Answer:
60 m
Explanation:
Given that a cheetah is able to reach quickly a maximum speed of 31.0 m/s. But it is able to maintain this speed for only about 10.0 s.
The distance = speed × time
The distance = 31 × 10
The distance = 310 m
Suppose that the cheetah stalks a prey that has a maximum speed of 25.0 m/s, but is able to maintain this speed for much longer than 10.0 s.
The prey distance = 25 × 10
Distance = 250m
If it is to catch its prey, the maximum distance the cheetah can be from the prey when the chase begins must be:
Maximum distance = 310 - 250
Maximum distance = 60 m
A 10 kg block is pushed with a constant horizontal force of 20 N against a constant horizontal frictional force of 10 N.
What is the acceleration of the block?
1. 2 m/s2
2.5 m/s2
3. Zero
4. None of these
5. 1 m/s2
6. 10 m/s2
7. Insufficient information is provided.
Answer:
1 m/s2
Explanation:
The net force on the block is 20 N-10 N in the direction of its acceleration, so by Newton’s law F=Ma
a=10N/10kg
=1 m/s2
If a volleyball accelerates towards the ground at 10m/s/s and it takes 1.6 seconds to hit the ground, how tall is the building
Answer:
Distance, S = 12.8m
Explanation:
Given the following data;
Acceleration = 10
Time = 1.6
Initial velocity = 0
To solve for acceleration, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting the values into the equation;
[tex] S = 0(1.6) + \frac {1}{2}*10*(1.6)^{2}[/tex]
[tex] S = 5 *2.56[/tex]
Distance, S = 12.8m
Therefore, the height of the building is 12.8 meters.
What is the sum of all of the forces acting on an object
Answer:
Explanation:
The sum of all the forces acting on an object is the net force or resultant force. If all the forces cancel out, the resultant force is zero, else, the unbalanced force will cause acceleration of the object. Force is a vector and hence has both a direction and magnitude. For example, gravitational force (on earth) acts in downward direction and has a magnitude equal to mass of the object and acceleration due to gravity. Once we know all the forces that are acting on a body, we resolve all of them into components (typically horizontal and vertical) and take summation of forces in each direction. If such forces cancel out (in each direction), the object maintains its state of rest or constant motion. If however, forces do not cancel out, there is a net resultant force on the object that will cause acceleration of the object (as given by Newton's second law of motion).
Hope this helps.
The sum of all of the forces acting on an object is called net force. It is categorized as a vector quantity because it has both direction and magnitude to be considered.
What is Force?Force may be defined as the process of pushing or pulling on an object with mass provoking it to change its velocity. It is an external agent capable of altering a body's state of rest or motion. It has a magnitude and a direction, so it is a vector quantity.
Net force in a case where forces of different magnitude and opposite directions will be the difference between greater and lesser force. The combination of the resultant of all the forces acting on an object is called Net Force, which is basically the sum of all the forces acting on that object.
Therefore, the sum of all of the forces acting on an object is called net force.
To learn more about Net force, refer to the link:
https://brainly.com/question/20795823
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If the block in the picture has an acceleration of 5 m/s2, what would be the block's mass?
Answer:
0.4 Kg
Explanation:
From the question given above, the following data were obtained from the question:
Acceleration (a) of block = 5 m/s²
Force in the right direction (Fᵣ) = 3 N
Force in the left direction (Fₗ) = 5 N
Mass (m) of block =...?
Next, we shall determine the net force acting on the block. This can be obtained as follow:
Force in the right direction (Fᵣ) = 3 N
Force in the left direction (Fₗ) = 5 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 5 – 3
Fₙ = 2 N
Thus the net force acting on the block is 2 N to the left.
Finally, we shall determine the mass of the block as follow:
Acceleration (a) of block = 5 m/s²
Net force (Fₙ) = 2 N
Mass (m) of block =...?
Net force (Fₙ) = mass (a) × acceleration (a)
Fₙ = m × a
2 = m × 5
Divide both side by 5
m = 2/5
m = 0.4 Kg
Therefore, the mass of the block is 0.4 Kg
Gas stored in a tank at 273 K has a pressure of 388 kPa. The safe limit for the pressure is 825 kPa. At what temperature will the gas reach pressure?
Answer: At 508k temperature the gas will reach the pressure.
Explanation:
[tex]T_{2} =\frac{P_{2} T_{1}}{P_{1}} \\T_{2} =\frac{825kPa * 237K }{388kPa} = 580k[/tex]
Answer: 580k
Explanation: Gradpoint
Look at SS and answer