The population of two different villages is modeled by the equations shown
Suppose y represents the population and x represents the number of years
since 1980. What year(s) were the populations of both villages the same?
What was the population of both villages in the year(s) they were the same
Montville: y = x2 – 30x + 540
Havertown: y = 20x + 15

Answers

Answer 1

Answer:

Year = 1995 and population = 315

Year = 2015 and population = 715

Step-by-step explanation:

It is given that the population of two different villages is modeled by the given equations:

[tex]y=x^2-30x+540[/tex]

[tex]y=20x+15[/tex]

The population of both villages are same after x years after 1980 if

[tex]x^2-30x+540=20x+15[/tex]

[tex]x^2-30x+540-20x-15=0[/tex]

[tex]x^2-50x+525=0[/tex]

Splitting the middle term, we get

[tex]x^2-15x-35x+525=0[/tex]

[tex]x(x-15)-35(x-15)=0[/tex]

[tex](x-15)(x-35)=0[/tex]

[tex]x=15,35[/tex]

It means, after 15 or 35 years, the population will same.

For x=15, years is [tex]1980+15=1995[/tex] and population is  

[tex]y=20(15)+15=315[/tex]

For x=35, years is [tex]1980+35=2015[/tex] and population is  

[tex]y=20(35)+15=715[/tex].

Therefore, population are equation in Year = 1995 and population = 315 or Year = 2015 and population = 715.

Answer 2

Year = 1995 and population = 315

Year = 2015 and population = 715

Calculation:

The equation is

[tex]y = x^2 - 30x + 540\\\\y = 20x + 15[/tex]

Now

[tex]x^2 - 30x + 540 = 20x + 15\\x^2 - 30x + 540 - 20x - 15=0\\\\x^2 - 50x + 525 = 0\\\\x^2 - 35x - 15x + 525=0\\\\x(x - 15) -35(x-15) = 0\\\\(x-15) (x-35) = 0[/tex]

x = 15,35

so,

When x is 15 , the population is = 20(15 )  +15 = 300 + 15 = 315

And, x is 35 , the population is = 20(35 )  +15 = 700 + 15 = 715

Learn more about the population here: https://brainly.com/question/905400?referrer=searchResults


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Answers

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Answers

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Answers

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Answer:

6 units by 12 units

Step-by-step explanation:

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Suppose that a storm front is traveling at 33 mph. When the storm is 13 miles away a storm chasing van starts pursuing an average speed of 54 mph. How long does it take for the van to catch up with the storm? How far have they driven? (Hint: we can let our two variables be x= distance and t= time. Additionally, [speed x time= distance]. Won’t the van catch up when the distances are equal?

Answers

Answer:

= 15mins 18 seconds. The storm chaser van drove 13.53 miles to catch up with the storm which obviously has moved less than 0.53 miles as it was same time but multiplied below by 0.5 per minute as speed per minute is 0.5 for the storm. See right at the end the storm only moved 1.11 mile.

Step-by-step explanation:

We count in 1 minutes

54 mph = 54/60 = 0.9 miles per minute

Storm = 13 m +  1 minute  is;

33/60 = 0.55 miles = 11/20

M = (16 7/10 * 9/10x) = ( 3 7/10 * 11/20y ) +13

M = 15 3/10x = ( 407/200y +13)       (407/200 = y starting value +13)

M = 15 3/10x =  15 3/10 = 16 7/10x (the same as 16 7/10* 9/10 for x)

M = 15 3/10 x = 15 3/10  = 15.03    

M = 16 7/10x  / 9/10y                      (is also the same as 186/1000)

X = 185⁄1000 = 37⁄200xy x 16 7/10  (as starting value)

7/10 of 60 = 42 minutes

3/10 of 60 = 18 minutes

x = 15 mins 18 seconds.

y = 15 mins  18 seconds.

as 0.005 left over for y 3/10 was actually 15.035 gives us 0.005 of 60 can not be rounded up to a second.

However as we started with 16mins and 7/10 we can see that we multiplied by 9/10 so when we divide 16 7/10 by 9/10 we find  185⁄1000 = 37⁄200

To equal the mileage of the storm of where we multiplied 3 7/10 by 17/10

= 37/200 just the same

We added 13 miles of the storm to find each was multiplied by the larger x sum 9/10 and y was multiplied  

As 35/200 + 13 =  

13 37/200  

37/200 of 60 = 11.1 = 11.06 minutes which is

= 15.04 % more for y as 13 + 2 mins + 06 seconds = 15.06 = 15.035

The percentage looks the same but valued different as 2 of 13 as a percentage is multiplied as 13 x 15.04%  to equal the 2 of 15 miles as 15.04%.

To find how many miles we go back and see 15.035 = 15 7/200

Then we multiply this by 0.9 miles for the storm van

= 15 7/200 x 0.9 = 13.5315 = 13.53 miles

For the storm itself we can prove 0.53  increase of mileage

417/200 x 0.53 = 1.10505 = 1.11 miles. rounded up

I need help with this I have a few minutes left cuz it's timed.

Answers

Answer:

She wronged in V1.

Step-by-step explanation:

She write wrongly for the values of length and height. The length of V1 should be 7ft + 4ft which is 11ft and the height is 5ft.

So the volume of V1 is :

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