária de pão e o lucro médio que corresponde a cada demanda.
Os valores diários de demanda registrados variaram de 1000 a 1800.
E o lucro médio correspondente às demandas de cada demanda diária fornecida mostrou um aumento constante de US $ 0,10, com uma demanda diária de 1000, passando por US $ 0,15, atingindo um pico de US $ 0,20 com uma demanda diária de 1400.
Após esse ponto, o lucro médio começa a declinar novamente à medida que nos afastamos do pico obtido com uma demanda diária de 1400.
Portanto, é evidente que a demanda diária que corresponde ao lucro médio máximo é de 1.400.
Uma demanda diária de 1400 é onde é obtido o lucro médio máximo de US $ 0,20.
Qualquer outra demanda menor ou maior que 1400 corresponde a um afastamento do pico de lucro obtido nesse momento, de acordo com a tabela de demanda diária e lucros médios fornecidos na pergunta.
Hope this Helps!!!
Espero que isto ajude!!!
Want Brainliest? Get this correct , Which rule should be applied to reflect f(x) = x^3 over the y-axis?
Answer:
B
Step-by-step explanation:
When you flip over the y-axis you the x is multiplied by -1
OMG THIS QUESTION IS SO HARD WILL RATE IF U GET IT
Answer:
the answer is 290
Step-by-step explanation:
A = 2(wl + hl + hw)
Answer:
Step-by-step explanation:
This is a pretty easy one. Use the equation SA=2lw+2lh+2hw and substitute in the length, width, and height. Substitute than solve and you get 290 in^2
Which shapes can the composite figure be decomposed into? Check all that apply.
Answer:
rectangle ,triangle ,trapezoid ,octagon ..
The estimator Yis a random variable that varies with different random samples; it has a probability distribution function that represents its sampling distribution, and mean and variance. Using the properties on expected values and variances of linear functions of random variables and sum operators, show that:
A. E(Y) = μ
B. Var(Y) σ2/N.
Answer:
Check Explanation
Step-by-step explanation:
According to the Central limit theorem, the population mean (μ) is approximately equal to the mean of sampling distribution (μₓ).
And the standard deviation of the sampling distribution (σₓ) is related to the population standard deviation (σ) through
Standard deviation of the sampling distribution = (Population standard deviation)/(√N)
where N = Sample size
σₓ = (σ/√N)
So, population mean (μ) = Mean of sampling distribution (μₓ)
Population Standard deviation = (Standard deviation of the sampling distribution) × √N
= σ × √N
A) The expected value of a given distribution is simply equal to the mean of that distribution.
Hence, the expected value of random variable Y thay varies with different samples is given as
E(Y) = Mean of sampling distribution = μₓ
But μₓ = μ
Hence, E(Y) = μ (Proved)
B) Var (Y) is given as the square of the random distribution's standard deviation.
Var (Y) = (standard deviation of the sampling distribution)²
= (σ/√N)²
= (σ²/N) (Proved)
Hope this Helps!!!
a cell phone company test 95 cell phones and finds that seven of them have defects out of the 760 cell phones how many would you expect to have defects
Answer:
56
Step-by-step explanation:
simple ratio: 7/95 = x/760
first, calculate 7/95 which is 0.0736
next, multiply that by 760, which would be 56
A consumer agency is investigating the blowout pressures of Soap Stone tires. A Soap Stone tire is said to blow out when it separates from the wheel rim due to impact forces usually caused by hitting a rock or a pothole in the road. A random sample of 29 Soap Stone tires were inflated to the recommended pressure, and then forces measured in foot-pounds were applied to each tire (1 foot-pound is the force of 1 pound dropped from a height of 1 foot). The customer complaint is that some Soap Stone tires blow out under small-impact forces, while other tires seem to be well made and don't have this fault. For the 29 test tires, the sample standard deviation of blowout forces was 1358 foot-pounds.
(a) Soap Stone claims its tires will blow out at an average pressure of 26,000 foot-pounds, with a standard deviation of 1020 foot-pounds. The average blowout force is not in question, but the variability of blowout forces is in question. Using a 0.1 level of significance, test the claim that the variance of blowout pressures is more than Soap Stone claims it is.
Classify the problem as being a Chi-square test of independence or homogeneity, Chi-square goodness-of-fit, Chi-square for testing or estimating σ2 or σ, F test for two variances, One-way ANOVA, or Two-way ANOVA, then perform the following.
(ii) Find the sample test statistic. (Use two decimal places.)
(iii) Find the P-value of the sample test statistic. (Use four decimal places.)
(b) Find a 99% confidence interval for the variance of blowout pressures, using the information from the random sample. (Use one decimal place.)
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: Impact force needed for Sap Stone tires to blow out. (foot-pounds)
n= 29, S= 1358 foot-pound
a)
Soap Stone claims that "The tires will blow out at an average pressure of μ= 26000 foot-pounds with a standard deviation of σ= 1020 foot-pounds.
According to the consumer's complaint, the variability of the blown out forces is greater than the value determined by the company.
I)
Then the parameter of interest is the population variance (or population standard deviation) and to test the consumer's complaint you have to conduct a Chi-Square test for σ².
σ²= (1020)²= 1040400 foot-pounds²
H₀: σ² ≤ 1040400
H₁: σ² > 1040400
α: 0.01
II)
[tex]X^2= \frac{(n-1)S^2}{Sigma^2} ~~X^2_{n-1}[/tex]
[tex]X^2_{H_0}= \frac{(n-1)S^2}{Sigma^2}= \frac{(29-1)*(1358)^2}{1040400} = 49.63[/tex]
III)
This test is one-tailed to the right and so is the p-value. This distribution has n-1= 29-1= 28 degrees of freedom, so you can calculate the p-value as:
P(X²₂₈≥49.63)= 1 - P(X²₂₈<49.63)= 1 - 0.99289= 0.00711
⇒ The p-value is less than the significance level so the test is significant at 1%. You can conclude that the population variance of the blowout forces is less than 1040400 foot-pounds², at the same level the population standard deviation of the blow out forces is less than 1020 foot-pounds.
b)
99% CI for the variance. Using the X² statistic you can calculate it as:
[tex][\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ][/tex]
[tex]X^2_{n-1;\alpha /2}= X^2_{28; 0.005}= 13.121[/tex]
[tex]X^2_{n-1;1-\alpha /2}= X^2_{28; 0.995}= 49.588[/tex]
[tex][\frac{28*(1358)^2}{49.588} ;\frac{28*(1358)^2}{13.121} ][/tex]
[1041312.253; 3935415.898] foot-pounds²
I hope this helps!
looking for the 2 correct answers please
Answer:
ROQQOPStep-by-step explanation:
The sine of an angle is equal to the cosine of its complement, and vice versa.
sin ∠QOP = cos ∠ROQ
cos ∠ROQ = sin ∠QOP
what is 1+1, this is for you to get points.
Answer:
2
Step-by-step explanation:
1+1 = 2
Hope this helps;)
Answer:
1 + 1 =2
Step-by-step explanation:
Hi, how are you?
Do u want to be my friend?
Also, I hope this answered your question?
A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weight is known to be normal, with a standard deviation of 0.4 ounces. A random sample of 25 boxes yielded a sample mean weight of 19.87 ounces. Test at the 1% significance level the null hypothesis that the population mean weight is at least 20 ounces.
Answer:
[tex]z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625[/tex]
The p value for this case would be given by:
[tex]p_v =P(z<-1.625)=0.052[/tex]
Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.
Step-by-step explanation:
Information provided
[tex]\bar X=19.87[/tex] represent the sample mean
[tex]\sigma=0.4[/tex] represent the population deviation
[tex]n=25[/tex] sample size
[tex]\mu_o =68[/tex] represent the value that we want to test
[tex]\alpha=0.01[/tex] represent the significance level
z would represent the statistic
[tex]p_v[/tex] represent the p value
Hypothesis to test
We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:
Null hypothesis:[tex]\mu \geq 20[/tex]
Alternative hypothesis:[tex]\mu < 20[/tex]
The statistic is given by:
[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)
Replacing the info given we got:
[tex]z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625[/tex]
The p value for this case would be given by:
[tex]p_v =P(z<-1.625)=0.052[/tex]
Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.
You plan to purchase dental insurance for your three remaining years in school. The insurance makes a​ one-time payment of ​$1200 in case of a major dental repair​ (such as an​ implant) or a​ one-time payment of ​$160 in case of a minor repair​ (such as a​ cavity). If you​ don't need dental repair over the next 3​ years, the insurance expires and you receive no payout. You estimate the chances of requiring a major repair over the next 3 years as 6​%, a minor repair as 59​% and no repair as 35​%. Complete parts a through c.
Required:
a. Why is X= payout of dental insurance a random variable?
A. The amount of the payout for major, mincr, or no dental repair varies over the next 3 years.
B. The probability of needing major, minor or no dental repair over the next 3 years is estimated.
C. The probability of needing major, minor, or no dental repair over the next 3 years varies.
D. The value of the payout depends on whether you will need major, minor, or no dental repair over the next 3 years.
b. Is X discrete or continuous? What are its possible values?
c. Give the probability distribution of X
Answer:
(a)D. The value of the payout depends on whether you will need major, minor, or no dental repair over the next 3 years.
(b)Discrete
(c) See below
Step-by-step explanation:
For a major dental repair, the insurance company pays $1200For a minor dental repair, the insurance company pays $160For no dental repair, the insurance company pays $0(a) X= payout of dental insurance a random variable
The payout of dental insurance, X is a random variable because the value of the payout depends on whether you will need major, minor, or no dental repair over the next 3 years. The correct option is D.
(b) X is a discrete variable. This is because its values are whole numbers.
The possible values are $1200, $160 and $0.
(c)
The probability of requiring a major dental repair (with payout of $1200) is 6%.The probability of requiring a minor dental repair (with payout of $160) is 59%.The probability of requiring no dental repair (with payout of $0) is 35%.Therefore, the probability distribution of X is given below:
[tex]\left|\begin{array}{c|c|c|c}--------------&---&---&---\\X$(Payout of dental insurance)&\$1200&\$160&\$0\\--------------&---&---&---\\P(X)&0.06&0.59&0.35\\--------------&---&---&---\end{array}\right|[/tex]
The square rootof which number is rational a7. b 1.96. c. 0.04. d. 13
Answer:
B and C
Step-by-step explanation:
We need to find which one of these numbers is a perfect square. We know 7 and 13 can be eliminated since they're prime numbers so they can't be perfect squares. B and C are both perfect squares so that's the answer.
Answer:
B and C
Step-by-step explanation:
7 = 7
1.96 = [tex]\frac{196}{100}[/tex]
0.04 = [tex]\frac{4}{100}[/tex]
13 = 13
Type the correct answer in the box. Spell all words correctly.
Which term describes the solution to a multiplication problem?
The
describes the solution to a multiplication problem.
Answer:
product is right
Step-by-step explanation:
Find the value of -1/3-(-5/12)
According to the image whats the answer? 80 points brainliest
Answer:
Hey!
Your answer is 150 square meters!
Step-by-step explanation:
13*3=39 (the tilted face)
12*3=36 (the flat face)
5*3=15 (the base)
TO FIND THE TRINGLULAR AREA:
1/2 base x height...
1/2 x 5 x 12 = 30
(WE DOUBLE THIS BECAUSE THERE ARE TWO TRIANGLES)
SO 60...
ADD THESE TOGETHER...
39 + 36 + 15 + 30 + 30...
GIVES US 150 square metres
HOPE THIS HELPS!!Answer:
150 square meters
Step-by-step explanation:
Determine whether b can be written as a linear combination of Bold a Subscript Bold 1a1, Bold a Subscript Bold 2a2, and Bold a Subscript Bold 3a3. In other words, determine whether weights x 1x1, x 2x2, and x 3x3 exist, such that x 1x1Bold a Subscript Bold 1a1plus+x 2x2Bold a Subscript Bold 2a2plus+x 3x3Bold a Subscript Bold 3a3equals=b. Determine the weights x 1x1, x 2x2, and x 3x3 if possible.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b can be written as a linear combination of [tex]a_1 \ and \ a_2[/tex]
b
The values of [tex]x_1 = 4 \ and \ x_2 = 2[/tex]
Step-by-step explanation:
From the question we are told that
[tex]x_1 a_1 +x_2 a_2 = b[/tex]
Where [tex]a_ 1 = (4, 5,-4)[/tex], [tex]a_2 = (-4 , 3, 3)[/tex] and [tex]b = (8,26 , -10)[/tex]
So
[tex]x_1 ( 4, 5,-4) + x_2 (-4 , 3, 3) = (8,26 , -10)[/tex]
[tex]4x_1, 5x_1,-4x_1 + -4x_2 , 3x_2, 3x_2 = (8,26 , -10)[/tex]
=> [tex]4x_1 -4x_2 =8[/tex]
[tex]x_1 -x_2 =2 ---(1)[/tex]
=> [tex]5x_1 + 3x_2 = 26 --- (2)[/tex]
=> [tex]-4x_1 + 3x_2 = -10 ---(3)[/tex]
Now multiplying equation 1 by 3 and adding the product to equation 2
[tex].\ \ \ 3x_1 -3x_2 = 6\\+ \ \ 5x_1 + 3x_2 = 26 \\=> \ \ \ 8x_1 = 32[/tex]
=> [tex]x_1 = 4[/tex]
substituting [tex]x_1[/tex] into equation 1
[tex]4 - x_2 =2[/tex]
[tex]x_2 =2[/tex]
Now to test substitute [tex]x_1 \ and \ x_2[/tex] into equation 3
[tex]-4(4) + 3(2) = -10[/tex]
[tex]-10 = -10[/tex]
Since LHS = RHS then there exist values [tex]x_1 = 4 \ and \ x_2 = 2[/tex] such that
[tex]x_1 a_1 +x_2 a_2 = b[/tex]
Hence b can be written as a linear combination of [tex]a_1 \ and \ a_2[/tex]
What is the quadratic formula?
Answer:
The quadratic formula is x= -b±√b²-4ac all over 2a
Step-by-step explanation:
The -b±√b²-4ac is part of the numerator of the fraction. And b²-4ac is all under the radical sign. The denominator is 2a so you divide -b±√b²-4ac by 2a to get the solutions of the quadratic function. Hope this helps!!
Please answer this correctly
Answer:
2198
Step-by-step explanation:
10×10×3.14=314
314×7
Convert 8.25% to a decimal
Answer: 0.0825
Step-by-step explanation:
8.25% to decimal is simply divide 8.25 by 100
8.25/100= 0.0825
The required solution after convert it into decimal is,
⇒ 0.0825
We have to given that,
Convert 8.25% into a decimal.
We can change it as,
⇒ 8.25%
Since, 1% = 1/100
Hence,
⇒ 8.25/100
⇒ 0.0825
Therefore, After convert it into decimal number solution is,
⇒ 0.0825
Learn more about the percent visit:
https://brainly.com/question/24877689
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Pedro is selling candy bars for his school baseball team each candy bar cost 1.25 and a box contains 20 bars
Answer:
$25
Step-by-step explanation:
You do 1.25. Y 20
In a study, 37% of adults questioned reported that their health was excellent. A researcher wishes to study the health of people living close to nuclear plant. Among 12 adults randomly selected from this area, only 3 reported that their health was excellent. Find the probability that when 12 adults are randomly selected, 3 or fewer are in excellent health.
Answer:
The probability that when 12 adults are randomly selected, 3 or fewer are in excellent health is 0.2946
Step-by-step explanation:
BIONOMIAL DISTRIBUTION
pmf of B.D is = f ( k ) = ( n k ) p^k * ( 1- p) ^ n-k
where
k = number of successes in trials
n = is the number of independent trials
p = probability of success on each trial
I.
mean = np
where
n = total number of repetitions experiment is excueted
p = success probability
mean = 12 * 0.37
= 4.44
II.
variance = npq
where
n = total number of repetitions experiment is excueted
p = success probability
q = failure probability
variance = 12 * 0.37 * 0.63
= 2.7972
III.
standard deviation = sqrt( variance ) = sqrt(2.7972)
=1.6725
the probability that when 12 adults are randomly selected, 3 or fewer are in excellent health
P( X < = 3) = P(X=3) + P(X=2) + P(X=1) + P(X=0)
= ( 12 3 ) * 0.37^3 * ( 1- 0.37 ) ^9 + ( 12 2 ) * 0.37^2 * ( 1- 0.37 ) ^10 + ( 12 1 ) * 0.37^1 * ( 1- 0.37 ) ^11 + ( 12 0 ) * 0.37^0 * ( 1- 0.37 ) ^12
= 0.2947
Benson asked a group of 9th, 10th, 11th, and 12th graders the
number of hours they work per week in the summer. The means of
each group are provided below:
9th: 14.2 hours
10th: 18.8 hours
11th: 21.2 hours
12th: 24.9 hours
Which conclusion can be made from this data?
Answer:
YlThe higher the grader the more hours they can work.
Step-by-step explanation:
We can see that the higher the grader the more hours they can work ; which could mean less academic work if the work defined is that with which to earn money but if the work defined is academic it means more hours of academic work
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
Weights of Dogs in Shelter A
6
8
10
12
14
16
18
20
22
24
26
28
30
Weights of Dogs in Shelter B
Which describes the spread of the data in the two box plots?
O
The data in shelter A show more spread than the data in shelter B.
The data in shelter B show more spread than the data in shelter A
The data in shelter A range from about 17 to 28, while the data in shelter B range from about 16 to 20
The data in shelter A range from about 21 to 28, while the data in shelter B range from about 18 to 20.
Answer:
The data in shelter A show more spread than the data in shelter B.
Step-by-step Explanation:
Judging from the data set given for shelter A and shelter B in the diagram of the box plots attached below, shelter A has a data set that ranges from 8 pounds to 30 pounds, while shelter B ranges from e can infer that the data in shelter A has more spread than the data in shelter B ranges from 10 to 28.
Taking into consideration the range of the data set of each shelter, shelter A obviously has a larger range compared to shelter B. This implies that, the data in shelter A show more spread than the data in shelter B.
Answer:
A
Step-by-step explanation:
Please answer this correctly
Answer:
h = 20
Step-by-step explanation:
These two shapes are similar, so you can set up a proportion like so:
[tex]\frac{72}{45} =\frac{32}{h}[/tex]
→Cross multiply:
[tex]\frac{72h}{1440}[/tex]
→Divide 1440 by 72:
h = 20
Find the sample space for a committee of two chosen from Alice (A), Bill (B), Carol (C), and David (D).
A. {(A, B), (C, D)}
B. {A, B, C, D}
C. {(A, B), (A, C), (A, D), (B, C), (B, D), (C, D)}
D. {(A, B), (A, D), (B, C), (C, D)}
Find the sample space if both sexes must be represented.
A. {(A, B), (A, C), (A, D), (B, C), (B, D), (C, D)}
B. {(A, B), (C, D)}
C. {(A, B), (A, D), (B, C), (C, D)}
D. {A, B, C, D}
Answer:
(a) C. {(A, B), (A, C), (A, D), (B, C), (B, D), (C, D)}
(b) C. {(A,B),(A,D),(B,C),(C,D)}
Step-by-step explanation:
Given four members eligible for selection:
Alice (A), Bill (B), Carol (C), and David (D).
The possible combinations are:
(A,B),(A,C),(A,D),(B,A),(B,C),(B,D),(C,A),(C,B),(C,D), (D,A),(D,B), (D,C)
Part A
Since the same pairs are equal i.e. (A, B)=(B , A),
The Sample space for a committee of two is:
{(A,B),(A,C),(A,D),(B,C),(B,D),(C,D)}
This is Option C.
Part B
If both genders must be represented, we remove the entries that contain the same gender from the sample space above.
A and C -Female
B and D - Male
{(A,B),(A,C),(A,D),(B,C),(B,D),(C,D)}
Therefore, the sample space if both genders are to be represented is:
{(A,B),(A,D),(B,C),(C,D)}
This is Option C.
Answer:
1. A
2. C
Not 100% sure but its my best guess
Rachel is conducting a study in her cognitive psychology lab about people's ability to remember rhythms. She played
a short rhythm to 425 randomly chosen people. One minute later, she asked them to repeat it by clapping. If 121
people were able to successfully reproduce the rhythm, estimate the proportion of the population (including margin
of error) that would be able to successfully reproduce the rhythm.
Answer:
Rachel can conclude that 28% were able to successfully reproduce the rhythm plus or minus 5.6%
Step-by-step explanation:
To find the sample proportion that is able to successfully reproduce the rhythm = 121/425 = 0.2847 = p
Using this formula, we can calculate the margin of error
Margin of error = z*√{[p (1-p)] / n}
Where we assume a 95% level of confidence so that z* = 1.96. since one is not given, p = 0.28457 and n = 245.
Margin of error = 1.96 x √(0.28457 (1-0.28457)] / 245}
Margin of error = 1.96 x √[(0.28457 (0.7154)] / 245
= 1.96 x √(0.20/245)
= 1.96 x √0.000816
= 1.96 x 0.03
= 0.056.
Thus, Rachel can conclude that 28% were able to successfully reproduce the rhythm plus or minus 5.6%
Can someone help me on this question please
Answer:
about 11.11%, or 4/36
Step-by-step explanation:
Answer:
1/9
Step-by-step explanation:
There are 4 possible ways to get a sum of 5 out of total ways of 6*6= 36
So the probability of getting sum of 5 is 4/36= 1/9
what is an equation of the line that passes through the point (-3,-1) and is perpendicular to the line y=1/2x - 3
Answer:
Step-by-step explanation: gradient of perpendicular line is
-2
y+1/x+3=-2
y+1=-2x-6
y=-2x-7
What is the solution to the following system?
a
x+y+z= 6
X-Y+Z= 8
X+y-Z=0
Answer:
x= 4
Y= -1
Z= 3
step by step procedure:
let x+y+z=6, x-y+z=8, x+y-z=0 be equations 1, 2, and 3 respectively.
subtract equation 2 from equation 1 ; x+y+z-(x-y+z) = 6 - 8 y+y = -2 , 2y = -2, therefore y = -1substituting the value of y into equations 1, 2, and 3 . we get x+z=7---eqn 4, x+z=7---eqn 5 and x-z=1---eqn 6now add equation 6 to equation 5 ; x+z+(x-z)=7+1 ,x+x=7+1, 2x=8, therefore x=4put the value of x (x=4) back into equation 5; 4+z=7, z=7-4, therefore z=3.you are welcome bro....