Answer:
R = 0.1 ohms
Explanation:
It is given that,
Voltage of the battery, V = 12.5 V
Current flowing in the car's starter, I = 125 A
We need to find the effective resistance of a car's starter. It can be calculated using Ohm's law. Let R is the resistance.
[tex]V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{12.5}{125}\\\\R=0.1\ \Omega[/tex]
So, the resistance of the car's starter is 0.1 ohms.
Collision 1: Blue Cart Initially at Rest Set the initial blue cart velocity to 0 m/s. Set the mass values to different values. Run the simulation and record the mass and velocity values. Before Collision After Collision mRed = _________ kg mBlue = _________ kg Use mass and velocity values to complete the following momentum table. Before Collision After Collision ∆Momentum Red Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s Blue Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s
Answer:
it is very hard but i am trying to help you.
Explanation:
What is the force of gravity on a 24.0 kg table sitting on the earth
Answer:
24×9.8Explanation:
the process of converting a solid into liquid at its melting point is called fusion(true or false)
False, the process of converting a solid into liquid at its melting point is called melting.
What is fusion ?
When two light atoms combine to form a new heavier nucleus this process is known as fusion. For example, when two hydrogen atoms combine to form helium atom.
Upon reaching a substance's melting point, the heat supplied by the substance (latent heat of fusion) causes the molecules to drift apart and the substance changes state (solid to liquid) by increasing its internal energy, resulting in a temperature decrease and a change of state (solid to liquid).
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how is matter identified
Answer:
It can be identified using physical properties such as density
Explanation:
Matter is any substance that has mass and takes up space. Therefore, it can be identified using physical properties such as density
Explanation:
We can identify matter by:
1.physical properties.
2.chemical properties.
Hope this helps...
What does a simple pulley do?
A. It makes you have to pull harder on the rope.
B. It increases the force.
O O O O
C. It redirects the force.
D. It makes the load heavier.
Answer:
C. It redirects the force
how can the nail be demagnetised
Explanation:
How do you demagnetize a nail?
To unscrew the magnetized nail or to demagnetize a nail magnetized by prolonged contact or rub, banging the nail on a hard surface or dropping it to the ground shaking up the aligned atoms with a sharp effect. For the electric magnet, simply separating one end of the copper wire from the terminal kills the magnetic field
Hope this can help you. Good Luck!
If you push on a wall of a building what will happen
Answer: It will push back with an equal amount of force.
A women walks 550m North,then 350 m west,then 250 m south ,then 450m east, and finally 150 m south.The whole journey took 1 hour 45 minutes.
a)construct a scale diagram to illustrate the path of the women.Scale:1cm=100
Answer:
The scale diagram is in the image attached
Explanation:
The scale diagram is in the image attached.
The North direction is upwards in the diagram, the West is to the left, the East is to the right and the South is downwards.
First movement: 550m north -> 5.5 cm upwards
Second movement: 350m west -> 3.5 cm to the left
Third movement: 250m south -> 2.5 cm downwards
Fourth movement: 450m east -> 4.5 cm to the right
Fifth movement: 150m south -> 1.5 cm downwards
Hope it helps!
Which are referred to as greenhouse gases?
nitrogen and oxygen
oxygen and carbon dioxide
water vapor and oxygen
water vapor and carbon dioxide
(Plz help)
A small object is placed on the principal axis of a convex mirror of focal length 10cm . Determine the position of the image when the object is 15cm from the mirror.
Answer:
v = 6 cm
Explanation:
We have,
A small object is placed on the principal axis of a convex mirror of focal length 10 cm. The focal length of a convex mirror is positive. So, f = +10 cm
It is required to find the position of the image when the object is 15 cm from the mirror. Using mirror's formula :
[tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]
v is image distance
[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{+10}-\dfrac{1}{(-15)}\\\\v=6\ cm[/tex]
Hence, the image will formed at a distance of 6 cm form the mirror.
a footballer took a penalty kick and ball moved with a velocity of 4mls, calculate the work done by the footballer if the mass of the ball was 40g
Answer:
Work done = 80 gm/s
Explanation:
Given:
Final velocity (v) = 4 m/s
Initial velocity (u) = 0 m/s
Mass of ball (m) = 40 g
Find:
Work done.
Computation:
Using work energy rule
Work done = Change in kinetic energy
Work done = 1/2[mv-mu]
Work done = 1/2[(40)(4) - (40)(0)]
Work done = 1/2[(40)(4)]
Work done = 80 gm/s
A woman stands in a boat at rest on a calm lake. She throws a 10 kg anchor off the front of the boat, which has a mass of 1,000 kg
What is the initial momentum of the anchor-boat system?
A)1,000 kg m/s
B)zero because both objects are at rest.
C)1,010 kg m/s
D)10,000 kg m/s
PLEASE HELP!! I don’t understand
Answer: B) zero because both objects are at rest
Explanation:
Given the following :
Mass of anchor = 10kg
Mass of boat = 1000kg
Note : both boay and anchor are at rest, this gives a Velocity of zero
The momentum of a body is given as the product of Mass and velocity, that is,
Momentum = mass × velocity
Initial Momentum of anchor-boat system =
(mass of boat× initial velocity of boat) + (mass of anchor × initial velocity of anchor)
Initial Velocities of boat and anchor = 0
Therefore,
Initial momentum = (1000 × 0) + (10 × 0)
Initial momentum = (0 + 0) = 0
This is ecause both objects are at rest.
he Volume in an experiment is changed (in mL) is 200, 100, 50, 25, 12.5 and we measured the pressure (in atm) is 0.1000, 0.2000, 0.4000, 0.8000, 1.6000 then the slope of the graph will be... (Hint: You may want to draw it out first. Keep the numbers in order when you create your data table.)
Answer: Slope = - 1000.
Explanation:
The line of best fit of the graph will be linear.
The general linear equation can be expressed as;
Y = MX + C
Where the Y variable represents the volume in the experiment as dependent variable and the X represent the pressure as independent variable.
The equation can be rewritten as:
V = MP + C
Where C is the intercept.
Given that
V = 200, 100, 50, 25, 12.5 and
Pressure P = 0.1000, 0.2000, 0.4000, 0.8000, 1.6000
The slope M can be calculated by using the formula
M = (V2 - V1)/ (P2 - P1)
Where V1 = 200, V2 = 100, P1 = 0.1, P2 = 0.2
Substitute all the parameters into the formula
M =( 100 - 200)/ ( 0.2 - 0.1 )
M = -100/0.1
Slope M = - 1000
8. An object starts from rest and accelerates at
1.30 m/s2 [N] for 6.00 s. What is the final
velocity of the object?
need help
Answer:
here is the answer
Explanation:
initial velocity= u= 0
final velocity = v
acceleration= 1.30m/s²
time= 6 seconds
using formula
a = v-u/t
1.30 = v - 0/6
1.30*6 = v - 0
7.8= v - 0
7.8 = v
therefore, final velocity is 7.8 m/s
A positive charge of 1 µC is taken from points A & B such that VA-VB = 100 V. Then the
energy of charge increases by 10-3 J
energy of charge decreases by 10-3 J
energy of charge remains unchanged
energy of charge decreases by 103
Explanation:
It is given that,
Let Charge of [tex]1\ \mu C[/tex] is taken from points A & B such that [tex]V_A-V_B=1000\ V[/tex].
We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,
[tex]W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J[/tex]
So, the energy of charge decreases by [tex]10^{-3}\ J[/tex]. Hence, the correct option is (a).
A car of mass 750 kg has an initial speed of 75 mph. Traveling in a straight line, its speed is increased uniformly to 120 mph in 2.0 miles. What is the net force that was exerted?
Explanation:
ESTE PROBLEMA ES MEJOR HACERLO EN SI. PRIMERO CONVIERTES
LA VELOCIDAD INICIAL Y LA VELOCIDAD FINAL A m/s
[tex]v_{0}[/tex] = 33.52 m/s v = 53.67 m/s x = 3220 m
PRIMERO ENCUENTRAS LA ACELERACIÓN DEL COCHE CON LA ECUACIÓN
DE GALILEO GALILEI
a = [tex](53.67 m/s)^{2} - (33.52 m/s)^{2}/3220 m[/tex] = [tex]0.5453 m/s^{2}[/tex]
AHORA CON LA ACELERACIÓN USMOS LA SEGUNDA LEY DE NEWTON
F = 75 kg([tex]0.5453 m/s^{2}[/tex]) = 40.9 N
the force exerted by the mass is 204 N.
The given parameters;
mass of the car, m 750 kg
initial speed of the car, u = 75 mph
final speed of the car, v = 120 mph
distance traveled by the car, s = 2 miles
The acceleration of the car is calculated as;
[tex]v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{120^2 - 75^2}{2\times 2} \\\\a = 2193.75 \ mi/hr^2\\\\a = 2193.75 \frac{mi}{hr^2} \times \frac{1609.3 \ m}{1 \ mile} \times \frac{1hr^2}{(3600 \ s)^2} \\\\a = 0.272 \ m/s^2[/tex]
The force exerted by the mass is calculated as follows;
F = ma
F = 750 x 0.272
F = 204 N
Thus, the force exerted by the mass is 204 N.
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a runner with a mass of 62 kg running at speed of 0.8m/s
According to the question,
Mass, m = 62 kgSpeed, v = 0.8 m/sThe Kinetic Energy will be:
= [tex]\frac{1}{2}mv^2[/tex]
By putting the values,
= [tex]\frac{1}{2}\times 62\times (0.8)^2[/tex]
= [tex]31\times 0.64[/tex]
= [tex]20 \ Nm[/tex]
Thus the above answer is right.
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If the mass of the tritium nucleus is 3.02 universal mass units and the mass of the helium nucleus is 4.00 universal mass units, how much energy (in Megaelectronvolts) is absorbed as the tritium decays into helium?
Answer: the answer is a
Explanation just did the test
at what point does the external energy enter the system?
Spaceship 1 and spaceship 2 have equal masses of 150kg. Spaceship 1 has the speed of 0 m/s and spaceship 2 has a speed of 6 m/s. They collide and stick together and what is their speed ?
Answer:
3 m/s
Explanation:
The computation of speed is shown below:-
We will compute the equation by using the law of conservation of momentum; also, the total momentum prior and following the collision must be conserved. Therefore we can write the equation is the following manner:-
[tex]m_1 u_1 + m_2 u_2 = (m_1 +m_2)v[/tex]
where the symbols represent
150 kg is the mass of spaceship 1 = m1
150 kg is the mass of spaceship 2 = m2
0 m/s is the initial velocity of spaceship 1 = u1
6 m/s is the initial velocity of spaceship 2 = u2
and v is the velocity of the 2 ships so that they can collide and combined together
For v we will get the following equation to reach the speed
[tex]v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}[/tex]
[tex]=\frac{0+(150)(6)}{150+150}[/tex]
[tex]=3 m/s[/tex]
Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is Sasha’s tangential speed?
-0.9 m/s
-1.3 m/s
-2.7 m/s
Answer: 2.7 m/s
Explanation:
Given the following :
Period (T) = 8.2 seconds
Radius = 3.5 m
The tangential speed is given as:
V = Radius × ω
ω = angular speed = (2 × pi) / T
ω = (2 × 22/7) / 8.2
ω = 6.2857142 / 8.2
ω = 0.7665505
Therefore, tangential speed (V) equals;
r × ω
3.5 × 0.7665505 = 2.6829268 m/s
2.7 m/s
Answer:
2.7
Explanation:
edge
Why do your legs appear shorter when standing in water
difinition of static coefficient friction
Explanation:
Static friction is a type of friction in which two objects don't move relative to each other. The force due to static friction is given by :
[tex]F=\mu_s N[/tex]
N is normal force
[tex]\mu[/tex] is coefficient of static friction
For the kinetic friction, the force becomes :
[tex]F=\mu_kN[/tex]
An electric pole casts a shadow of 24 m long . If the tip of the shadow is 25m far from the top of the pole , how high is the pole?????
Answer:
7 m
Explanation:
a^ + b^=c^
a^ + 24^=25^
a^+576=625
a^=625-576
a^=49
a=7
A rocket weighing 560,000 N is taking off from Earth with a total thrust of
700,000 N at an angle of 20 degrees, as shown in the image below. What is
the approximate vertical component of the net force that is moving the rocket
away from Earth?
A. 76,000 N
B. 112,000 N
C. 132,000 N
D. 98,000 N
Answer:
D
Explanation:
LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL
COHETE.
[tex]F_{y}[/tex] = 700000 N(sen 90° - 20°) - 560000 N = 97785 N
The approximate vertical component of the net force that is propelling the rocket away from Earth is 112,000 N. Option B is correct.
The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. The thrust force is pointing upwards at an angle of 20 degrees, and the weight of the rocket is pointing downwards. The thrust force is the force that is generated by the rocket engine. It is the force that propels the rocket upwards.
The weight of the rocket is the force of gravity acting on the rocket. It is the force that pulls the rocket downwards. The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. If the net force is positive, the rocket will accelerate upwards. If the net force is negative, the rocket will accelerate downwards. If the net force is zero, the rocket will remain at rest.
net force = thrust force + weight
vertical component of net force = thrust force * cos(angle)
vertical component of net force = 700,000 N * cos(20 degrees) = 112,000 N. Option B is correct.
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A ramp with a mechanical advantage of 4 is used to move a 38-newton load. What
effort force is needed to push the load up the ramp?
A.9.5 N
B.15.2N
C.3.9 N
D.0.11 N
Explanation:
It is given that,
Mechanical advantage of a ramp is 4
It is used to move a 38 N load
We need to find the force needed to push the load up the ramp. The mechanical advantage is equal to the ratio of output force to the input force. We have output force as 38 N
So,
[tex]4=\dfrac{38}{F_i}\\\\F_i=\frac{38}{4}\\\\F_i=9.5\ N[/tex]
So, the force of 9.5 N is needed to push the load up the ramp.
The law of conservation of energy states...
1) A U-tube, in which both ends are open to the atmosphere, is partially filled with water. Oil which does not mix with water is poured into one side of the tube until it stands a distance d=12.3 mm above the water level on the other
side which has meanwhile risen a distancea=67.5 mm from its original level Find the density of the oil
2) The mercury column in a barometer has a measured height h of 740.35 mm. the temperature is-5.0 C
which temperature the density of mercury is 1.3608 104 kg/m3. the free-fall acceleration at the site of the
barometer is 9.7835 m/s2. What is the atmospheric pressure?
Answer:
1) 916 kg/m³
2) 9.8566×10⁴ Pa
Explanation:
1) Originally, the water is at the same level on both sides. When the oil is added, one side goes down 67.5 mm and the other side goes up 67.5 mm. The top of the oil is 12.3 mm above the water, so the total height of the oil relative to the low end of the water is:
12.3 mm + 67.5 mm + 67.5 mm = 147.3 mm
And the height of the water relative to the low end is:
67.5 mm + 67.5 mm = 135 mm
The pressure at the bottom of the oil equals the pressure of the water at the same elevation.
P = P
ρgh = ρgh
ρh = ρh
ρ (147.3 mm) = (1000 kg/m³) (135 mm)
ρ = 916 kg/m³
2) P = ρgh
P = (1.3608×10⁴ kg/m³) (9.7835 m/s²) (0.74035 m)
P = 9.8566×10⁴ Pa
the weight of a body of certain mass becomes zero in space.why?write with reasons
Answer:
Weight is what you get when a certain amount of gravity is acting on that mass, and something, like the surface of a planet, is resisting that action. In space, when falling freely, there's nothing resisting the pull of gravity so weight disappears. Mass however stays.
hope this helps u
Explanation:
what is the method of charging used when you run a straw with fur
Answer:
charging by friction
Explanation:
Friction is another method of making a charge become higher than the other.
With either straw or a fur,charging by friction is used.