The diagonal of a rhombus are 14cmand 10 cm find the area of
rhombus.
​

Answer:

.shsnxbjsjJsjsiakzjxjisksjxjs

It would be -1.4f-18. I hope this helps!!

Answer:

Simplify the expression.

− 1.4 f − 18

Step-by-step explanation:

Answer:

where is the diagram? please provide the diagram.

Answer:

by x:

Answer:

amelia

Step-by-step explanation:

Answer:

Step-by-step explanation:

To compare fractions, they need to have a common denominator.

The least common denominator of 1/2 and 2/3 is 6.

1/2 = 3/6

2/3 = 4/6

Now find the fraction with the larger numerator.

4/6 > 3/6, so 2/3 > 1/2

Answer:

According to the associative property of equality: (a + b) + c = a + (b + c) we can see that the parenthesis do not mean anything when we are only doing addition.

So answers 1. and 3. are correct.

Step-by-step explanation:

Answer:

person above seems corect and he said a and c

Answer:

false

Step-by-step explanation:

I took the test

Answer:

I think the answer is false

Answer: 13

Step-by-step explanation:

12^2+5^2=13^2

Answer:

-3/4

Step-by-step explanation:

y2-y1/x2-x1 =

-1-2/4-0=

-3/4

Answer: C and D are functions.

Step-by-step explanation:

Answer:

36.5 degrees Celsius

Step-by-step explanation:

38.5-2=36.5 degrees Celsius

Answer:

1

Step-by-step explanation:

The use of

Parenthesis(1+2)=3

Exponents- none

Multipy- 2 times the 3 is 6

Divide 6/6 is 1

Add- none

Subtract- none

Answer:

9

Step-by-step explanation:

you should have  search it up :)

HAVE A GREAT DAY

Answer:

2 real roots and 1 imaginary roots

Step-by-step explanation:

f(x) = [tex](x-a)(x-b)^{2} (x^{2}+c)[/tex]

There are only 2 real roots and one imaginary roots.

Separate the equation into sections because the function is a multiplication with no outside sum or substraction:

Real Roots:

[tex](x-a)[/tex] = 0 when x = a

[tex](x-b)^{2}[/tex] = 0 when x = b

Imaginary roots:

[tex](x^{2}-c)[/tex] = 0 when x = [tex]\sqrt{-c}[/tex]

Answer:

it's B,C and D

Step-by-step explanation:

I had the USA testprep

hope this helps :)

Answer:

dkdkkdjdkdkdkkskzksskisks

Answer: 3/10

Step-by-step explanation:

1/5 isn’t equivalent to it

Answer:

Just random ones?

1/2, 1/3, 1/4, 1/6, 1/7

Step-by-step explanation:

Answer:

[tex] \huge \boxed{ \boxed{ \sf x + 52 ^{o} + 7 {2}^{o} =18 {0}^{o} }}[/tex]

Step-by-step explanation:

[tex]\text{since a triangle contains 180° the sum of the interior angles has to be 180°}[/tex]

[tex]\text{therefore the equation is}[/tex]

[tex] \mathfrak{x + {52}^{o} + {78}^{o} = 180 ^{0} }[/tex]

Answer:

9m×7m:10m-2m paràllelogram

Answer:

A = 70 m²

Step-by-step explanation:

The area (A) of a parallelogram is calculated as

A = bh ( b is the base and h the perpendicular height )

Here b = 10 and h = 7 , then

A = 10 × 7 = 70 m²

Answer: — Cramer: Tesla is the first non-traditional tech stock that could move the market ... The electric car maker has a 1.69% weighting in the index, the fifth largest. ... (S&P Dow Jones uses float-adjusted market value rather than the outright number.) ... For every $11.11 Tesla moves, the S&P 500 changes 1 point, ...

pls Brainliest

Answer:

72 lb

Step-by-step explanation:

Write and solve an equation of ratios:

80 pounds             x

----------------- = ------------------

100 pounds      90 pounds

Cross multiplying, we get (100 pounds)x = 7200, or x = 72 pounds.

The 80 pound child's weight includes 72 pounds of water.

Answer:

Step-by-step explanation:

0.5^(t/5600) = 0.08

2^(-t/5600) = 0.08

-t/5600 = log₂0.08

t = -5600 log₂0.08 ≈ 20406 years

Your equation is wrong. See below for correct equation.

The ball will hit the ground when h(t) is 0.

Here is the set up:

0 = -16t^2 + 5t + 5

Solve for t to find your answer.

Answer:

2.899

Step-by-step explanation:

Given that:

[tex]f' (x) =3 tan ^{-1} (x^2 -3x +2)[/tex]

[tex]\text{applying integration on both sides with respect to x}[/tex]

[tex]\int \limits ^{3}_{1}} f'(x) \ dx = \int ^3_1 3tan ^{-1} (x^2 -3x+2) \ dx[/tex]

[tex]f(3)-f(1)= 3 \int ^3_1 3tan ^{-1} (x^2 -3x+2) \ dx[/tex]

[tex]f(3) = \dfrac{\pi}{2}+3\int^{3}_{1} tan^{-1} (x^2 -3x+2)dx ---(1)[/tex]

[tex]\text{consider } \ \ 3\int^{3}_{1} tan^{-1} (x^2 -3x+2)dx[/tex]

[tex]h = \dfrac{b-a}{n}[/tex]

[tex]where; n = 10 , a =1, b= 3[/tex]

[tex]h = \dfrac{3-1}{10}[/tex]

[tex]h = \dfrac{2}{10}[/tex]

[tex]h = 0.2[/tex]

[tex]\text{The value of x and corresponding } y = 3tan^{-1}(x^2-3x+2) \ are:[/tex]

x     1      1.2      1.4      1.6      1.8      2      2.2      2.4      2.6      2.8      3

y   f(0)  f(1.2)   f(1.4)   f(1.6)   f(1.8)   f(2.0)  f(2.2)  f(2.4)  f(2.6)  f(2.8)   f(3)

By simpson's rule:

[tex]\int \limits ^3_1 \ 3 tan^{-1} (x^2-3x+2) dx \simeq \dfrac{h}{3}(y_o+y_{10}) +4(y_1+y_3+y_5+y_7+y_9)+2(y_2+y_4+y_6+y_8)][/tex]

[tex]=\dfrac{0.2}{3}\Big[(0+3.3214)+(-1.9039+2.8265+1.4133+6.1259+11.5657)+2(-1.4133-0.9519+1.4133+4.5899)\Big][/tex]

[tex]= 1.32804[/tex]

[tex]\text{From}; f(3) = \dfrac{\pi}{2}+1.32804 \\ \\ f(3) = 2.89883633 \\ \\ \mathbf{f(3) \simeq 2.899}[/tex]

Trapezoidal rule is used to evaluate the area of the curve by using various strips of equal width which is in the form of trapezoids. The value of [tex]f(3)[/tex] is 2.8989.

Given information

In the given problem [tex]f[/tex] is the function such that,

[tex]f(1)=\dfrac{\pi}{2} \\[/tex]

The differentiated function is,

[tex]f'(x)=3\tan^-(x^2-3x+2)[/tex]

Integrate the above equation with respect to the x,

[tex]\int\limits^3_1 {f'(x)} \, dx =\int\limits^3_1 {3\tan^-(x^2-3x+2)} \, dx\\f(3)-f(1) =\int\limits^3_1 {3\tan^-(x^2-3x+2)} \, dx\\f(3) =3\int\limits^3_1 {\tan^-(x^2-3x+2)} \, dx +f(1)\\f(3) =3\int\limits^3_1 {\tan^-(x^2-3x+2)} \, dx +\dfrac{\pi}{2}[/tex]           .........1

Let the above equation is the equation number 1.

Let the integrated function,

[tex]y=3\int\limits^3_1 {\tan^-(x^2-3x+2)} \, dx[/tex]

Solve the above equation using the trapezoidal rule.

Trapezoidal rule is used to evaluate the area of the curve by using various strips of equal width which is in the form of trapezoids.

In the given problem,

[tex]h=\dfrac{b-a}{n}[/tex]

Use this formula for the integrated function,

[tex]h=\dfrac{3-1}{10}\\h=0.2[/tex]

Use the Simpson formula to solve the above equation,

[tex]=3\int\limits^3_1 {\tan^-(x^2-3x+2)} \, dx[/tex]

[tex]=\dfrac{h}{3} (y_0+y_{10})+4(y_1+y_3+y_{5}+y_7+y_{9})+2(y_2+y_{4}+y_6+y_{8})[/tex]

Find the value of y by putting the values in the given formula. Thus,

[tex]=\dfrac{0.2}{3} (0+3.3214)+4(-1.9039+2.8266+1.4133+6.1259+11.5657)+2(-1.4133-0.9519+1.4133+4.5899)\\=1.32804[/tex]

Put this value in equation 1,

[tex]f(3) =1.30824 +\dfrac{\pi}{2}\\f(3)=2.8989[/tex]

Thus the value of [tex]f(3)[/tex] is 2.8989.

Learn more about the trapezoidal rule here;

https://brainly.com/question/15323877

Answer:

800

Step-by-step explanation:

80000 / 100 is 800

Answer:

80,000/100= 800

....................

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Isosceles triangles.

Since, the sides are equal, we can equate them, so we get as,

==> 16x + 13 = 24x -19

=> 24x -16x = 13+19

=> 8x = 32

x = 4

hence ==> x = 4.

Answer:

x = 33/8

Step-by-step explanation:

2/3 x + 1/4 = 3

Subtract 1/4 from both sides.

2/3 x = 3 - 1/4

2/3 x = 12/4 - 1/4

2/3 x = 11/4

Multiply both sides by 3/2.

3/2 * 2/3 x = 3/2 * 11/4

x = 33/8

Answer:

[tex]0 \le t \le 3[/tex]

Step-by-step explanation:

Given

[tex]h(t) = -16t^2 + 144[/tex]

Required

Determine a reasonable domain

The domain is the possible values of t for which h(t) is true

Before the object is released, the value of t is:

[tex]t = 0[/tex]

Next, is to calculate the value of t after the ball reaches the ground.

At this point, h = 0.

So, we have:

[tex]h(t) = -16t^2 + 144[/tex]

[tex]0 = -16t^2 + 144[/tex]

[tex]16t^2 = 144[/tex]

Divide both sides by 16

[tex]t^2 = 9[/tex]

Take the positive square root of both sides

[tex]t = 3[/tex]

This means that the ball reaches the ground in 3 seconds.

So, the domain is:

[tex]0 \le t \le 3[/tex]

Answer:

11

Step-by-step explanation:

cuz i know lol