Answer:
These are all right answers, just pick the one that matches an answer choice
n^2 * (n-1)/3
(n^3-n^2)/3
((n-1)n^2)/3
Step-by-step explanation:
The general area for a square pyramid is base * height/3
Since we know the edge is n units, we can subsitute the base for:
n*n = n^2 = b
The height is n-1, so lets plug that into the formula too:
n^2 * (n-1)/3
Its a bit hard to tell what the answer choices are, since your formatting is a bit strange, So in the answer section, I will list a couple of different expressions that are all equal, so that I get the right answer choice included.
Alan found 444 marbles to add to the 555 marbles in his collection. Then, he went to the store and tripled the number of marbles he had.
Answer:444+555=999 then(999)^3=9970029999.97*10^8
Step-by-step explanation:
Answer:
the anwser is c
Step-by-step explanation:
What’s the correct answer for this?
｡☆✼★ ━━━━━━━━━━━━━━ ☾
A tangent to a circle forms a right angle with the radius
As it is a right angled triangle, we can use Pythagoras' theorem
a^2 + b^2 = c^2
Rearrange this for a side length:
a^2 = c^2 - b^2
Sub the values in:
a^2 = 6.5^2 - 6^2
a^2 = 6.25
Square root this for the answer
a = 2.5
Thus, your answer is option D
Have A Nice Day ❤
Stay Brainly! ヅ
- Ally ✧
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Answer:
2.5 ft
Step-by-step explanation:
As radius is perpendicular to tangent ,
LT [tex]\perp[/tex]KT
By pythagoras theorem:
LT² = LK² - KT²
LT² = (6.5)² - 6²
LT² = 42.25 - 36
LT² = 6.25
LT = 2.5 ft
LT = radius = 2.5 ft
Suppose that the polynomial function is defined as follows. f(x) = 4(x -11) (x + 9) (x - 5)^3List each zero of according to its multiplicity in the categories below. If there is more than one answer for a multiplicity, separate them with commas. If there is no answer, click on "None." Zero(s) of multiplicity one:_________Zero(s) of multiplicity two:_________ Zero(s) of multiplicity three:_________
Answer:
Zero(s) of multiplicity one: 11,-9
Zero(s) of multiplicity two: None
Zero(s) of multiplicity three: 5
Step-by-step explanation:
Suppose that we have a polynomial function in the following format:
[tex]f(x) = a*(x - x_{0})^{m_{0}}*(x - x_{1})^{m^{1}}*...*(x - x_{n})^{m^{n}}[/tex]
The zeros are [tex]x_{0}, x_{1}, ..., x_{n}[/tex].
The multiplicites are [tex]m_{0}, m_{1},..., m_{n}[/tex]
In this question:
f(x) = 4(x -11) (x + 9) (x - 5)^3
So
11 is a zero of multiplicity 1
-9 is a zero of multiplicity 1
5 is a zero of multiplicity 3.
So the answer is:
Zero(s) of multiplicity one: 11,-9
Zero(s) of multiplicity two: None
Zero(s) of multiplicity three: 5
Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, connuing unl a policy with a claim is found and then stopping. Actuary Toby follows the same procedure with high-risk policies. Each low-risk policy has a 10% probability of having a claim. Each high-risk policy has a 20% probability of having a claim. The claim statuses of polices are mutually independent. Calculate the probability that Actuary Rahul examines fewer policies than Actuary Toby.
Answer:
The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857
Step-by-step explanation:
It is said that Actuary Rahul examines a low risk policy
Probability of a low risk policy having a claim = 10% = 0.1
Actuary Toby examines high risk policy
Probability of a high risk policy having a claim = 20% = 0.2
Let the number of policies examined by actuary Rahul before he finds a claim and stop be n
Probability that actuary Rahul examines exactly n policies = [tex]0.9^{n-1} (0.1)[/tex]
Probability that Toby examines more than n policies = [tex]0.8^n[/tex]
Since the claim statuses of policies are mutually independent, the probability that both events happen simultaneously = [tex]0.9^{n-1} (0.1) (0.8)^n[/tex]
probability that both events happen simultaneously = [tex]\frac{0.1}{0.9} (0.72^{n})[/tex]
The probability that Actuary Rahul examines fewer policies that Actuary Toby = [tex]\sum\limits^ \infty_1 {\frac{0.1}{0.9} 0.72^{n} }[/tex] = [tex]\frac{1}{9}\sum\limits^ \infty_1 { 0.72^{n} } = \frac{1}{9} (\frac{0.72}{1-0.72} ) = \frac{1}{9} (\frac{0.72}{0.28} )[/tex]
The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857
What is the insignificant digit in 0.09040?
Answer:
0
Step-by-step explanation:
The 0, or the last digit is the insignificant digit because it serves no purpose.
Answer:
The last zero in the number is insignificant.
Step-by-step explanation:
The 0 at the extreme right indicates that the number is accurate to the fifth decimal place, that is, one in ten thousandths.
A rectangle has a base length of 12 inches and an unknown height, h. The area of the rectangle is less than 60 square inches. Which inequality can be used to model the problem?
12h < 60
12h > 60
12 + h < 60
12 + h > 60
Answer:
12h < 60
Step-by-step explanation:
A rectangle, with height h and base length l, has the following area.
[tex]A = l*h[/tex]
In this question:
[tex]l = 12, A < 60[/tex]
So
[tex]A < 60[/tex]
[tex]l*h < 60[/tex]
[tex]12h < 60[/tex]
So the correct answer is:
12h < 60
Answer:
12h < 60
hope this helps, its right because i took the test and it shows
3. Compute the nominal annual rate of interest compounded semi-annually on a loan of $48000 repaid in installments of $4000 at the end of every 6 months in 10 years.
Answer:
Rate = 51.74%
Step-by-step explanation:
Principal amount= $48000
Amount paid is done 2 times in a year for ten years
= $4000*2*10
Amount paid= $80000
A= p(1+r/n)^nt
80000= 48000(1+r/20)^(20*10)
(80000/48000)= (1+r/20)^(200)
(200)√(1.6667)= 1+ r/20
1.025870255-1= r/20
0.025870255*20= r
0.5174= r
Rate in decimal= 0.5174
In percentage= 51.74%
Find the value of y.
Answer:
60°
Step-by-step explanation:
The value of y is half the measure of the arc the chord subtends:
y = 120°/2
y = 60°
In converting 10 pounds to ounces, what unit (omit the number) would you
place in the numerator of your ratio? Use the plural form in your answer.
Remember that there are 16 ounces in 1 pound.
Answer:
pounds
Step-by-step explanation:
pounds : ounces
10 : [tex]x[/tex]
1 : 16
[tex]x=160[/tex]
The numerator would be pounds. [tex]\frac{10 pounds}{160 ounces}[/tex]
ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.
Answer:
A. x - 3
Step-by-step explanation:
Set it up like this:
(3x - 2) - (2x + 1)
Combine like terms:
3x - 2 - 2x - 1
3x - 2x = x
-2 - 1 = -3
Put it together:
x - 3
What is the sum 2/x^2 + 4/x^2
There are 560 third- and fourth-grade students in King Elementary School. If there are 80 more third-graders than fourth-graders, how many third-graders are there in the school? work has to be shown
Answer:
There are 200 4th grades and 360 third graders
Step-by-step explanation:
560/2=280-80=200 280+80=360
Cotton On Ltd. currently has the following capital structure: Debt: $3,500,000 par value of outstanding bond that pays annually 10% coupon rate with an annual before-tax yield to maturity of 12%. The bond issue has face value of $1,000 and will mature in 20 years. Ordinary shares: $5,500,000 book value of outstanding ordinary shares. Nominal value of each share is $100. The firm plan just paid a $8.50 dividend per share. The firm is maintaining 4% annual growth rate in dividends, which is expected to continue indefinitely. Preferred shares: 45,000 outstanding preferred shares with face value of $100, paying fixed dividend rate of 12%. The firm's marginal tax rate is 30%. Required: a) Calculate the current price of the corporate bond? (4 marks) b) Calculate the current price of the ordinary share if the average return of the shares in the same industry is 9%? (3 marks) c) Calculate the current price of the preferred share if the average return of the shares in the same industry is 10% (3 marks)
Answer:
a) Calculate the current price of the corporate bond? (4 marks)
$818,18b) Calculate the current price of the ordinary share if the average return of the shares in the same industry is 9%? (3 marks)
$176.80c) Calculate the current price of the preferred share if the average return of the shares in the same industry is 10% (3 marks)
$120Step-by-step explanation:
total debt = $3,500,000 par value 10$ coupon with a YTM of 12%
YTM = [coupon + (F - P)/n] / [(F + P)/2]
0.12 = [100 + (1,000 - P)/20] / [(1,000 + P)/2]
0.12(500 + 0.5P) = 100 + 50 - 0.05P
60 + 0.06P = 150 - 0.05P
0.11P = 90
P = 90/0.11 = $818.18
total debt = $818.18 x 3,500
stock price:
Div₀ = $8.50
Div₁ = $8.50 x 104% = $8.84
g = 4%
rrr = 9%
using the perpetuity growth model:
stock price = $8.84 / (9% - 4%) = $8.84 / 5% = $176.80
preferred stock:
Div = $12
rrr = 10%
using the perpetuity formula:
preferred stock = $12 / 10% = $120
1- A train is travelling at 125mph. How far will it travel in 2 hours?
Answer:
250 miles
Step-by-step explanation:
d= sxt
d= 125x2
125x2= 250
or
mph= miles per hour
there are two hours so 125 +125 =250
Answer=250 miles
In Seaton Park school, 60% of the boys play baseball and 24% of the boys play baseball and football. What percentage of those that play baseball also play football?
Answer:
[tex]0.4\%[/tex]
Step-by-step explanation:
Given: 60% of the boys play baseball and 24% of the boys play baseball and football in Seaton Park School
To find: percentage of those that play baseball also play football
Solution:
Let B denotes boys who play baseball and F denotes boys who play football.
[tex]P(B)=60\%[/tex]
[tex]P(F\cap B)=24\%[/tex]
Percentage of those that play baseball also play football = [tex]P\left ( F|B \right )=\frac{P(F\cap B)}{P(B)}=\frac{24}{60}=\frac{2}{5}=0.4\%[/tex]
In one area, monthly incomes of technology-related workers have a standard deviation of $650. It is believed that the standard deviation of the monthly incomes of non-technology workers is different. 71 non-technology workers are randomly selected and it is determined that these selected workers have a standard deviation of $950. Test the claim that the non-technology workers have a different standard deviation (so different from $650). Use a 0.10 significance level.
Answer:
There is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.
Step-by-step explanation:
Here we have our null hypothesis as H₀: σ² = s²
Our alternative hypothesis is then Hₐ: σ² ≠ s²
We therefore have a two tailed test
To test the hypothesis of difference in standard deviation which is the Chi squared test given as follows
[tex]\chi ^{2} = \dfrac{\left (n-1 \right )s^{2}}{\sigma ^{2}}[/tex]
Where:
n = Size of sample
s² = Variance of sample = 950²
σ² = Variance of population = 650²
Degrees of freedom = n - 1 = 71 - 1 = 70
α = Significance level = 0.1
Therefore, we use 1 - 0.1 = 0.9
From the Chi-square table, we have the critical value as
1 - α/2 = 51.739,
α/2 = 90.531
Plugging the values in the above Chi squared test equation, we have;
[tex]\chi ^{2} = \dfrac{\left (23-1 \right )950^{2}}{650 ^{2}} = 49.994[/tex]
Therefore, since the test value within the critical region, we do not reject the null hypothesis, hence there is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.
Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)?
Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot
Answer:
-3
Step-by-step explanation:
Answer:
[tex](x-4)^2 + y^2= 100[/tex]
Step-by-step explanation:
edgenuity 2020
hope this helps!
Consider the transformation T: x = \frac{56}{65}u - \frac{33}{65}v, \ \ y = \frac{33}{65}u + \frac{56}{65}v
A. Computer the Jacobian:
\frac{\partial(x, y)}{\partial(u, v)} =
B. The transformation is linear, which implies that ittransforms lines into lines. Thus, it transforms the squareS:-65 \leq u \leq 65, -65 \leq v \leq 65 into a square T(S) with vertices:
T(65, 65) =
T(-65, 65) =
T(-65, -65) =
T(65, -65) =
C. Use the transformation T to evaluate the integral\int \!\! \int_{T(S)} \ x^2 + y^2 \ {dA}
Answer:
Step-by-step explanation:
[tex]T: x = \frac{56}{65}u - \frac{33}{65}v, \ \ y = \frac{33}{65}u + \frac{56}{65}v[/tex]
A)
[tex]\frac{d(x,y)}{d(u,v)} =\left|\begin{array}{ccc}x_u&x_v\\y_u&y_v\end{array}\right|[/tex]
[tex]=(\frac{56}{65} )^2+(\frac{33}{65} )^2\\\\=\frac{(56)^2+(33)^2}{(65)^2} \\\\=\frac{4225}{4225} \\\\=1[/tex]
B )
[tex]S:-65 \leq u \leq 65, -65 \leq v \leq 65[/tex]
[tex]T(65,65)=(x=\frac{56}{65} (65)-\frac{33}{65} (65),\ \ y =\frac{33}{65} (65)+\frac{56}{65} (65)\\\\=(23,89)[/tex]
[tex]T(-65,65)=(-56-33,\ \ -33+56)\\\\=(-89,23)[/tex]
[tex]T(-65,-65) = (-56+33,-33-56)\\\\=(-23,-89)[/tex]
[tex]T(65,-65)=(56+33, 33-56)\\\\=(89,-23)[/tex]
C)
[tex]\int \!\! \int_{T(S)} \ x^2 + y^2 \ {dA}[/tex]
[tex]=\int\limits^{65}_{v=-65} \int\limits^{65}_{u=-65}(x^2+y^2)(\frac{d(x,y)}{d(u,v)} du\ \ dv[/tex]
Now
[tex]x^2+y^2=(\frac{56}{65} u-\frac{33}{65} v)^2+(\frac{33}{65} u+\frac{56}{65} v)^2[/tex]
[tex][(\frac{56}{65} )^2+(\frac{33}{65}) ^2]u^2+[(\frac{33}{65} )^2+(\frac{56}{65}) ^2]v^2[/tex]
[tex]=\frac{(65)^2}{(65)^2} u^2+\frac{(65)^2}{(65)^2} v^2=u^2+v^2[/tex]
[tex]\int \!\! \int_{T(S)} \ x^2 + y^2 \ {dA}[/tex]
[tex]=\int\limits^{65}_{v=-65} \int\limits^{65}_{u=-65}(u^2+v^2) du\ \ dv[/tex]
[tex]=\int\limits^{65}_{-65}\int\limits^{65}_{-65}u^2du \ \ dv+\int\limits^{65}_{-65}\int\limits^{65}_{-65}v^2du \ \ dv[/tex]
By symmetry of the region
[tex]=4\int\limits^{65}_0 \int\limits^{65}_0u^2 du \ \ dv + u\int\limits^{65}_0 \int\limits^{65}_0v^2 du \ \ dv[/tex]
[tex]= 4(\frac{u^3}{3} )^{65}_{0}(v)_0^{65}+(\frac{v^3}{3} )^{65}_{0}(u)_0^{65}\\\\=4[\frac{(65)^4}{3} +\frac{(65)^4}{3} ][/tex]
[tex]=\frac{8}{3} (65)^4[/tex]
Can someone help me with this is the hardest one by far
Answer:
10 units
Explanation:
Create a right triangle, determine the a and b side lengths of the triangle by looking at the graph. (See image)
Then use the Pythagorean theorem to find c.
a² + b² = c²
(8)² + (6)² = c²
64 + 36 = c²
100 = c²
Square root both sides to get c.
[tex]\sqrt{100}[/tex] = c
10 = c
What is the complete factorization of p(x)=32x5y−2xy5 over the integers?
Answer:
[tex]p(x)=2xy(2x-y)(2x+y)(4x^2+y^2)[/tex]
Step-by-step explanation:
[tex]p(x)=32x^5y-2xy^5=2xy(16x^4-y^4)=2xy(4x^2-y^2)(4x^2+y^2)\\\\\boxed{p(x)=2xy(2x-y)(2x+y)(4x^2+y^2)}[/tex]
__
The factoring of the difference of squares is applicable:
a^2 -b^2 = (a -b)(a +b)
What is 200÷30=??
Round your answer to the nearest tenths.
Answer: the answer will be 7
Step-by-step explanation:
when i round my answer to the nearest tenths I got 7.
My first answer is 6.66666666667
then I round my answer and got 7 because 6 is bigger than 5 so i can put it as a whole number.
Answer: the answer will be 7
Step-by-step explanation:
when i round my answer to the nearest tenths I got 7.
My first answer is 6.66666666667
then I round my answer and got 7 because 6 is bigger than 5 so i can put it as a whole number.
Let mu denote the true average number of minutes of a television commercial. Suppose the hypothesis H0: mu = 2.1 versus Ha: mu > 2.1 are tested. Assuming the commercial time is normally distributed, give the appropriate rejection region when there is a random sample of size 20 from the population and we would like to test at the level of significance 0.01. Let T be the appropriate test statistic.
A, T > 2.539
B. > 2.845
C. T> .528D. T >2.861
Answer:
A. T > 2.539
Step-by-step explanation:
We have a hypothesis test of the mean, with unknown population standard deviation.
The hypothesis are:
[tex]H_0: \mu = 2.1 \\\\H_a: \mu > 2.1[/tex]
From the hypothesis we can see that the test is right-tailed, so the critical value of t should be a positive value.
The degrees of freedom can be calculated as:
[tex]df=n-1=20-1=19[/tex]
The significance level is 0.01, so the critical value tc should be the one that satisfies:
[tex]P(t>t_c)=0.01[/tex]
Looking up in a t-table, for 19 degrees of freedom, this critical value is tc=2.539.
Question 1
Pogo sells shirts for $14.99 each. Baja Coast has a special deal: buy 2 and
get the third at 30% off the least expensive shirt. There are 3 shirts you want
to buy. At Baja Coast, the 3 shirts you want are $16.99, $15.99, and $15.50.
What is the least amount you can pay for all 3 shirts?
Note - Use the calculator above for help,
Answer:
the cheapest for the 3 shirts you can get is 43.83 (Baja Coast)
Step-by-step explanation:
For the three shirts at Pogo it costs $44.97. However, at the Baja Coast it costs $43.83. So the least amount you pay is $43.87.
Sides KM and FH in the triangles below will be placed together to form a quadrilateral.
Triangle M L K. Side M L has a length of 15 and side L K has a length of 35. Angle L is 110 degrees.Triangle F G H. Side F G has a length of 35 and side G H has a length of 15. Angle G is 110 degrees.
Answer:
Parallelogram (A)
Question:
Sides KM and FH in the triangles below will be placed together to form a quadrilateral.
Triangle M L K. Side M L has a length of 15 and side L K has a length of 35. Angle L is 110 degrees. Triangle F G H. Side F G has a length of 35 and side G H has a length of 15. Angle G is 110 degrees.
Which best describes the quadrilateral that will be formed?
parallelogram
rectangle
rhombus
trapezoid
Step-by-step explanation:
Given:
∆MLK:
Side ML = 15
Side LK = 35
Angle L = 110°
∆ FGH:
Side FG = 35
Side GH = 15
Angle G = 110°
Side MK and FH placed together to form a quadrilateral.
A quadrilateral is a polygon which has 4 sides.
See attachment for diagram
From the diagram and information given:
LK is parallel to FG
ML is parallel to GH
MK = FH
∠L = ∠G (opposite angles are congruent)
Since two pairs of opposite sides are parallel and opposite angles are congruent, it is a paralellogram.
A parallelogram is a quadrilateral which has pairs of opposite sides are parallel and equal.
Answer: Option A
(A) parallelogram
Step-by-step explanation:
Which of the following is NOT a from AGI deduction?
A. Standard deduction
B. Itemized deduction
C. Personal exemption
D. None of these.
All of these are from AGI deductions
The relationship requirement for qualifying relative requires the potential qualifying relative to have a family relationship with the taxpayer.
1. True
2. False
In year 1, the Bennetts' 25-year-old daughter, Jane, is a full-time student at an out-of-state university but she plans to return home after the school year ends. In previous years, Jane has never worked and her parents have always been able to claim her as a dependent. In year 1, a kind neighbor offers to pay for all of Jane's educational and living expenses. Which of the following statements is most accurate regarding whether Jane's parents would be allowed to claim an exemption for Jane in year 1 assuming the neighbor pays for all of Jane's support?
A. No, Jane must include her neighbor's gift as income and thus fails the gross income test for a qualifying relative.
B. Yes, because she is a full-time student and does not provide more than half of her own support, Jane is considered her parent's qualifying child.
C. No, Jane is too old to be considered a qualifying child and fails the support test of a qualifying relative.
D. Yes, because she is a student, her absence is considered as "temporary." Consequently she meets the residence test and is a considered a qualifying child of the Bennetts.
Answer:
1) D. None of these.
2) False
3) C. No, Jane is too old to be considered a qualifying child and fails the support test of a qualifying relative.
Step-by-step explanation:
1) AGI deductions are subtracted from the gross income to calculate the taxable income. Not all the individual's earnings are subject to taxation, therefore some expenses are deducted to calculate the Adjusted Gross Income, the one that will be taxed.
All of the three options listed ( Standard deduction, Itemized deduction, and personal exemption) are AGI deductions.
2) False
The potential qualifying relative does not have to be family/biologically related with the taxpayer. The IRS condition states that he/she is either family related or have lived in the taxpayer's abode for a whole year to be a qualified relative of the taxpayer. So far any of the two conditions are met, it is fine.
C. For a student to be regarded as a qualifying relative of her parents, she must not be up to 24 years at the end of the year according to IRS. Jane is already 25, she is too old and fails the test as a qualifying relative.
Dan earns £388 over the course of a five-day week. How much is that per day?
Answer:
£77.6 per day
Step-by-step explanation:
388/5 = 77.6
Answer:
£77.60
Step-by-step explanation:
388/5=77.6
but remember that this is money so add the 0.
Brittany rents bicycles to tourists. She recorded the height (in cm) of each customer and the frame size (in cm) of the bicycle that customer rented. After plotting her results, Brittany noticed that the relationship between the two variables was fairly linear, so she used the data to calculate the following least squares regression equation for predicting bicycle frame size from the height of the customer: y=x+ What is the residual of a customer with a height of 155 cm who rents a bike with a 51 cm frame?
Answer: -1
Step-by-step explanation:
Here is the complete question:
Brittany rents bicycles to tourists. She recorded the height (in cm) of each customer and the frame size (in cm) of the bicycle that customer rented. After plotting her results, Brittany noticed that the relationship between the two variables was fairly linear, so she used the data to calculate the following least squares regression equation for predicting bicycle frame size from the height of the customer: y'=1/3x + 1/3.
What is the residual of a customer with a height of 155 cm who rents a bike with a 51 cm frame?
The regression equation is given as:
y'=(1/3)x + (1/3)
Since the height is given as 155cm, x=155 cm
The predicted frame size,
y'=(1/3)x + (1/3)
y'=(1/3) × 155+ (1/3)
= 51 2/3 + 1/3
= 52
The observed frame size,
y=51
Residual = Observed y- predicted y
=51-52
= -1
The residual of a customer with a height of 155 cm who rents a bike with a 51 cm frame is -1.
Answer:
-1
Step-by-step explanation:
A can of StarKist tuna has a volume LaTeX: 18\pi\:cm^318 π c m 3 and a height of 2 cm. Find the area of the StarKist label below the wraps around the entire can and does not overlap. Write your answers in terms of LaTeX: \piπ.
Answer:
Area of the StarKist label around the can in terms of π = 12π cm²
Step-by-step explanation:
Given;
the volume of a can of StarKist tuna, V = 18 π cm³
height of the can of StarKist tuna, h = 2 cm
To determine the area of the StarKist label that wraps around the entire can and does not overlap, we assume the can to have a shape of a cylinder.
Volume of the can = πr²h
where;
r is radius of the can
h is height of the can
πr² x 2 = 18 π
2r² = 18
r² = 18/2
r² = 9
r = 3
Area around the can = curved surface area of the can (cylinder)
Curved surface area of the can = 2πr × h = 2πrh
Curved surface area of the can = 2πrh = 2π x 3 x 2 = 12π cm²
Area of the StarKist label around the can in terms of π = 12π cm²
What is the range of the function f(x) = -2(64) + 3?
Answer:
Step-by-step explanation:
f(x) = -2(64) + 3 is not a function of x; it's a constant with the single value -125.
Ensure that you have copied down this problem correctly.
Answer: -2 multiply 64 add 3 equals -125
Step-by-step explanation:
-2 multiply 64 add 3
then multiply 2 and 64 which is 128
then add/subtract: -128 add 3 which is -125
Then final answer -2 multiply 64 add 3 equals -125
Simplify (20!+21!+22!)/44
Answer:
11*20!
Step-by-step explanation:
(20!+21!+22!)/44=
20!(1+21+21*22)/44=
20!(22+22*21)/44=
20!*22*22/44= 11*20!
The simplified expression of (20!+21!+22!)/44 is 20! * 11
How to simplify the expression?The expression is given as:
(20!+21!+22!)/44
The factorial of a number n is:
n! = n * (n - 1)!
So, we start by expanding 22!
(20!+21!+22!)/44 = (20!+21!+22 * 21 * 20!)/44
Next, we expand 21!
(20!+21!+22!)/44 = (20!+21 * 20!+22 * 21 * 20!)/44
Factor out 20!
(20!+21!+22!)/44 = 20! * (1 + 21 + 22 * 21)/44
Evaluate the expression in the bracket
(20!+21!+22!)/44 = 20! * 484/44
Divide
(20!+21!+22!)/44 = 20! * 11
Hence, the simplified expression of (20!+21!+22!)/44 is 20! * 11
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