The ratio of Michaels's points on an English test to Paloma's points on the same test is 12:11. The ratio of Michaels's points on the English test on the same test was 4:3. the 3 students score a total of 224 points on the same test. What is the difference between Palomas and Antons' points on the English test? Try to explain fully, if possible. Thank you SO MUCH!

Answer:

The basic way to calculate the number of members is finding the area under the curve. The total members are 20

Step-by-step explanation:

The given graph shows that how many team members have a particular weight.

The first rectangle shows that 5 team members have a weight of 115kg.

The second rectangle shows that 3 team members have a weight of 115kg.

The third rectangle shows that 2 team members have a weight of 115kg.

The forth rectangle shows that 0 team members have a weight of 115kg.

The fifth rectangle shows that 3 team members have a weight of 115kg.

The sixth rectangle shows that 4 team members have a weight of 115kg.

The seventh rectangle shows that 3 team members have a weight of 115kg.

So, the total team members are = 5 + 3 + 2 + 0 + 3 + 4 + 3 = 20

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Answer:

The answer is true!!!

Step-by-step explanation:

If m=100, 100-63=37 which is true.

Answer:

26

Step-by-step explanation:

Define the variables:

Given information:

Create an inequality from the defined variables and the given information:

⇒ 2(2n + 2n + 2) > 94

Solve the inequality:

⇒ 2(4n + 2) > 94

⇒ 8n + 4 > 94

⇒ 8n > 90

⇒ n > 11.25

Therefore:

As 2n and 2n+2 are even numbers:

Therefore, the smallest possible value of the larger number is 26.

Using the vertex of a quadratic function, it is found that:

a) The revenue is maximized with 336 units.

b) The maximum revenue is of $56,448.

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The vertex is given by:

[tex](x_v, y_v)[/tex]

In which:

Considering the coefficient a, we have that:

The demand function is given by:

p(x) = 336 - 0.5x.

Hence, the revenue function is:

R(x) = xp(x)

R(x) = -0.5x² + 336x.

Which has coefficients a = -0.5, b = 336.

Hence, the value of x that maximizes the revenue, and the maximum revenue, are given, respectively, as follows:

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Answer:

If Nardia is N and Pierre is P an equation that would represent this problem is 52-3n=p

Answer:

Step-by-step explanation:

Answer:

x=20

Step-by-step explanation:

80^1/4x

or,80/4=x

or,20=x

•°•x=20

ans

Answer: 0.88 (the 8 recurs)

Step-by-step explanation:

[tex]\frac{4}{9}[/tex]÷[tex]\frac{1}{2}[/tex]

[tex]\frac{4}{9}[/tex]×[tex]\frac{2}{1}[/tex]  (Then the the fraction should reciprocal so the values should shift to          the opposite side were 2 goes up and 1 goes down and the sign turns to the multiplication sign)

then u should multiply the two fractions which gives 8/9

next you should divide 8 by 9 which gives 0.88(the number eight is recurring which means that the number 8 keeps repeating no matter how many times you try to divide)

Given the polynomial f(x)=x³+5x²+2x-8 and f(1)=0.

Factorization is the process of determining the components of a given value or mathematical statement. The integers that are multiplied to create the original number are known as factors. The components of 18 include, for instance, 2, 3, 6, 9, and 18, as well as;

18 = 2 x 9

18 = 2 x 3 x 3

18 = 3 x 6

In a similar way, the factors in the case of polynomials are the polynomials that are multiplied to create the original polynomial. For instance, (x + 2) (x + 3) are the elements of x2 + 5x + 6. The original polynomial is produced when we multiply both x +2 and x +3. We can also locate the polynomials' zeros after factorization. Zeroes in this situation are x = -2 and x = -3.

2. Now, to write f(x) as the product of (x-1) and another factor.

x³+5x²+2x-8 = (x-1)(x²-6x+8).

3. Now, to write f(x) as the product of three linear factors.

x³+5x²+2x-8 = (x-1)(x²-6x+8)= (x-1)(x-4)(x-2)

4. Look at the sketch below.

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Answer: it's D

Step-by-step explanation:

Answer:

36 ft^2

Step-by-step explanation:

Perimeter = 4 + 4 + 2 +2 = 12 feet

  12 feet x 3 feet high = 36 ft^2

The equation of line is y = 92x – 182631. The slope is 92 and the y-intercept is the negative 182631. And the health expenditure in 2010 will be 2289.

Suppose the given points are (x₁, y₁) and (x₂, y₂), then the equation of the straight line joining both two points is given by

[tex]\rm (y - y_1) = \left [ \dfrac{y_2 - y_1}{x_2 - x_1} \right ] (x -x_1)[/tex]

In MODE, (second line), fix the number of decimal places to be 2.

Then the slope and the y-intercept values of the Lin Reg line will round to the nearest hundredth.

(x₁, y₁) → (1997, 1093)

(x₂, y₂) → (2002, 1553)

Then we have

y – 1093 = [(1553 – 1093) / (2002 – 1997)] (x – 1997)

y – 1093 = [460  / 5] (x – 1997)

y – 1093 = 92 (x – 1997)

           y = 92x – 182631

If x = 2010, then the value of y will be

y = 92 × 2010 – 182631

y = 184920 – 192631

y = 2289

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3.5

The triangle shown is a 30-60-90 special right triangle. All right triangles that have a 30-degree angle will be, but if needed you can use the equation: 180 - (90 + 30) = x, to find the missing angle.

Special Right Triangles

Special right triangles are useful because they allow us to easily find missing sides without having to use sin, cos, or tan. All special right triangles have formulas that can be used to find missing sides.

Formulas

30-60-90 triangles have 3 sides: the hypotenuse (c), the short leg (b), and the long leg (a).

The formulas are as follows:

Solving for b

We are already given c, so the easiest way to find b is to use the formula b = 0.5c. Just plugin the c-value.

Once simplified the final answer is

The probability of student A is 15/44

Given student A is 70% of time and student B is 60% of time

We need to find the probability of student A

Using formula of conditional probability is P(X/Y) = P(X and Y) / P(Y)

Here X = A and Y = A or B

Therefore,

P(A/A or B) = P(A and (A OR B) / P (A or B)

Now, There is none complement for at least 1

We know that Student A attends 70 % of time

So , his absence is 30% of the time .

Hence the probability of absence is 0.3

Now Considering B in the similar way

We get,

Probability of the absence is 0.4

They are both absent (0.3)(0.4)= 0.12

Here we can say that 12 % of time both are absent

So one or another present on that time is 88%

The probability of present of the time is 0.88

Now calculating the probability,

P(A/A or B) = P(A and (A OR B) / P (A or B)

= 0.3/0.88

= 30/88

= 15/44

Hence the Probability Of A is 15/44

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Step-by-step explanation:

the answer will be zero 0

Answer:

a^12+8

Step-by-step explanation:

let's check all the expressions

1. a^3+18

here 18 is not a perfect cube.

2. a^6+9

here 9 is not a perfect cube.

3. a^9+16

here 16 is not a perfect cube.

4. a^16+8

here 8 is a perfect cube, thus we can write above expression by using laws of exponents as

(a^4)^3+2^3

Thus,  is a sum of cubes.

a^12+8

Answer:

a = 46. Look down to find out more↓:

Step-by-step explanation:

a = kb²

4 = k(3)²

4 = k9

k = 4/9

a = 4/9(9²)

a = 4/9 (81)

a = 324/9

a = 36

7.7278 g/ml is the most accurate density of the substance.

It is define as the quantity per unit volume, unit area, or unit length.

i.e. the mass of a substance per unit volume.

Mathematically,

[tex]\rho =\frac{m}{v}[/tex]       ----- equation  (1)

Where,

p is the density

m is the mass

v is the volume

According to the question,

Mass = 27.82 grams  

Volume = 3.6 ml

By substituting the Value of m and v in equation 1.

[tex]\rho =\frac{27.82}{3.6}[/tex]

[tex]\rho = 7.7277777 g/ml[/tex]

Therefore,

The most accurate density of the substance in g/ml is  7.7277777 g/ml.

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The equation of the hyperbola with a given origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0) is  [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

Given, that a hyperbola centred at the origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0)

In mathematics, a hyperbola is a type of smooth curve lying in a plane, defined by its geometric properties or by equations for which it is the solution set. A hyperbola has two pieces, called connected components or branches, that are mirror images of each other and resemble two infinite bows.

The formula for a hyperbola centred at the origin is [tex]\frac{x^2}{a^2} -\frac{y^2}{b^2 } =1[/tex]

The vertices are located at (±a, 0), so we have that the value of a is [tex]\sqrt{61}[/tex].

The foci are located at (±c, 0), where [tex]c^2 = a^2 + b^2[/tex].

So if we have that [tex]c = \sqrt{98}[/tex], we can find the value of b:

[tex]98 = 61 + b^2[/tex]

⇒ [tex]b^2 = 37[/tex]

⇒ [tex]b = \sqrt{37}[/tex]

So, the formula for this hyperbola is [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

Therefore, the equation of the hyperbola with a given origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0) is  [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

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Answer:

$72

Step-by-step explanation:

Sue's estimate is best because she throws it more times than Eric. Regarding the probability of Aadi obtaining tails, Statement C is accurate.

The chances of an event occurring are defined by probability. Probability has several uses in games, and in business to create probability-based forecasts.

Ten biased coin throws are made by Eric. He is dealt 3 tails. Sue tosses a coin 50 times. I give her 20 tails.

Aadi will only toss the coin once. Regarding the probability of Aadi obtaining tails.

Sue's estimate is best because she throws it more times than Eric.

Hence option C is correct.

2)

An estimate for the likelihood that Aadi will receive tails using the findings of Eric and Sue. 3/20 will be the fraction of the form a/b.

The probability of the Aadi getting tails;

P(Aadi) = 3 / 360 = 1/120

P(Sue) = 20/50×36 = 1/90

Hence the fraction in the form of a/b willl be 4/3.

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Answer:

[tex]x=\pm3\sqrt{2}[/tex]

Step-by-step explanation:

1) Add 25 to both sides.

[tex]x^2 = -7 + 25[/tex]

2) Simplify -7 + 25 to 15.

[tex]x^2=18[/tex]

3) Take the square root of both sides.

[tex]x=\pm18[/tex]

4) Simplify [tex]\sqrt{18}[/tex] to [tex]3\sqrt{2}[/tex].

[tex]x=\pm3\sqrt{2}[/tex]

To answer this question, we need to know what absolute value is in the first place. ANSWERS ARE AT THE BOTTOM.

Absolute value represents how far something is from 0 in a number line.

For example, lets take 4.

4 is 4 units away from 0 on the number line, so the absolute value of 4 is 4.

Now lets look at another example, -4. -4 is also 4 units away from 0, just in the other direction. However, when calculating absolute value, we do not care about the direction. Therfore, the absolute value of -4 is also 4.

Now let's look at your problem.

You want the absolute value of 0 and -4/5

Following the same principle above about the distance from 0, here are your answers:

Absolute value of 0: 0

Absolute value of -4/5: 4/5

The equation that represents the relationship between the radius, r, and arc length, s is s = Θ * r

The attached image completes the question

The given parameters are:

Since, the angle is in radians.

The arc length is calculated as:

Arc length = Angle * Radius

So, we have:

s = Θ * r

Hence, the equation that represents the relationship between the radius, r, and arc length, s is s = Θ * r

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Answer:

this is what i got

Answer:

[tex]c=4 \sqrt{2}[/tex]

Step-by-step explanation:

Pythagoras Theorem

    [tex]a^2+b^2=c^2[/tex]

where:

Given values:

Substitute the given values into Pythagoras Theorem formula and solve for c:

[tex]\begin{aligned}a^2+b^2 & = c^2 \\\implies 4^2+4^2 & =c^2\\16+16 & =c^2\\32 & =c^2\\ \sqrt{c^2}& =\sqrt{32}\\ c & =\sqrt{16 \cdot 2}\\& = \sqrt{16}\sqrt{2}\\& =4\sqrt{2}\end{aligned}[/tex]

Therefore, the measure of the third side of the given right triangle is [tex]4 \sqrt{2}[/tex]

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Answer:

3  1/2

Step-by-step explanation:

Put '3' where 'y' is and compute :

[12 -3(3) ] / 2   + 3 [ (2(3)-4 )/3) =

   3/2              +   2  

    =   3  1/2

Answer:

400 children tickets and 600 adult tickets.

Step-by-step explanation:

children tickets in total cost=400x2.50

                                             =1000

adult tickets in total cost=600x5.00

                                             =3000

total cost is 4000