Answer:
You need 2 numbers whose product is 45 and whose difference is 4.
so the length is 9 and the width is 5.
Hope this helps.
What is the value of x
Enter your answer in the box
X=_
Answer:
25
Step-by-step explanation:
This is an equilateral triangle so all of its angle measures, and side lengths likewise, are equal.
To find x we can use the following equation:
3x - 5 = 2x + 20 export like terms to the same side of the equation
3x - 2x = 20 + 5 (notice how terms change from "+" to "-" and vice versa)
add/subtract like terms
x = 25
The price of a Year 7 mathematics textbook is $60. The store gives a discount of 20% on the textbook.
You have $50 to spend. Would you be able to buy the textbook? Explain.
Answer:
yes,you can buy the textbook
Step-by-step explanation:
determine discount
60 × 0.2(decimal form of 20%)
=12
apply discount
60-12
=48
50>48✓
The standard form of an absolute value function is f(x)-a|x-h|+k. Which of the following represents the vertex?
(-k.h)
(-h.k)
(k,b)
(h,k)
Answer:
(h, k )
Step-by-step explanation:
given the standard form of an absolute function
f(x) = a| x - h | + k , then
vertex = (h, k )
The standard form of an absolute value function is f(x) = a|x - h| + k, where (h,k) is the vertex of the absolute value function.
The correct option is (h,k).
What is a function?The term "function" refers to a relationship between a set of inputs and outputs. Just one output is connected to each input in a function, which connects inputs in that manner. Every function has a domain, co-domain, and range.
In general, the standard form of an absolute value function is given as:
f(x) = a |x - h| + k
where:
a is a non-negative constant that determines the shape and direction of the V-shaped graph of the absolute value function
h is the horizontal shift of the graph of the function from the origin (if h > 0, the graph shifts to the right; if h < 0, the graph shifts to the left)
k is the vertical shift of the graph of the function from the origin (if k > 0, the graph shifts up; if k < 0, the graph shifts down)
The vertex of the absolute value function is the point where the graph changes direction, that is, the point where the graph changes from sloping downwards to sloping upwards or vice versa.
Since the vertex is the point of the absolute value function where the graph changes direction, it lies at the center of the V-shaped graph. Thus, the vertex is located at the point (h,k).
Therefore, in the standard form f(x) = a |x - h| + k, (h,k) represents the coordinates of the vertex of the absolute value function.
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(This is an Edge question)
Question:
Which expression is equivalent to negative 3 minus 3 times a number minus 1 plus a number.
[tex] - 3 - 3x - 1 + x[/tex]
Answer Choices:
A.
[tex]2x - 4[/tex]
B.
[tex] - 2x + 4[/tex]
C.
[tex] - 2x - 4[/tex]
D.
[tex]4 - 2x[/tex]
I will verify the answer and give Brainlyest for fastest and most accurate answer and 15 pts.
Answer:
The answer is C. -2x -4
Step-by-step explanation:
Your given information.
-3 - 3x - 1 + x
Combine and simplify common numbers/variables.
(-3x + x) + (-3 - 1)
-2x - 4
Solve for y, Look at the picture to help.
Using two triangle concepts, it is found that the solution for y is of y = 70º.
What are the two triangle concepts used in this problem?The sum of the internal angles of a triangle is of 180º.The sum of an angle with it's external angle is also of 180º.Hence:
x + y + 70 = 180.y + 3x - 10 = 180 -> y = 190 - 3x.Then:
x + y + 70 = 180
x + 190 - 3x + 70 = 180.
2x = 80.
x = 40.
Hence:
y = 190 - 3x = 190 - 3(40) = 70º.
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On a coordinate plane, a circle has a center at (0, 0). Point (3, 0) lies on the circle.
Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot
Does the point (2, StartRoot 6 EndRoot) lie on the circle shown? Explain.
Yes, the distance from (3, 0) to (0, 0) is 3 units.
Yes, the distance from (0, 0) to (2, StartRoot 6 EndRoot) is 3 units.
No, the distance from (3, 0) to (2, StartRoot 6 EndRoot) is not 3 units.
No, the distance from (0, 0) to (2, StartRoot 6 EndRoot) is not 3 units.
Answer: Option (4)
Step-by-step explanation:
We know that the radius of the circle is 3.
Using the distance formula, the distance from the given point to the center is
[tex]\sqrt{(\sqrt{6}-0)^{2}+(2-0)^{2}} = \sqrt{10} \neq 3[/tex]
Answer:d
Step-by-step explanation:
12. Last month, a store sold a total of 182 pairs of jeans and shorts. The
number of shorts sold was 28 fewer than twice the number of jeans sold.
How many pairs of jeans were sold?
C. 105
A 51
D. 112
B. 70
Answer:
B. 70
Explanation:
A total of 182 pairs of jeans and shorts were sold and the number of shorts sold was 28 fewer than twice the number of jeans. This can be expressed with j being the number of jeans as:
j2 - 28 = number of shorts
As the number of shorts is 28 lower than twice the number of jeans, this means it can not be C or D, as these numbers are larger than 182 when doubled. The process of elimination can be done with the remaining using our equation.
51(2) - 28 = 102 - 28 = 74
70(2) - 28 = 140 - 28 = 112
Now that we have the number of shorts sold by using the equation, we can add them with what number was used as their number of jeans.
74 + 51 = 125
112 + 70 = 182
So the number of jeans sold is B. 70.
Kyla has the number of cherries that Denise has. If Kyla has 46 cherries, how many cherries do they have altogether?
Answer:
92
Step-by-step explanation:
46 + 46 = 92
80
Select the correct answer.
4
What is the solution to the equation?
5√x + 7 = -2
OA -39
OB. -17
OC 25
OD. no solution
Answer:
38 is the correct solution
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Answer:
Hey there : y= 3x - 3
Answer:
y = [tex]\frac{3}{2}[/tex] x + 3
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line
m = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{0+2}[/tex] = [tex]\frac{3}{2}[/tex]
the line crosses the y- axis at (0, 3 ) ⇒ c = 3
y = [tex]\frac{3}{2}[/tex] x + 3 ← equation of line
If f(x) = -3 and g(x) = 4x² + x − 4, find (ƒ+ g)(x).
Answer:
4x² + x - 7
Step-by-step explanation:
Given f(x) = -3 and g(x) = 4x² + x - 4, solve for (f + g)(x).
Step 1: Replace the function designators with the actual functions in f(x) and g(x); that gives us 4x² + x - 4 - 3.
Step 2: Simplify; that gives us the answer 4x² + x - 7.
Please mark me as Brainliest! Thanks :)if(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers
Answer:
a = 4/3 and b = 0============================
Given expression:[tex]\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}[/tex]
Simplify it in steps:Step 1Bring both fractions into common denominator:
[tex]\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}[/tex]
Step 2Simplify:
[tex]\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]
[tex]\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]
[tex]\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]
[tex]\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =[/tex]
[tex]\dfrac{4\sqrt{14} }{7-4} =[/tex]
[tex]\dfrac{4}{3} \sqrt{14} }[/tex]
Step 3Compare the result with given expression to get:
a = 4/3 and b = 0A business rents cars for $100 a day and vans for $200 a day. One day, it rented a total of 22 vehicles
and made a total of $2900. What is a possible number of cars and vans it rented that day?
Answer:
Vans - 7
Cars - 15
Step-by-step explanation:
$200 * 7 = $1400
$100 * 15 = $1500
$1400 + $1500 = $2900
The function y=x²-4x+8 approximates the height, y, of a bird, and its horizontal distance, x, as it flies from one
fence post to another. All distances are in feet. Complete the square to find and interpret the extreme value
(vertex).
Select two answers: one extreme value and one interpretation.
Height (feet)
Distance (feet)
A. When the bird is 4 feet away from the first fence post, it reaches its minimum height of 8 feet.
B. Minimum at (4,8)
C. When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet.
D. Minimum at (2,4)
When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet , Minimum at (2,4)
Therefore Option C and D is the correct answer.
What is a Quadratic Function?The equation for a quadratic function is given by
y = a(x-h)² +k²
where (h,k) is the extreme value(vertex).
Here the equation given is
y = x²-4x +8
y = x²-4x+4+4
y = (x-2)² +4
Here the value of a = 1 , h = 2 and k = 4
The extreme value is at (2,4)
Therefore When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet , Minimum at (2,4)
Therefore Option C and D is the correct answer.
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HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
write and solve a proportion to complete the statement. Round to the nearest hundredth if necessary.
1. 6km ≈ ?mi
2. 2.5 L≈ ?gal
3. 90lb ≈ ?kg
pls help
1. 6 km ≈ 3.73 mi
2. 2.5 L ≈ .66 gal
3. 90 lb ≈ 40.82 kg
Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three options.
The value of f(–10) = 82
The graph of the function is a parabola.
The graph of the function opens down.
The graph contains the point (20, –8).
The graph contains the point (0, 0).
Answer:
I will assume the equation is supposed to be f(x) = x^2 – 5x + 12 since it is said to be a quadratic equation.
Step-by-step explanation:
See attached graph.
The value of f(–10) = 82 False
f(-10) = (-10)^2 - 5*(-10) + 12
f(-10) = (100) +50 + 12
f(-10) = 162
The graph of the function is a parabola. True
The graph of the function opens down. False
The graph contains the point (20, –8). False
The graph contains the point (0, 0). False
how to solve this???
[tex]\large\sf{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}}[/tex]
[tex]\\[/tex]
[tex]\large \sf{=\frac{\left(\sqrt{1+sin\theta}\right)^{2}+\left(\sqrt{1-sin\theta}\right)^{2}}{\sqrt{(1-sin\theta)(1+sin\theta)}}}[/tex]
[tex]\\[/tex]
[tex]\large\sf{=\frac{1-sin\theta+1+sin\theta}{\sqrt{1^{2}-sin^{2}\theta}}}[/tex]
[tex]\\[/tex]
[tex]\large \sf{=\frac{2}{\sqrt{cos^{2}\theta}}}[/tex]
[tex]\\[/tex]
[tex]\large\sf{= \frac{2}{cos\theta}}[/tex]
[tex]\\[/tex]
[tex]\large\sf{= 2sec\theta}[/tex]
[tex]\\[/tex]
[tex]\large\sf{=RHS}[/tex]
Therefore,
[tex]\large\sf\red{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}=2sec\theta}[/tex]
Which equation represents this number sentence?
Three less than one-fifth of a number is 28.
3−15n=28
15n−3=28
(3−15)n=28
(15−3)n=28
The equation that represents this number sentence is 1/5n - 3 = 28
Translating word problemsLet the unknown number be "n". One-fifth of a number is expressed as 1/5n
Three less than one-fifth of a number is expressed as 1/5n - 3
Finally, if three less than one-fifth of a number is equal to 28, then the final expression will be 1/5n - 3 = 28
The equation that represents this number sentence is 1/5n - 3 = 28
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Factor the expression below.
36x² - 49
A. (6x + 7)(6x - 7)
B. (4x-7)(9x - 7)
C. (4x+7) (9x-7)
D. (6x-7)(6x-7)
Answer:
A. (6x + 7)(6x - 7)
Step-by-step explanation:
use difference of squares, which says a^2 - b^2 =(a+b)(a-b)
take the square roots of the two numbers, 6x and 7, and use them as a and b
What is the distance from -5 to 0?
0, because 151=0
O 5, because 1-51=5
O5, because 1-51=-5
O-5, because 1-51 = -5
7 of 23 QUESTIONS
SUBMIT
Answer:
distance between -5 to 0 = 5 units
Carol measured a straw and wrote down how long it was in inches. pete multiplied carol's straw length by and cut a straw to be that many inches long. joe multiplied carol's straw length by and cut a straw to be that many inches long. which straw belongs to whom?
Answer:
pete
Step-by-step explanation:
i think its pete???
Point T is located at (6, –2) and point S is located at (1, 13). What are the coordinates of the point that is `\frac{4}{5}` of the way from T to S?
The coordinates of the point that is 4/5 of the way from T to S is (2,10)
How to determine the coordinates of the point?The given parameters are:
T = (6,-2)
S = (1,13)
Location = 4/5
The location 4/5 means
Ratio, m : n = 4 : 1
The coordinate is then calculated as:
[tex](x,y) = \frac{1}{m +n} * (mx_2 + nx_1,my_2 + ny_1)[/tex]
This gives
[tex](x,y) = \frac{1}{4 +1} * (4 * 1 + 1 * 6 , 4 * 13 + 1 * -2)[/tex]
Evaluate
[tex](x,y) = \frac{1}{5} * (10 , 50)[/tex]
This gives
(x,y) = (2,10)
Hence, the coordinates of the point that is 4/5 of the way from T to S is (2,10)
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x2 - x - 42
a=?
b=?
C=?
help me
Step-by-step explanation:
thr standard form for a quadratic equation is:
ax²+bx+c
in this example, a=1, b=(-1), c=(-42)
square root of 342354456
Answer:
18502.8229198
Answer:
18502.82292
Step-by-step explanation:
calculator
Mary has 20 flowers in 5 vases. How many flowers are there in every vase?
Solve the following system of equations. (Hint: Use the quadratic formula.)
f(x)=2x^(2)-3x-10
g(x)=-3x^(2)+20
The solutions to the system of equation f(x) and g(x) are [tex]\frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex] and
[tex]\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]
Solving quadratic equationsQuadratic equations are equations that has a leading degree of 2. Given the following functions:
f(x)=2x^(2)-3x-10
g(x)=-3x^(2)+20
To solve, we will use the quadratic formula as shown below;
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
For the quadratic equation f(x)=2x^(2)-3x-10
a = 2
b = -3
c = -10
Substitute
[tex]x=\frac{-(-3)\pm \sqrt{(-3)^2-4(2)(-10)}}{2(2)}\\x=\frac{3\pm\sqrt{89}}{4}\\x= \frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex]
For the quadratic equation -3x² + 20
a =-3
b = 0
c = 20
[tex]x=\frac{0\pm \sqrt{(0)^2-4(-3)(20)}}{2(-3)}\\x=\frac{\pm4\sqrt{15}}{-6}\\x=\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]
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What was the problem at kenya airways described in this case? what management, organization, and technology factors contributed to this problem?
The management, organisation, and technology factors contributed to this problem are listed below.
What was the problem at Kenya Airways ?The problem in the airways was that corporation didn't know its customers, the airline hasn't been able to take use of its market opportunity in recent years.
Airways was unable to evaluate and keep track of its marketing efforts.
The technology factor that contributed were:
No reliable systems for tracking and accounting.The technology used was neither accurate nor consistent.The Organisation factors that contributed were
No communication between the organisation and the customersNo track record of the online campaigns and advertisement output Customer Relations Needed to be improved.The Management factors that contributed were
The management never gave reviews to the organisation about the failing system The management even didn't take reviews from the customers and from the people working.To know more about problem at Kenya Airways
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After covering 4/5 of the journey, James found that he has traveled 48 km. How much of the journey is still left?
Answer:
12 km
Step-by-step explanation:
Let the total distance to be traveled = x
[tex]\sf \dfrac{4}{5} \ of \ the \ journey = 48\\\\[/tex]
[tex]\sf \dfrac{4}{5}*x = 48\\\\[/tex]
[tex]x = 48*\dfrac{5}{4}[/tex]
= 12 * 5
x = 60 Km
Distance still to traveled = 60 - 48 = 12Km
Please Help! What is the value of x?
Answer:
4.1968
Explanation:
Given that:
angle: 25°
opposite: x
adjacent: 9
So, use the tan rule:
opposite/adjacent = tan(x)
x/9 = tan(25)
x = 9tan(25)
x = 4.1968
Option A
Help would be appreciated
Answer:
625 × 48 = 30,000
[tex]\sqrt[4]{30000} = 10 \sqrt[4]{3} [/tex]
answer = third option