Answer:
The new standard error is [tex]e_{new} = 23.4[/tex]
Step-by-step explanation:
From the question we are told that
The standard error is [tex]e = 52.4[/tex]
Generally the standard error is mathematically represented as
[tex]e = \frac{6}{\sqrt{n} }[/tex]
Where n is the sample size
for the original standard error we have
[tex]52.4 = \frac{6}{\sqrt{n} }[/tex]
Now sample size is quintuple
[tex]e_{new} = \frac{6}{\sqrt{5 * n} }[/tex]
[tex]but \ \ 52.4 = \frac{6}{\sqrt{n} }[/tex]
So [tex]e_{new} = \frac{52.4}{\sqrt{5} }[/tex]
[tex]e_{new} = 23.4[/tex]
The average marks of candidates in an aptituste test
was 128.5with a standard deviation of 8.2
Three scores extracted from the test are
148,102, 152, what is the average of the
extracted scores that are extreme values
fouthers (out the coutlier)
Answer:
102
Step-by-step explanation:
We must calculate the value of z for each value and then compare each one and thus manage to see what is an outlier, we know that z is equal to:
z = (x - m) / sd
where x is the value to evaluate, m the mean and sd the standard deviation. Now we have to:
For x = 148:
z = (148 - 128.5) /8.2
z = 2.37
For x = 102:
z = (102 - 128.5) /8.2
z = -3.23
For x = 152:
z = (152 - 128.5) /8.2
z = 2.86
The value of this is generally between -3.09 and 3.09, so when x is 102, it goes out of range of the value of z, which means that this is the outlier.
Some contact lens wearers report problems with dryness in their eyes. A study was conducted to evaluate the effectiveness of a new eye-drop solution to relieve dryness for contact lens wearers. Twenty-five volunteers who wore contact lenses agreed to use the new solution for one month. At the end of the month, 36 percent of the volunteers reported that the new solution was effective in relieving dryness. The company that produced the new eye-drop solution concluded that using the new solution is more effective in relieving dryness than using no solution. Which of the following best explains why the study does not support such a conclusion.
(A) The sample size was too small.
(B) The study had no control group.
(C) The participants were volunteers.
(D) The participants self-reported the frequency with which they used the new solution.
(E) The participants self-reported the effectiveness of the new solution.
The preceding help understand why the study doesn't really support such a conclusion: the sample size was too small.
The assumption is approximate [tex]\hat{P}[/tex] by a normal distribution will be:
[tex]np \geq 10[/tex][tex]n (1-p) \geq 10[/tex][tex]n = 25[/tex]→ [tex]np = 25\times 0.36[/tex]
[tex]=9[/tex]
→ [tex]n (1-p) = 25\times (1-0.36)[/tex]
[tex]= 25\times 0.64[/tex]
[tex]= 16[/tex]
The above assumption is not satisfied. Thus the above answer i.e., "option A" is the appropriate one.
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9(5r-2) and 14r-7 yes or no to tell if this expression is equivalent or not
Answer:
No instead of doing multiplication u did division
Step-by-step explanation:
This equation is called distributive property where u multiply the answer from the outside by the inside number
Determine whether the equation is exact. If it is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e Superscript t Baseline )dy equals 0et(7y−3t)dy2+7et dy=0 Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
Answer:
[tex]F(t,y)=(2+7e^t)y+3(1-t)e^t +C[/tex]
Step-by-step explanation:
You have the following differential equation:
[tex]e^t(7y-3t)dt+(2+7e^t)dy=0[/tex]
This equation can be written as:
[tex]Mdt+Ndy=0[/tex]
where
[tex]M=e^t(7y-3t)\\\\N=(2+7e^t)[/tex]
If the differential equation is exact, it is necessary the following:
[tex]\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}[/tex]
Then, you evaluate the partial derivatives:
[tex]\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}[/tex]
The partial derivatives are equal, then, the differential equation is exact.
In order to obtain the solution of the equation you first integrate M or N:
[tex]F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)[/tex] (1)
Next, you derive the last equation respect to t:
[tex]\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)[/tex]
however, the last derivative must be equal to M. From there you can calculate g(t):
[tex]\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t][/tex]
Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:
[tex]F(t,y)=(2+7e^t)y+3(1-t)e^t +C[/tex]
where C is the constant of integration
In an experiment to study the effect of temperature (x) on the yield of a chemical reaction (y), 30 experimental runs were conducted. The level of temperature was carefully controlled at each of five levels, coded as x = -2, -1, 0, 1, 2. Two catalysts were used. For each catalyst three runs were taken at each level of temperature, and the yield was measured. The model y = beta_0 + beta_1x + beta_2x^2 + beta_3z + epsilon, epsilon ~ N(0, sigma^2) was considered, where z = 0 for catalyst 1 and z = 1 for catalyst 2. a. Carefully interpret the parameter beta_3 in this model. b. The model was fit to the data and the output is summarized below. The residual sum of squares is 25.05, and Is there any evidence of a difference in the two catalysts? Find a 95% confidence interval for beta_2. c. We also know that (X'X)^-1 = [0.114 0 -0.023 -0.067 0 0.017 0 0 -0.023 0 0.012 0 -0.067 0 0 0.133] i. Explain why ^beta_1and ^beta_3 are independent random variables. ii. Find a 95% confidence interval for the expected yield when the standard temperature (x = 0) and catalyst 2 are used. iii. Find a 95% prediction interval for the yield of a new experiment run under standard temperature (x = 0) and with catalyst 2.
Answer:
=5
Step-by-step explanation:
Given that an experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.
a) Experimental runs possible if use of single temperature, pressure and catalyst is there = no of temperatures x no of pressures x no of catalysts
= b) Here pressure and temperature have no choice as lowest is selected.
no of methods = no of catalysts x 1 x1
= 5
Overeating for just four weeks can increase fat mass and weight over two years later, a Swedish study shows.Researchers recruited 18 healthy and normal-weight people with an average age of 26. For a four-week period, participants increased calorie intake by (mostly by eating fast food) and limited daily activity to a maximum of 5000 steps per day (considered sedentary). Not surprisingly, weight and body fat of the participants went up significantly during the study and then decreased after the study ended. Participants are believed to have returned to the diet and lifestyle they had before the experiment. However, two and a half years after the experiment, the mean weight gain for participants was 6.8 lbs with a standard error of 1.2 lbs. A control group that did not binge had no change in weight.
Required:
a. Give a 95% confidence interval for parameter.
b. Give the margin of error.
Answer:
a) [tex] 6.8 -2.110*1.2 =4.268[/tex]
[tex] 6.8 +2.110*1.2 =9.332[/tex]
b) [tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]
Step-by-step explanation:
For this case we have the following info given:
[tex] \bar X= 6.8[/tex] represent the sample mean
[tex] Se= 1.2[/tex] represent the standard error
[tex] n =18[/tex] the sample size
Part a
For this case the confidence interval for the mean is given by:
[tex] \bar X \pm t_{\alpha/2} SE[/tex]
The degrees of freedom are given by:
[tex] df =n-1=18-1=17[/tex]
And the critical value for a confidence interval of 95% is given by:
[tex] t_{\alpha/2}=2.110[/tex]
And the confidence interval would be:
[tex] 6.8 -2.110*1.2 =4.268[/tex]
[tex] 6.8 +2.110*1.2 =9.332[/tex]
Part b
The margin of error is given by:
[tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]
if you work make 15 an hour for 8 hour shift how much is that
Answer:
120
Step-by-step explanation:
15*8=120
I promise brainliest for the first to answer. If you roll two number cubes, what is the probability of their sum being 9 or higher? 5/12 1/6 5/36 5/18
Answer:
maybe 3/5
Step-by-step explanation:
I hope it's right
The mean gross annual incomes of certified welders are normally distributed with the mean of $26,589 and a standard deviation of $2,659. The ship building association wishes to find out whether their welders earn more or less than $26,589 annually. The alternate hypothesis is that the mean is not $26,589. Which of the following is the alternate hypothesis? a. H1: <$26,589 b. H1: -$26,589 с. HI:T-826,589 d. Hi: -326,589
Answer:
And based on the claim the system of hypothesis are:
Null hypothesis: [tex] \mu = 26589[/tex]
Alternative hypothesis: [tex] \mu \neq 26589[/tex]
And the best alternative would be:
b. [tex]H_1: \neq $26,589[/tex]
Step-by-step explanation:
For this case we want to test the hypotheis that the true mean is different from 26859. We have the following info given:
[tex] \bar X = 26589[/tex] represent the sample mean
[tex] \sigma =2659[/tex] represent the population deviation
And based on the claim the system of hypothesis are:
Null hypothesis: [tex] \mu = 26589[/tex]
Alternative hypothesis: [tex] \mu \neq 26589[/tex]
And the best alternative would be:
b. [tex]H_1: \neq $26,589[/tex]
On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (negative 6, negative 5) and (0, 0). Line J K goes through (negative 6, 1) and (0, negative 4). Line P Q goes through (negative 5, 4) and (0, negative 2). Which line is perpendicular to a line that has a slope of Negative five-sixths? line JK line LM line NO line PQ
Answer:
no pq
Step-by-step explanation:
Answer:
Line LM
Step-by-step explanation:
Got it right on Edge2020
29 POINTS AND BRAINLIEST !!! Jim likes to rock climb in his spare time. Recently, he climbed down from the top of a cliff to the bottom. At the top, where Jim started, he was 2500 ft above the ground. He moved down the cliff at a speed of 20 ft/min.
a) Write an equation to represent the height h, in feet, that Jim was above the ground after t minutes.
b) Make a table of values for Jim's height above the ground for values of t from 0 to 4.
c) What was Jim's height above the ground after 40 minutes?
d) How many minutes did it take to reach the ground?
Answer:
Step-by-step explanation:
A) y = -20x + 2500
The above equation is written in slope intercept form - y=mx+b - the y int. is 2500, while the rate of change, aka the slope, is -20 feet per minute.
B) (0,2500) (1,2480) (2,2460) (3,2440) (4,2420)
For this question just plug in the x values 0 to 4 into the equation above. For example -20(0) +2500 = 2500
C) 1700 feet above the ground
Plug the number 40 into the equation above. -20(40) + 2500 = 1700
D) 125 minutes
The y-int. represents the time it takes him to reach the ground, this means you can set the equation equal to zero and solve to find the answer.
0 = -20x + 2500
subtract 2500 from both sides
-2500 = -20x
divide -20 from both sides
125 = x
Answer:50m
Step-by-step explanation: the highest
It is known that 25% of inhabitants of a community favour a political party A.
A random sample of 20 inhabitants was selected from the community and each person was asked he/she will vote for party A in an impending election. This follows a Binomial distribution, what is the probability that:
(i) exactly two persons will vote for party A?
(ii) at least three persons will vote for party A?
(iii) fewer than two persons will vote for party A?
Answer:
i) [tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]
ii) [tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]
[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]
[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]
And replacing we got:
[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]
iii) [tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]
Step-by-step explanation:
Let X the random variable of interest "number of inhabitants of a community favour a political party', on this case we now that:
[tex]X \sim Binom(n=20, p=0.25)[/tex]
The probability mass function for the Binomial distribution is given as:
[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]
Where (nCx) means combinatory and it's given by this formula:
[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]
Part i
We want this probability:
[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]
Part ii
We want this probability:
[tex]P(X\geq 3)[/tex]
And we can use the complement rule and we have:
[tex]P(X\geq 3) = 1-P(X<3)= 1-P(X \leq 2) =1- [P(X=0) +P(X=1) +P(X=2)][/tex]
And if we find the individual probabilites we got:
[tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]
[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]
[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]
And replacing we got:
[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]
Part iii
We want this probability:
[tex] P(X <2)= P(X=0) +P(X=1)[/tex]
And replacing we got:
[tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]
which expression is equivalent to -f-5(2f-3)
[tex]\text{One of the expressions can be the simplified version}\\\\\text{Simplify:}\\\\-f-5(2f-3)\\\\\text{Use the distributive property}\\\\-f-10f+15\\\\\text{Combine like terms}\\\\\boxed{-11f+15}\\\\\text{That expression is equivalent to the expression listed in the question}[/tex]
Answer:
11f+5
Step-by-step explanation:
khan
A volleyball is an example of a____a0.
Answer:
sphere
Step-by-step explanation:
A volleyball is a three dimensional object
It is a three dimensional circle which is called a sphere
Answer:
sphere
Step-by-step explanation:
hope this helps:]
To generate new leads for business, Gustin Investment Services offers free financial planning seminars at major hotels in Southwest Florida. Gustin conducts seminars for groups of 25 individuals. Each seminar costs Gustin $3500, and the average first-year commission for each new account opened is $5000. Gustin estimates that for each individual attending the seminar, there is a 0.01 probability that he/she will open a new account.
a. Determine the equation for computing Gustin's profit per seminar, given values of the relevant parameters.
b. What type of random variable is the number of new accounts opened?
c. Construct a spreadsheet simulation model to analyze the profitability of Gustin's seminars. Would you recommend that Gustin continue running the seminars?
d. How large of an audience does Gustin need before a seminar's expected profit is greater than zero?
Answer:
(A) The equation for computing Gustin's profit per seminar; given the values of the relevant parameters is:
π = 0.01AC - 3500
Where π = profit per seminar
A = attendance per seminar
C = commission earning per new account opened
(B) A continuous random variable
(C) No
(D) An audience of 71 persons
STEP BY STEP EXPLANATION:
(A) Profit is equal to total revenue minus total cost.
TR = PAC
Where P = probability that an attendee will open a new account
A = number of attendees per seminar
C = commission Gustin gets from each new account opened.
TC = $3,500
Where cost of organizing 1 seminar is constant at $3,500
So the function for profit per seminar is given thus:
π = TR - TC = 0.01AC - 3500
(B) There are 2 types of random variable; discrete random variable and continuous random variable
We say the number of new accounts opened (NNAO) is a continuous random variable because it is not specific. It is a function of both P and A. It depends on both P and A.
From the profit function or equation we have, we can see that you can't derive the exact NNAO per attendee. It is based on probability so if you were to measure it distinctly, you would have a very minimal value.
Discrete random variables occur in specific intervals e.g. 4, 5, 6,... while continuous random variables occur over an interval; e.g. 4.01, 4.02, 4.03,...
(C) Constructing a spreadsheet simulation model to analyze the profitability of Gustin's seminars, I would not recommend that Gustin continue running the seminars!
(D) The question points to A; which is the total attendance per seminar.
So if we calculate profit with the values given in the full question, we see that profit is negative, hence Gustin is running at a loss with 25 people attending one seminar.
π = (0.01 × 25 × 5000) - 3500
π = -$2,250
So, to make a profit greater than zero, we first check how many attendees it takes for TR to equal TC or for Profit to equal 0.
We set pie π to zero.
0 = (0.01 × 5000 × A) - 3500
0 = 50A - 3500
50A = 3500
A = 70 attendees
So Gustin needs an audience of more than 70 persons before a seminars expected profit will be greater than zero.
A recipe uses cup of brown sugar to make 18 cookies. How many cups of brown sugar are needed to make 45 cookies? ASAP
Answer:
2.5
Step-by-step explanation:
it takes 1 cup to make 18 cookies so you divide 45 by 18 to get your answer
Twenty percent of what number is equal to five percent of 680
Answer:
170
Step-by-step explanation:
5/100 ×680
=34
20%=34what about 100%=?
(100×34)÷20
170
Twenty percent of 170 is equal to five percent of 680.
What is percentage?The term ‘per cent’ means ‘out of a hundred’. In mathematics, percentages are used like fractions and decimals, as ways to describe parts of a whole. When you are using percentages, the whole is considered to be made up of a hundred equal parts. The symbol % is used to show that a number is a percentage.
Let the number be x
According to question:
20% of x = 5% of 680
[tex]\frac{20}{100}[/tex] x = [tex]\frac{5}{100}[/tex] × 680
20 x = 5 × 680
x = 170
Hence, Twenty percent of 170 is equal to five percent of 680.
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Explain how to find the relationship between two quantities, x and y, in a table. How can you use the relationship to calculate the missing values in the table?
Explanation:
In general, for arbitrary (x, y) pairs, the problem is called an "interpolation" problem. There are a variety of methods of creating interpolation polynomials, or using other functions (not polynomials) to fit a function to a set of points. Much has been written on this subject. We suspect this general case is not what you're interested in.
__
For the usual sorts of tables we see in algebra problems, the relationships are usually polynomial of low degree (linear, quadratic, cubic), or exponential. There may be scale factors and/or translation involved relative to some parent function. Often, the values of x are evenly spaced, which makes the problem simpler.
Polynomial relations
If the x-values are evenly-spaced. then you can determine the nature of the relationship (of those listed in the previous paragraph) by looking at the differences of y-values.
"First differences" are the differences of y-values corresponding to adjacent sequential x-values. For x = 1, 2, 3, 4 and corresponding y = 3, 6, 11, 18 the "first differences" would be 6-3=3, 11-6=5, and 18-11=7. These first differences are not constant. If they were, they would indicate the relation is linear and could be described by a polynomial of first degree.
"Second differences" are the differences of the first differences. In our example, they are 5-3=2 and 7-5=2. These second differences are constant, indicating the relation can be described by a second-degree polynomial, a quadratic.
In general, if the the N-th differences are constant, the relation can be described by a polynomial of N-th degree.
You can always find the polynomial by using the given values to find its coefficients. In our example, we know the polynomial is a quadratic, so we can write it as ...
y = ax^2 +bx +c
and we can fill in values of x and y to get three equations in a, b, c:
3 = a(1^2) +b(1) +c
6 = a(2^2) +b(2) +c
11 = a(3^2) +b(3) +c
These can be solved by any of the usual methods to find (a, b, c) = (1, 0, 2), so the relation is ...
y = x^2 +2
__
Exponential relations
If the first differences have a common ratio, that is an indication the relation is exponential. Again, you can write a general form equation for the relation, then fill in x- and y-values to find the specific coefficients. A form that may work for this is ...
y = a·b^x +c
"c" will represent the horizontal asymptote of the function. Then the initial value (for x=0) will be a+c. If the y-values have a common ratio, then c=0.
__
Finding missing table values
Once you have found the relation, you use it to find missing table values (or any other values of interest). You do this by filling in the information that you know, then solve for the values you don't know.
Using the above example, if we want to find the y-value that corresponds to x=6, we can put 6 where x is:
y = x^2 +2
y = 6^2 +2 = 36 +2 = 38 . . . . (6, 38) is the (x, y) pair
If we want to find the x-value that corresponds to y=27, we can put 27 where y is:
27 = x^2 +2
25 = x^2 . . . . subtract 2
5 = x . . . . . . . take the square root*
_____
* In this example, x = -5 also corresponds to y = 27. In this example, our table uses positive values for x. In other cases, the domain of the relation may include negative values of x. You need to evaluate how the table is constructed to see if that suggests one solution or the other. In this example problem, we have the table ...
(x, y) = (1, 3), (2, 6), (3, 11), (4, 18), (__, 27), (6, __)
so it seems likely that the first blank (x) will be between 4 and 6, and the second blank (y) will be more than 27.
Here is your answer | To determine the relationship between quantities, you must determine what to do to the x-values to make them into y-values. The correct operation must turn every x-value into the corresponding y- value in the table. Once you know the relationship, you can use the same operation on all of the x-values that have unknown y-values.
what is 9 1/2 x 1/4? i just need it for a math question on study island.
Answer:
[tex]2 \frac{3}{8} [/tex]
Step-by-step explanation:
[tex]9 \frac{1}{2} \times \frac{1}{4} \\ \frac{19}{2} \times \frac{1}{4} \\ = \frac{19}{8} \\ = 2 \frac{3}{8} [/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
Answer:
2 3/8
Hope this helps :)
what number is to be multiplied with 1/3 to get 1/21
Answer:
1/7
Step-by-step explanation:
Since we do not know the number let us use the alphabet A to represent the unknown number
A × 1/3= 1/21
A/3= 1/21
Cross multiply both sides
A×21= 3×1
21A= 3
Divide both sides by the coefficient of A which is 21
21A/21=3/21
A=1/7
Hence the unknown number is 1/7
Answer:
The number to multiply with 1/3 to get 1/21 is 1/7.
Step-by-step explanation:
The question wants us to find the number you can multiply with 1/3 to get 1/21. The number is unknown but when you multiply that unknown number by 1/3 your answer should be 1/21.
Let
the number to be multiplied with = a
Therefore,
1/3 × a = 1/21
a/3 = 1/21
cross multiply
21a = 3
divide both sides by 21
a = 3/21
a = 1/7
The number to multiply with 1/3 to get 1/21 is 1/7.
Eric’s average income for the first 4 months of the year is $1,450.25, what must be his
average income for the remaining 8 months so that his average income for the year is
$1,780.75?
Answer:
Average income of Eric for the remaining 8 months = [tex]\$1946[/tex]
Step-by-step explanation:
Given: Average income of Eric for the first 4 months of the year is equal to $1,450.25
To find: average income for the remaining 8 months so that his average income for the year is $1,780.75
Solution:
Average income = Total income for the year/Total number of months
Average income of Eric for the first 4 months = $1,450.25
So,
Total income of Eric for the first 4 months = 1,450.25 × 4 = 5801
Let x denotes total income of Eric for the remaining 8 months
Total income for the year = 5801 + x
Therefore,
Average income for the year = [tex]\frac{5801+x}{12}[/tex]
Also, average income for the year is $1,780.75
[tex]1780.75=\frac{5801+x}{12}\\1780.75\times 12=5801+x\\21369=5801+x\\21369-5801=x\\15568=x[/tex]
Total income of Eric for the remaining 8 months = $15568
Average income of Eric for the remaining 8 months = [tex]\frac{15568}{8}=\$1946[/tex]
In a blind taste test, do people prefer pâté or dog food? To investigate, Bohannon et al. (2010) presented 1818 college‑educated adults with unlabeled samples of dog food (Newman's Own Organics Canned Turkey & Chicken) and four meat products meant for humans (duck liver mousse, pork liver pâté, liverwurst, and Spam). Participants were asked to rank their preferences. Two of 1818 participants ranked the dog food first, whereas the other 1616 participants chose one of the other items. Based on these results, can you conclude that people are less likely to prefer dog food over all human food than would be expected by chance? Use the significance level ????=0.05.level α=0.05. C
Answer:
The conclusion is that people are less likely to prefer dog food over all human food than would be expected by chance
Step-by-step explanation:
From the question we are told that
The sample size for first sample is [tex]n_1 = 18[/tex]
The sample size for second sample is [tex]n_2 = 18[/tex]
The number that ranked the dog food first [tex]d = 2[/tex]
The number that chose one of the other items is [tex]h = 16[/tex]
The sample proportion for first sample is
[tex]p(d) = \frac{d}{n}[/tex]
=> [tex]p(d) = \frac{2}{18}[/tex]
=> [tex]p(d) = 0.11[/tex]
The sample proportion for second sample is
[tex]p(h) = \frac{h}{n}[/tex]
[tex]p(h) = \frac{16}{18}[/tex]
[tex]p(h) = 0.8889[/tex]
The value of the pooled proportion is evaluated as
[tex]\= p = \frac{h+d}{18 +18}[/tex]
[tex]\= p = \frac{2+16}{18 +18}[/tex]
[tex]\= p = 0.5[/tex]
[tex]H0: p(d) = p(h)[/tex]
[tex]Ha : p(d) < p(h)[/tex]
Test statistics
[tex]z = \frac{(p(d)) - (p(h))}{\sqrt{\= p (1- \= p) (\frac{1}{n_1} + \frac{1}{n_2} )} }[/tex]
[tex]z = \frac{ 0.1111 - 0.8889}{\sqrt{0.5 (1- 0.5) (\frac{1}{18} + \frac{1}{18} )} }[/tex]
[tex]z = -4.67[/tex]
So since the test statistics is within the rejection region for the left tailed test
The null hypothesis is rejected
The conclusion is that people are less likely to prefer dog food over all human food than would be expected by chance
Please answer this correctly
Answer:
t=13
Step-by-step explanation:
the ratio of the shorter sides is t/4 and the ratio of the longer sides is 26/8 so t=26×4/8=104/8=13
Answer: t=13in
Step-by-step explanation: As you can see in the smaller square, the number 4 is in the place of the letter t. Which means that the width (4) is half of the longitud (8). Therefore, in the bigger square all you need to do it divide the longitud (26) by two, to find the width (t). Which is equal to 13in.
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f(x)=log2(x-3) find the domain of x
Please answer this correctly
Answer:
volume = 75 cubic yards
Step-by-step explanation:
Base is 3×5 or 15 yd²
110-15-15=b×3×2+b×5×2
80=6b+10b
80=16b
Divide both sides by 16
b=5
The height of the rectangular prism is 5 yards
Now the volume is l×w×h
3×5×5=
75 yd³ or 75 cubic yards
Answer:
Volume = 75 yards³
Step-by-step explanation:
Surface Area = 110 yards²
But
Surface area = 2(wl+lb+bw) --(1)
Where w is the width , l is length and b is height
L = 5 yards, w = 3 yards
Putting in (1)
110 = 2{(3)(5)+(5)b+3b}
110 = 2(15+5b+3b)
110 = 2(15+8b)
110 = 30+16b
16b = 110-30
16b = 80
Dividing both sides by 18
b = 5
Now
Volume of rectangular prism = wlb
Where w is width, l is length and b is height
= (5)(3)(5)
= 75 yards³
A committee of six is to be chosen randomly from 50 people, 20 of whom support Party X and 30 support Party Y. What is the probability that the majority of the committee will be Party Y supporters
Ok to choose a committee of six people and the probability that it will be majority of the party supporters.
Probabilty= 30C6/50C6
Probability= 593775/15890700
Probabilty= 0.037
Elizabeth is returning to the United states from Canada. She charges the remaining 300 canadian dollars she has to $250 US dollars. What was $1 US dollar worth in canadian dollars? I got 75000 what did I do wrong?
Answer:
1 us dollar would be worth $0.8333333 Canadian dollars
Step-by-step explanation:
i don't know what you did wrong but you would divide 250/300 to get the amount it's worth. I guess you tried to multiply it, don't do that.
Leah ran the track 8 times. She ran a total of 2,000 meters. How many meters equals 1 lap?
Answer:
250m
Step-by-step explanation:
2000m/ 8laps = 250m
0.38, 1.52)
3
4
Over which interval does the growth rate of the exponential function continue to exceed the growth rate of the linear
function?
x = 0 to x= 3
x = 0 to x= 1.79
x=0.38 to x = 1.79
x= 1.79 to x - 3
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Answer:
The best correct option is C
x = 1.79 to x = 3
Step-by-step explanation:
Making the sport off all little thing that crowed. They are still grouped into 7. Option C is theost appropriate.
Answer:
An exponential function and a linear function are graphed below
Over which interval does the growth rate of the exponential function continue to exceed the growth rate of the linear function?
a) x=0 to x=3
b) x=0 to x=1.79
c) x=0.38 to x= 1.79
d) x= 1.79 to x=3 <<<<<<< correct answer
Step-by-step explanation:
EDGE 2021
5) Horatio Reyes earns 3.625% interest on his account. If his principal is
$6000 and he deposits $150 into the account every 6 days, how much total
interest will Horatio earn after 30 days? *
Answer:
$20.11
Step-by-step explanation:
Solution:-
- We will define the interest rate ( R ) earned on his deposits in the account per annum ( 365 days ).
- He deposits a principal amount of ( P ) = $6,000 once at the start of the accounting period.
- After the principal amount is deposited he deposits $ 150 in the account after every 6 days.
- We will first determine the amount in his account at the end of 30 days.
- We need to see how many additional deposits of $150 were made in these 30 days.
- The ( n ) number of additional deposits can be determined from the ratio of time-span of each deposition and the total accounting period:
[tex]n = \frac{30}{6} = 5[/tex]
- Horatio Reyes makes ( n = 5 ) additional deposits after the principal amount till the end of 30th day.
- Now we can calculate the total amount accumulated ( A ) in his account at the end of 30 days time period. It comprises of the initial principal amount and the 5 series of $150 deposits:
[tex]A = P + $150*n[/tex]
- Plug in the respective amounts ( P and n ):
[tex]A = 6000 + 150*5\\\\A = 6000 + 750\\\\A = 6750[/tex]
- At the end of 30th day Horatio Reyes has $6,750 in his account.
- The interest rate ( r ) applied at the end of the 30-day time period is sub-part of the total interest rate ( R ) applied per annum.
- So the interest rate applied at the end of 30-day tim period is determined from simple proportional ratios of time-period:
Rate(%) Time(days)
R: 3.625 365
r: x 30
========================================
x = 30*3.625 / 365 = 0.29795%
========================================
- Now we will apply the rate ( r ) on the accumulated amount ( A ) by the end of 30-day time period in the account to determine the interest earned ( I ):
[tex]I= \frac{r*A}{100} \\\\I = \frac{0.29795*6750}{100} \\\\I = 20.111[/tex]
- The amount of interest earned ( I ) is $20.11 after 30 days.