State the null and alternative hypotheses to test if the population represented by Sample 1 has a mean that is 2.0 units higher than the population represented by Sample 2. Let µd be the population mean of​ matched-pair differences for Sample 1 - Sample 2. State the null and alternative hypotheses.

Pair 1 2 3 4 5 6 7
Sample1 5 6 10 3 6 7 8
Sample2 4 4 3 5 5 5 3

The answer is C. 65........

Answer:

25

Step-by-step explanation:

The angle of an arc is the same as the central angle. MarcCD is the same as the central angle COD which is given as 130o.

That means there are 50 degrees left for COA and DOA and because the chord and the diameter are equal, COA = DOA

That means that COA is 1/2 what is left over from 180 when 130 is subtracted from it.

1/2 * 50 = 25

The answer is A 25.

Answer:

The number of passes in a class of 180 is 75.

Step-by-step explanation:

The problem does not state, so I will suppose the passing grade is 70.

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 67.4, \sigma = 12[/tex]

Proportion of students who passed:

This is 1 subtracted by the pvalue of Z when X = 70. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{70 - 67.4}{12}[/tex]

[tex]Z = 0.22[/tex]

[tex]Z = 0.22[/tex] has a pvalue of 0.5871.

1 - 0.5871 = 0.4129

Out of 180:

0.4129*180 = 74.32

Rounding up

The number of passes in a class of 180 is 75.

Answer:

  199

Step-by-step explanation:

All of the terms of the sum cancel except the last two.

The total is 199.

Answer: A = 93.8 cm so if you round up it's about 100 cm

Step-by-step explanation:

Area means you have to multiply all measurements by each other in any order of course because it doesn't matter in this case.

                                    14 * 10 * 10     =     1400

Now you can/should divide the answer which is (1400) by how many measurements you have times the sides it has, sides - which is 5 , measurements - which is 3, so it would look like this:

                                     1400   /    15    =    93.8

Answer: is that the full question?

Step-by-step explanation:

Answer:

The top left picture and top right picture

Step-by-step explanation:

Answer:

h = 400 ft

The bird is 400 ft above the submarine

Step-by-step explanation:

Given;

The submarine is 300 feet below sea level

Vertical distance between submarine and sea level h1 = 300 feet

The bird is flying at 100 feet above sea level

Vertical distance between the sea level and the bird h2 = 100 feet

The total vertical distance between the bird and the submarine is the sum of the vertical distance between submarine and sea level and the vertical distance between the sea level and the bird.

h = h1 + h2

h = 300 ft + 100 ft

h = 400 ft

The bird is 400 ft above the submarine

Answer:

The bird is 400 ft above the submarine

Step-by-step explanation:

Answer:

The roots (zeros) are the  x   values where the graph intersects the x-axis. To find the roots (zeros), replace   f(x)  with  0   and solve for x  

No solution

Answer:

[tex]x^{12} =400[/tex]

[tex]w^{-10} =\frac{1}{20}[/tex]

Step-by-step explanation:

[tex]x^{6} =20[/tex]

[tex]x^{12} =(x^{6} )^{2} =20^{2} =400[/tex]

[tex]w^{10} =20[/tex]

[tex]w^{-10} =\frac{1}{w^{10} } =\frac{1}{20}[/tex]

[tex]x^{12} *w^{-10} =400*\frac{1}{20} =20[/tex]

Answer:

I'm not so clear with the question but I hope this helps

Answer:

A, of money in the account after 3 years subject to interest ... If you deposit P dollars at rate r, in decimal form, subject to compound interest paid

Step-by-step explanation:

Answer:

May we see the graph?

Step-by-step explanation:

Step-by-step explanation:

the two A's in the buttom is correct

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is

Coaching companies claim that their courses can raise the SAT scores of high school students. But students who retake the SAT without paying for coaching also usually raise their scores. A random sample of students who took the SAT twice found 427 who were coached and 2733 who were uncoached. Starting with their verbal scores on the first and second tries, we have these summary statistics:

Try 1 Try 2 Gain

n x s x s x s

Coached 427 500 92 529 97 29 59

Uncoached 2733 506 101 527 101 21 52

Use Table C to estimate a 90% confidence interval for the mean gain of all students who are coached.

at 90% confidence.

Now test the hypothesis that the score gain for coached students is greater than the score gain for uncoached students. Let μ1 be the score gain for all coached students. Let μ2 be the score gain for uncoached students.

(a) Give the alternative hypothesis:

μ1 - μ2.

(b) Give the t test statistic:

(c) Give the appropriate critical value for \alpha =5%:

Solution:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean score gain for all coached students

x2 = sample mean score gain for all uncoached students

s1 = sample standard deviation score gain of coached students

s2 = sample standard deviation score gain of uncoached students

For a 90% confidence interval, the z score is 1.645

From the information given,

x1 = 29

s1 = 59

n1 = 427

x2 = 21

s2 = 52

n2 = 2733

x1 - x2 = 29 - 21 = 8

z√(s1²/n1 + s2²/n2) = 1.645√(59²/427 + 52²/2733) = 4.97

90% Confidence interval = 8 ± 4.97

a) The population standard deviations are not known. it is a two-tailed test. The random variable is μ1 - μ2 = difference in the score gain for coached and uncoached students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 > μ2 H1 : μ1 - μ2 > 0

This is a right tailed test.

b) Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (29 - 21)/√(59²/427 + 52²/2733)

t = 2.65

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [59²/427 + 52²/2733]²/[(1/427 - 1)(59²/427)² + (1/2733 - 1)(52²/2733)²] = 9.14/0.1564

df = 58

c) from the t distribution table, the critical value is 1.67

In order to reject the null hypothesis, the test statistic must be smaller than - 1.67 or greater than 1.67

Since - 2.65 < - 1.67 and 2.65 < 1.67, we would reject the null hypothesis.

Therefore, at 5% significance level, we can conclude that the score gain for coached students is greater than the score gain for uncoached students.

Answer:

Rotation = 1.

Reflection = 5 or 4.

Step-by-step explanation:

A regular octagon is the octagon that has eight, 8 sides and all these eight sides are equal.

So, if we are going to consider rotation and reflection distinct in order to color one diagonal red and another diagonal blue so that the two colored diagonals cross (in the interior) we can do that by following the steps Below;

=> Make sure that the first diagonal with the red color is drawn first.

=> to another make fixing to another end.

=> Determine the possibilities.

The numbers of times can be gotten by using Burnside Lemma which gives Rotation = 1 And Reflection = 5 or 4.

Answer:

(C)On a coordinate plane, 2 rays form an angle. One ray sits on the x-axis.

Step-by-step explanation:

An angle is stated in the standard position with respect to the x-axis.

Therefore, for an angle to be in standard position, one of its rays must be on the x-axis.

From the given options, only Option C has a ray on the x-axis and therefore is the angle that is in standard position.

Answer:

The answer to this question is C) (the third graph)

Answers to the entire test are

1. A) Quadrant 1

2. B) –270° and 90°

3. D) 126° + (720n)°, for any integer n

4. A) –90° and 630°

5. A) (the first graph)

6. D) n = 6

7. C) x = y + 360 n, for any positive integer n

8. B) 10°

9. C) (the third graph)

10. C) 495°

Step-by-step explanation:

Just took it. Edg 2021. Hope this helps :) (smiley's name is George, George says hi)

Answer:

(a) The confidence coefficient is 2.779.

(b) The desired sampling error for this study is the margin of error, ±3.

(c) The sample size required to obtain the desired estimate of the true mean is 55.

Step-by-step explanation:

The information provided is:

[tex]\bar x=53.4\ \text{grams}\\s=8.6\ \text{grams}\\n=27\\\text{Confidence Level} = 99\%[/tex]

(a)

As the sample size is n = 27 < 30 and the population standard deviation is not provided a t-interval would be used to estimate the true mean.

So, the confidence coefficient for the 99% confidence interval for true mean is:

[tex]t_{\alpha/2, (n-1)}=t_{0.01/2, (27-1)}=t_{0.005, 26}=2.779[/tex]

*Use the t-table.

Thus, the confidence coefficient is 2.779.

(b)

The error caused due to incorrect sample selection, i.e. a sample that is not a true representative of the population is known as the sampling error.

In this case the sampling error is known as the margin of error of the confidence interval.

The margin of error is:

MOE = 3 grams

Thus, the desired sampling error for this study is the margin of error, ±3.

(c)

Assume that the ample size required to obtain the desired estimate of the true mean is quite large, such that the sampling distribution of sample mean follows a normal distribution according to the central limit theorem.

Then the margin of error for a z-interval for mean is:

[tex]\text{MOE}=z_{\alpha/2}\times \frac{s}{\sqrt{n}}[/tex]

MOE = 3 grams

The critical value of z for 99% confidence level is:

[tex]z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58[/tex]

*Use a z-table.

Compute the sample size as follows:

[tex]\text{MOE}=z_{\alpha/2}\times \frac{s}{\sqrt{n}}[/tex]

      [tex]n=[\frac{z_{\alpha/2}\times s}{MOE}]^{2}[/tex]

         [tex]=[\frac{2.58\times 8.6}{3}]^{2}\\\\=54.700816\\\\\approx 55[/tex]

Thus, the sample size required to obtain the desired estimate of the true mean is 55.

Answer:

Step-by-step explanation:

This problem is on the mensuration of solid shapes, a box/cube.

Given data

[tex]Length l = 3in\\\\Width w= \frac{1}{12}in \\\\Height h = 4in[/tex]

we know that the expression for the volume of a cube is

[tex]volume= l*w*h\\\\substituting \\\\volume= 3* \frac{1}{12}* 4\\ volume= \frac{12}{12} = 1 in^{3}[/tex]

Answer: While tending to his flower garden, Sherlock Holmes discovers a body buried in his backyard. Forensic analysis yields the value 0.045 for the ratio (R/L). Use the least squares equation to estimate the age of Sherlock Holmes' surprise garden visitor. years

Step-by-step explanation:

Answer:  The change represents  growth with 89% of growth rate.

Step-by-step explanation:

The exponential function is given by :-

[tex]f(x)= Ab^x[/tex]... (i)

Where , A = initial value , b= multiplicative factor and  x= time period

The given function : [tex]y = 940(1.89)^x[/tex].

By comparing this to (i) , we get

b= 1.89 > 1 , thus it represent the growth.

Also,

[tex]b= 1+r\Rightarrow\ 1.89 = 1+r\\\\\Rightarrow\ r=1.89-1=0.89[/tex]

i.e. Percentage rate of growth = 0.89 x 100 = 89%.

Answer:

[tex]\dfrac{dA}{dt}+ \dfrac{A}{100}=0[/tex]

A(0) = 70  (i.e the pounds of salt dissolved into the tank)

Step-by-step explanation:

Given that:

a large mixing tank initially holds 400 gallons of water  in which 70 pounds of salt have been dissolved.

The rate at which pure water is pumped into the tank is 4 gal/min

After stirring; the pure water is then pumped out at the same rate.

The objective is to determine the differential equation  for the amount of salt A(t) in the tank at time t > 0. What is A(0)

Taking the differential of:

[tex]\dfrac{dA}{dt}=R_{in}-R_{out}[/tex]     ---- (1)

where ;

[tex]R_{in[/tex] = 0

[tex]R_{out} =\dfrac{A(t)}{400}*4[/tex]

[tex]R_{out} =\dfrac{A}{100}[/tex]

replacing them into (1) ; we have:

[tex]\dfrac{dA}{dt}=0 - \dfrac{A}{100}[/tex]

[tex]\dfrac{dA}{dt}=- \dfrac{A}{100}[/tex]

[tex]\dfrac{dA}{dt}+ \dfrac{A}{100}=0[/tex]

A(0) = 70 (i.e the pounds of salt dissolved into the tank)

The differential equation for the amount of salt A(t) in the tank at time t > 0 is [tex]\frac{dA}{dt} + \frac{A}{100} = 0[/tex]

A (0)= 70

Given that,

[tex]dA\div dt=R_{in}-R_{out}[/tex]

Rin=0

[tex]R_{out}=A(t)\div 400 \times (4)\\\\ =A\div 100[/tex]

so,

[tex]dA\div dt=R_{in}-R_{out}\\\\dA\div dt=0- A\div 100[/tex]

So,

[tex]dA\div dt +A\div 100=0[/tex]

A(0)=70

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Answer:

16/75, D

Step-by-step explanation:

6/5*1/3. We can cross simplify to make it 2/5*1/1. That is 2/5. Then, 2/5*8/15 is 16/75 which is answer choice D.

Answer:

[900, 1300]

Step-by-step explanation:

According to the empirical rule, 95% is within ±2 standard deviations.

1100 − 2(100) = 900

1100 + 2(100) = 1300

Answer:

Option D.

Step-by-step explanation:

The given graph represents the function f(x).

If graph of a function f(x) intersect x axis at x=c, then (x-c) is a factor of f(x).

From the given graph it is clear that the graph of f(x) intersect x axis at x=-6,-3,0. It means factors of given function are

[tex](x-(-6))=(x+6)[/tex]

[tex](x-(-3))=(x+3)[/tex]

[tex](x-0)=x[/tex]

It means (x+6), (x+3) and x are factors of given function.

Therefore, option D is correct.

Answer:

The answer is (x+6)

Step-by-step explanation:

Just took the test

Hope this helps

Answer:

Mass of other chemicals to be evaporated is 24 grams.

Step-by-step explanation:

The initial mass of the hand sanitizer = 400 grams, and has an alcohol content of 24%.

mass of its alcohol content = [tex]\frac{24}{100}[/tex] × 400

                                            = 96 grams

mass of non-alcoholic content = 400 - 96

                                                  = 304 grams

If the percentage of alcohol is increased to 30%, then;

mass of its alcohol content = [tex]\frac{30}{100}[/tex] × 400

                                             = 120 grams

The mass of other chemicals to be evaporated = 120 - 90

                                                 = 24 grams

Answer:

150.72 cm^2

Step-by-step explanation:

The blue area has an angle of 120 degrees, and 120/360 = 1/3, which shows that the blue area is 1/3 of the circle. In that case, the blue area is just 144pi/3. That simplifies to 48 pi.

48*3.14 = 150.72

Answer:

3 I think it's 3. sorry if I'm wrong

The correct answer is (3) they map lines to parallel lines

Transformation is the movement of a point from the initial location to a new location. Types of transformation is rotation, reflection, translation and dilation.

Translation is the movement of a point up, down, left or right in the coordinate plane.

Translation is a rigid transformation, that is, it preserves the size and shape of the figure. Reflection and rotation are also rigid transformation.

Translation maps lines to parallel lines whereas rotation does not since it changes the direction of the line.

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Answer:0.007

Step-by-step explanation:

Answer:

Dilation is done by the scale factor of Five-halves.

Step-by-step explanation:

Please refer to the image attached,

The graph clearly shows the triangles [tex]\triangle[/tex]ABC and [tex]\triangle[/tex]A'B'C'.

Let us calculate the sides of triangles first then we will be able to find scale factor of dilation.

Using the distance formula:

Distance between 2 points [tex]P (x_1,y_1) \text{ and } Q (x_2,y_2)[/tex] is given by formula:

PQ = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Side AB is along x-axis, side AB =

[tex]\sqrt{(2-0)^2+(2-2)^2}\\\Rightarrow \sqrt{4}\\\Rightarrow 2\ units[/tex]

Similarly side, BC = 2 units

Now, in [tex]\triangle[/tex]A'B'C', A'B' can be calculated by distance formula:

[tex]\sqrt{(1+4)^2+(-1- (-1))^2}\\\Rightarrow \sqrt{25}\\\Rightarrow 5\ units[/tex]

B'C' = 5 units

The ratio of sides:

AB : A'B' = 2:5

[tex]\Rightarrow \dfrac{AB}{A'B'} = \dfrac{2}{5}\\\Rightarrow A'B' = \dfrac{5}{2} AB[/tex]

So, scaling factor is [tex]\dfrac{5}{2}[/tex] or 2.5.

OR

Scaling factor is Five-halves.

Answer:

The answer is C on Edge.

Step-by-step explanation: