Suppose that the functions f and g are defined as follows.
Find f.g and f+ g. Then, give their domains using interval notation.

Answer:

surface area=bh+2ls+lb

Step-by-step explanation:

If you think it is too long to remember, just find the area of each of the shapes on it and add them together.

Hope this helps :)

The equation to find the volume of the cylinder is: V = 45π cubic inches.

The volume of things or containers is often measured in cubic inches in the United States. It is the amount of area that a cube with one inch sides takes up. A cubic inch is about equal to 16.387 millilitres or 0.016387064 litres. The displacement of an engine—a measurement of the total amount of air and fuel the engine can compress into its cylinders—is frequently discussed in terms of cubic inches.

The formula to find the volume of a cylinder is:

V = πr²h

Where V is the volume, r is the radius, and h is the height.

Substituting the values given in the problem, we get:

V = π(3²)(5)

V = π(9)(5)

V = 45π

Therefore, the equation to find the volume of the cylinder is:

V = 45π cubic inches.

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Answer:

The surface area of a rectangular prism is calculated by adding the areas of all six faces. The formula for the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l is the length, w is the width and h is the height.

In this case, the length is 7 cm, the width is 3 and three-fifths cm (or 3.6 cm), and the height is 2 and two-fifths cm (or 2.4 cm). Plugging these values into the formula gives us a surface area of 2(7) (3.6) + 2(7) (2.4) + 2(3.6) (2.4), which simplifies to 50.4 + 33.6 + 17.28, or 101.28 square centimeters.

So, the surface area of this rectangular prism is 101.28 square centimeters.

Received message. The surface area of a rectangular prism is calculated by adding the areas of all six faces. The formula for the surface area of a rectangular prism is `2lw + 2lh + 2wh`, where `l` is the length, `w` is the width and `h` is the height. In this case, the length is 7 cm, the width is 3 and three-fifths cm (or 3.6 cm), and the height is 2 and two-fifths cm (or 2.4 cm). Plugging these values into the formula gives us a surface area of `2(7)(3.6) + 2(7)(2.4) + 2(3.6)(2.4)`, which simplifies to `50.4 + 33.6 + 17.28`, or **101.28 square centimeters**. So, the surface area of this rectangular prism is **101.28 square centimeters**.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Based on the information given, it is not possible to determine whether the sample may be biased or not.

However, there is a possibility that the sample may be biased if the company's computer database does not accurately represent its entire customer base. For example, if the database contains only a specific type of customers, such as those who frequently make large purchases, then the sample may not be representative of the company's entire customer base. In this case, the survey results may not accurately reflect the opinions of all the company's customers.

It is also important to consider other factors such as how the survey was conducted and how the questions were framed, as these can also affect the validity of the survey results

Answer:

2 x 3 matrix

Step-by-step explanation:

Answer:

HH

HT

TH

TT

Step-by-step explanation:

Answer:

TT, TH, HT, HH

Step-by-step explanation:

Answer:

Set your calculator to degree mode.

Please sketch the figure to confirm my answer.

tan(18°) = h/510

h = 510tan(18°) = 165.7 feet

Answer:

Construction Model Stats

User

Consider the time taken to completion time (in months) for the construction of a particular model of homes: 4.1 3.2 2.8 2.6 3.7 3.1 9.4 2.5 3.5 3.8 Find the mean, median mode, first quartile and third quartile. Find the outlier?

ChatGPT

To find the mean, we add up all the values and divide by the number of values:

Mean = (4.1 + 3.2 + 2.8 + 2.6 + 3.7 + 3.1 + 9.4 + 2.5 + 3.5 + 3.8) / 10

Mean = 36.7 / 10

Mean = 3.67

To find the median, we need to put the values in order:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4

The middle number is the median, which is 3.35 in this case.

To find the mode, we look for the value that appears most often. In this case, there is no mode as no value appears more than once.

To find the first quartile (Q1), we need to find the value that separates the bottom 25% of the data from the top 75%. We can do this by finding the median of the lower half of the data:

2.5, 2.6, 2.8, 3.1, 3.2

The median of this lower half is 2.8, so Q1 = 2.8.

To find the third quartile (Q3), we need to find the value that separates the bottom 75% of the data from the top 25%. We can do this by finding the median of the upper half of the data:

3.7, 3.8, 4.1, 9.4

The median of this upper half is 3.95, so Q3 = 3.95.

To find the outlier, we can use the rule that any value more than 1.5 times the interquartile range (IQR) away from the nearest quartile is considered an outlier. The IQR is the difference between Q3 and Q1:

IQR = Q3 - Q1

IQR = 3.95 - 2.8

IQR = 1.15

1.5 times the IQR is 1.5 * 1.15 = 1.725.

The only value that is more than 1.725 away from either Q1 or Q3 is 9.4. Therefore, 9.4 is the outlier in this data set.

We can use trigonometry to solve this problem. Let h be the height of the building, and let d be the distance from the base of the building to the point where the angle of elevation is measured. Then we have:

tan(18 degrees) = h / d

Solving for h, we get:

h = d * tan(18 degrees)

Substituting d = 510 feet and using a calculator to evaluate the tangent of 18 degrees, we get:

h = 510 feet * tan(18 degrees)

h ≈ 157.3 feet

Rounding this to the nearest whole number, we get that the height of the building is approximately 157 feet.

The complete statement is, if 8 = m/4, then m - 12 = 20.

Algebra is a branch of mathematics that deals with the study of mathematical symbols and the rules for manipulating these symbols. It involves solving equations and inequalities, manipulating expressions, and working with mathematical formulas to describe and analyze relationships between variables. Algebraic equations and expressions are used to represent and solve problems in a wide range of fields, including science, engineering, economics, and finance. Algebra is an essential tool for problem-solving and critical thinking, and it provides the foundation for more advanced mathematical concepts such as calculus, statistics, and linear algebra.

The main goal of algebra is to find unknown values or variables, typically represented by letters such as x, y, or z. Algebraic equations involve a variety of mathematical operations, including addition, subtraction, multiplication, and division. These equations may also include exponents, logarithms, and other advanced mathematical concepts.

To solve the problem, we can use algebraic manipulation.

Given 8 = m/4, we can solve for m by multiplying both sides by 4:

8 × 4 = m

32 = m

Now we can substitute m = 32 into the expression m - 12 to find:

m - 12 = 32 - 12 = 20

Therefore, if 8 = m/4, then m - 12 = 20.

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The complete question is:

Complete the statement: if 8= m/4, then m-12=

The measures of the trigonometric relations and reference angles are solved

Given data ,

Let the measure of the angle be θ = 2π/3

Now , from the trigonometric relation ,

The tangent of the function tan ( 2π/3 ) = -√3

And , the reference angle of the θ = 2π/3  is given by A = π/3

So , A = 60°

Hence , the reference angle is 60°

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Based on the above, the width of the field is 62 meters.

Based on the question, Let's say that the width of the field is  denoted with 'w'.

Note that the formula for the perimeter (P) of a rectangle is:

P = 2(l + w)

where"

l = length

w =  width.

Fixing the values into the equation, it will be:

300 = 2(88 + w)

So, Divide both sides by 2:

150 = 88 + w

Subtract 88 from both sides:

w = 150 - 88

w = 62

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Se text below

The perimeter of a rectangular field is 300 m. If the length of the field is 88 , what is its width?

Answer: 44%, 26%, less likely

Step-by-step explanation:

just do the math!!

The unit rate that relates the two quantities of distance and volume of gas is:

U = 30 miles per gallon.

To do so, we can find the unit rate.

This would say how many gallons are consumed to drive a unit of distance, or which distance can you drive with one gallon.

Here we have the values:

10 gallons and 300 miles.

Then the unit rate is the quotient between these:

300miles/10 gallons = 30 miles per gallon

This says that with one gallon of gas you can travel 30 miles.

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According to the information, the router cannot cover the kitchen area.

To calculate if the router covers the kitchen area, we must identify the area that the router can cover. In this case, the router covers an area of 850 square feet. However, we must take into account that this area is counted around the router. So, we have to calculate the square root of 850 ft^2.

From the above, we can infer that the router has signal coverage of 14 meters around it, so it would only cover the living room area.

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The actual consumer spending at a price of $27 per unit is $268.26.

Substitute the given price into the supply equation to get the corresponding quantity supplied:

p = q + 10

27 = q + 10

q = 17

Substitute q = 17 into the demand equation to get the corresponding price:

4q² + p² = 1405

4(17)² + p² = 1405

p² = 1405 - 1156

p² = 249

p = 15.78

The actual consumer spending can be calculated by multiplying the quantity demanded by the price:

Actual consumer spending = quantity demanded x price per unit

= 17 x 15.78

= $268.26

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The demand and supply equations for a certain product are given by space 4 q squared plus p squared equals 1405 and p equals q plus 10 where p is in dollars per unit and q is in units. For a price of $27 per unit, determine the actual consumer spending.

Answer:

14

Step-by-step explanation:

28/2 is equivalent to 14. This is because when you divide a number by 2, you are essentially cutting it in half. So, 28/2 is the same as cutting 28 into two equal parts, which is 14.

Answer:

28

2

looks like a fraction but it is actually the whole number 14.

There is an infinity number of equivalent fractions to 28

2

.

To find an equivalent fraction to 28

2

, or to any other fraction, you just need to multiply (or divide, if the fraction is not yet reduced), both the numerator and the denominator of the given fraction by any non-zero natural number. For example:

By dividing the original fraction by 2, we get:

28 ÷ 2

2 ÷ 2

= 14

1

By multiplying the original fraction by 2, we get:

28 × 2

2 × 2

= 56

4

Here is the full list of equivalent fractions to 28

2

.

14

1

, 28

2

, 42

3

, 56

4

, 70

5

, 84

6

, 98

7

, 112

8

, 126

9

, 140

10

, 154

11

, 168

12

, 182

13

, 196

14

, 210

15

, 224

16

, 238

17

, 252

18

, 266

19

, 280

20

...

The most appropriate measure of variability to use in this case is the IQR (Interquartile Range) of 13.

The reason for this is that the data appears to be skewed towards the higher values, with more donations in the higher range (from 40 to 59 dollars) and fewer in the lower range (from 10 to 39 dollars).

Using the range (which is the difference between the highest and lowest values) would not accurately represent the variability of the data, as it would be heavily influenced by the outliers. On the other hand, the IQR, which is the range of the middle 50% of the data, is a more robust measure of variability that is not influenced by outliers. Therefore, the IQR of 13 is the most appropriate measure of variability to use in this case.

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Answer:

x=9km

Step-by-step explanation:

Pythagorean Theorem: [tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

The hypotenuse is [tex]c^{2}[/tex], so the equation will be

[tex]12^{2}[/tex] + [tex]b^{2}[/tex] = [tex]15^{2}[/tex]

Evaluating the equation gives us

144 + [tex]b^\\{2}[/tex] = 225

Subtract 144 from each side to have [tex]b^{2}[/tex] alone

[tex]b^{2}[/tex] = 81
square root on each side to get rid of the exponent

[tex]\sqrt{b^2[/tex] = [tex]\sqrt{81}\\[/tex]

[tex]\sqrt{b^2[/tex]'s square root is b and          [tex]\sqrt{81[/tex]'s is 9,-9, giving us b=±9

As distance cannot be negative, x = 9km

Answer:

Step-by-step explanation:

15.) [tex]\sqrt{12}[/tex]

      [tex]\sqrt{4}[/tex] * [tex]\sqrt{3}[/tex]

      Answer: 2[tex]\sqrt{3}[/tex]

17.) Distribute 3[tex]\sqrt{3}[/tex] into both sides of the parentheses

     3[tex]\sqrt{3}[/tex] * 4 = 12[tex]\sqrt{3}[/tex]

     3[tex]\sqrt{3}[/tex] * -3[tex]\sqrt{5}[/tex] = -9[tex]\sqrt{15}[/tex]

     Answer: 12[tex]\sqrt{3}[/tex] - 9[tex]\sqrt{15}[/tex]

19.) Distribute 4[tex]\sqrt{15}[/tex] into both sides of the parentheses

      4[tex]\sqrt{90}[/tex] + 4[tex]\sqrt{75}[/tex]

      4*[tex]\sqrt{9}[/tex]*[tex]\sqrt{10}[/tex] + 4*[tex]\sqrt{25}[/tex]*[tex]\sqrt{3}[/tex]

      4*3*[tex]\sqrt{10}[/tex] + 4*5*[tex]\sqrt{3}[/tex]

      12[tex]\sqrt{10}[/tex] + 20[tex]\sqrt{3}[/tex]

21.) Distribute [tex]\sqrt{15}[/tex] into both sides of the parentheses

      2[tex]\sqrt{150}[/tex] - 4[tex]\sqrt{90}[/tex]

      2*[tex]\sqrt{25}[/tex]*[tex]\sqrt{6}[/tex] - 4*[tex]\sqrt{9}[/tex]*[tex]\sqrt{10}[/tex]

      2*5*[tex]\sqrt{6}[/tex] - 4*3*[tex]\sqrt{10}[/tex]

      10[tex]\sqrt{6}[/tex] - 12[tex]\sqrt{10}[/tex]

The Bowstring Shirt Company, a firm in the 21% tax bracket, would be willing to pay (on a non-discounted basis) the sum of $25,200  for Celluloid Collar Corporation’s carryforward alone.

The value of Celluloid Collar Corporation's tax loss when it is said to be carryforward to Bowstring Shirt Company will be be calculated  using the steps below

Value = Tax Loss Carryforward x Tax Rate

Value = $120,000 x 21%

        = $25,200

Therefore, Bowstring Shirt Company have to pay $25,200 for Celluloid Collar Corporation's tax loss to  be carryforward.

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Cell 1 is in the "7th grade" row and "Pets" column. Have your student circle these labels or highlight them. Then it should be clear why choice E is the final answer.

Another way to rephrase it: the 35 people in cell 1 represent the number of 7th graders with pets.

Answer:

A line that is perpendicular to another is one that has a slope that is the multiplicative reciprocal of the original funtion's slope and it also has the opposite sign in front. Considering a slope with a value of [tex]\dfrac{1}{7}[/tex], the reciprocal multiplicative is 7, because is a number that equals 1 if multiplied by the original value. Then, we change the sign for it, making it -7.

Thus, correct answer is a. -7.

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The answer

4.16666667 yards

From the interior angle theorem:

The Interior Angle Theorem states that if two secants or chords intersect inside a circle, then the measure of the angle formed is equal to half the sum of the measures of the intercepted arcs.

Considering the given circles:

m∠AED = ¹/₂(45 + 109)

m∠AED = 77°

m∠AEB = 180 - 77

m∠AEB = 103°

m∠LK = (2 * 62) - 74)

m∠LK = 50°

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Answer:

We can use the given formula to calculate the decibel level D when the intensity level I is 63,096 times Io:

D = 10log(I/lo)

Where Io is the reference intensity level and is typically taken to be the threshold of hearing, which is 10^−12 watts/m^2.

So, substituting the values, we get:

D = 10log(63,096*Io/Io) = 10log(63,096)

Using a calculator, we find:

D ≈ 47.1 dB

Rounding this to the nearest whole number, we get:

The decibel level is 47 dB when I is 63,096 times Io.

I hope this helps mate.

The conversion of 2,000 Swiss francs to United States dollars and from United States dollars into Dutch guilders (Holland) based on Wednesday's currency exchange rate is D. ƒ4,032.

The exchange rate represents the unit rate at which one currency is exchanged for or converted to another.

Exchange rate conversions rely on the mathematical operations of division or multiplication.

1 CHF = $1.12

2,000 CHF = $2,240 ($1.12 x 2,000 CHF)

On Wednesday April 26, 2023, $1.00 =  ƒ‎1.80

$2,240 = ƒ4,032 ($2,240 x ƒ1.80)

Thus, we can conclude that 2,000 CHF (Swiss francs) are worth 4,032 Dutch guilders.

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The matrix operation add -4(row 1) to row 3 is[tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\0&-9&2&12\end{array}\right][/tex]

From the question, we have the following parameters that can be used in our computation:

[tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\4&-1&6&-8\end{array}\right][/tex]

From the question, we understand that

We are to add -4(row 1) to row 3

This means that

row 3 = row 3 - 4 * row 1

When these values are evaluated, we have

4: 4 - 4 * 1 = 0

-1: -1 - 4 * 2 = -9

6: 6 - 4 * 1 = 2

-8: -8 - 4 * -5 = 12

This means that we relace 4, -1, 6, and -8 in row 3 with 0, -9, 2 and 12

Using the above as a guide, we have the following:

[tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\0&-9&2&12\end{array}\right][/tex]

Hence, the result of the matrix expression is [tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\0&-9&2&12\end{array}\right][/tex]

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The quadratic function in standard form is f(x) = x² - 4x - 12.

The coefficients of the quadratic function in standard form is calculated as follows;

The quadratic function is in the form of;

f(x) = ax² + bx + c

when x = -4, f(x) = -12

16a - 4b + c = -12

when x = -3, f(x) = -15

9a - 3b + c = -15

when x = -2, f(x) = -16

4a - 2b + c = -16

when x = -1, f(x) = -15

1a - 1b + c = -15

when x = 0, f(x) = -12

0a + 0b + c = -12

c = -12

Simplifying the equations, the value of a and b is calculated as;

16a - 4b + c = -12

9a - 3b + c = -15

4a - 2b + c = -16

a - b + c = -15

16a - 4b = 0

9a - 3b = -3

4a - 2b = -4

a - b = -3

16a = 4b

a = b/4

Substituting this expression for a into the last equation, we get:

b/4 - b = -3

b - 4b = -12

-3b = -12

b = 4

a = b/4

a = 4/4

a = 1

Therefore, the quadratic function in standard form is:

f(x) = x² - 4x - 12

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The statement that best describes the potential bias in this scenario is option B: The survey results are most at risk for department members not being able to answer honestly.

The reason for this is that department members may be afraid to share their true thoughts and opinions, especially if they believe their ideas may be seen as too innovative or risky. They may be concerned about how their managers or colleagues will perceive them if they express ideas that go against the status quo or challenge established norms.

This type of bias is known as social desirability bias, which refers to the tendency of respondents to answer questions in a way that is socially acceptable or desirable, rather than in a way that reflects their true beliefs or behaviors.

In this case, department members may feel pressure to conform to the expectations of their superiors or colleagues, even if it means not expressing their true opinions or ideas.

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Complete Question

A department manager recently launched a new initiative so the members of her department can more easily present innovative ideas they have. To get feedback on the initiative, she emails a link to all department members for an anonymous online survey.

Which statement is true?

A. The survey results are most at risk for nonresponse bias.

B. The survey results are most at risk for department members not being able to answer honestly.

C. The survey results are not at risk of any bias.

D. The survey results are most at risk for under coverage.

A. The distance she must walk to return to the starting point is approximately 1912.325 ft, or 1912 ft 3 in.

B. She is walking towards the north, the heading is N 1° 20' W.

C. Acreage = 7.55 acres (rounded to 3 decimal places).

A. Convert the angles to decimal degrees:

N. 27° 40′ E. = 27.667°

N. 56° 31′ E. = 56.517°

S. 4° 26′ W. = -4.433°

Now, calculate the distances between the points:

AB = √(696.2917² + 3.5² - 2*696.2917*3.5*cos(27.667°)) = 696.2227 ft

BC = √(487.9792² + 11.75² - 2*487.9792*11.75*cos(56.517°)) = 487.9385 ft

CD = √(1691.125² + 1.5² - 2*1691.125*1.5*cos(-4.433°)) = 1691.1415 ft

B. Finding the distance from D back to A, calculate the distance and angle between AD:

AD = √(AB² + BD² - 2*AB*BD*cos(θ)) where θ = 180° - 4°26' - 27°40' = 147.9°

Substituting AB and BD:

AD = √(696.2227² + 1691.1415² - 2*696.2227*1691.1415*cos(147.9°)) = 1912.3246 ft

Therefore, the distance she must walk to return to the starting point is approximately 1912.325 ft, or 1912 ft 3 in.

C. Finding the heading she walks from D back to A, calculate the angle between AD and the north-south axis:

θ' = atan((AB*sin(27.667°) - BD*sin(θ))/AD) = atan((696.2227*sin(27.667°) - 1691.1415*sin(147.9°))/1912.3246)

θ' = -1.344°

Since she is walking towards the north, the heading is N 1° 20' W.

Lastly, to calculate the acreage of this plot of land, we use Heron's formula to determine the area of triangle ABC:

s = (AB + BC + AC)/2 = (696.2227 + 487.9385 + 1392.625)/2 = 788.8931 ft

A = √(s(s-AB)(s-BC)(s-AC)) = 328756.0207 ft²

Convert to acres:

Acreage = 328756.0207/43560 = 7.55 acres (rounded to 3 decimal places).

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Answer:

Step-by-step explanation:To find the limit of p(x) as x approaches -3, we can first simplify the expression by factoring the numerator:

p(x) = (x^4 - x^3 - 1) / x^2(x + 1)

= [(x - 1)(x^3 + x^2 - x - 1)] / [x^2(x + 1)]

Now, when x approaches -3, the denominator of the fraction becomes zero, which means we have an indeterminate form of the type 0/0. To evaluate the limit, we can use L'Hopital's rule, which states that if we have an indeterminate form of the type 0/0 or infinity/infinity, we can take the derivative of the numerator and denominator separately and then evaluate the limit again.

Taking the derivative of the numerator and denominator, we get:

p'(x) = [(3x^2 - 2x - 1)(x^2 + 2x) - 2(x - 1)(2x + 1)] / [x^3(x + 1)^2]

Now, plugging in x = -3 into the derivative, we get:

p'(-3) = [(3(-3)^2 - 2(-3) - 1)((-3)^2 + 2(-3)) - 2((-3) - 1)(2(-3) + 1)] / [(-3)^3((-3) + 1)^2]

= [28 - 44] / [(-3)^3(-2)^2]

= -16 / 108

= -4 / 27

Since the derivative is defined and nonzero at x = -3, we can conclude that the original limit exists and is equal to the limit of the derivative, which is:

lim x->-3 p(x) = lim x->-3 [(x - 1)(x^3 + x^2 - x - 1)] / [x^2(x + 1)]

= p'(-3)

= -4 / 27

Therefore, the limit of p(x) as x approaches -3 is equal to -4/27.

Answer:

[tex]\lim_{x \to -3}p(x) =-\dfrac{107}{18}[/tex]

Step-by-step explanation:

Given the function [tex]p(x)=\dfrac{x^4-x^3-1}{x^2(x+1)}[/tex]

Let's give the expressions in the numerator and denominator their own function names so they are easy to refer to:

n, for numerator: [tex]n(x)=x^4-x^3-1[/tex]

d, for denominator:  [tex]d(x)=x^2(x+1)[/tex]

So [tex]p(x)=\dfrac{n(x)}{d(x)}[/tex]

Now, we want the limit of p(x) as x goes to -3.

[tex]\lim_{x \to -3}p(x) =\lim_{x \to -3}\dfrac{n(x)}{d(x)}[/tex]

For limits of quotients, it is important to analyze the numerator and the denominator.

Take a moment to observe that inputting -3 into the denominator is defined and does not equal zero:  [tex]d(-3)=(-3)^2((-3)+1)=-18\ne0[/tex]

Also, observe that inputting -3 into the numerator is defined:  [tex]n(-3)=(-3)^4-(-3)^3-1=81+27-1=107[/tex]

Importantly, both functions n & d are polynomials, which are functions that are continuous over [tex]\mathbb{R}[/tex].

Since both functions n & d are continuous, both n & d are defined at [tex]x=-3[/tex], and [tex]d(-3)\ne0[/tex], then the limit of the quotient is the quotient of the limits:

[tex]\lim_{x \to -3}\dfrac{n(x)}{d(x)}=\dfrac{ \lim_{x \to -3}n(x)}{ \lim_{x \to -3}d(x)}[/tex]

From here, again, since n & d are continuous over [tex]\mathbb{R}[/tex] and defined at the limit, [tex]\lim_{x \to -3}n(x)}=n(-3)[/tex] and [tex]\lim_{x \to -3}d(x)}=d(-3)[/tex].

Therefore,

[tex]\lim_{x \to -3}p(x) =\lim_{x \to -3}\dfrac{n(x)}{d(x)}=\dfrac{ \lim_{x \to -3}n(x)}{ \lim_{x \to -3}d(x)}=\dfrac{n(-3)}{d(-3)}=\dfrac{107}{-18}=-\dfrac{107}{18}[/tex]