Answer:
There are 0.09996826 moles per liter of the solution.
Explanation:
Molar mass of HNO3: 63.02
Convert grams to moles
0.63 grams/ 63.02= 0.009996826
Convert mL to L and place under moles (mol/L)
100mL=0.1 L
0.009996826/0.1= 0.09996826 mol/L
The concentration of the HNO₃ solution is 10⁻¹ moles per liter.
What is Molar Concentration ?
Molar Concentration is known as Molarity. It is the number of moles of solute present in per liter of the solution.
Molar concentration in terms of Molecular weight
C = [tex]\frac{m}{V} \times \frac{1}{M.W}[/tex]
where,
C is the molar concentration in mol/L
m is the mass or weight of solute in grams
V is volume of solution in liters
M.W is the molecular weight in g/mol
Molar concentration of HNO₃ = [tex]\frac{\text{Mass of}\ HNO_3}{\text{Liter of solution}} \times \frac{1}{\text{Molecular weight of}\ HNO_3}[/tex]
Molecular weight of HNO₃ = Atomic weight of H + Atomic weight of N + 3 (Atomic weight of O)
= 1 + 14 + 3 (16)
= 15 + 48
= 63 g/mol
Convert mL into L
1 mL = 0.001 L
100 mL = 100 × 0.001
= 0.1 L
Now, put the value in above formula we get
Molar concentration of HNO₃ = [tex]\frac{\text{Mass of}\ HNO_3 / \text{Liter of solution}}{\text{Molar mass of}\ HNO_3}[/tex]
= [tex]\frac{0.63\ g / 0.1\ L}{63\ g/mol}[/tex]
= [tex]\frac{6.3}{63}[/tex]
= 0.1
= 10⁻¹ moles per liter
Thus, we can say that 10⁻¹ moles per liter is the concentration of the HNO₃ solution.
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How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start text, space, g, end text of \text{Na}Nastart text, N, a, end text and 23.0 \text{ g}23.0 g23, point, 0, start text, space, g, end text of \text{Cl}_2Cl
2
start text, C, l, end text, start subscript, 2, end subscript?
Answer:
18.7887 g of NaCl
Explanation:
The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?
Let us start by writing out the balanced equation of the reaction:
Na + Cl2 ---> NaCl2
1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.
mole = mass/molar mass
Therefore
18 g of Na = 18/23 = 0.7826 mole
23 g of Cl2 = 23/71 = 0.3239 mole
In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence
0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.
mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g
Hence, 18.7887 grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.
Which pathogen do you think responds faster to treatments provided by doctors? Explain your reasoning.
ANSWER: From experience and observation, the pathogen that responds more faster to treatments are PARASITES.
This is because, our body are already used to parasite, as they feed and mostly live inside our body. Parasites becomes harmful to our body, when it is allowed to be much in the body, thereby weakening the immune system of the body. Intake of vaccination reduces the number of parasites in the body, which gives the immune system the chance of recovering and protecting the body.
Parasite does not replicate more faster like viruses and other pathogens. These makes it more easier for treatment to work more faster. They are also easily killed by taking the proper treatment, and the rate of their replications are very slow when compared to the rate of their death when vaccinated.
Some example disease caused by parasites are:
1) Giardiasis
2) Trichomoniasis
3) Malaria
4) Toxoplasmosis
5) Intestinal worms
6) Pubic lice
All this disease above responds very fast to medical treatment, unless when they is complications, which are mostly when the parasite has been allowed to cause more harm and replicate much in the body, without any treatment. This is why doctors advice patients that lives at the tropical regions to periodically vaccinate themselves on parasitic infections.
The number of molecules in one mole of lithium acetate are...
Answer:
6.0221409e+23
Explanation:
The number of molecules in a mole of any substance is Avogadro's number, 6.0221409e+23.
Calculate the standard enthalpy of formation of NOCl(g) at 25 ºC, knowing that the standard enthalpy of formation of NO(g) at that temperature is 90.25 kJ / mol, and that the standard molar enthalpy of the reaction 2 NOCl(g) → 2 NO(g) + Cl2(g) is 75.5 kJ / mol at the same temperature.
Answer:
The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol
Explanation:
The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:
Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants
In this case, you have: 2 NOCl(g) → 2 NO(g) + Cl₂(g)
So, ΔH=[tex]2*H_{NO} +H_{Cl_{2} }-2*H_{NOCl}[/tex]
Knowing:
ΔH= 75.5 kJ/mol[tex]H_{NO}[/tex]= 90.25 kJ/mol[tex]H_{Cl_{2} }[/tex]= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound the chlorine Cl₂)[tex]H_{NOCl}[/tex]=?Replacing:
75.5 kJ/mol=2* 90.25 kJ/mol + 0 - [tex]H_{NOCl}[/tex]
Solving
-[tex]H_{NOCl}[/tex]=75.5 kJ/mol - 2*90.25 kJ/mol
-[tex]H_{NOCl}[/tex]=-105 kJ/mol
[tex]H_{NOCl}[/tex]=105 kJ/mol
The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol
(a) Show that the pressure exerted by a fluid P (in pascals) is given by P = hdg, where h is the column of the fluid in metres, d is the density in kg/m-3, and g is the acceleration due to gravity (9.81 m/s2). (Hint: See Appendix 2.). (b) The volume of an air bubble that starts at the bottom of a lake at 5.24C increases by a factor of 6 as it rises to the surface of water where the temperature is 18.73C and the air pressure is 0.973 atm. The density of the lake water is 1.02 g/cm3. Use the equation in (a) to determine the depth of the lake in metres.
Answer:
B) THE DEPTH OF THE LAKE IS 0.060 m
Explanation:
b) Determine the depth of the lake in metres
1. Using the general gas law, we will calculate the initial pressure of the air bubbles.
P1V1 /T1 = P2V2/T2
P1 = Unknown
T1 = 5.24 °C
T2 = 18.73 °C
P2 = 0.973 atm
V1 = V1
V2 = 6V1
P1 = P2 V2 T1 / V1 T2
P1 = 0.973 * 6V1 * 5.24 / V1 * 18.73
P1 = 5.09852 * 6 / 18.73
P1 = 30.59112 / 18.73
P1 = 1.633 atm.
2. Calculate the depth of the lake:
Pressure = length * density * acceleration
length = Pressure / density * acceleration
Pressure = 1.633 atm = 1.633 * 101, 325 Nm^2 = 165, 463.725 Nm^2
Density = 1.02 g/cm3 = 1.02 * 10^3 kg/m^3
Acceleration = 9.8 m/s^2
So therefore, the length in metres is:
Length = density * acceleration / pressure
Length = 1.02 *10^3 * 9.8 / 165, 463.725
Length = 9.996 * 10^3 / 165 463.725
Length = 0.06 m
Hence, the depth of the lake is 0.06 m
An unknown substance has a mass of 15.5 g . When the substance absorbs 1.395×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to 45.0 ∘C . What is the most likely identity of the substance?
Answer:
iron (Fe)
Explanation:
Use q = mcΔT.
q = 1.396 x 10^2 J
m = 15.5g
ΔT = (45.0 - 25.0) = 20 degrees celcius
1.396 x 10^2 = 15.5 x c x 20
c = .450 J/g x degrees celcius
This is closest to the specific heat of iron/steel.
A mountain has a height of 2.74 miles. How high is the mountain in meters? Use the fact that 1 mi=1.609 km .
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a
Answer:
Explanation:
Hydrobromic acid solution of unknown concentration is titrated with a 0.500M LiOH solution.
20.00mL of the acid are poured into an Erlenmeyer flask.
40.00mL of the base solution is required to reach the equivalence point.
What is the molarity of the Hydrobromic acid solution?
Answer:
1.00 M
Explanation:
Step 1: Write the balanced equation
HBr + LiOH ⇒ LiBr + H₂O
Step 2: Calculate the reacting moles of lithium hydroxide
40.00 mL of 0.500 M solution react. The reacting moles of LiOH are:
[tex]40.00 \times 10^{-3} L \times \frac{0.500mol}{L} = 0.0200 mol[/tex]
Step 3: Calculate the reacting moles of hydrobromic acid
The molar ratio of HBr to LiOH is 1:1. The reacting moles of hydrobromic acid are 1/1 × 0.0200 mol = 0.0200 mol.
Step 4: Calculate the molarity of hydrobromic acid
0.0200 moles of HBr are in 20.00 mL of the solution. The molarity of the hydrobromic acid solution is:
[tex]M= \frac{0.0200 mol}{20.00 \times 10^{-3} L } =1.00 M[/tex]
I NEED HELP PLEASE, THANKS!
Solids, liquids and gases are the three most commonly accepted phases of matter. Explain the properties of each phase, including their relative energy.
Answer:
Solids have a definite shape and volume. Liquids have a definite volume, but take the shape of the container. Gases have no definite shape or volume.
Explanation:
Answer:
Liquids properties include retention of volume and its conformation to the shape of its container. The
particles in a liquid have more kinetic energy than the particles in the corresponding solid. Solids are
structurally rigid and resist changing shape or volume. Solid particles have the least amount of kinetic
energy. Properties of gas include easily compressible, the expand to fill their container and they occupy
more space than a solid or liquid. Gas particles have the most amount of kinetic energy
Explanation:
The pyruvate dehydrogenase complex is subject to allosteric control, especially inhibition by reaction products. From the list below, select the main regulatory processes controlling pyruvate dehydrogenase's activity in eukaryotes.
a. AMP binding to and activating the enzyme.
b. Phosphorylation by a kinase using ATP (which turns the complex off) and dephosphorylation by a phosphatase (which turns the complex on).
c. Exchange of ADP and ATP on the pyruvate dehydrogenase complex.
d. Phosphorylation by a kinase using ATP (which turns the complex on) and dephosphorylation by a phosphatase (which tums the complex off).
Answer:
The correct option is B
b. Phosphorylation by a kinase using ATP (which turns the complex off) and dephosphorylation by a phosphatase (which turns the complex on).
Explanation:
The pyruvate dehydrogenase complex is described as a complex having many enzymes that catalyse decarboxylation of pyruvate by oxidation to yield NADH and acetyl‐CoA, which makes the influx of acetyl-coA from glycolysis to increase into the Krebs cycle.
It can be found in the mitochondrial matrix and pyruvate which is conveyed through enzyme Pyruvate Translocase to PDH complex.
Regulation of pyruvate dehydrogenase complex occured through allosteric effectors as well as phosphorylation.the main regulatory processes controlling pyruvate dehydrogenase's activity in eukaryotes such as plants and animals Phosphorylation is by a kinase using ATP which first turns the complex off and the later dephosphorylation by a phosphatase which turns the complex on
2) A sample of 113min has a half-life of 100. minutes. What amount of 113m In remains (in CPM) if a
10,000 CPM sample is allowed to decay for 5.0 hours?
Answer:
THE AMOUNT OF THE SAMPLE REMAINING AFTER 5 HOURS IS 1250 CPM
Explanation:
A sample has a half life of 100 minutes. To solve for the amount remaining after a given amount of 10000CPM decay in 5 hours, we use the formula:
Nt = No * (1/2)^t/t1/2
Where:
Nt = amount remaining = unknown
No = initial amount = 10000 CPM
t = time elapsed for decay = 5 hours = 60*5minutes = 300 minutes
t1/2 = half life = 100 minutes
Putting the values into the formula, we have:
Nt = 10000 * (1/2)^ 300/100
Nt = 10000 * (1/2)^3
Nt = 10000 * 0.125
Nt = 1250 CPM
The amount of the sample remaining after 5 hours is 1250 CPM.
Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
Answer: D=8.27 g/cm³
Explanation:
Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.
[tex]D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}[/tex]
With this equation, the m³ and kg cancel out, and we are left with g/cm³.
D=8.27 g/cm³
What volume does 49.0g of KBr need to be dissolved in to make a 8.48% (w/v) solution?
Answer:
578mL is the volume you need to dissolve the mass of KBr
Explanation:
The percent by mass volume, % (w/v) is defined as the ratio between mass of solute in grams and volume of the solution in mililiters times 100. The formula is:
% (w/v) = mass solute (g) / volume solution (mL) × 100
As you want a solution 8.48% and the solute is 49.0g of KBr:
8.48% = 49.0 (g) / volume solution (mL) × 100
Volume solution = 578mL is the volume you need to dissolve the mass of KBr
Acetic acid has a pKa of 4.74. Buffer A: 0.10 M HC2H3O2, 0.10 M NaC2H3O2 Buffer B: 0.30 M HC2H3O2, 0.30 M NaC2H3O2 Buffer C: 0.50 M HC2H3O2, 0.10 M NaC2H3O2 Which of the above buffers has the highest buffer capacity? [ Select ] Which of the above buffers has the lowest buffer capacity? [ Select ]
From the data provided;
Buffer B has the highest buffer capacityBuffer C has the lowest buffer capacityWhat is a buffer?A buffer is a solution which resists changes to its pH when a small quantity of acid or base is added to it.
The buffer capacity is determined using the Henderson-Hasselbach equation:
pH = pKa + log ([CH3COO-]/[CH3COOH])For Buffer A: pH = 4.74 + log(0.10/010) = 4.74
Buffer B: pH = 4.74 + log(0.30/030) = 4.74
For Buffer C: pH = 4.74 + log (0.10/0.50) = 4.04
Buffer A and Buffer B has same pH value as the pKa of acetic acid.
However, Buffer B has higher concentration of the components compared to buffer A, therefore, Buffer B has the highest buffer capacity.
The pH of buffer C is lower than pKa of acetic acid. Hence, buffer C has the lowest buffer capacity.
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How many K atoms are there in 5K2CO3?
Select one:
15
10
6
2
Answer:
10
Explanation:
The 5 will multiply the subscript 2 on the K atoms making it 10
In the covalent compound C3H8 the Greek prefix used to represent the cation is?
Answer:the answer is DI
Explanation:APΣX
A student wishes to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.
What volume of the
12.0 M HCl should he/she start with?
A student should start with 4.74 mL of the 12.0 M HCl to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.
What is Molarity ?Molarity (M) is the amount of a substance in a certain volume of solution.
Molarity is defined as the moles of a solute per liters of a solution.
Molarity is also known as the molar concentration of a solution.
Formula used for the given question ;
M₁V₁ = M₂V₂
M₁ = 12.0 M HCl.V₁ = ?M₂ = 0.875 M HCV₂ = 65.0 mLM₁V₁ = M₂V₂
V₁ = 0.875M x 65.0 mL / 12.0 M HCl.
= 4.74 ml
Therefore , A student should start with 4.74 mL of the 12.0 M HCl to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.
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Consider two solutions: one formed by adding 10.0 grams of glucose (C6H12O6) to 1.0 L of water
and another formed by adding 10.0 grams of sucrose (C12H22O11) to 1.0 L of water. Which of the
two solutes produces the lower reduction in the vapor pressure of the solvent? Explain fully.
Answer:
Explanation:
Lowering of vapour pressure of solvent is proportional to number of moles of solute dissolved in it per litre .
No of moles of glucose dissolved
= mass dissolved / molecular weight of glucose
= 10 / 180
= .055 moles.
No of moles of sucrose dissolved = 10 / 342
= .029 moles.
So reduction in vapour pressure will be lower of solution dissolving sucrose . It is so because , no of moles of solute dissolved in it is low.
What are examples of a chemical reaction?
Select all that apply.
A(2AgI + Na2S → Ag2S + 2NaI
B)4FeS + 7O2 → 2Fe2O3 + 4SO2
C) H2O → SiO2
D)SnO2 → Sn + 2H2O
Examples A and B are examples of chemical reaction as new substances are formed in these reactions which have different chemical compositions.
What are chemical reactions?
Chemical reactions are defined as reactions which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical reaction.
There are several characteristics of chemical reactions like change in color, change in state , change in odor and change in composition . During chemical reaction there is also formation of precipitate an insoluble mass of substance or even evolution of gases.
There are three types of chemical reactions:
1) inorganic reactions
2)organic reactions
3) biochemical reactions
During chemical reactions atoms are rearranged and changes are accompanied by an energy change as new substances are formed.
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How many moles of HCI are needed to prepare 8.0 liters of a 4.0 M solution of HCI?
0.5 mol HCL
32 mol HCI
12 mol HCL
2 mol HCI
Answer: 32 mol HCI
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in Liters
Now put all the given values in the formula of molarity, we get
[tex]4.0M=\frac{moles}{8.0L}[/tex]
[tex]moles={4.0M\times 8.0L}=32mol[/tex]
Therefore, the moles of HCI needed to prepare 8.0 liters of a 4.0 M solution of HCI are 32.
A chemistry student needs of ethanolamine for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of ethanolamine is . Calculate the mass of ethanolamine the student should weigh out. Round your answer to significant digits.
Answer:
mass of ethanolamine 61.2 g
Explanation:
Data:
V (Volume) = 60 mL
ρ (Density)= 1.02 [tex]\frac{g}{cm^{3} }[/tex] = 1.02 [tex]\frac{g}{mL}[/tex]
With the given data and using the density formula:
ρ = [tex]\frac{mass}{volume}[/tex]
It is possible to calculate the grams of ethanolamine that the student should weigh out. The mass in the formula is cleared and the data is replaced.
mass = ρ * volume
mass = 1.02 [tex]\frac{g}{mL}[/tex] * 60 mL = 61.2 g of ethanolamine
a solid block of substance is 74.0 cm by 55.0 cm by 29.0 cm and it weighs 625 kg. Determine the density. Would it float in water? The density of water is 1 g/cm^3. Show your work.
Explanation:
It is given that,
Dimension of a solid block of substance is 74.0 cm by 55.0 cm by 29.0 cm
Mass of solid block is 625 kg or 625000 grams
We need to find the density of solution. The mass per unit its volume is called density.
[tex]\rho=\dfrac{m}{V}\\\\\rho=\dfrac{625000}{74\times 5\times 29}\\\\\rho=58.24\ g/cm^3[/tex]
So, the density of solid block is [tex]58.24\ g/cm^3[/tex]. The density of water is [tex]1\ g/cm^3[/tex]. The density of block is more than water. Hence, it will sink.
How many Joules of energy are required to change 10.0 gram of ice at -2.0 C to water at 20.0 C?
(use your constants)
440 J
66,000 J
880
4220 J
How does the disturbance travel through the coil when you raise your arm up and down?
Answer:
What happens to the wavelength when you increase the rate of vibration (how fast your hand moved back and forth). After increasing the rate of vibration, the wavelength decreased.\
Why do heart diseas patient's eat oil instead of fat? please explain
Answer:
substituting unsaturated fats—like those found in olive oil—for saturated fats could lower your chance of developing heart disease.
Which of the following is not a reason that power plants are unable to achieve 100 percent efficiency?
A. The amount of work obtained from a process never has work needing to go into it.
B. Not all energy is converted heat from chemical reactions into useful work.
C. Entropy increases.
D. Heat is often a waste product
Is water the most common acid?
Answer: Yes
Explanation: Since strong acids react with and use up water molecules, and strong bases do not
Arrange the following compounds in order of increasing solubility in water and explain your sequence: C7H15OH, C6H13OH, C6H6, C2H5OH
Answer:
C6H6 < C7H15OH < C6H13OH < C2H5OH
Explanation:
Hello,
In this case, since the organic molecules solubility is defined in terms of the presence of hydrogen bonds as intermolecular forces, which are formed between oxygen and hydrogen and the length of the organic chain, we can notice that hydroxyl-containing longer chains tend to be less water soluble whereas shorter chains more soluble as the polar part of the chain will lead the solubility. In addition to it, chains with lack of oxygen tend to be highly water insoluble. Therefore, we can notice that C6H6 is the least water soluble, next C7H15OH, then C6H13OH and the most soluble is C2H5OH.
Best regards.
Assuming ideal solution behavior, what is the freezing point of a solution of 9.04 g of I2 in 75.5 g of benzene?
Answer:
3.1°C
Explanation:
Using freezing point depression expression:
ΔT = Kf×m×i
Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).
Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:
9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m
Replacing in freezing point depression formula:
ΔT = 5.12°cm⁻¹×0.472m×1
ΔT = 2.4°C
As freezing point of benzene is 5.5°C, the new freezing point of the solution is:
5.5°C - 2.4°C =
3.1°C
Suppose of potassium iodide is dissolved in of a aqueous solution of silver nitrate. Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn't change when the potassium iodide is dissolved in it.
The given question is incomplete, the complete question is:
Suppose 1.27 g of potassium iodide is dissolved in 100. mL of a 44.0 m M aqueous solution of silver nitrate. Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn't change when the potassium iodide is dissolved in it. Round your answer to 3 significant digits.
Answer:
The correct answer is 0.0325 M.
Explanation:
The mass of potassium iodide or KI mentioned in the question is 1.27 grams, the molar mass of KI is 166 g/mol. The formula for determining the no of moles of the substance is mass/molar mass. Thus, the moles of KI in 1.27 grams will be,
= 1.27g / 166 g/mol = 0.00765 moles.
KI = K⁺ + I⁻
Therefore, the moles of KI will be equivalent to moles of iodide anion, that is, 0.00765 moles.
The moles of silver nitrate or AgNo3 in the solution can be determined by using the formula, molarity (M) * volume in liters. The molarity of silver nitrate given in the question is 44 mM and the volume used is 100 ml or 100/1000 L. Now putting the values we get,
= (44 M/1000) * (100 L/1000) = 0.0044 moles
The moles of silver nitrate is equivalent to moles of silver ion, which is further equivalent to the moles of iodide ion that has taken part in precipitation = 0.0044 moles.
The moles left of I⁻ in the solution will be,
0.00765 - 0.0044 = 0.00325
Now, the final molarity of iodide ion in the solution will be,
= moles/volume in liters
= 0.00325 moles / 0.100 L = 0.0325 M