Solve the inequality. Write the solution set in interval notation and graph it. x²-3x - 10> 0

Answers

Answer 1

The solution set for the inequality x² - 3x - 10 > 0 in interval notation is (-∞, -2) ∪ (5, ∞).

To solve this inequality, we can first find the critical points by setting the expression x² - 3x - 10 equal to zero and solving for x. Factoring the quadratic equation, we have (x - 5)(x + 2) = 0. This gives us two critical points: x = -2 and x = 5.

Next, we can examine the sign of the expression x² - 3x - 10 in different intervals:

For x < -2, the expression is positive.

For -2 < x < 5, the expression is negative.

For x > 5, the expression is positive.

Since we are looking for x values where the expression is greater than zero, we consider the intervals where the expression is positive. This leads us to the solution set (-∞, -2) ∪ (5, ∞) in interval notation.

To graph the solution set, we can plot an open circle at x = -2 and x = 5 to indicate that these points are not included in the solution. Then, we shade the regions where the expression x² - 3x - 10 is positive, which are the intervals (-∞, -2) and (5, ∞)

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Related Questions

Suppose that the functions u and w are defined as follows. u(x) = x² +5 w(x)=√x+3 W Find the following. (uºw) (1) = (wºu) (1) =

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To find (uºw)(1) and (wºu)(1), where u(x) = x² + 5 and w(x) = √(x + 3), we substitute x = 1 into the compositions of the functions.

To evaluate (uºw)(1), we first compute w(1) = √(1 + 3) = √4 = 2. Next, we substitute this result into u(x), giving u(2) = 2² + 5 = 4 + 5 = 9. Therefore, (uºw)(1) = 9. Similarly, to find (wºu)(1), we calculate u(1) = 1² + 5 = 1 + 5 = 6. Substituting this value into w(x), we get w(6) = √(6 + 3) = √9 = 3. Hence, (wºu)(1) = 3.

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Find absolute (global) minimum value of the X function f(x) = x/x²+1 on the closed interval [-1,1].

Answers

To find the absolute (global) minimum value of the function f(x) = x/(x^2 + 1) on the closed interval [-1, 1], we need to evaluate the function at the critical points and endpoints within the interval and determine the smallest value.

Step 1: Find the critical points by setting the derivative of f(x) equal to zero and solving for x:

f'(x) = [(1)(x^2 + 1) - (x)(2x)] / (x^2 + 1)^2

= (x^2 + 1 - 2x^2) / (x^2 + 1)^2

= (1 - x^2) / (x^2 + 1)^2

Setting f'(x) = 0:

1 - x^2 = 0

x^2 = 1

x = ±1

So, the critical points are x = -1 and x = 1.

Step 2: Evaluate the function at the critical points and endpoints:

f(-1) = (-1) / ((-1)^2 + 1) = -1/2

f(1) = (1) / ((1)^2 + 1) = 1/2

f(-1) = (-1) / ((-1)^2 + 1) = -1/2

Step 3: Compare the values to determine the minimum value.

From the calculations, we can see that the function attains its smallest value at x = -1 and x = 1, both yielding -1/2. Therefore, the absolute (global) minimum value of f(x) = x/(x^2 + 1) on the closed interval [-1, 1] is -1/2.

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Simplify. Write with positive exponents only. Assume (6x³/⁷y¹⁷/⁶ ) (2x²¹/⁴y¹/⁶) =

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For y, we have y¹⁷/⁶ * y¹/⁶. Similar to x, we add the exponents of y: 17/6 + 1/6, which equals 18/6 or simply 3. And, the expression becomes y³.

In this problem, we are asked to simplify the expression (6x³/⁷y¹⁷/⁶) (2x²¹/⁴y¹/⁶) by writing it with positive exponents only. We need to simplify the expression and combine the terms.

To simplify the given expression (6x³/⁷y¹⁷/⁶) (2x²¹/⁴y¹/⁶), we can combine the variables with the same base and add their exponents. For the variables x and y, we add the exponents separately.

For x, we have x³/⁷ * x²¹/⁴. To simplify this, we can add the exponents of x: 3/7 + 21/4. To add these fractions, we need a common denominator, which is 28. So, 3/7 becomes 12/28, and 21/4 becomes 147/28. Adding these fractions gives us 159/28. Therefore, the expression becomes x^(159/28).

For y, we have y¹⁷/⁶ * y¹/⁶. Similar to x, we add the exponents of y: 17/6 + 1/6, which equals 18/6 or simply 3. Therefore, the expression becomes y³.

Combining the simplified terms, the final expression is (6x^(159/28)) (y³).

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The movement of an object attached to a spring with no friction and with an oscillating external force is modeled by the following differential equation:
(d²y/dt²) + w²y = sin(wt).
where w is positive constant. Use the method of undetermined coefficients to find the general solution of the above equation (in terms of w).

Answers

The general solution of the given differential equation, (d²y/dt²) + w²y = sin(wt), using the method of undetermined coefficients, can be summarized as follows: The general solution consists of the complementary function, which represents the solution to the homogeneous equation, and the particular integral, which represents the solution to the non-homogeneous equation.

For the complementary function, the general solution is y_c = A*cos(wt) + B*sin(wt), where A and B are arbitrary constants. For the particular integral, assuming a particular solution of the form y_p = C*sin(wt + φ), where C and φ are constants to be determined, and substituting it into the differential equation, we find that C = 1/(1-w²) and φ = -π/2. Therefore, the general solution of the given differential equation is y = y_c + y_p = A*cos(wt) + B*sin(wt) + (1/(1-w²))*sin(wt + φ), where A, B, and w are  positive constants.

To find the general solution, we begin by solving the homogeneous equation (d²y/dt²) + w²y = 0. The characteristic equation is λ² + w² = 0, which yields the complex roots λ = ±iw. Using Euler's formula, we can express the complementary function as y_c = A*cos(wt) + B*sin(wt), where A and B are arbitrary constants.

Next, we look for a particular solution to the non-homogeneous equation in the form y_p = C*sin(wt + φ). Substituting this into the differential equation, we have (d²y_p/dt²) + w²y_p = -C*w²*sin(wt + φ) + w²*C*sin(wt + φ) = sin(wt). To satisfy this equation, we must have -C*w²*sin(wt + φ) + w²*C*sin(wt + φ) = sin(wt). By comparing the terms on both sides, we find that C = 1/(1-w²) and φ = -π/2.

Therefore, the particular integral is y_p = (1/(1-w²))*sin(wt - π/2). Combining the complementary function and the particular integral, we obtain the general solution as y = y_c + y_p = A*cos(wt) + B*sin(wt) + (1/(1-w²))*sin(wt - π/2), where A, B, and w are positive constants. This represents the complete solution to the given differential equation, incorporating the oscillating external force.

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Solve the following equations using Gaussian elimination. Write the row operation you used next to the row. 4x + 2y + 2z -7 2x + y - 4z = -1 x-7z = 2.

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To solve the given system of equations using Gaussian elimination, row operations are performed to reduce the system to row-echelon form. The goal is to eliminate variables and create a triangular system that can be easily solved.

The given system of equations is:

4x + 2y + 2z = -7 -- (1)

2x + y - 4z = -1 -- (2)

x - 7z = 2 -- (3)

To solve this system using Gaussian elimination, we perform row operations to eliminate variables. The goal is to transform the system into a triangular form.

Step 1: Multiply equation (1) by 2 and subtract equation (2) from it.

Row operation: R1 = 2R1 - R2

New system:

4x + 2y + 2z = -7 -- (1)

0x + 3y + 10z = -5 -- (2)

x - 7z = 2 -- (3)

Step 2: Multiply equation (1) by 1/4.

Row operation: R1 = (1/4)R1

New system:

x + (1/2)y + (1/2)z = -7/4 -- (1)

0x + 3y + 10z = -5 -- (2)

x - 7z = 2 -- (3)

Step 3: Multiply equation (1) by 3/2 and subtract equation (2) from it.

Row operation: R1 = (3/2)R1 - R2

New system:

x + (1/2)y + (1/2)z = -7/4 -- (1)

0x + 3y + 10z = -5 -- (2)

x - 7z = 2 -- (3)

At this point, we have a triangular system that can be easily solved. By back-substitution, we can find the values of x, y, and z:

From equation (3), x = 2 + 7z

Substitute this value into equation (1):

2 + 7z + (1/2)y + (1/2)z = -7/4

Simplifying the equation gives:

(15/2)z + (1/2)y = -15/4

From equation (2), 3y + 10z = -5

Solving these two equations simultaneously will give the values of y and z, which can then be substituted back into any of the original equations to find the value of x.

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1. Suppose that X and Y have a continuous joint distribution for which the joint p.d.f. is as follows: f(x, y) = x+y, for 0≤x≤ 1,0 ≤ y ≤ 1, otherwise. (a) Find E(YX) and Var(YX). (b) If it is

Answers

We can conclude that the joint PDF given in the question is not valid.

Given that the joint PDF is:f(x, y) = x+y, for 0≤x≤ 1,0 ≤ y ≤ 1, otherwise

(a) Find E(YX) and Var(YX):To find E(YX), we can use the formula: E(YX) = ∫∫ yx f(x,y) dydx

And to find Var(YX), we can use the formula:

Var(YX) = E(Y^2 X^2 ) - [E(YX)]^2a)

Now, let's find E(YX) as follows:

E(YX) = ∫∫ yx f(x,y) dydx= ∫0¹ ∫0¹ yx(x+y) dydx= ∫0¹ x ∫0¹ y(x+y) dydx+ ∫0¹ x ∫0¹ x(x+y) dydx= ∫0¹ x [(1/2)(x + 1)^2] dx + ∫0¹ x [(1/2)(x^2 + x)] dx= (1/6) + (1/4) = 5/12

Therefore, E(YX) = 5/12

Now, let's find Var(YX) as follows:

Var(YX) = E(Y^2 X^2 ) - [E(YX)]^2= ∫0¹ ∫0¹ y^2 x^2 (x+y) dydx - [5/12]^2= ∫0¹ x^2 [(1/3)(x+1)^3] dx + ∫0¹ [(1/3)x^2 (x^2 + 2x)] dx - [5/12]^2= (1/60) + (1/40) - 25/144= (1/60) - (5/36)= -1/90

Therefore, Var(YX) = -1/90b)

We know that Var(YX) must be non-negative because it is a variance, but the value we got in part (a) is negative.

Therefore, we can conclude that the joint PDF given in the question is not valid.

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Which is a zero of the function f(x)= x^ - 3x - 4

a) -4
b) -1
c) 0
d) 1

Answers

Answer:

B) -1

Step-by-step explanation:

[tex]f(x)=x^2-3x-4\\0=x^2-3x-4\\0=(x-4)(x+1)\\x=4,-1[/tex]

Therefore, B is the best choice

A fair coin is tossed; if heads come up x₁(t) = cos (5лt) is sent. If tails come up x2(t)= 6t is sent. The resulting random process X(t) is the ensemble of the realizations of a sine wave and a ramp. Find the mean and the variance of X(t) at t=0, 1/5, and 1/10q

Answers

To find the mean and variance of the resulting random process X(t) at t = 0, 1/5, and 1/10, we need to consider the probabilities of getting heads and tails and the corresponding signals sent.

Given:

If heads come up, x₁(t) = cos(5πt)

If tails come up, x₂(t) = 6t

Let's calculate the mean and variance at each specific time point:

At t = 0:

P(heads) = P(tails) = 0.5

Mean at t = 0:

E[X(0)] = P(heads) * E[x₁(0)] + P(tails) * E[x₂(0)]

= 0.5 * cos(5π * 0) + 0.5 * 6 * 0

= 0.5 * 1 + 0

= 0.5

Variance at t = 0:

Var[X(0)] = P(heads) * Var[x₁(0)] + P(tails) * Var[x₂(0)]

= 0.5 * Var[cos(5π * 0)] + 0.5 * Var[6 * 0]

= 0.5 * Var[1] + 0.5 * Var[0]

= 0.5 * 0 + 0.5 * 0

= 0

At t = 1/5:

P(heads) = 0.5

P(tails) = 0.5

Mean at t = 1/5:

E[X(1/5)] = P(heads) * E[x₁(1/5)] + P(tails) * E[x₂(1/5)]

= 0.5 * cos(5π * 1/5) + 0.5 * 6 * (1/5)

= 0.5 * cos(π) + 0.5 * 6/5

= 0.5 * (-1) + 0.5 * 6/5

= -0.5 + 0.6

= 0.1

Variance at t = 1/5:

Var[X(1/5)] = P(heads) * Var[x₁(1/5)] + P(tails) * Var[x₂(1/5)]

= 0.5 * Var[cos(5π * 1/5)] + 0.5 * Var[6 * (1/5)]

= 0.5 * Var[cos(π)] + 0.5 * Var[6/5]

= 0.5 * Var[-1] + 0.5 * Var[1.2]

= 0.5 * 0 + 0.5 * 0

= 0

At t = 1/10:

P(heads) = 0.5

P(tails) = 0.5

Mean at t = 1/10:

E[X(1/10)] = P(heads) * E[x₁(1/10)] + P(tails) * E[x₂(1/10)]

= 0.5 * cos(5π * 1/10) + 0.5 * 6 * (1/10)

= 0.5 * cos(π/2) + 0.5 * 6/10

= 0.5 * 0 + 0.5 * 0.6

= 0.3

Variance at t = 1/10:

Var[X(1/10)] = P(heads) * Var[x₁(1/10)] + P(tails) * Var[x₂(1/10)]

= 0.5 * Var[cos(5π * 1/10)] + 0.5 * Var[6 * (1/10)]

= 0.5 * Var[cos(π/2)] + 0.5 * Var[0.6]

= 0.5 * Var[0] + 0.5 * Var[0.6]

= 0

In summary, the mean and variance of the resulting random process X(t) at t = 0, 1/5, and 1/10 are:

At t = 0:

Mean = 0.5

Variance = 0

At t = 1/5:

Mean = 0.1

Variance = 0

At t = 1/10:

Mean = 0.3

Variance = 0

Please note that the variances are all zero because the signals being added (cosine and ramp) are deterministic and have no randomness.

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We wish to determine the average GPA of students with Day Care provided by the college, What level of confidence would you use? Explain your answer.__ C=.90, 95, 99 (circle one) _.99 I I choose this confidence level because think this is a really important question_

Answers

In choosing the level of confidence for estimating the average GPA of students with Day Care provided by the college, it is important to consider the trade-off between precision and confidence.

A higher level of confidence requires a wider confidence interval, which means the estimate will be less precise.

Given the information provided, you have circled 99 as the desired level of confidence. A 99% confidence level would be appropriate if you prioritize a high level of confidence in the estimate, even if it comes at the expense of a wider confidence interval and slightly less precision. This confidence level implies that if you were to repeat the sampling and estimation process multiple times, 99% of the resulting confidence intervals would contain the true average GPA of students with Day Care.

While a 99% confidence level offers a high degree of certainty, it's important to note that it comes with a wider margin of error compared to lower confidence levels. If precision is of utmost importance and you are willing to accept a slightly lower level of confidence, you could consider using a lower confidence level such as 90% or 95%. This would result in narrower confidence intervals and a more precise estimate.

Ultimately, the choice of confidence level depends on the specific requirements of your study, the importance of the question being addressed, and the acceptable trade-off between precision and confidence in the estimated average GPA of students with Day Care.

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please make answer legible and thank you
Find the equation of the tangent line to y = 2²-2x+¹ at x = 4. y =

Answers

The equation of the tangent line to the curve at the point (x, y) = (3, 17) is y = 25 · x - 58.

A line is tangent to the curve when it intercepts the curve in only one point.

According to analytical geometry, the equation of the line in explicit form is described by the following expression:

y = m · x + b

Where:

m - Slope

b - Intercept

The slope of the tangent line is the first derivative of the equation of the curve evaluated at the given point.

Slope

m = 3 · x² - 2

m = 3 · 3² - 2

m = 27 - 2

m = 25

Intercept

b = y - m · x

b = 17 - 25 · 3

b = 17 - 75

b = - 58

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Find the equation of the tangent line to the curve y = x³ - 2x - 4 at the point (3, 17).

please help me with this question

Answers

The correct simplified form of the expression is x + 5.

a) The mistake that Hannah has made is incorrectly combining the terms 3x and -2x. Instead of subtracting the coefficients of x, she subtracted the entire expression 2x from 3x.

b) To simplify the expression correctly, we need to combine like terms. In this case, the like terms are the ones with the variable x.

The expression 3x + 5 - 2x can be rewritten as (-2x + 3x) + 5.

Now, let's combine the like terms:

(-2x + 3x) + 5 = x + 5

Therefore, the correct simplified form of the expression is x + 5.

To further clarify, Hannah mistakenly thought that subtracting 2x from 3x would result in 1x (or just x). However, when subtracting or adding terms with the same variable, we need to consider the coefficients. In this case, 3x - 2x simplifies to x, not 1x.

It's important to pay attention to the signs and operations when combining terms. In this scenario, Hannah overlooked the need to subtract the coefficients of x and ended up with an incorrect result.

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If 3x + 5,000 = 6x + 10,000, what is the value of x ?

Answers

The value of x is approximately -1,666.67.

To find the value of x in the equation 3x + 5,000 = 6x + 10,000, we can solve for x by isolating it on one side of the equation.

Let's begin by simplifying the equation:

3x + 5,000 = 6x + 10,000

We can start by moving the terms involving x to one side:

3x - 6x = 10,000 - 5,000

Combining like terms:

-3x = 5,000

Now, we can solve for x by dividing both sides of the equation by -3:

x = 5,000 / -3

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The manager of the city pool has scheduled extra lifeguards to be on staff for Saturdays. However, he suspects that Fridays may be more popular than the other weekdays as well. If so, he will hire extra lifeguards for Fridays, too. In order to test his theory that the daily number of swimmers varies on weekdays, he records the number of swimmers each day for the first week of summer. Test the manager's theory at the 0.10 level of significance. Swimmers at the City Pool Monday Tuesday Wednesday Thursday Friday 56 46 68 67 70 Number Copy Data Step 2 of 4: Calculate the expected value for the number of swimmers on Thursday. Enter your answer as a fraction or a decimal rounded to three decimal places.

Answers

The expected value for the number of swimmers on Thursday, based on the average number of swimmers across all weekdays, is 61.4.



To test the manager's theory, we need to compare the observed number of swimmers on each weekday with the expected number of swimmers. We will use a chi-square test of independence to determine if there is a significant difference in the number of swimmers on different weekdays.

First, let's calculate the expected value for the number of swimmers on Thursday.

To do this, we need to find the average number of swimmers across all weekdays. We'll sum up the number of swimmers from Monday to Friday and divide it by the number of weekdays (5 in this case) to get the average:

(56 + 46 + 68 + 67 + 70) / 5 = 307 / 5 = 61.4

The expected value for Thursday would be the same as the average number of swimmers:

Expected value for Thursday = 61.4 (rounded to three decimal places)

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A school administrator wants to see if there is a difference in the number of students per class for Bloomington Public School district (group 1) compared to the Lakeville School district (group 2). A random sample of 27 Bloomington classes found a mean of 33 students per class with a standard deviation of 6. A random sample of 26 Lakeville classes found a mean of 32 students per class with a standard deviation of 5. Assume all conditions are met for inference. Find a 95% confidence interval in the difference of the means.

Answers

The interval will provide an estimated range within which the true difference in means between the two school districts is likely to fall with 95% confidence interval.

The administrator can use the formula for constructing a confidence interval for the difference in means:[tex]CI = (X1 - X2) \pm (Z\times \sqrt{((s_1^2/n_1) + (s_2^2/n_2))})[/tex]

Where:

- CI is the confidence interval

- X1 and X2 are the sample means of group 1 (Bloomington) and group 2 (Lakeville), respectively

- Z is the critical value for the desired confidence level (in this case, 95%)

- s1 and s2 are the sample standard deviations of group 1 and group 2, respectively

- n1 and n2 are the sample sizes of group 1 and group 2, respectively

Substituting the given values into the formula, the administrator can calculate the confidence interval for the difference in means. This interval will provide an estimated range within which the true difference in means between the two school districts is likely to fall with 95% confidence.

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Find the exact values of the six trigonometric functions of the angle. -675° sin(-675°) = cos(-675°) = tan(-675°) = (Simplif.

Answers

The answer is -1. Thus, it is equal to 360° - 675° = -315°.So, the values of six trigonometric functions of angle -675° are as follows: sin(-675°)

= sin(-315°)

= -sin(315°) =

-1/√2 ≈

-0.707cos(-675°) = cos(-315°)

= cos(315°)

= 1/√2

≈ 0.707tan(-675°)

= tan(-315°)

= -tan(45°)

= -1cot(-675°)

= cot(-315°)

= -cot(45°) = -1

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Determine whether or not the below series converges or diverges. If it converges, then give rea- sons as to why it converges and find its value. If it diverges, then give reasons as to why it diverges and tell the nature of its divergence. That is, if it diverges, does it diverge to infinity, or does it oscillate and never reaches a definite end point? 1 k(k + 2) k=1

Answers

The sum of the given series is n(n+1)(n+4) / 3."

Series converges or diverges The given series is ∑1 k(k + 2) k=1.

To determine whether or not the given series converges or diverges, one can use the comparison test which is given as follows:

Let aₙ and bₙ be two series such that 0 ≤ aₙ ≤ bₙ for all n and the series ∑bₙ is convergent.

Then, the series ∑aₙ is convergent.

The given series can be compared to the series ∑1 k² k=1,

since k(k + 2) ≤ k² for all k.

Hence,∑1 k(k + 2) k=1 ≤ ∑1 k² k=1.

Here, ∑1 k² k=1 is a convergent series with the sum given by the formula ∑1 k² k=1

= n(n+1)(2n+1) / 6.

Therefore, by the comparison test, the series ∑1 k(k + 2) k=1 is also convergent.

Moreover, to find the sum of the given series, we can simplify the expression k(k + 2) as k² + 2k.

Hence, the series can be written as ∑k² + 2k k=1.

Using the formula for the sum of first n squares, we have ∑k² k=1 = n(n+1)(2n+1) / 6,and using the formula for the sum of first n natural numbers, we have ∑k k=1 = n(n+1) / 2.

Hence, ∑k² + 2k k=1 = ∑k² k=1 + 2 ∑k k=1= n(n+1)(2n+1) / 6 + n(n+1) = n(n+1)(n+4) / 3.

Therefore, the sum of the given series is n(n+1)(n+4) / 3.

The given series is ∑1 k(k + 2) k=1.

We can use the comparison test to determine whether or not the given series converges or diverges.

We compare it to the series ∑1 k² k=1,

since k(k + 2) ≤ k² for all k.

Hence, ∑1 k(k + 2) k=1 ≤ ∑1 k² k=1. Here, ∑1 k² k=1 is a convergent series with the sum given by the formula ∑1 k² k=1 = n(n+1)(2n+1) / 6.

Therefore, by the comparison test, the series ∑1 k(k + 2) k=1 is also convergent.

Moreover, to find the sum of the given series, we can simplify the expression k(k + 2) as k² + 2k.

Hence, the series can be written as ∑k² + 2k k=1. Using the formula for the sum of first n squares,

we have ∑k² k=1 = n(n+1)(2n+1) / 6, and using the formula for the sum of first n natural numbers,

we have ∑k k=1 = n(n+1) / 2.

Hence, ∑k² + 2k k=1 = ∑k² k=1 + 2 ∑k k=1= n(n+1)(2n+1) / 6 + n(n+1)

= n(n+1)(n+4) / 3.

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Suppose that a matrix A has the characteristic polynomial (λ+1)³ (a λ + λ² + b) for some a, b € R.
If the trace of A is 4 and the determinant of A is -6, find all eigenvalues of A. (a) Enter the eigenvalues as a list in increasing order, including any repetitions. For example, if they are 1,1,0 you would enter 0,1,1:
(b) Hence determine a:
(c) and b:

Answers

(a) The eigenvalues of matrix A are -1, -1, and -1, corresponding to the three factors of the characteristic polynomial (λ+1)³.

(b) The trace of a matrix is the sum of its eigenvalues. Since the trace of A is 4, we have -1 + -1 + -1 = 4. Therefore, the sum of the eigenvalues is 4.

(c) The determinant of a matrix is the product of its eigenvalues. The determinant of A is -6, so we have (-1) * (-1) * (-1) = -6. Therefore, the product of the eigenvalues is -6.

To determine the value of a, we need to consider the quadratic factor in the characteristic polynomial, (aλ + λ² + b). Since we know that the eigenvalues are -1, -1, and -1, we can substitute these values into the quadratic factor:

(-1) * (-1) + a * (-1) + b = 0

1 - a + b = 0

To determine the value of b, we can use the fact that the determinant is the product of the eigenvalues:

-1 * -1 * -1 = -6

-1 = -6

Therefore, b = -6.

Now we can substitute the values of a and b into the equation we obtained earlier to find a:

1 - a + (-6) = 0

-a - 5 = 0

a = -5

So, the value of a is -5 and the value of b is -6.

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students in the journalist class at o’henry high school conducted a survey. they ask 25 students to monitor their texting for one month. at the end of the month, each report his or her average daily text for the month the results of the survey are shown in the table

Answers

A dot plot that represent this data set is shown in the image attached below.

What is a dot plot?

In Mathematics and Statistics, a dot plot can be defined as a type of line plot that is typically used for the graphical representation of a data set above a number line, especially through the use of crosses or dots.

Based on the information provided about this high school survey, we can reasonably infer and logically deduce that the average daily text for the month with the highest frequency is 300.

In this scenario, we would use an online graphing calculator to construct a dot plot with respect to a number line that accurately fit the data set.

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The competitors in the 'under 16' age group think the triathlon course was particularly difficult compared with previous events and so the mean time to complete this event was slower than usual. They claim that the population mean time to complete the triathlon for the under 16 age group is 59.5 minutes. The results for the 'under 16' class of competitors have been extracted from the file winter.mwx and saved in a new file under16.mwx. (a) Write down suitable null and alternative hypotheses to test the theory that the population mean time for under 16's to complete the triathlon is 59.5 minutes. State clearly the meaning of any symbols that you use. (b) Using the data in under16.mwx, carry out a one-sample t-test to test the hypotheses that you wrote down in part (a). In your answer, make sure to include the following: • the estimated standard error • the value of the test statistic • the p-value or the values of CV5 and CV1 what conclusions can be drawn from the results of this test. (c) Calculate by hand the 95% confidence interval for the population mean time taken for under 16s to complete the triathlon based on the t-test. Show your working. (d) Would a 90% confidence interval for the population mean time taken for under 16s to complete the triathlon be wider or narrower than the 95% confidence interval that you calculated in part (c).

Answers

(a) Null hypothesis (H₀): The population mean time for under 16's to complete the triathlon is 59.5 minutes.

Alternative hypothesis (H₁): The population mean time for under 16's to complete the triathlon is not equal to 59.5 minutes.

(b) Conducting a one-sample t-test using the data from under16.mwx, we can calculate the estimated standard error, the test statistic, and the p-value or critical values (CV5 and CV1). Based on these results, conclusions can be drawn regarding the hypotheses.

(c) By hand, calculate the 95% confidence interval for the population mean time taken for under 16s to complete the triathlon based on the t-test. Show working.

(d) A 90% confidence interval for the population mean time taken for under 16s to complete the triathlon would be narrower than the 95% confidence interval calculated in part (c).

(a) The null hypothesis (H₀) states that the population mean time for under 16's to complete the triathlon is 59.5 minutes. The alternative hypothesis (H₁) states that the population mean time for under 16's to complete the triathlon is not equal to 59.5 minutes. In symbols:

H₀: μ = 59.5 (where μ represents the population mean time)

H₁: μ ≠ 59.5

(b) To test the hypotheses, a one-sample t-test is conducted using the data from the under16.mwx file. The estimated standard error measures the variability of the sample mean around the hypothesized population mean. The test statistic is calculated by dividing the difference between the sample mean and the hypothesized population mean by the estimated standard error. The p-value or critical values (CV5 and CV1) are used to determine the significance of the test. Based on the calculated test statistic and p-value or critical values, conclusions can be drawn about the hypotheses.

(c) To calculate the 95% confidence interval for the population mean time taken for under 16s to complete the triathlon, the t-test is used. The formula for the confidence interval is:

Confidence interval = sample mean ± (t-value * standard error)

The t-value is obtained from the t-distribution table or calculated using software, and it corresponds to the desired confidence level and degrees of freedom. The standard error is the estimated standard error from the t-test. By substituting these values into the formula, the lower and upper bounds of the confidence interval can be determined.

(d) A 90% confidence interval for the population mean time taken for under 16s to complete the triathlon would be narrower than the 95% confidence interval calculated in part (c). This is because a higher confidence level requires a wider interval to capture a higher percentage of the population. In contrast, a lower confidence level allows for a narrower interval as it needs to capture a smaller percentage of the population.

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Fill in each blank so that the resulting statement is true. √-147 = __√147 = __√493 = __√3 Fill in each answer box so that the resulting statement is true. √-147 = __√147 = __√493 = __√3 (Simplify your answer)

Answers

To fill in the blanks and make the resulting statements true, we need to simplify the given square root expressions. The original expressions involve the square roots of negative numbers and irrational numbers, which require further simplification.

√-147:

The square root of a negative number is not a real number. Therefore, we cannot simplify √-147 further, and it remains as √-147.

√147:

To simplify the square root of 147, we can factorize the number into its prime factors: 147 = 3 * 49. Taking the square root of 147, we have √147 = √(3 * 49). Since 49 is a perfect square (7 * 7), we can simplify further: √147 = 7√3.

√493:

To simplify the square root of 493, we can factorize the number into its prime factors: 493 = 17 * 29. Taking the square root of 493, we have √493 = √(17 * 29). Since both 17 and 29 are prime numbers, we cannot simplify further, and the expression remains as √493.

√3:

The square root of 3 is an irrational number and cannot be simplified further. Therefore, √3 remains as √3.

In conclusion:

√-147 cannot be simplified further.

√147 can be simplified to 7√3.

√493 cannot be simplified further.

√3 cannot be simplified further.

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20% of a number is 5.Find a quarter of the number

Answers

Answer:

6.25

Step-by-step explanation:

5 is 20%

so to get 100% , multiply by 5  (20% x 5 = 100%)

5 x 5 = 25

The number is 25

To find a quarter , divide by 4 .

25 / 4 = 6.25

Answer:

To find a quarter of the number, we can use the following steps:

1. Write the given information as a fraction: 20% of a number is 5 means 20/100 * x = 5, where x is the number we want to find.

2. Solve for x by multiplying both sides by 100/20: x = 5 * 100/20 = 25. This means the number is 25.

3. Find a quarter of the number by dividing it by 4: 25 / 4 = 6.25. This means a quarter of the number is 6.25.

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compute the winner of each match is the team who has the highest
score. the team that is winner scores 3 and 1 point for a draw and
the team with the most points at the end of the season is the
winner

Answers

It is clear that the team that has accumulated the most points by the end of the season is declared the winner.

The winner of each match is the team who has the highest score. The team that is the winner scores 3 points, and 1 point is for a draw. The team with the most points at the end of the season is the winner. The league system is a format in which teams compete against each other in a regular season, with the team with the most points being crowned the winner at the end of the season.

When two teams compete against each other in a match, the winner of the match is the team that has the most points at the end of the match.

This typically means that the team with the most goals is the winner, although some leagues may use other criteria to determine the winner, such as the number of corners, free kicks, or other statistical measures . For each win, a team gets three points. In a case where both teams score the same number of goals, the match ends in a draw, and each team receives one point.

For example, let us assume that Team A won 10 matches, drew three, and lost five matches. If Team B won eight matches, drew five, and lost five matches, Team A would be declared the winner because they had 33 points (10 x 3 points for a win + 3 x 1 point for a draw), while Team B had only 29 points (8 x 3 points for a win + 5 x 1 point for a draw).

Therefore, it is clear that the team that has accumulated the most points by the end of the season is declared the winner.

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A company runs food service concessions for sporting events throughout the country. The marketing research department chose a particular football stadium to test market a new Jimbo hot dog was found that the demand for the new hot dog is given approximately by
p = 4-In(x), S≤x≤500
where as the number of hot dogs in thousands; that can be sold during one game at a price of p dollars. If the company pays 1 dollar for each hot dog, how should the hot dogs be priced to the profit per game?
Price

Answers

To determine the price at which the company should sell the hot dogs to maximize profit per game, we need to consider the demand function and the cost function.

The demand function is given by:

p = 4 - ln(x)

Here, p represents the price in dollars and x represents the number of hot dogs in thousands. The demand function indicates that as the price increases, the demand decreases.

The cost function can be expressed as:

C = 1x

Here, C represents the cost in dollars per hot dog, and since the company pays $1 for each hot dog, the cost function is simply equal to the number of hot dogs sold.

To maximize profit, we need to find the price (p) that maximizes the difference between revenue and cost. The revenue can be calculated by multiplying the price (p) by the number of hot dogs sold (x), which is expressed as Rx = xp.

The profit function (P) can be expressed as:

P = Rx - C

= xp - x

To maximize profit, we need to find the value of x that maximizes the profit function.

Taking the derivative of the profit function with respect to x and setting it equal to zero, we can find the critical points:

dP/dx = dp/dx * x + p - 1 = 0

Substituting the value of p from the demand function:

dp/dx * x + (4 - ln(x)) - 1 = 0

Solving this equation for x analytically is challenging. However, we can use numerical methods or approximation techniques to find the approximate value of x that maximizes the profit function.

Once we find the value of x, we can substitute it into the demand function to find the corresponding price (p) at which the hot dogs should be priced to maximize profit per game.

Without further information or calculations, it is not possible to provide the exact price at which the hot dogs should be priced to maximize profit per game.

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piecewise function g of x is equal to the piecewise function of the quantity x squared plus 3 times x end quantity over the quantity x squared plus x minus 6 end quantity for x is less than 3 and the function log in base 2 of the quantity x plus 5 end quantity for x is greater than or equal to 3 question mark
(–[infinity], [infinity])
(–[infinity], 2) ∪ (2, [infinity])
(–[infinity], 2) ∪ (2, 3) ∪ (3, [infinity])
(–[infinity], –3) ∪ (–3, 2) ∪ (2, [infinity])

Answers

The correct choice is (–∞, 2) ∪ (2, ∞), which represents the domain of the function g(x) based on the given piecewise definition.

The piecewise function g(x) is defined as follows:

For x < 3:

g(x) = (x^2 + 3x) / (x^2 + x - 6)

For x ≥ 3:

g(x) = log₂(x + 5)

To determine the domain of the function g(x), we need to consider the restrictions imposed by the individual pieces of the function.

In the first piece, g(x) is defined as a rational function, which means the denominator cannot be equal to zero. So we need to find the values of x that make the denominator (x^2 + x - 6) equal to zero and exclude those values from the domain.

Factoring the denominator, we have:

(x^2 + x - 6) = (x - 2)(x + 3)

Setting the denominator equal to zero, we find:

(x - 2)(x + 3) = 0

This equation gives us two values for x: x = 2 and x = -3. Therefore, the rational function is undefined at x = 2 and x = -3, and we need to exclude these values from the domain.

Next, we consider the second piece of the function. The logarithmic function is defined for positive values of the argument, so we need to ensure that (x + 5) > 0 for x ≥ 3.

Solving the inequality (x + 5) > 0, we find x > -5. Since x is restricted to be greater than or equal to 3, the inequality is satisfied.

Combining these results, we determine that the domain of the function g(x) is the interval (–∞, 2) ∪ (2, ∞) for x < 3, and the interval [3, ∞) for x ≥ 3.

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EXAMPLE 2 The set {sint, cost} is linearly independent in C[0, 1], the space of all continuous functions on 0 ≤ t ≤ 1. Explain why?

Answers

The set {sine of t, cosine of t} forms a linearly independent set in C[0, 1] due to the fact that the sole method of representing the zero function as a linear combination of sine of t and cosine of t is by assigning a value of zero to each coefficient.

Why the set is linearly independent?

To prove this, we suppose that there exist constants a and b such that;

[tex]a sin t + b cos t = 0[/tex]

For t in [0, 1]. We can differentiate both sides of this equation with respect to t to get

[tex]a cos t - b sin t = 0[/tex]

Substitute equation (1), we have;

[tex]a cos t - b sin t = a sint + b cos t[/tex]

The equation holds true for any t only when both a and b have a value of zero. The  set {sint, cost} is therefore said to be linearly independent.

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Suppose the demand function for movies for college students is: Q₁ = 20-0.125p and for other town residents is: Q2 = 80-0.500p. The town's total demand function is: Q= 100-0.625p. Draw the following on the graph to the right. 1.) Use the line drawing tool to draw the demand curve for movies for college students. Label this line 'D₁'. 2.) Use the line drawing tool to draw the demand curve for other town residents. Label this line 'D₂'. 3.) Use the line drawing tool to draw the total demand curve. Label this line 'D'. Carefully follow the instructions above, and only draw the required objects.

Answers

I can describe how the graphs would look based on the given information.

1. The demand curve for movies for college students, labeled 'D₁', can be drawn as a straight line with a negative slope. The equation for this demand curve is Q₁ = 20 - 0.125p, where Q₁ represents the quantity demanded by college students and p represents the price.

To draw the line, you can start at the point (0, 20) on the y-axis (where the quantity demanded is 20 when the price is 0) and then find another point on the line by using a different price value and calculating the corresponding quantity demanded. Connect these two points with a straight line, indicating the downward slope of the demand curve.

2. The demand curve for movies for other town residents, labeled 'D₂', can also be drawn as a straight line with a negative slope. The equation for this demand curve is Q₂ = 80 - 0.500p, where Q₂ represents the quantity demanded by other town residents.

Similarly, start at the point (0, 80) on the y-axis and find another point on the line by using a different price value and calculating the corresponding quantity demanded. Connect these two points with a straight line.

3. The total demand curve, labeled 'D', represents the combined demand of both college students and other town residents. The equation for the total demand curve is Q = 100 - 0.625p, where Q represents the total quantity demanded.

To draw the total demand curve, you can follow the same procedure as before. Start at the point (0, 100) on the y-axis and find another point on the line by using a different price value and calculating the corresponding total quantity demanded. Connect these two points with a straight line.

Remember that the demand curves will have a negative slope, indicating the inverse relationship between price and quantity demanded. The specific angles and positions of the lines will depend on the price values chosen.

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For each of the following, solve exactly for the variable .
(a) 1+x+x²+x³+.... = 4
x = ....
(b) x - (x^(3)/3!) + (x^(5)/5!) - .... = 0.9
x = ....

Answers

(a) The equation 1 + x + x² + x³ + ... is an infinite geometric series with a common ratio of x. To find the sum of the series, we can use the formula for the sum of an infinite geometric series: S = a / (1 - r), where a is the first term and r is the common ratio.

In this case, a = 1 and r = x. Plugging these values into the formula, we get S = 1 / (1 - x). Now, we need to find the value of x when the sum of the series equals 4x. Setting the equation 1 / (1 - x) = 4x, we can solve for x. The solution is x = 1/5.

(b) The equation x - (x^(3)/3!) + (x^(5)/5!) - ... represents an alternating series that converges to 0.9x. To find the value of x, we need to solve the equation x - (x^(3)/3!) + (x^(5)/5!) - ... = 0.9x. Since this is a convergent alternating series, we can use the formula for the sum of an infinite alternating series: S = a / (1 + r), where a is the first term and r is the common ratio. In this case, a = x and r = -x^(2)/2!. Plugging these values into the formula, we get S = x / (1 - x^(2)/2!). By setting S equal to 0.9x, we can solve for x. The solution is x = 0.9486.

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If the value of sinx 4 0≤x≤, the value of cosx within the same domain is:

Answers

There is no real value of cos(x) within the domain 0 ≤ x ≤ π/2 when sin(x) is equal to 4.

If the value of sin(x) is 4 for 0 ≤ x ≤ π/2, within the same domain the value of cos(x) can be determined using the Pythagorean identity:

cos²ˣ + sin²ˣ  = 1.

Given sin(x) = 4, we can square both sides to get:

(4)² + sin²ˣ  = 1,

16 + sin²ˣ  = 1,

sin²ˣ  = 1 - 16,

sin²ˣ  = -15.

Since sin²ˣ  cannot be negative for real values of x, there is no real solution for cos(x) within the specified domain when sin(x) = 4.

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Statistics Exercise sheet 10 1. In a survey on consumption and dietary habits, 317 people were asked about their use of nicotine and caffeine. The respondents were divided into smokers and non-smokers (less than 5 cigarettes per week) as well as into coffee drinkers (more than one cup per day) and non-coffee drinkers: Nicotine Coffee smokers Coffe drinkers 100 39 non-smokers 103 75 Non-Coffe drinkers a) Calculate row and column percentages and interpret the results. b) Using a x² test at the 5% level of significance, test the null hypothesis that nicotine consump- tion is independent of caffeine consumption. (i) To do this, state the null and alternative hypotheses, (ii) calculate the frequencies expected under the null hypothesis, (iii) calculate the test statistic relevant to the test, (iv) compare the test statistic to the critical value, (v) interpret the test result. c) Unify your findings from the above points into a final interpretation.

Answers

a) For smokers, the row percentage of coffee drinkers is 0.4184, and for non-coffee drinkers, it is 0.5816.

For non-smokers, the row percentage of coffee drinkers is 0.5798, and for non-coffee drinkers, it is 0.4202.

For non-coffee drinkers, the column percentage of smokers is 139/239 ≈ 0.5816, and for non-smokers, it is 75/178 ≈ 0.4202.

b) The x² test is used to determine if nicotine consumption is independent of caffeine consumption, with the null hypothesis being independence and the alternative hypothesis being dependence.

c) The final interpretation depends on the results of the x² test, which will determine if there is a significant association between nicotine and caffeine consumption or if they are independent..

a) To calculate row and column percentages, we divide the frequency in each cell by the total number of respondents.

Row percentages:

For smokers, the row percentage of coffee drinkers is 100/239 ≈ 0.4184, and for non-coffee drinkers, it is 139/239 ≈ 0.5816.

For non-smokers, the row percentage of coffee drinkers is 103/178 ≈ 0.5798, and for non-coffee drinkers, it is 75/178 ≈ 0.4202.

Column percentages:

For coffee drinkers, the column percentage of smokers is 100/239 ≈ 0.4184, and for non-smokers, it is 103/178 ≈ 0.5798.

For non-coffee drinkers, the column percentage of smokers is 139/239 ≈ 0.5816, and for non-smokers, it is 75/178 ≈ 0.4202.

Interpretation: The row percentages provide the proportion of smokers or non-smokers among coffee drinkers or non-coffee drinkers. The column percentages provide the proportion of coffee drinkers or non-coffee drinkers among smokers or non-smokers. These percentages allow us to observe the distribution of nicotine and caffeine consumption within different groups.

b)

(i) Null hypothesis (H0): Nicotine consumption is independent of caffeine consumption.

Alternative hypothesis (Ha): Nicotine consumption is dependent on caffeine consumption.

(ii) To calculate the frequencies expected under the null hypothesis, we need to find the expected count for each cell. The expected count is calculated as (row total * column total) / total number of respondents.

Expected counts:

For smokers who are coffee drinkers: (239 * 175) / 317 ≈ 132.28

For smokers who are non-coffee drinkers: (239 * 142) / 317 ≈ 106.78

For non-smokers who are coffee drinkers: (178 * 175) / 317 ≈ 98.65

For non-smokers who are non-coffee drinkers: (178 * 142) / 317 ≈ 79.35

(iii) To calculate the test statistic relevant to the test, we use the chi-square (χ²) test statistic formula:

χ² = Σ [(Observed frequency - Expected frequency)² / Expected frequency]

(iv) We compare the test statistic to the critical value from the chi-square distribution with the appropriate degrees of freedom and the chosen level of significance (5% in this case).

(v) We interpret the test result by comparing the calculated test statistic to the critical value. If the calculated test statistic is greater than the critical value, we reject the null hypothesis and conclude that there is a significant association between nicotine consumption and caffeine consumption. If the calculated test statistic is not greater than the critical value, we fail to reject the null hypothesis and conclude that there is not enough evidence to support a significant association.

c) The final interpretation unifies the findings from parts a) and b). It would depend on the results of the chi-square test. If the test statistic is greater than the critical value, we would conclude that there is a significant association between nicotine consumption and caffeine consumption. If the test statistic is not greater than the critical value, we would conclude that there is not enough evidence to support a significant association and that nicotine consumption is independent of caffeine consumption.

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please answer questions questions 2-5 as they all pertain to
the same question!
PROBLEM 2: A sample consists of the following N=3 scores: 0, 4, 12. Step 1: Compute the mean and SD for the sample (HINT: is the mean the same as above? Is the SS the same as above? What about the VAR

Answers

Hence, the answer is YES. The answer to "Is the SS the same as above?" is NO. The answer to "What about the VAR?" is the variance is different, so the new standard deviation will also be different.

Given, N=3 scores: 0, 4, 12

Step 1:

Compute the mean and SD for the sample

To calculate the mean, we need to add up all the scores and divide the total by the number of scores. So, the mean is given by;

(0+4+12)/3 = 16/3 = 5.33

To calculate the standard deviation (SD), we need to first calculate the variance (VAR). Variance is the average of the squared differences from the mean, while the standard deviation is the square root of the variance. We can use the following formula to calculate variance;

Var = [(x₁ - μ)² + (x₂ - μ)² + ... + (xₙ - μ)²] / N

Substituting the values we get;

Var = [(0 - 5.33)² + (4 - 5.33)² + (12 - 5.33)²] / 3

Var = 42.22/3

Var = 14.07

To get the SD, we take the square root of the variance;

SD = √Var

SD = √14.07

SD = 3.75

Therefore, the mean of the sample is 5.33 and the standard deviation is 3.75.

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Let X be the random variable of the number of times this robot is able to succeed in completing i the task. a. What type of distribution can be used for the random variable X? What are it's parameters? b. What is the expected number of times the robot will succeed? What is the variance? c. What is the probability that the robot succeeds less than or equal to 80 times? d. Use the compliment rule to reduce the number of operations needed in part c. Find another way to compute the needed probability. e. Now say two robots are going to attempt the same task. The robots operate independently from one another. What is the probability that both robots succeed less than or equal to 80 times out of 100? f. Now say the single robot begins to learn the more it tries. That is to say, it gets better at succeeding at the task the more it tries. Can the distribution from part a. still be used? In a sentence or two explain why or why not. 4. Now say the same robot from question 5 is used. Now we are interested in how many times the robot has to attempt the task before it succeeds. Assume the same scenario from question 5, the robot does not remember its attempts and the probability of success on a given trial is 0.85. Let X be the number of attempts the robot needs before it completes the task. a. What is the support of X? b. What is the expected number of attempts the robot needs before it succeeds? What is the variance? Would you expect to need to let the robot attempt the task many times before it succeeds? c. What is the probability that the robot needs more than 2 attempts to succeed at the task? d. Say a robot consumes 2 batteries on each attempt as a power source. Also, say that we now have two independent robots. How many batteries should we expect to be used before both robots complete the task (each robot has the same task, and attempts the task independently)? graph the line passing through (4,1) whose slope is m=-4/5 A cube of brass has sides of 0.10 m. a. Draw the situation. b. Determine the applied tangential force to displace the top of the block 1.2x 10 5 m given that S brass =3.510 10 N/m 2 . iid geometric(0), where we model the number of failures until the first success: P(X = x|0) = 0(1-0), for x = 1, 2, 3, . . . Consider the following questions: a. Determine the family of conjugate prio BestBurger has determined that their business unit devoted to French fries is a star according to the Boston Consulting Group growth-share matrix. Which of the following strategies will likely produce the best results?Group of answer choicesRaise the costs of the fries to increase profits.Immediately divest from French fries, and focus on onion ringsHarvest as much cash as possible from the fries before shutting the business unit downIncrease the investment in promoting the fries to encourage future growth Which construction sector has the highest establishment failure rate? A) Specialty contractors B) Heavy and civil construction C) Residential OD) Non-residential building Suppose the short-run production function is q = 10L2. Suppose that the wage rate is $110 per unit of labor. What is the marginal cost at q = 253? Your Answer: QUESTION 14Areej invested BD 14000 12 years ago, today this investment is worth BD 52600, based on this what annualced cats has Pred tedO a. 11.66%O b. 2.75%O c. 17.43%O d. 8.91% Which of the following is responsible for the change in dynamic instability in microtubules during mitosis?A. Phosphorylation of a protein with microtubule stabilizing activity, which results in decreased microtubule stability.B. Phosphorylation of a protein with microtubule destabilizing activity, which results in increased microtubule stability.C. Dephosphorylation of a protein with microtubule destabilizing activity, which results in increased microtubule stability.D. Dephosphorylation of a protein with microtubule stabilizing activity, which results in decreased microtubule stability. . What are the key issues to be considered when designing gain-sharing plans?2. What issues should you consider when designing a goal-sharing plan for a group of sales employees?3. Discuss are pros and cons of non-monetary reward programs? List at least three special considerations when seekinginternational sources of materials. Compare how each differs fromdoing business only within the United States. Here is a bivariate data set looking at the change in web traffic (y) (1000s of visits) over a certain amount of time (x). seconds change in web traffic 43.7 48 72.1 -17.2 70 -19.4 19.4 152.8 40.4 75.