Answer:
a) the power loss due to irreversible head loss is 4.57 kW
b) the efficiency of the piping is 95%
c) the electric power output is 72.9918 kW
Explanation:
Given the data in the question below;
Irreversible loses [tex]h_L[/tex] = 7m
Total head, H = 140 m
flow rate Q = 4000 L/min = 0.0666 m³/s
Generator efficiency n₀ = 84% = 0.84
we know that density of water is 1000 kg/m³
g = 9.81 m/s²
a) power loss due to irreversible head loss [tex]P_L[/tex] is;
[tex]P_L[/tex] = p × Q × g × [tex]h_L[/tex]
we substitute
[tex]P_L[/tex] = 1000 × 0.0666 × 9.81 × 7
[tex]P_L[/tex] = 4573.422 W
[tex]P_L[/tex] = 4573.422 / 1000
[tex]P_L[/tex] = 4.57 kW
Therefore, the power loss due to irreversible head loss is 4.57 kW
b) the efficiency of the piping n is;
n = (Actual head / maximum head) × 100
n = (( H - [tex]h_L[/tex] ) / H) × 100
so we substitute
n = (( 140 - 7 ) / 140) × 100
n = (133/140) × 100
n = 0.95 × 100
n = 95%
Therefore, the efficiency of the piping is 95%
c) the electric power output if the turbine-generator efficiency is 84 percent;
n₀ = [tex]Power_{outpu[/tex] / [tex]power_{inpu[/tex]
[tex]Power_{outpu[/tex] = n₀ × [tex]power_{inpu[/tex]
[tex]Power_{outpu[/tex] = n₀ × ( pQg( H - [tex]h_L[/tex] ))
so we substitute
[tex]Power_{outpu[/tex] = 0.84 × ( 1000 × 0.0666 × 9.81( 140 - 7 ))
[tex]Power_{outpu[/tex] = 0.84 × 653.346( 133)
[tex]Power_{outpu[/tex] = 0.84 × 86895.018
[tex]Power_{outpu[/tex] = 72991.815 W
[tex]Power_{outpu[/tex] = 72991.815 / 1000
[tex]Power_{outpu[/tex] = 72.9918 kW
Therefore, the electric power output is 72.9918 kW
An interest rate of norminal 12% per year , compounded weekly is
Answer: It is a nominal rate per year
A heat pump operates on a vapor-compression refrigeration cycle with R-134a as the working fluid. The refrigerant enters the compressor as saturated vapor at X kPa, and exits at 800 kPa and 60oC. The refrigerant leaves the condenser as saturated liquid at 800 kPa. The number of letters in your first name multiplied by 10 plus 50
Answer:
Hello your question has some missing information below are the missing information
The refrigerant enters the compressor as saturated vapor at 140kPa Determine The coefficient of performance of this heat pump
answer : 2.49
Explanation:
For vapor-compression refrigeration cycle
P1 = P4 ; P1 = 140 kPa
P2( pressure at inlet ) = P3 ( pressure at outlet ) ; P2 = 800 kPa
From pressure table of R 134a refrigerant
h1 ( enthalpy of saturated vapor at 140kPa ) = 239.16 kJ/kg
h2 ( enthalpy of saturated liquid at P2 = 800 kPa and t = 60°C )
= 296.8kJ/kg
h3 ( enthalpy of saturated liquid at P3 = 800 kPa ) = 95.47 kJ/kg
also h4 = 95.47 kJ/kg
To determine the coefficient of performance
Cop = ( h1 - h4 ) / ( h2 - h1 )
∴ Cop = 2.49
a) The initial moisture content of a food product is 77% (wet basis), and the critical moisture content is 30% (wet basis). If the constant drying rate in a fluidized bed dryer is 0.1 kg water removed/m2-s, determine the time required for the product to begin the falling-rate drying period. The product has a cube shape with 5-cm sides; the initial product density is 950 kg/m3.
Answer:
≈ 53 seconds
Explanation:
calculate Time required for the product to begin the falling-rate drying period
Initial moisture content = 0.77 kg water /kg of product
= 3.35 kg water /kg solids
Critical moisture content = 0.3 kg water / kg product
= 0.43 kg water / kg solids
∴ amount of water to be removed = 3.35 - 0.43 = 2.95kg water /kg solids
next: calculate surface are a of product during drying
= (0.05 * 0.05 ) * 6
= 0.015 m^3
Drying rate = 0.1 kg water m^2.s^-1 * 0.015 m^3 = 1.5 * 10^-3 kg water s^-1
applying product density
initial product mass = 0.11875 * 0.23 = 0.0273kg solid
hence total amount of water to removed = 2.92 * 0.0273 = 0.07972 kg
therefore : Time required for the product to begin the falling-rate drying period
= 0.07972 / 1.5 * 10^-3
= 53 seconds
other examples of joption
Answer:
Profit from stock price gains with limited risk and lower cost than buying the stock outright.
Profit from stock price drops with limited risk and lower cost than shorting the stock.
Profit from sideways markets by selling options and generating income.
Get paid to buy stock.
Explanation:
I don’t know if you meant option but I hope this helps.
what technology has been used for building super structures
Answer: Advanced technologixal machines
Explanation: such as big cranes, multiple workers helping creat said structure, and big bull dozers
Q5) Write C++ program to find the summation of sines of the even values that can be divided by 7 between -170 and -137.
Answer:
In C++:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double total = 0;
for(int i = -170; i<=-130;i++){
if(i%2 == 0 && i%7==0){
double angle = i*3.14159/180;
total+=sin(angle); } }
cout<<"Total: "<<total;
return 0; }
Explanation:
This initializes the total to 0
double total = 0;
This iterates from -170 to - 130
for(int i = -170; i<=-130;i++){
This checks if the current number is even and is divided by 7
if(i%2 == 0 && i%7==0){
This converts the number from degrees to radians
double angle = i*3.14159/180;
This adds the sine of the number
total+=sin(angle); } }
This prints the calculated total
cout<<"Total: "<<total;