the correct answer is supposedly 3​

The probability that cards #1, #2, and #3 are still in order on the top of the stack is 0.03%. Therefore, the correct option is D.

To find the probability, we need to calculate the number of ways in which the first 3 cards can remain in order on the top of the stack, and divide it by the total number of ways the cards can be arranged.

The number of ways in which the first 3 cards can remain in order is 3! (3 factorial), because there are 3 cards and they can be arranged in 3! = 6 ways.

The total number of ways the cards can be arranged is 10!, because there are 10 cards and they can be arranged in 10! = 3,628,800 ways.

So, the probability is:

3! / 10! = 6 / 3,628,800 = 0.000166 = 0.0166%

We can convert it to a percentage by multiplying by 100:

0.0166 x 100 = 1.66%

However, this is the probability that the first 3 cards are in a specific order, not necessarily the original order. Since the question asks for the probability that the original order is maintained, we need to divide the probability by 3!, which gives:

0.0166 / 3! = 0.000277 = 0.0277%

This is closest to answer choice D) 0.03%.

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Sean's percentage profit is 20% on selling 24 chocolate bars.

Sean's cost price for each chocolate bar is:

£10 / 24 bars = £0.4167 per bar

Sean sells each chocolate bar for 50p, which is £0.5

Sean's revenue from selling all 24 chocolate bars is:

24 bars x £0.5 per bar = £12

Sean's profit is the difference between his revenue and his cost:

Profit = £12 - £10 = £2

To calculate the percentage profit, we can use the following formula:

Percentage profit = (Profit / Cost price) x 100%

So, plugging in the values we get:

Percentage profit =[tex](2 / 10) x 100% = 20%[/tex]= 20

Therefore, Sean's percentage profit is 20%. He earned a profit of £2 on his initial investment of £10, which is equivalent to a 20% return on investment.

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The exact value of secθ secθ in simplest radical form is 106/81.

The length of the hypotenuse is the distance from the origin to the point (-9, 5):

√((-9)^2 + 5^2) = √(81 + 25) = √106

cosθ = adjacent/hypotenuse = -9/√106

Therefore, secθ = 1/cosθ = -√106/9.

In order to find the value of secθ secθ, we simply multiply secθ by itself:

secθ secθ = (-√106/9) * (-√106/9) = 106/81

The exact value of secθ secθ is 106/81.

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Answer: Box and whisker plots are plots on number lines with a box and two lines off the edges, called whiskers. The box has a line at the upper quartile(1), one at the lower quartile(2), and one in the center of the box at the median(3). The two lines go to the ends of the data, one at the minimum(4) and one at the maximum(5).

  4     2     3       1             5

   |-----[___|____]-----------|

₀__₁__₂__₃__₄__₅__₆__₇__₈

I hope this helps.

Answer:

Step-by-step explanation:

I assume you mean to solve for M in terms of a, b, x, and y.

To solve for M, we can first simplify the given polynomial:

2x^2 - (1/3)ax + by - M = 0

Multiplying through by -1 to isolate M:

M = 2x^2 - (1/3)ax + by

Therefore, the polynomial M is:

M = 2x^2 - (1/3)ax + by

The solutions of equation 2sin²θ + 1 = 0 in the interval [0, 21) in radians are [tex]\theta \approx \frac{5\pi}{4}, \frac{7\pi}{4}[/tex].

Let's solve the equation and find the solutions within the given interval [0, 21) in radians.

The equation is 2sin²θ + 1 = 0.

Subtracting 1 from both sides, we get:

2sin²θ = -1

Dividing both sides by 2, we have:

sin²θ = [tex]-\frac{1}{2}[/tex]

Taking the square root of both sides, considering both the positive and negative square roots, we get:

sinθ = [tex]\± -\sqrt\frac{1}{2}[/tex]

Since the sine function is negative in the third and fourth quadrants, we only need to consider the negative square root.

sinθ = [tex]-\sqrt(\frac{1}{2})[/tex]

To find the solutions within the interval [0, 21), we need to consider the values of θ between 0 and 21 in radians.

Using a calculator or trigonometric tables, we can find the solutions for sinθ = [tex]-\sqrt(\frac{1}{2})[/tex] within the interval [0, 21):

θ ≈ 5π/4, 7π/4

Therefore, the solutions of the equation 2sin²θ + 1 = 0 in the interval [0, 21) in radians are:

[tex]\theta \approx \frac{5\pi}{4}, \frac{7\pi}{4}[/tex]

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The weight of the statue to the nearest ounce is 576 ounces.

The volume of a sphere can be calculated using the formula V = (4/3)πr^3, where r is the radius of the sphere. Since the diameter is given as 10 inches, the radius is half of that, or 5 inches.

Using the formula, we can find the volume of the sphere:

V = (4/3)πr^3

V = (4/3)π(5^3)

V = (4/3)π(125)

V = 523.6 cubic inches (rounded to one decimal place)

Since we know the weight of the clay per cubic inch, we can find the weight of the statue by multiplying the volume by the weight per cubic inch:

Weight = Volume × Weight per cubic inch

Weight = 523.6 in^3 × 1.1 oz/in^3

Weight = 575.96 oz (rounded to two decimal places)

Therefore, the weight of the statue is approximately 576 ounces or 36 pounds (rounded to the nearest pound).

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Sydney can row a canoe at a speed of 5 mph in still water.

Let x represent Sydney's speed in still water. When rowing upriver, her effective speed will be (x - 2) mph because she's going against the current, which flows at 2 mph. When rowing downriver, her effective speed will be (x + 2) mph, since she's going with the current.

According to the problem, the time it takes her to row 6 miles upriver is the same as the time it takes her to row 14 miles downriver. We can set up the equation using the formula time = distance / speed:

6 / (x - 2) = 14 / (x + 2)

To solve for x, first cross-multiply:

6(x + 2) = 14(x - 2)

Expand:

6x + 12 = 14x - 28

Now, rearrange and solve for x:

12 + 28 = 14x - 6x

40 = 8x

x = 5

So, Sydney can row a canoe at a speed of 5 mph in still water.

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The probability that on a particular Monday, they each suggest a different activity is 0.11.

The probability that in a period of four consecutive Mondays, they all suggest the same activity on exactly two of the four Mondays is 0.0504.

1. Probability that on a particular Monday, they each suggest a different activity:

The probability is calculated using the formula below:

Probability = P(SMC) + P(MCS) + P(CSM)

Probability = (0.4 x 0.55 x 0.5) + (0.3 x 0.2 x 0.3) + (0.3 x 0.25 x 0.2)

Probability = 0.11

2. The probability that in a period of four consecutive Mondays, they all suggest the same activity on exactly two of the four Mondays is determined using the binomial distribution.

Let success be suggesting the same activity on exactly two of the four Mondays.

The probability of success on any Monday is:

P(success) = P(SSNN) + P(NSSN) + P(NNSS)

P(success) = 3 x (0.4 x 0.4 x 0.6 x 0.6)

P(success) = 0.3456

The probability of failure is:

P(failure) = 1 - P(success)

P(failure)= 1 - 0.3456

P(failure) = 0.6544

Choose exactly two Mondays out of four is ⁴C₂

The probability of exactly two successes = ⁴C₂ * P(success)² * P(failure)²

P(exactly 2 successes) = 6 x (0.3456)² x (0.6544)²

P(exactly 2 successes) = 0.0504 or 5.04%

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The simplified form of the expression 3(w+11) / 6w  is w + 11 / 2w .

Simplifying expressions mean rewriting the same algebraic expression with no like terms and in a compact manner.

In other words, we have to expand any brackets, next multiply or divide any terms and use the laws of indices if necessary, then collect like terms by adding or subtracting and finally rewrite the expression.

Therefore, let's simplify the expression:

3(w+11) / 6w

Hence, let's divide both the numerator and denominator by 3

Therefore,

3(w+11) / 6w =  w + 11 / 2w

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The probability of randomly selecting a quarter from the bag is 5/16

Assuming that all the coins have the same probability of being randomly drawn, the probability of getting a quarter is equal to the quotient between the total number of quarters and the total number of coins in the bag.

There are 6 quarters, and the total number of coins is 16, then the probability of randomly selecting a quarter is:

P = 5/16

The correct option is the last one.

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Answer:

Since it is a right triangle, we can apply pythagores theorem.

Answer: a = 8.7 miles

Step-by-step explanation:

a^2 = c^2 - b^2

a^2 = 10^2 - 5^2

a^2 = 100 - 25

a^2 = 75

a ≈ 8.7

Therefore, the length of the missing leg is approximately 8.7 miles.

our final estimate for the area under the curve f(x)=1/x on [1,2] using 4 approximating rectangles and taking the average of the left and right endpoints is 0.76.

To estimate the area under the curve f(x)=1/x on [1,2], we can use 4 approximating rectangles.

a) Using left endpoints, the width of each rectangle is (2-1)/4 = 0.25. The left endpoints of the rectangles are 1, 1.25, 1.5, and 1.75. The height of each rectangle is f(x) evaluated at the left endpoint.

So, the heights are f(1) = 1/1 = 1, f(1.25) = 1/1.25 = 0.8,

f(1.5)=1/1.5 = 0.67, and f(1.75) = 1/1.75 = 0.57.

The area of each rectangle is width times height, so the areas are

0.25*1 = 0.25, 0.25*0.8 = 0.2, 0.25*0.67 = 0.1675, and 0.25*0.57 = 0.1425.

Adding these areas together, we get an estimate of the total area under the curve as

0.25 + 0.2 + 0.1675 + 0.1425 = 0.76.

b) Using right endpoints, the width of each rectangle is the same as before. The right endpoints of the rectangles are

1.25, 1.5, 1.75, and 2.

The heights are f(x) evaluated at the right endpoint. So, the heights are

f(1.25) = 0.8, f(1.5) = 0.67, f(1.75) = 0.57, and f(2) = 0.5.

The areas of the rectangles are the same as before, so adding them up, we get an estimate of the total area as

0.2 + 0.1675 + 0.1425 + 0.25 = 0.76,  

which is the same as before.
c) To get the average of the two estimates, we add them together and divide by 2:

(0.76+0.76) / 2 = 0.76.

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The amount that the first rank takes is 1934 dinars, and the amounts that the second and third ranks take are 967 dinars and 483.5 dinars (rounded to 484 dinars), respectively.

Let's assume that there are three brothers, including Musa. Let X be the amount of money that the brother with the highest average takes, and let Y be the amount of money that the brother with the third rank takes.

According to the given conditions, we can write the following equations:

Let's simplify equation 1:

X + Y = 2900

Also, we know that:

X = (2Y + X)/2

(The amount that the third rank takes is half of what the first rank takes)

Simplifying this equation:

2X = 2Y + X

X = 2Y

Substituting this value of X in equation X + Y = 2900:

3Y = 2900

Y = 2900/3

Y ≈ 966.67

As the amount given must be a whole number between two consecutive natural numbers, we can round Y to the nearest natural number:

Y = 967

Then, X = 2Y = 2*967 = 1934

Therefore, the amount that the first rank takes is 1934 dinars, and the amounts that the second and third ranks take are 967 dinars and 483.5 dinars (rounded to 484 dinars), respectively.

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The polynomial, a⁸ - a²·B⁶ in factored form is; a²·(a³ - B³)·(a³ + B³)

A polynomial consists of the differences or sums of terms that are the product of powers of the same variable.

The specified polynomial can be presented as follows;

a⁸ - a²·B⁶

The common factor in the terms of the polynomial is a², therefore, we get;

a⁸ - a²·B⁶ = a⁶ × a² - a²·B⁶

a⁶ × a² - a²·B⁶ = a²·(a⁶ - B⁶)

(a⁶ - B⁶) = (a³ - B³) × (a³ + B³)

The polynomial is therefore; a⁸ - a²·B⁶ = a²·(a³ - B³)·(a³ + B³)

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Out of the 100 students, 20 like only cola b. Therefore, the probability that a randomly chosen student likes only cola b and does not like cola a is 0.2 or 20%, which is the answer. The answer is option B.

The probability that the student likes cola b and does not like cola a can be calculated as follows

Let's start by finding the number of students who like only cola b. We know that 50 students like cola b in total, but 30 of those students also like cola a. Therefore, the number of students who like only cola b is

50 - 30 = 20

So, out of 100 students, 20 like only cola b. Therefore, the probability that a randomly chosen student likes only cola b is

P(likes only cola b) = 20/100 = 0.2

Therefore, the probability that the student likes cola b and does not like cola a is 0.2.

The answer is option B: 0.2.

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--The given question is incomplete, the complete question is given

" In a class of 100 students, 60 students likes cola a, 50 students likes cola b  and 30 students likes both.  

From class a student is randomly chosen from the group.

what is the probability that the student likes cola b and does not like cola a?

0.1

0.2

0.3

0.4 "--

When x = 3 and dx = 0.4, the differential dy is approximately 4.056, and when x = 3 and dx = 0.8, the differential dy is approximately 8.113.

Differential,

To find the differential dy, we use the formula:

dy = f'(x) * dx

where f'(x) is the derivative of the function y = tan(5x + 5) with respect to x.

Taking the derivative, we get: f'(x) = sec^2(5x + 5) * 5 Plugging in x = 3, we get: f'(3) = sec^2(20) * 5

Now we can find the differential dy for dx = 0.4 and dx = 0.8:

When dx = 0.4: dy = f'(3) * dx dy = sec^2(20) * 5 * 0.4 dy ≈ 4.056

When dx = 0.8: dy = f'(3) * dx dy = sec^2(20) * 5 * 0.8 dy ≈ 8.113

Therefore, when x = 3 and dx = 0.4, the differential dy is approximately 4.056, and when x = 3 and dx = 0.8, the differential dy is approximately 8.113.

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The percent of the customers at Harris Teeter that are adults is 70%

From the question, we have the following parameters that can be used in our computation:

Customers = 160

Children = 48

using the above as a guide, we have the following:

Adults = Customers - Children

substitute the known values in the above equation, so, we have the following representation

Adults = 160 - 48

So, we have

Adults = 112

Next, we have

Percentage = 112/160 * 100%

Evaluate

Percentage = 70%

Hence, the percentage is 70%

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Answer: 72 m²

Step-by-step explanation:

The description concerns Uruguay, option B, since it is the only country among the answer choices that is located in South America to the South of Brazil.

South America is a continent located in the western hemisphere of the Earth. It is situated south of North America, east of the Pacific Ocean, and west of the Atlantic Ocean. The continent is home to 12 independent countries and 3 dependent territories, with a total population of approximately 422 million people.

The largest country in South America is Brazil, followed by Argentina, Peru, and Colombia. The continent is characterized by diverse topography, including the Andes mountain range, the Amazon rainforest, the Atacama Desert, and the Patagonian plains. The region is also known for its rich cultural heritage, including pre-Columbian civilizations such as the Incas and the Mayas, as well as colonial influences from Spain and Portugal. Today, South America is a rapidly developing region with a diverse economy, including agriculture, mining, and manufacturing industries.

Uruguay is also a part of South America. It is located South of Brazil and, as a matter of fact, during colonization, it was a part of Brazil. We can conclude option B is the right answer.

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There are 9 tables with 4 chairs in the restaurant.

Let's establish the variables:

Let x be the number of tables with 4 chairs

Let y be the number of tables with 5 chairs

Let z be the number of tables with 6 chairs

We know that there are a total of 19 tables, therefore:

x + y + z = 19 (equation 1)

We also know that the total number of people that can be accommodated in tables with 4 or 5 chairs is 64, therefore:

4x + 5y = 64 (equation 2)

We want to find the value of x, so we need to eliminate y from the equations above. We can do this by multiplying equation 2 by 4, and then subtracting it from equation 1:

x + y + z - 16x - 20y = 19 - 256

Simplifying:

-15x - 19y = -237

Dividing both sides by -19:

x = 9

Therefore, there are 9 tables with 4 chairs.

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Translated Question: Clear the selection Question 2: In a restaurant for 94 people there are 19 tables that can seat 4.5 or 6 people. If we know that the total number of tables with 4 or 5 chairs can accommodate 64 people, how many tables have 4 chairs?

This function is not differentiable at all points in [tex]R^2[/tex]. To see this, consider the points on the x-axis, where y = 0. At these points, the function is not differentiable because it has a sharp corner.

To show that the function f(x, y) = |y| is differentiable at (0, 0), we need to show that there exists a linear transformation L such that:

[tex]lim (h,k) - > (0,0) [f(0+h,0+k) - f(0,0) - L(h,k)] / \sqrt{(h^2 + k^2)} = 0[/tex]

where f(0,0) = 0 since |0| = 0.

We have:

f(0+h,0+k) - f(0,0) = |k|

Now we need to find L(h,k), which is a linear transformation of (h,k) that approximates f(0+h,0+k) - f(0,0) near (0,0). We can take:

L(h,k) = 0

Since L is a constant function, it is a linear transformation. Also, we have:

f(0+h,0+k) - f(0,0) - L(h,k) = |k|

So we have:

[tex]lim (h,k) - > (0,0) [f(0+h,0+k) - f(0,0) - L(h,k)] / \sqrt{(h^2 + k^2) } = lim (h,k) - > (0,0) |k| / \sqrt{(h^2 + k^2)}[/tex]

Using the squeeze theorem, we can show that this limit is equal to 0, since[tex]|k| < = \sqrt{(h^2 + k^2)}[/tex] for all (h,k) and[tex]lim (h,k) - > (0,0)\sqrt{ (h^2 + k^2) } = 0.[/tex]

Therefore, f(x, y) = |y| is differentiable at (0,0).

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o find the coordinates of the gates in the third quadrant, we need to find the points where the circle and the line intersect in the third quadrant.

Substituting y = 2x into x² + y² - 4x = 9, we get:

x² + (2x)² - 4x = 9

5x² - 4x - 9 = 0

Using the quadratic formula, we find:

x = (-(-4) ± √((-4)² - 4(5)(-9))) / (2(5))

x = (4 ± √136) / 10

We can discard the positive root since it is in the first quadrant. The negative root corresponds to the x-coordinate of the point of intersection in the third quadrant:

x = (4 - √136) / 10 ≈ -0.433

Substituting this value into y = 2x, we get:

y = 2(-0.433) ≈ -0.866

Therefore, the ordered pair that represents the location of the gates in the third quadrant is (-0.433, -0.866).

The polynomial that models the area of Molly's cardboard is 6x^2 + 13x - 5.

How can the area of Molly's cardboard be modeled with a polynomial?

First, we were given that the length of the cardboard can be modeled by 3x - 1 and the width can be modeled by 2x + 5. To find the area, we use the formula:

Area = length x width

So, we substitute the expressions for the length and width:

Area = (3x - 1) x (2x + 5)

Next, we use the distributive property of multiplication to expand the expression:

Area =[tex]6x^2 + 15x - 2x - 5[/tex]

Simplifying, we get:

Area = [tex]6x^2 + 13x - 5[/tex]

Therefore, the polynomial that models the area of Molly's piece of cardboard is [tex]6x^2 + 13x - 5.[/tex]

This polynomial gives us a way to calculate the area of the cardboard for any value of x. For example, if we know that the length of the cardboard is 5 units, we can substitute x = 2 into the polynomial to find the area:

Area =[tex]6x^2 + 13x - 5[/tex]

Area =[tex]6(2)^2 + 13(2) - 5[/tex]

Area = 24 + 26 - 5

Area = 45

So, the area of the cardboard when x = 2 (and the length is 3x - 1 = 5) is 45 square units.

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Answer:

$7973.26

Step-by-step explanation:

PV = $6700

i = 5.8% ÷ 365

n = 3 years · 365

Compound formula

FV = PV (1 + i)^n

FV = 6700 (1 + 5.8% ÷ 365)^(3 · 365)

FV = $7973.26 (rounded to the nearest cent)

Answer:

The value of Eva's investment after 3 years will be approximately $8,108.46. Rounded to the nearest cent, this is $8,108.45.

Step-by-step explanation:

We can use the formula for compound interest:

where:

In this case, we have:

Plugging these values into the formula, we get:

Therefore, the value of Eva's investment after 3 years will be approximately $8,108.46. Rounded to the nearest cent, this is $8,108.45.

The equation to find the number of hours, t, until Patty and Carol are at the same location is: 70t + 50t = 300.


1. Patty and Carol start driving at the same time, towards each other on the same highway.
2. The distance between their cities is 300 miles.
3. Patty drives at an average speed of 70 mph, so in t hours she covers 70t miles.
4. Carol drives at an average speed of 50 mph, so in t hours she covers 50t miles.
5. As they drive towards each other, the sum of the distances they cover should equal the total distance between their cities.
6. Therefore, combining the distances covered by Patty and Carol, we get: 70t (Patty's distance) + 50t (Carol's distance) = 300 (total distance).

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The library is about 26.1 miles from the courthouse.

To solve this problem, we will apply the Pythagorean theorem, which tells us that during a right triangle, the square of the period of the hypotenuse( the longest side) is same to the total of the places of the lengths of the different two sides.

In this instance, the park is on the right angle, and the library and courthouse are the opposite two factors. we can consider the distance among the library and the park because the length of 1 leg of the triangle, and the space among the courthouse and the park as the length of the other leg.

So, using the Pythagorean theorem, we're suitable to calculate the period of the hypotenuse( the distance among the library and the courthouse)

library- to- park distance2 courthouse- to- park distance2 = library- to- courthouse distance2

[tex](14.5)^2 + (21.7)^2 = library-to-courthouse distance^2[/tex]

[tex]210.25 + 471.29 = library-to-courthouse distance^2[/tex]

[tex]681.54 = library-to-courthouse distance^2[/tex]

Taking the square root of both aspects, we get

library- to- courthouse distance[tex]= sqrt(681.54) \approx26.1[/tex]

Accordingly, the library is about 26.1 miles from the courthouse.

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PA is tangent to circle k(O), ∠OAP is a right angle. Similarly, ∠OBP is a right angle.

To prove that m∠P=2·m∠OAB, we need to use the properties of tangents to a circle and the angle relationships between tangent lines and chords in a circle.

First, let's draw a diagram of the situation:

              P

             / \

            /   \

           /     \

          /       \

         /         \

       A-----------B

       /               \

      /                  \

     /                     \

    O                      \

    |                          \

    |                            \

    |                              \

    ----------------------------

We are given that PA and PB are tangents to circle k(O) at A and B, respectively. This means that PA and PB are perpendicular to OA and OB, respectively, at the points of tangency A and B. We can also infer that OA and OB are radii of the circle k(O).

Let ∠OAB = x. Then, ∠OBA = x (since OA = OB), and ∠APB = 180° - ∠OAB - ∠OBA = 180° - 2x.

Since PA is tangent to circle k(O), ∠OAP is a right angle. Similarly, ∠OBP is a right angle. Therefore, ∠OAP + ∠OBP = 180°.

Let ∠P = y. Then, we have:

∠OAB + ∠OBA + ∠APB + ∠P = 180°

x + x + (180° - 2x) + y = 180°

y = 2x

Therefore, we have shown that m∠P = 2·m∠OAB, as required.

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